Answer:
the answer is D . our galaxy
Answer:
our galaxy of course
Lithium diorganocopper (Gilman) reagents are prepared by treatment of an organolithium compound with copper(I) iodide. Decide what lithium diorganocopper (Gilman) reagent is needed to convert 1-bromopropane into propylcyclohexane. Draw the structure of the organolithium compound that is used to prepare Gilman.
Answer:
See explanation and image attached
Explanation:
The Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi. R is an alkyl or aryl group.
They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.
In this particular instance, we intend to synthesize propylcyclohexane. The structure of the lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.
Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene
Answer:The correct names for the structure are:
--> 1. 1-bromo-3-chlorobenzene.
--> 3. meta-bromochlorobenzene.
--> 6. m-bromochlorobenzene.
Explanation:
Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.
Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.
The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:
--> the functional group is benzene
--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)
--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.
The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.
--> ortho or O : this is used when the substituents are close to each other in the benzene ring.
--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.
--> para or (p): This is used when the substituents are across each other in the benzene ring
From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.
Pls answer this two ASAP PLSSSSSSSS
Answer:
1. aa
2. They have similar DNA
Explanation:
1. According to the question 1, wrinkled seeds (A) are dominant over round seeds (a) in pea plants. This means that, based on the law of dominance proposed by Mendel, wrinkled seeds will be expressed over round seeds in a heterozygous state (Aa).
However, since the round seed phenotype is a recessive trait, it will only be expressed when the alleles for round seeds (a) are the same in the gene i.e. aa genotype.
2. Based on the information in question 2, Ricky, who is working on a family tree for his school project, realizes that his close relatives all look similar in the pictures he collected. This is possible because of the SIMILARITY OF THEIR DNA (genetic material). Note that, relatives are connected by the genes that are inherited from one another, hence, they possess a similar DNA, which is the most valid reason for the resemblance.
35.2 J of heat is
applied to 16.0 g
of a substance.
Temp rises by 7.2
K. Specific Heat?
The specific heat : c = 0.306 J/g K
Further explanationGiven
Heat = 35.2 J
Mass = 16 g
Temperature difference : 7.2 K =
Required
The specific heat
Solution
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
Input the value :
c = Q / m.∆T
c = 35.2 / 16 x 7.2
c = 0.306 J/g K
WORTH 18 POINTS! MY LIFE DEPENDS ON THIS ANSWER!!!
Which compound listed below is most likely to have to following properties?
-solid at room temperature
- high melting points
-solble in water
-conductive when dissolved
1.sodium chloride
2.carbon monoxide
3.nitrogen trifluoride
4.none of these compounds could have all of the properties listed
Answer:
1.sodium chloride
Explanation:
because the others dont have all the listed properties
Would you consider an aquifer a renewable resource? Why or why not?
Answer:
an aquifer is a renewable resource
Explanation:
Aquifers are defined as the groundwater found deep in the layers of rocks.
An aquifer is considered as a renewable resource because groundwater is renewed over time. Aquifers are water resources and follow hydrological cycle through which it can renew itself.
Some of the deep aquifers are considered as nonrenewable resource because it toll hundreds of years to accumulate.
Hence, the correct answer is yes an aquifer is a renewable resource except some deep aquifers.
How do you write 0.000157 in scientific notation
Answer:
1.57 × 10^-4
one point five seven times ten to the power of negative four