Answer:
8 hours
Step-by-step explanation:
72 miles per hour
576/72= 8
1. A relation contains the ordered pairs shown. One of the ordered pairs is missing an x-coordinate. {(-1,4),(0,4),(2,5),(3,-6),(?,7)} What could be the missing x-coordinate if the relation is not a function?
Answer:
There are 4 possible scenarios where given relation could not be a function:
i) [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]
ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]
iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]
iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]
Step-by-step explanation:
From Function Theory, we remember that a relation is not a function when at least one element from domain (x-coordinate) is related to one or more elements from range (y-coordinate). Hence, there are four possibilities of making the relation not a function:
i) [tex](-1, 4), (0,4), (2,5), (3,-6), (-1, 7)[/tex]
ii) [tex](-1, 4), (0,4), (2,5), (3,-6), (0, 7)[/tex]
iii) [tex](-1, 4), (0,4), (2,5), (3,-6), (2, 7)[/tex]
iv) [tex](-1, 4), (0,4), (2,5), (3,-6), (3, 7)[/tex]
Graph this system of equations on the coordinate plane
y= -3x+3
y= 1/2x -4
Answer:
see the figure
Step-by-step explanation:
see the figure
Answer:
(2,-3)
Step-by-step explanation:
Desmos graphing calculator
Raise to the power:
[tex](-2abx)^{4}[/tex]
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
[tex]( { - 2abx})^{4} = ({ - 2})^{4} \times ( {a})^{4} \times ({b})^{4} \times ({x})^{4} = \\ [/tex]
[tex]16 {a}^{4} {b}^{4} {x}^{4} [/tex]
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
19. Jake thinks of a secret number. He says that his secret number is more than 6 units away from 2. Write a
compound inequality that gives the possible values of Jake's number. Graph the inequality.
2nd try again please help
Answer:
0.8
Step-by-step explanation:
25.4-23.8=1.6
25.4+1.6=27
For two cycles, the increase is 1.6. So, divide that by two to get 0.8. Hope this helps!
Answer:
0.8
Step-by-step explanation:
Each increase is 1.6 apart. Because they're going by two cycles just divide that by two and you get 0.8
What is the exact value of Tangent (StartFraction pi Over 12 EndFraction)
Answer:
a
Step-by-step explanation:
just did it and got right
The required value of the trigonometric operator tan(π/12) = 2 -√3. None of them is correct.
These are the equation that contains trigonometric operators such as sin, cos.. etc. In algebraic operation.
Let,
= [tex]tan(\pi /12) = tan((3-2)\pi /12)[/tex]
[tex]= tan[(3\pi -2\pi )/12]\\=tan(3\pi /2-2\pi /12)\\=tan(\pi /4-\pi /6)\\=\frac{tan(\pi/4)-tan(\pi/6)}{1+tan(\pi/4)tan(\pi/6)}[/tex]
= [tex]\frac{1-1/\sqrt{3} }{1+1*1/\sqrt{3} } \\[/tex]
[tex]=\frac{(\sqrt{3}-1)/\sqrt{3}}{(\sqrt{3}+1))/\sqrt{3}}[/tex]
[tex]=\frac{(\sqrt{3}-1)}{(\sqrt{3}+1)}\\=\frac{(\sqrt{3}-1)(\sqrt{3}+1)}{(\sqrt{3}+1)(\sqrt{3}+1)}\\=\frac{(3-2\sqrt{3}+1)}{(3-1)}\\\\=\frac{(4-2\sqrt{3})}{(2)}\\={(2-\sqrt{3})}\\[/tex]
Thus, the required value of the trigonometric operator tan(π/12) = 2 -√3. None of them is correct.
Learn more about trigonometry equations here:
brainly.com/question/22624805
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A question on a test asks students to find the speed at which a car travels. The graph shows a proportional relationship between the distance traveled in miles and time in hours. Billy incorrectly says that the speed of the car is 1/60 mile per hour. What is the speed of the car? What error might Billy have made?
Answer:
Step-by-step explanation:
Since, speed of a car = [tex]\frac{\text{Distance traveled}}{\text{Time taken}}[/tex]
From the graph attached,
A point (1, 60) lies on the line shown in graph.
At this point speed of the car = [tex]\frac{\triangle y}{\triangle x}[/tex]
[tex]=\frac{60-0}{1-0}[/tex]
= 60 miles per hour
But Billy says the speed of the car is [tex]\frac{1}{60}[/tex] miles per hour.
So the error in the Billy's answer is that he has used the wrong formula to calculate the speed.
(As per Billy, speed = [tex]\frac{\text{Time taken}}{\text{Distance covered}}[/tex])
Central City High's basketball team will be entering the playoffs at the end of their regular season. There will be 3 other teams in the playoffs, with season average scores of 87, 92, and 119. Central City High has played 7 games with an average score of 91. What score range could they have in their eighth and last regular season game to have the second highest season average score in the tournament?
Answer:
99<x<315
Step-by-step explanation:
Answer:
C.
Step-by-step explanation:
edg. 2021
Is this true or false? Ill give brainliest
i think true because 0,4 on there is correct and so is 2,0
Giving brainiest explain answer
Answer:
A.) -5
Step-by-step explanation:
Slope Formula ---> [tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex] m = slope
[tex]m = \frac{2 - (-3)}{-2 - (-1)}[/tex]
Eliminate negatives:
[tex]m = \frac{2 + 3}{ -2 + 1}[/tex]
Solve:
[tex]m = \frac{5}{-1}[/tex]
Simplify:
[tex]m = -5[/tex]
2b+ 9r use b=2 and r=7
Answer:
67
Step-by-step explanation:
2b+9r
2(2)+9(7)
4+63
67
Answer:
67
Step-by-step explanation:
2(2)+9(7)
4+63=67
Have a great day
Which of these describes the system of linear equations below?
3x-2y=7
6x-4y=14
a) the system has no solutions.
b) the system has infinitely many solutions.
c) the ration of the-coordinate to the y-coordinate of the only solution is 2 : 1.
d) the difference between the x-coordinate and y-coordinate of the only solution is one.
Given:
The system of equations is
[tex]3x-2y=7[/tex]
[tex]6x-4y=14[/tex]
To find:
The correct statement for the given system of equations.
Solution:
On comparing the given equations and general form of linear equation, i.e., [tex]ax+by+c=0[/tex], we get
[tex]a_1=3,b_1=-2,c_1=-7[/tex]
[tex]a_2=6,b_2=-4,c_2=-14[/tex]
Here,
[tex]\dfrac{a_1}{a_2}=\dfrac{3}{6}=\dfrac{1}{2}[/tex]
[tex]\dfrac{b_1}{b_2}=\dfrac{-2}{-4}=\dfrac{1}{2}[/tex]
[tex]\dfrac{c_1}{c_2}=\dfrac{-7}{-14}=\dfrac{1}{2}[/tex]
Since, [tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}[/tex], therefore, the two equations are equivalent and the system has infinitely many solutions.
Hence, the correct option is b.
Which expression is equivalent to StartFraction negative 18 a Superscript negative 2 Baseline b Superscript 5 Baseline Over Negative 12 a Superscript negative 4 Baseline b Superscript negative 6 Baseline EndFraction? Assume a not-equals 0, b not-equals 0.
A. StartFraction 2 a squared b Superscript 11 Baseline Over 3 EndFraction
B. StartFraction 2 a squared b Superscript 30 Baseline Over 3 EndFraction
C. StartFraction 3 a squared b Superscript 11 Baseline Over 2 EndFraction
D. StartFraction 3 a squared b Superscript 30 Baseline Over 2 EndFraction
Answer:
B
Step-by-step explanation:
I just took the test
Answer:
A.
Step-by-step explanation:
Subtract 7b(2a 2 +5a-7) from (7a 2 -a+3 )-3b(6a 2 -b+3)
Answer:
[tex]\huge\boxed{-32a^2b+7a^2+3b^2-35ab-a+40b+3}[/tex]
Step-by-step explanation:
[tex]7b(2a^2+5a-7)\qquad|\text{use the distributive property}\\\\=(7b)(2a^2)+(7b)(5a)+(7b)(-7)=14a^2b+35ab-49b\\\\\\(7a^2-a+3)-3b(6a^2-b+3)\qquad|\text{use the distributive property}\\\\=7a^2-a+3+(-3b)(6a^2)+(-3b)(-b)+(-3b)(3)\\\\=7a^2-a+3-18a^2b+3b^2-9b[/tex]
Substraction
[tex](7a^2-a+3-18a^2b+3b^2-9b)-(14a^2b+35ab-49b)\\\\=7a^2-a+3-18a^2b+3b^2-9b-14a^2b-35ab+49b\\\\\text{combine like terms}\\\\=(-18a^2b-14a^2b)+7a^2+3b^2-35ab-a+(-9b+49b)+3\\\\=-32a^2b+7a^2+3b^2-35ab-a+40b+3[/tex]
The perimeter of a football field is 920 feet. The width is 60 feet more than one-third of the length. What are the dimensions of a football field?
Given:
Perimeter of a football field = 920 feet.
The width is 60 feet more than one-third of the length.
To find:
The dimensions of a football field.
Solution:
Let the length of the field be x.
Then, width = [tex]\dfrac{1}{3}x+60[/tex]
We know that,
[tex]Perimeter = 2( length + width)[/tex]
[tex]920 = 2(x+\dfrac{1}{3}x+60)[/tex]
[tex]920 = 2(\dfrac{4}{3}x+60)[/tex]
[tex]920 =\dfrac{8}{3}x+120[/tex]
Subtract both sides by 120.
[tex]920-120 =\dfrac{8}{3}x+120-120[/tex]
[tex]800 =\dfrac{8}{3}x[/tex]
Multiply both sides by 3.
[tex]2400 =8x[/tex]
Divide both sides by 8.
[tex]300 =x[/tex]
Now,
[tex]Length = 300\text{ feet}[/tex]
[tex]Width=\dfrac{1}{3}(300)+60[/tex]
[tex]Width=100+60[/tex]
[tex]Width=160\text{ feet}[/tex]
Therefore, the length and width of the football field are 300 feet and 160 feet respectively.
The percentage of sprouted seeds for a single crop can be modeled by a logistic function that is represented by y=100/1+99e^-0.89x. Which statements about the scenario are true? Check all that apply.
Answer:
A, B, and C
Step-by-step explanation:
If f(x) = 2x + 1, what is f(x) when x = 3?
a)1
b)7
c)13
d)19
Answer:
7
Step-by-step explanation:
part B is the correct answer
Answer:
B) 7
Step-by-step explanation:
f(x)=2(3)+1
2(3)=6
6+1=7
True or false, f(x) is a function
Answer:
Step-by-step explanation:
True!!
—16t^2 + 64t + 3
Please help as soon as possible 33 points if you do it!!
Answer:
51t^3
Step-by-step explanation:
64+3=67
67 +(-16)=51
t^2 +t= t^3
now you just add them up but they cant be combined because one is a number and the other a variable w an exponent so we just get 51t^3
Which ordered pair is a solution of the equation? Y = 7x - 3
Answer:
y-intercept: ( 0 , − 3 )
x-intercept: ( 3 7 , 0 )
Step-by-step explanation:
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What is the coefficient of the fourth term in this expression?
m3+2kn2+mn2+6k2n
What fraction of a metre is 20cm?
Answer:
1/5
Step-by-step explanation:
A metre is 100cm, thus
20cm/100cm= 1/5
y = 3x = 2
=
- x + 6
3x + 12 – 6x ≤ -9 Solve, graph, and express the following inequalities in interval notation.
The solution of inequality 3x + 12 – 6x ≤ –9 will be greater than or equal to 7.
What is inequality?Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.
The inequality is given below.
3x + 12 – 6x ≤ –9
Simplify the equation, then the value of 'x' is calculated as,
3x + 12 – 6x ≤ –9
6x – 3x ≥ 12 + 9
3x ≥ 21
x ≥ 21 / 3
x ≥ 7
The solution of inequality 3x + 12 – 6x ≤ –9 will be greater than or equal to 7.
The solution is shown on the number line.
More about the inequality link is given below.
https://brainly.com/question/19491153
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Need help on this Math problem
Answer:
I hope I helped :)
Step-by-step explanation:
a. The y-intercept represents b. (y = mx + b) also b is 20 because that's where the line touches the y-axis.
b. The slope represents Sam's monthly fee.
c. Sam's monthly fee is 0.4 or 2/5
d. Every 50 minutes is $20.
multiply 532 and 734 using natural logarithms
i don’t know how to do this
Answer:
A2: 55
A1: 99-55+x:180
X:26
Is 12 even or odd? Pick you choice
Answer:
Even
Step-by-step explanation:
number of boys and girls are in the class are in the ratio of 7 : 5 the number of boys is 8 more than the number of girls what is a total class strength?
Answer:
Step-by-step explanation:
Given ratio of boys and girls in the class =7:5
No of boys is 8more than the girls
So
Let no of boys in the class =7x
No of girls in the class=5x
7x=5x+8
2x=8
X=8/2
X=4.
Total strength =no of boys + no of girls
=7x+5x
=7×4+5×4
= 28+20
=48.
Total strength in the class is 48.
Answer:
Total class strength = 48
Step-by-step explanation:
Boys : Girls = 7 : 5
Number of boys = 7x
Number of girls = 5x
7x - 5x = 8
2x = 8
x = 8/2
x = 4
Total strength = 7x + 5x = 12x = 12*4 = 48
cal d gradient B(4,-7), c(-6-5) and d two point find d gradient
Answer:
d = - 1/5
Step-by-step explanation:
slope form: m= y2-y1/x2-x1
m= -5-(-7)/-6-4
m= 2/-10
m= - 1/5