Answer:
Step-by-step explanation:
2 units squared.
Explanation:
You can go about this in two ways: Algebra and Integrals.
Algebra
y = 2x-6 is linear, thus if we take the value over the x interval [2,4] we can use geometry to calculate the area.
graph{2x-6 [-2.27, 7.73, -2.18, 2.82]}
You can see two triangles in the graph (you could also find this algebraically). Thus, you can calculate the area.
=
2
⋅
(
1
2
⋅
b
⋅
h
)
=
2
⋅
(
1
2
⋅
1
⋅
2
)
=
2
square units
Integrals
An integral gives the area under the curve. Remember though that if a function goes below the X axis, the integral is negative Thus you have to do two separate integrals based on the X intercept.
finding the X intercept (that is where y = 0)
2
x
−
6
=
0
x
=
3
when
y
=
0
When
x
<
3
, then y is negative. Thus, we have to find the negative integral from 2 to 3 and the positive integral from 3 to 4
=
−
∫
3
2
2
x
−
6
d
x
+
∫
4
3
2
x
−
6
d
x
=
−
[
x
2
−
6
x
]
3
2
+
[
x
2
−
6
x
]
4
3
=
−
[
9
−
18
−
4
+
12
]
+
[
16
−
24
−
9
+
18
]
=
−
[
−
1
]
+
[
1
]
=
2
units squared. And Tada, that is the same as the other answer!
Using integrals, it is found that the area of the function is of 6 squared units.
The area of a function f(x) over an interval [a,b] is given by:
[tex]A = \int_{a}^{b} f(x) dx[/tex]
In this problem:
Interval (-4, 2), thus [tex]a = -4, b = 2[/tex].Function [tex]f(x) = 2x + 3[/tex], thus:[tex]A = \int_{-4}^{2} 2x + 3 dx[/tex]
[tex]A = x^2 + 3x|_{x = -4}^{x = 2}[/tex]
[tex]A = 2^2 + 3(2) - [(-4)^2 + 3(-4)][/tex]
[tex]A = 4 + 6 - 4[/tex]
[tex]A = 6[/tex]
The area is of 6 squared units.
A similar problem is given at https://brainly.com/question/20733870
A contractor is required by a county planning department to submit 1, 2, 3, 4, or 5 forms (depending on the nature of the project) when applying for a building permit. Let y denote the number of forms required for an application, and suppose the mass function is given by p(y) 5 cy for y 5 1, 2, 3, 4, or 5. Determine the value of c, as well as the long-run proportion of applications that require at most three forms and the long-run proportion that require between two and four forms, inclusive.
Answer:
[tex](a)\ c = \frac{1}{15}[/tex]
[tex](b)\ 40\%[/tex]
[tex](c)\ 60\%[/tex]
Step-by-step explanation:
The given parameters can be represented as:
[tex]P_Y(y) \ge 0, y =1,2,3,4,5[/tex]
[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]
Solving (a): The value of c
To do this, we make use of the following rule;
[tex]\sum\limit^5_{y=1}P_Y(y_i) = 1[/tex]
Given that:
[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]
This is translated to:
[tex]c*1 + c * 2 + c * 3 + c * 4 + c * 5 = 1[/tex]
[tex]c + 2c + 3c + 4c + 5c = 1[/tex]
[tex]15c = 1[/tex]
Solve for c
[tex]c = \frac{1}{15}[/tex]
(b) The proportions of applications that requires at most 3 forms
This implies that: y = 1,2,3
So, we make use of:
[tex]P(Y \le 3) = P(Y=1) + P(y=2) + P(Y=3)[/tex]
Recall that:
[tex]P_y(y) = cy, y=1,2,3,4,5[/tex]
Substitute [tex]c = \frac{1}{15}[/tex]
[tex]P_y(y) =\frac{1}{15}y[/tex]
So:
[tex]P(Y \le 3) = P(Y=1) + P(y=2) + P(Y=3)[/tex]
[tex]P(Y\le 3) = \frac{1}{15} * 1 +\frac{1}{15} * 2 +\frac{1}{15} * 3[/tex]
[tex]P(Y\le 3) = \frac{1}{15} +\frac{2}{15} +\frac{3}{15}[/tex]
Take LCM
[tex]P(Y\le 3) = \frac{1+2+3}{15}[/tex]
[tex]P(Y\le 3) = \frac{6}{15}[/tex]
[tex]P(Y\le 3) = 0.4[/tex]
Express as percentage
[tex]P(Y\le 3) = 0.4*100\%[/tex]
[tex]P(Y\le 3) = 40\%[/tex]
(c) The proportions of applications that requires between 2 and 4 forms (inclusive)
This implies that: y = 2,3,4
So, we make use of:
[tex]P(2 \le Y \le 4) = P(Y=2) + P(Y=3) + P(Y=4)[/tex]
[tex]P(2 \le Y \le 4) = 2 * \frac{1}{15} + 3 * \frac{1}{15} + 4 * \frac{1}{15}[/tex]
[tex]P(2 \le Y \le 4) = \frac{2}{15} + \frac{3}{15} + \frac{4}{15}[/tex]
Take LCM
[tex]P(2 \le Y \le 4) = \frac{2+3+4}{15}[/tex]
[tex]P(2 \le Y \le 4) = \frac{9}{15}[/tex]
[tex]P(2 \le Y \le 4) = 0.6[/tex]
Express as percentage
[tex]P(2 \le Y \le 4) = 0.6 * 100\%[/tex]
[tex]P(2 \le Y \le 4) = 60\%[/tex]
¿para cuantos días alcanza una bolsa de 7,5 kg de alimento balanceado, si la ración diaria que le dan al perro de paula equivale a las dos quintas partes de 1kg?
Answer:
7,5*1000/2=37,5
Step-by-step explanation:
Find the cost of 6 kg rice, if the cost of 10 kg rice is 325 rupees .
Answer:
195 rupees
Step-by-step explanation:
10kg=325 rupees
6kg=?
Cross multiplication;
=6×325/10
=1950/10
=195 rupees
Multiply the polynomials (y −5)(2y+ 3)
Answer:
(-3 + -2y)(5 + -1y) = 0
Step-by-step explanation:
Simplifying
(y + -5)(2y + 3) = 0
Reorder the terms:
(-5 + y)(2y + 3) = 0
Reorder the terms:
(-5 + y)(3 + 2y) = 0
Multiply (-5 + y) * (3 + 2y)
(-5(3 + 2y) + y(3 + 2y)) = 0
((3 * -5 + 2y * -5) + y(3 + 2y)) = 0
((-15 + -10y) + y(3 + 2y)) = 0
(-15 + -10y + (3 * y + 2y * y)) = 0
(-15 + -10y + (3y + 2y2)) = 0
Combine like terms: -10y + 3y = -7y
(-15 + -7y + 2y2) = 0
Solving
-15 + -7y + 2y2 = 0
Solving for variable 'y'.
Factor a trinomial.
(-3 + -2y)(5 + -1y) = 0
Figure WXYZ is a rectangle. What are the
coordinates of point W?
Answer:
(2,9)
Step-by-step explanation:
Answer:
(2,9)
Step-by-step explanation:
because you move up by 6. which makes it (2,3)+6
Determine whether the given value makes a true statement.
NO LINKS-DRIVES-DOCS ETC.
WILL MARK BRAINLYEST
EARN LOTS OF POINTS
Answer:
How can you determine whether a given number makes an equation true?
Determine whether a number is a solution to an equation.
Substitute the number for the variable in the equation.
Simplify the expressions on both sides of the equation.
Determine whether the resulting equation is true. If it is true, the number is a solution. If it is not true, the number is not a solution.
Shim bougth a pair of shoes fo $600.If she got a discount of 30% ,home much did she paid for the shoes?
Answer:
she paid 420 dollars for it
Step-by-step explanation:
30 percent of 600 is 180
Graph y = 2.3 - 7.
y
→
AU
8+
7+
6+
5
CO
3+
2+
1+
MY
-9-8-7 -6 -5 4 -3 -2
1 2 3 4 5 6 7 8 9
Cou
-3
SA
-5-
-6-
-7-
-8
MY
Pra
Answer:
4b+7h+935*213
Step-by-step explanation:
A random sample of students was surveyed on what they eat for lunch at school. The results are shown in the table
below.
Lunch Item
Number of Students
Pizza
52
Salad
26
Burger
30
Chicken Sandwich
48
Brought lunch from home
44
If the school has 1,000 students, about how many students can the cafeteria expect to buy pizza?
208
1,000
260
52
Answer:
260
Step-by-step explanation:
you would divide 52/200 because all the numbers added up is 200 and it comes out to 0.26 and the original number of students they wanted is 1,000 so look at those zeros and move the decimal 3 times and add the zero in the empty space to get 260.
A ratio shows us the number of times a number contains another number. The number of students the cafeteria should expect to buy pizza is 260.
What is a Ratio?A ratio shows us the number of times a number contains another number.
The ratio of the number of students to the number of total students can be written as,
Ratio = (Number of students)/(Number of total students)
Ratio = 52/(52+26+30+48+44) = 52/200
Now, the same ratio is applicable to 1000 students, therefore, the ratio will be,
Number of students who prefer pizza = 1000 × (52/200) = 260
Hence, the number of students the cafeteria should expect to buy pizza is 260.
Learn more about Ratios:
https://brainly.com/question/1504221
#SPJ2
Pleaseee helppp which one is and whyy!!!!
Answer:
c = 17(83)-17(16)=1139
Step-by-step explanation:
9. A juice glass holds 180mL. If a client drinks 7/2 glasses , how many milliliters did
the client consume? (5 points)
Answer:
630 ml
Step-by-step explanation:
1 glass contains 180 ml juice
7/2 glasses contains = 180 × 7/2 = 630 ml
Find the average value of a function
Answer:
The average value of g is:
[tex]\displaystyle g_{ave}=\frac{1}{6}e^6-\frac{49}{6}\approx 59.071[/tex]
Step-by-step explanation:
The average value of a function is given by the formula:
[tex]\displaystyle f_{ave}=\frac{1}{b-a}\int_a^b f(x)\, dx[/tex]
We want to find the average value of the function:
[tex]g(x)=e^{3x-3}-4x[/tex]
On the interval [1, 3].
So, the average value will be given by:
[tex]g_{ave}=\displaystyle \frac{1}{3-1}\int_1^3 e^{3x-3}-4x\, dx[/tex]
Simplify. We will also split the integral:
[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\int_1^3e^{3x-3}\, dx-\int _1^3 4x\, dx\right)[/tex]
We can use u-substitution for the first integral. Letting u = 3x - 3, we acquire:
[tex]\displaystyle u=3x-3\Rightarrow du = 3\, dx\Rightarrow \frac{1}{3} du=dx[/tex]
We will also change the limits of integration for our first integral. So:
[tex]u(1)=3(1)-3=0\text{ and } u(3)=3(3)-3=6[/tex]
Thus:
[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\frac{1}{3}\int_0^6 e^{u}\, du-\int _1^3 4x\, dx\right)[/tex]
Integrate:
[tex]g_{ave}=\displaystyle \frac{1}{2}\left(\frac{1}{3}e^u\Big|_0^6-2x^2\Big|_1^3\right)[/tex]
Evaluate. So, the average value of g on the interval [1, 3] is:
[tex]\displaystyle g_{ave}=\frac{1}{2}\left(\frac{1}{3}\left[e^6-e^0\right]-\left[2(3)^2-2(1)^2\right]\right)[/tex]
Evaluate:
[tex]\displaystyle\begin{aligned} g_{ave}&=\frac{1}{2}\left(\frac{1}{3}(e^6-1)-16\right)\\&=\frac{1}{2}\left(\frac{1}{3}e^6-\frac{1}{3}-16\right)\\&=\frac{1}{6}e^6-\frac{49}{6}\approx59.071\end{aligned}[/tex]
What is the slope of the line tangent to the curve square root (x) +square root (y) = 2 at the point ( 9/4, 1/4 )? (photo attached of answer choices)
Answer:
B. [tex]\displaystyle -\frac{1}{3}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to RightEquality Properties
Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of EqualityAlgebra I
Terms/CoefficientsExponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Rule [Root Rewrite]: [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]Calculus
Derivatives
Derivative Notation
Derivative of a constant is 0
The definition of a derivative is the slope of the tangent line
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Implicit Differentiation
Step-by-step explanation:
Step 1: Define
[tex]\displaystyle \sqrt{x} + \sqrt{y} = 2[/tex]
[tex]\displaystyle (\frac{9}{4}, \frac{1}{4})[/tex]
Step 2: Differentiate
Implicit Differentiation
[Function] Rewrite [Exponential Rule - Root Rewrite]: [tex]\displaystyle x^{\frac{1}{2}} + y^{\frac{1}{2}} = 2[/tex][Function] Basic Power Rule: [tex]\displaystyle \frac{1}{2}x^{\frac{1}{2} - 1} + \frac{1}{2}y^{\frac{1}{2} - 1}\frac{dy}{dx} = 0[/tex][Derivative] Simplify: [tex]\displaystyle \frac{1}{2}x^{\frac{-1}{2}} + \frac{1}{2}y^{\frac{-1}{2}}\frac{dy}{dx} = 0[/tex][Derivative] Rewrite [Exponential Rule - Rewrite]: [tex]\displaystyle \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0[/tex][Derivative] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex] term [Subtraction Property of Equality]: [tex]\displaystyle \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}[/tex][Derivative] Isolate [tex]\displaystyle \frac{dy}{dx}[/tex] [Multiplication Property of Equality]: [tex]\displaystyle \frac{dy}{dx} = -\frac{2y^{\frac{1}{2}}}{2x^{\frac{1}{2}}}[/tex][Derivative] Simplify: [tex]\displaystyle \frac{dy}{dx} = -\frac{y^{\frac{1}{2}}}{x^{\frac{1}{2}}}[/tex]Step 3: Evaluate
Find slope of tangent line
Substitute in point [Derivative]: [tex]\displaystyle \frac{dy}{dx} \bigg| \limit_{(\frac{9}{4}, \frac{1}{4})} = -\frac{(\frac{1}{4})^{\frac{1}{2}}}{(\frac{9}{4})^{\frac{1}{2}}}[/tex][Slope] Exponents: [tex]\displaystyle \frac{dy}{dx} \bigg| \limit_{(\frac{9}{4}, \frac{1}{4})} = -\frac{\frac{1}{2}}{\frac{3}{2}}[/tex][Slope] Simplify: [tex]\displaystyle \frac{dy}{dx} \bigg| \limit_{(\frac{9}{4}, \frac{1}{4})} = -\frac{1}{3}[/tex]Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Differentiation - Implicit Differentiation
Book: College Calculus 10e
Malia and her sister walk at a constant rate of 4 miles per hour. At this constant rate, how long should it take Malia and her sister to walk 3 miles?
A. 0.75
B. 1.25
C. 1.5
D. 12
Just need the answer
Answer:
It seems no one can eat just one potato ship
Step-by-step explanation:
In an effort to determine the most effective way to teach safety principles to a group of employees, four different methods were tried. Some employees were given programmed instruction booklets and worked through the course at their own pace. Other employees attended lectures. A third group watched a television presentation, and a fourth group we divided into small discussion groups. A high of 10 was possible. A sample of 5 tests were selected from each group. The results were: Sample Programmed Instruction Lecture TV Group Discussion 1 6 8 7 8 2 7 5 9 5 3 6 8 6 6 4 5 6 8 6 5 6 8 5 5 At the 0.01 level, what is the critical value
Answer:
critical value = 5.29
Step-by-step explanation:
Given that they are divided into 4 groups and a sample of 5 test was selected
N = 5 * 4 = 20
k = 4
∝ = 0.01
Df for numerator ( SS group )= k - 1 = 3
Df for denominator ( SSE group ) = N - k = 20 - 4 = 16
DF ( degree of freedom )
Next we will use the F table to determine the critical value
Critical value = [tex]F_{16,3,0.01}[/tex] = 5.29
What shape is the cross-section?
a. Triangle
b. Circle
c. Ellipse
d. Hexagon
e. Square
f. Rectangle
g. Pentagon
Marvin earns $9.75 per hour at his summer job. He wants to buy a video game system that costs $263.25
Enter an equation to model the relationship between the number of hours worked h and the amount earned e
The equation is:
Answer:
$9.75h=e-$263.25
Step-by-step explanation:
Two high schools have a similar number of students and parking lots of similar size. The safety officers at both schools want to investigate whether there is an average difference in the number of cars parked per day in the student parking lots for the school year. A random sample of 15 school days will be selected. For each selected day, the number of cars parked in the student parking lots will be counted at both schools and the difference will be recorded. Assuming all conditions for inference are met, which of the following is the appropriate test for the investigation?
a. A two-sample 2-test for a difference between proportions
b. A two-sample t-test for a difference between means
c. A matched-pairs t-test for a mean difference
d. A chi-square test of homogeneity
e. A chi-square test of independence
Answer: c. . A matched-pairs t-test for a mean difference
Step-by-step explanation:
Based on the information given in the question and assuming all conditions for inference are met, the appropriate test for the investigation will be a matched-pairs t-test for a mean difference.
Since a matched-pairs t-test can be used to determine if a significant mean difference exist between two paired data, then this will be appropriate in this case since the safety officers at both schools want to know if there's an average difference in the number of cars parked per day in the student parking lots for the school year.
The appropriate test for the investigation of the given case is done by: Option C: A matched-pairs t-test for a mean difference
When to use the matched pair t test and when to use the t test?When there has to be done comparison between means of two sets of paired data, then we use matched pair t test.
For the given case the investigation is to know whether there is an average difference in the number of cars parked per day in the student parking lots for the school year for both the schools in consideration.
So there are two data sets and comparison of their mean is to be done.
Thus, the appropriate test for the investigation of the given case is done by: Option C: A matched pairs t-test for a mean difference.
Learn more about matched pair t-test here:
https://brainly.com/question/14690592
pls answer fast will give branliest
if u send links will report so mf fast
Answer:
m∠1= 17°
m∠2=73°
m∠3=90°
m∠4=51°
m∠5=17°
m∠6=129°
Step-by-step explanation:
Hope it helps...
Have a great day!!
The length of a rectangular garden is 8m greater than twice the width the area of the garden is 280m^2 what is the width of the garden
Step-by-step explanation:
Given :-
The length of the garden 8m greater than 2 times the width.
Area of the garden is 280 m²
Let us consider the length as x and width as y.
Sp, we can day length as :-
x = 8 + 2y ---(1)
Now, we know that:-
Area of Rectangle = Length × Breadth
280 = x * y
We can replace the value of x now,
280 = y × ( 8 + 2y)
280 = 8y + 2y²
2y² + 8y - 280 = 0
y² + 4y - 140 = 0
Factorise it.
(y -10)(y + 14)
Cancelling -ve value, we get the width as 10 metres.
Hope it helps :)
Answer:
Step-by-step explanation:
Width = w
Length = 2w + 8
Area of rectangular garden = 280 square meter
length * width = 280
(2w + 8 ) *w = 280
2w * w + 8*w = 280
2w² + 8w = 280
2w² + 8w - 280 = 0
Divide the whole equation by 2
w² + 4w - 140 = 0
w² + 14w - 10w - 14 *10 = 0
w(w + 14) - 10(w + 14) = 0
(w + 14)(w - 10)= 0
w - 10 = 0 {Ignore w + 14, as measurements will not be -ve}
w = 10 m
l = 2*10 +8
= 20 +8
l = 28 m
Ivy deposited some money into a savings account that earns 1%
annual simple interest. At the end of 5 years, she earned $32.50 in
interest. How much money did she put into the account initially?
Round to the nearest dollar.
Answer:
Ivy initially put $ 650 in the account.
Step-by-step explanation:
Given that Ivy deposited some money into a savings account that earns 1% annual simple interest, and at the end of 5 years, she earned $ 32.50 in interest, to determine how much money did she put into the account initially, the following calculation must be performed:
32.50 / 5 = 6.5
1 = 6.5
100 = X
100 x 6.5 = X
650 = X
Therefore, Ivy initially put $ 650 in the account.
can anyone help me please
Simplify the expression Z^0⋅(Z^2⋅Z^−5)^4 using positive exponents
possible answers:
a.)Z^81
b.) 0
c.) 1/Z^12
d.) 1/Z^40
Janey paints a block of wood with gold glitter for an art project. The block measures 8 inches by 10 inches by 20 inches. After she's done, she decides to make two blocks by cutting through the block on the red line. She still wants each block to be covered with gold glitter
1. what is the shape of each cut surface? What are its dimensions? and what is the total area of paint she still needs to paint?
2. What is the area of each cut surface?
Answer:
1. Square, 10in x 8in, 160in^2
2. Each surface has an area of 80in^2
Step-by-step explanation:
1. Rectangle is the shape of each cut surface which is 10in by 8 in. Since the block was already painted with glitter, she needs to paint both sides of the cut surface only, 2*8in * 10in = 160in^2.
2. Each cut will have a surface area of 10in * 8in = 80in^2
Please leave a like if this is the answer you were looking for
Find the slope of the line passing through the points (2,-9) and )1,-3)
Answer:
5
Step-by-step explanation:
Slope = (-3 - 2) / (1 - 2) = -5 / -1 = 5
Hi there!
[tex]\large\boxed{\text{slope =} 6}[/tex]
We can calculate slope using the following formula:
[tex]slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Plug in the corresponding points:
[tex]slope = \frac{-9-(-3)}{2-1}[/tex]
Simplify:
[tex]slope = \frac{-6}{1} = -6[/tex]
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!! DUE TODAY I NEED HELP ASAP
A restaurant has a 15% mandatory tip rate.
(a) Complete the ratio table shown. Show your work.
Pre-Tax Bill ($): 10 __ 60 __
Tip ($) __ 12 __ 15
(b) Using the table, how can you find the total tip paid on $70?
Answer:
Subtotal 70.00
15% Tip 10.50
Total 80.50
Step-by-step explanation:
1% 0.70
2% 1.40
3% 2.10
4% 2.80
5% 3.50
6% 4.20
7% 4.90
8% 5.60
% Tip
9% 6.30
10% 7.00
11% 7.70
12% 8.40
13% 9.10
This dude above is trash and wrong, I got a 0 because of him
Determine whether the given value makes a true statement.
NO LINKS-DRIVES-DOCS ETC.
WILL MARK BRAINLYEST
EARN LOTS OF POINTS
Answer:
Yes it is true
Step-by-step explanation:
cause 11 + 8 = 19
now give me the brainliest lol
Find the circumference of the circle and round to the nearest tenth
Answer: 13.8
Step-by-step explanation: (3.14)(4.4) round to the nearest tenth
what is tariffwhat is tariff
Answer:
Step-by-step explanation:
A tariff is a tax imposed by a government of a country or of a supranational union on imports or exports of goods. Besides being a source of revenue for the government, import duties can also be a form of regulation of foreign trade and policy that taxes foreign products to encourage or safeguard domestic industry