Question 7Partially correct answer. Your answer is partially correct. Try again.An article in Knee Surgery, Sports Traumatology, Arthroscopy (2005, Vol. 13, pp. 273-279), considered arthroscopic meniscal repair with an absorbable screw. Results showed that for tears greater than 25 millimeters, 13 of 19 repairs were successful while for shorter tears, 22 of 30 repairs were successful.(a) Is there evidence that the success rate is greater for longer tears

This question is incomplete, the complete question is;

An article in Knee Surgery, Sports Traumatology, Arthroscopy (2005, Vol. 13, pp. 273-279), considered arthroscopic meniscal repair with an absorbable screw. Results showed that for tears greater than 25 millimeters, 13 of 19 repairs were successful while for shorter tears, 22 of 30 repairs were successful.

a) Is there evidence that the success rate is greater for longer tears? Use alpha=0.05

Answer:

P-value = 0.6443

Now, since the p-value( 0.6443 ) is greater than the significance level (0.05), We fail to reject null hypothesis.

Therefore, there is no significant difference in the successive proportion ( rate ). [tex]p[/tex]₁ =  [tex]p[/tex]₂

Step-by-step explanation:

Given the data in the question;

         Sample of tears greater than 25;

number of successive repairs X₁ = 13

number of repair n₁ = 19

proportion of successive repairs [tex]p[/tex]₁ = 13/19 = 0.68

q₁ = 1 -  [tex]p[/tex]₁ = 1 - 0.68 = 0.32

        Sample of tears shorter than 25;

number of successive repairs X₂ = 22

number of repair n₂ = 30

proportion of successive repairs [tex]p[/tex]₂ = 22/30 = 0.73

q₂ = 1 -  [tex]p[/tex]₂ = 1 - 0.73 = 0.27

so;

H₀ : There is no significant difference in the successive proportions;  [tex]p[/tex]₁ =  [tex]p[/tex]₂

Hₐ : The successive rate is greater for longer tears [tex]p[/tex]₁ >

Significance level ∝ = 0.05

Test Statistics

Z =  ([tex]p[/tex]₁ -

so we substitute

Z =  ( 0.68 - 0.73 / √[ (0.68 ×0.32 / 19) + ( 0.73×0.27 / 30 ) ]

Z = -0.05 / √[ 0.01802 ]

Z = -0.05 / 0.1342

Z = -0.37  

P-value for the given test, p = P( Z > -0.37 )

= 1 - P( Z ≤ - 0.37 )

= 1 - 0.35569

P-value = 0.6443

Now, since the p-value( 0.6443 ) is greater than the significance level (0.05), We fail to reject null hypothesis.

Therefore, there is no significant difference in the successive proportion ( rate ). [tex]p[/tex]₁ =  [tex]p[/tex]₂

What is the opposite of -45?

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quería saber el problema este q no me se la respuesta ​

The frequency table represents the job status of a number of high school students. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 12, 38, 50. The third column is labeled not looking for a job with entries 28, 72, 100. The fourth column is labeled total with entries 40, 110, 150. Which shows the conditional relative frequency table by column? A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.3, nearly equal to 0.33, 1.0. The third column is labeled not looking for job with entries 0.7, nearly equal to 0.65, 1.0. the fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column is blank with entries currently employed, not currently employed, total. The second column is labeled Looking for a job with entries 0.12, 0.38, 050. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.00. The fourth column is labeled total with entries 0.4, 1.1, 1.5. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for a job with entries 0.24, 0.76, 1.0. The third column is labeled not looking for a job with entries 0.28, 0.72, 1.0. The fourth column is labeled total with entries nearly equal to 0.27, nearly equal to 0.73, 1.0. A 4-column table with 3 rows titled job status. The first column has no label with entries currently employed, not currently employed, total. The second column is labeled looking for job with entries 0.08, nearly equal to 0.25, nearly equal to 0.33. The third column is labeled not looking for a job with entries nearly equal to 0.19, 0.48, nearly equal to 0.67. The f

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B. parallel lines
D. perpendicular lines
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0%

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