Answer:
-3.33 ms^-2
Explanation:
Hope it helps
draw position time graph when speed is increasing
Explanation:
We need to draw position-time graph when the speed is increasing.
The slope of position-time graph gives the speed of an object.
Position means distance covered.
When the speed of an object is increasing with time. It means it is moving with increasing speed.
The attached figure shows the position -time graph when speed is increasing.
13. Austin rode his bike 10 m/s for two minutes. How far did he travel? A. 200 meters B. 1200 meters C. 1000 meters D. 20 meters
Answer:
B. 1200
Explanation:
60 sec in one min in 2 min there will be 120 sec. 10x120=1200
NEED AWNSER NOW! WILL MARK BRAINLY! Which term is defined as the ratio of the speed of light in a vacuum to the speed of light in the material it is passing through?
index of reflection
index of refraction
angle of reflection
angle of incidence
Answer:
Index of refraction.
Answer:
index of refraction
Explanation:
I just took the k12 quiz.
9. A student notices that wearing darker colors in sunlight makes him feel warmer, so he decides to conduct an experiment. He takes five pieces of different
colored cloth and wraps
each one around a water bottle. He then places all five bottles in direct sunlight and measures the temperature of the water in each bottle an hour later
What is the dependent variable in this experiment?
O the time he leaves it in the sunlight
O the amount of water in each bottle
O the color of the cloth
O the temperature of the water
Answer: 4
Explanation:
The dependent variable is the temperature of the water.
) prove that the acceleration due to gravi
is independent to the mass of the falling body
Explanation:
Let the mass of the body is m. The gravitational force acting on the object is given by :
[tex]F=\dfrac{GMm}{r^2}[/tex] ....(1)
G is universal gravitational constant
M is mass of Earth
r is the distance between the body
The acceleration of falling objects due to the gravitational force of Earth is equal to the acceleration due to gravity (g).
F = mg ...(2)
g is acceleration due to gravity
From equation (1) and (2) :
[tex]\dfrac{GMm}{r^2}=mg\\\\g=\dfrac{GM}{r^2}[/tex]
Here, M is mass of Earth and r is the distance. Hence, the acceleration due to gravi ty is independent to the mass of the falling body
Give one example where friction is useful. Can someone feed me with correct answer pls c:
Answer:
Friction is what holds your shoe to the ground. The friction present on the ice is very little, this is the reason why it is hard to walk on the slippery surface of the ice.
Explanation:
please help! i'll give brainliest.
what is it called when a magnet causes the atoms in a non-magnetic metal to line up and act like a magnet?
a: oriented magnet
b: permanent magnet
c: non-magnet
d: induced magnet
Answer:
I think It's induced magnet
Explanation:
Because a magnet and non magnet can be chicken nuggets
If a magnet causes the atoms in a non-magnetic metal to line up and act like a magnet, the non magnet is said to be an induced magnet by the magnetic induction by a permanent magnet.
What is magnetic induction ?A permanent magnet is made of ferromagnetic materials which are having permanent magnetic properties. The magnetic field lines from permanent magnet always align with an applied magnet.
As in the case of dipole molecules capable of inducing a polarity to a nonpolar molecule, a magnetic field by a strong magnet can induce a magnetic property to a nonmagnet.
The induced magnetic field only reside in the object as long as the induction source is there. For example the a rotating electric filed causes magnetic moment in a nonmagnet.
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A golf ball is sitting on a tee. The ball is struck with a golf club and flies
through the air. How does the force on the club compare with the force on the
ball when momentum is transferred between the club and ball?
Answer:
c i kn now it is
Explanation:
Definition of distance travelled?
Answer:
distance traveled is a total length of the path traveled between two positions.
The diagram shows a model of an atom. Who first proposed this model?
A. Bohr
B. Thomson
C. Rutherford
ОО
D. Dalton
A.Bohr
His model postulated the existence of energy levels or shells of electrons. Electrons could only be found in these specific energy levels; in other words, their energy was quantised, and couldn’t take just any value. Electrons could move between these energy levels but had to do so by either absorbing or emitting energy.
A. Bohr!
This answer is correct because I read the information.
A container with a mass of 5 kg is lifted to a height of 8 m. How much work is done by the gravitational force
Answer:
work done=392J
Explanation:
work done =Mgh
DATA
M=5kg
g= 9.8
h=8m
W=Mgh
W=5*9.8*8
W=392J
The work done by the gravitational force is equal to -400 J.
What is gravitational force?The gravitational force can be described as a force that attracts a body towards the center of the earth or any physical object that has mass. Every object has mass and exerts a gravitational pull on another object with mass.
Given, the mass of the container, m = 5 Kg
The height from the ground level, h = 8 m
The work done can be calculated by using the below-mentioned formula:
[tex]W = m\times g\times h[/tex]
Where g is the gravitational acceleration.
As the container is lifted in the upward direction therefore the value of the g will be negative.
Substitute the values of m, g, and h in the above formula:
W = 5 × (-10) × 8
W = -400 J.
The negative sign shows that the work is done against the gravitational force.
Therefore, the work done by the gravitational force is equal to -400 J.
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What muscle movement do we use to close a joint.
Answer: Your using your skeletal muscle
Explanation:
A 0.15 kg ball is moving with a velocity of
35 m/s. Find the momentum of the ball.
Answer:
5.25 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 0.15 × 35
We have the final answer as
5.25 kg.m/sHope this helps you
An object that falls and accelerates solely as a result of gravity is said to be in
(2 points)
A. terminal velocity
B. free fall
C. air resistance
D. terminal acceleration
1. While riding a chairlift, a 55-kg skier is raised a vertical distance of 370 m. What is the total change in the skier's gravitational potential energy
Answer:
199,430Joules
Explanation:
Gravitational potential energy is the energy possessed by a falling object due to virtue of its position.
gravitational potential energy = mass * acceleration due to gravity * height
gravitational potential energy = 55 * 9.8 * 370
gravitational potential energy = 539 * 370
gravitational potential energy = 199,430
Hence the total change in the skier's gravitational potential energy is 199,430Joules
ANSWER:
99,430 Joules (in multiple choice question sometimes appear as 200,000J)
Explanation:
Gravitational potential energy is the energy possessed by a falling object due to virtue of its position.
gravitational potential energy = mass * acceleration due to gravity * height
gravitational potential energy = 55 * 9.8 * 370
gravitational potential energy = 539 * 370
gravitational potential energy = 199,430
Hence the total change in the skier's gravitational potential energy is 199,430 Joules (or 200,00J)
please heart!VVV or stars :D vvv
With what force will a car hit a tree if the car has a mass of 3,000 kg and an acceleration of 2m/s squared
Answer:
6000 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 3000 × 2
We have the final answer as
6000 NHope this helps you
Answer:
6000n
Explanation:
A 75kg bicyclist (including the bicycle), initially at rest at the top of a hill, coasts down the hill, reaching a speed of 14.6m/s at the bottom of the hill. The distance and height of the hill are shown. Neglect any friction impeding the motion and the rotational energy of the wheels. List the energy types at the initial and final time and whether work and loss (due to non-conservative forces) occur as well as the corresponding amounts of energy.
The energy type at the initial time is potential energy and the energy at the final time or position is kinetic energy.
What is the law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.
Based on the law of conservation of mechanical energy, the formula for the change in the kinetic energy and the potential energy of the bicyclist is given as;
K.Ei + P.Ei = K.Ef + P.Ef
where;
K.Ei is the initial kinetic energy of the bicyclistK.Ef is the final kinetic energy of the bicyclistP.Ei is the initial potential energy of the bicyclistP.Ef is the final potential energy of the bicyclistThe kinetic energy of the bicyclist increases with increase in the velocity of the bicyclist while the potential energy increases with increase in the height of the bicyclist.
At the initial position when the bicyclist is at rest, the kinetic energy is zero, so the only energy at the initial position is potential energy because the height is maximum.
In addition, at the final position, the velocity of the bicyclist is maximum and the height is zero, so the only energy at the final position is kinetic energy.
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what is it that makes a magnet different from a piece of iron that is not mangetic?
Answer:
Under normal conditions, a magnetic material like iron doesn't behave like a magnet because the domains don't have a preferred direction of alignment. On the other hand, the domains of a magnet (or a magnetized iron) are all aligned in s specific direction.
show your work. john uses a 25N force to push a boulder off a cliff that is 312m tall. What is the work done on the boulder?
Answer:7800
work=force x distance
Force in Newtons
Distance in Meters
Work in Joules
why is physics to study the heat absorbed by the ocean
Answer:
Heat is a source of energy
Explanation:
Just took the test
In a place covered by shadow of cloud sun cannot be seen . Explain with reasons .
Answer:
Because even though our eyes have a huge dynamic range (ability to pick out details in sharply lit and lesser lit areas simultaneously) than any camera, there's a limit.
When there's strong sunlight, your pupils contract and let less light in, which makes the shadows look darker.
When it's cloudy, your pupils widen and let more light in, which makes the shadows look less dark.
Do some experiments with a camera and you'll soon get the hang of it.
NOTE: Also test HDR (high dynamic range) photography, where the camera takes three or more pictures in quick succession, with different exposure settings, and combines them to get the most detail of both bright and dark areas. The result is more or less what we percieve.
A fish swimming at a rate of .6 m/s notices a huge shark. Three seconds later, the fish is swimming at a speed of 3 m/s. What is the fish's acceleration?
0.8 m/s/s
-0.8 m/s/s
12.5 m/s/s
-12.5 m/s/s
Answer:
C
Explanation:
???
i think
How much would a pair of 0.5 kg shoes weigh on Earth? (Include units in
your answer) *
Answer:
1.1 lbs
Explanation:
To convert kg to lbs you multiply kilograms by 2.2. So 0.5kg × 2.2 equals to 1.1 lbs
Under what circumstances will the projectile have the greatest velocity when it hits the ground? Explain please
WRITE A PARAGRAPH ABOUT PRESSURE
Answer:
pressure is a horrible thing to go through, it can lead to many bad side effects, like burn out and it can also lead to high blood pressure, head aches, heart problems, depression, anxiety, and many more damaging effects. Pressure can destroy someones mental health if not dealed worth properly
I hope this is okay! I'm not sure what pressure you meant
Describe what happens to the moving boat when the oars are out of the water and the forward thrust is zero
Answer:
The boat won't be able to move if the oars were out and there was no thruster. If there was a flow of the water then yes there would be a moving boat.
An illustration of a ball sitting at the top of a hill of height labeled h Subscript 1 Baseline = 2 m. A the the bottom of the hill it levels off and the leveled surface is at a height labeled h Subscript 2 Baseline = .5 m. A ball is released from the top of a hill. How fast is the ball going when it reaches the base of the hill? Approximate g as 10 m/s2 and round the answer to the nearest tenth. m/s
Answer:
5.5 m/s
Explanation:
Right on Edge
The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.
What is RNA polymerase?RNA polymerase is an enzyme that aids in the transcription of DNA into RNA during transcript in the nucleus. The enzymes prevent many genetic mutations from being expressed.
Primase is an enzyme that synthesizes short RNA sequences called primers. These primers serve as a starting point for DNA synthesis during replication as the DNA polymerases cannot begin the synthesis of the new strand, they only extend it after primase begins it and primase produces RNA molecules, the enzyme can be said to be a type of RNA polymerase.
Therefore, The statement explains the importance of enzymes that check for and repair mistakes during DNA replication is the enzymes prevent many genetic mutations from being expressed. Thus, the option C is correct.
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5) A 20.0 kg cart with no friction wheels sits on a table. A light string is attached to it and runs over a low friction pulley to a 0.0150 kg mass.
Draw a free body diagram showing all the forces acting on each object
Calculate the acceleration of the masses
Calculate the tension force in the cord
How long will it take the block to get to go 1.2 m to the edge of the table.
What will the velocity be as soon as it gets to the edge?
Answer:
1) Please find attached, created with Microsoft Visio
2) The acceleration of the masses connected by the light string is 0.00735 m/s²
3) The tension in the cord is 0.147 N
4) The time it would take the block to go 1.2 m to the edge of the table is approximately 18.07 s
5) The velocity of the cart as soon as it gets to the edge of the table is 0.042 m/s
Explanation:
1) Please find attached, the required free body diagram, showing the tension, weight and frictional (zero friction) forces acting on the cart and the mass created with Microsoft Visio
2) The acceleration of the masses connected by the light string is given as follows;
F = Mass, m × Acceleration, a
The mass of the truck, M = 20.0 kg
The mass attached to the string, hanging rom the pulley, m = 0.0150 kg
The force, F acting on the system = The pulling force on the cart = The tension on the cable = The weight of the hanging mass = 0.0150 × 9.8 = 0.147 N
The pulling force acting on the cart, F = M × a
∴ F = 0.147 N = 20.0 kg × a
a = 0.147 N/(20.0 kg) = 0.00735 m/s²
The acceleration of the truck = a = 0.00735 m/s²
3) The tension in the cord = F = 0.147 N
4) The time, t, it would take the block to go 1.2 m to the edge of the table is given by the kinematic equation, s = u·t + 1/2·a·t²
Where;
s = The distance to the edge of the table = 1.2 m
u = The initial velocity = 0 m/s (The cart is assumed to be initially at rest)
a = The acceleration of the cart = 0.00735 m/s²
t = The time taken
Substituting the known values, gives;
s = u·t + 1/2·a·t²
1.2 = 0 × t + 1/2 ×0.00735 × t²
1.2 = 1/2 ×0.00735 × t²
t² = 1.2/(1/2 ×0.00735) ≈ 326.5306
t = √(1.2/(1/2 ×0.00735)) ≈ 18.07
The time it would take the block to go 1.2 m to the edge of the table = t ≈ 18.07 s
5) The velocity, v, of the cart as soon as it gets to the edge of the table is given by the kinematic equation, v² = u² + 2·a·s as follows;
v² = u² + 2·a·s
u = 0 m/s
v² = 0² + 2 × 0.00735 × 1.2 = 0.001764
v = √(0.001764) = 0.042
The velocity of the cart as soon as it gets to the edge of the table = v = 0.042 m/s.
Answer:
There's no answer I'm just taking points like you did me, so thank you for your points I'll put them to good use ;)
Es muy común que cuando se viaja hacia un río o lago se juegue "ranita", el cual consiste en lanzar una piedra horizontalmente hacia adelante para que cuando ésta toque la superficie del agua haga varios "saltos" sobre el agua. Durante un juego de estos, un desocupado nota que una de las piedras que arroja se demora 0,4 s en tocar la superficie del agua y la toca a 2,5 m de la orilla del lago, desde donde fue lanzada. Encuentre: a) La altura de la que fue lanzada la piedra. b) La velocidad con la que fue lanzada.
Answer:
a) La piedra es lanzada desde una altura de 0,785 metros.
b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.
Explanation:
a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:
[tex]y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2}[/tex] (1)
Donde:
[tex]y[/tex] - Altura final, medida en metros.
[tex]y_{o}[/tex] - Altura inicial, medida en metros.
[tex]v_{o,y}[/tex] - Componente vertical de la velocidad inicial, medida en metros por segundo.
[tex]t[/tex] - Tiempo, medido en segundos.
[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo cuadrado.
Si sabemos que [tex]y = 0\,m[/tex], [tex]v_{o,y} = 0\,\frac{m}{s}[/tex], [tex]t = 0,4\,s[/tex] y [tex]g = -9,807\,\frac{m}{s^{2}}[/tex], entonces la altura inicial de la piedra es:
[tex]y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}[/tex]
[tex]y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}[/tex]
[tex]y_{o} = 0,785\,m[/tex]
La piedra es lanzada desde una altura de 0,785 metros.
b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:
[tex]v_{o,x} = \frac{x-x_{o}}{t}[/tex] (2)
Donde:
[tex]x_{o}[/tex], [tex]x[/tex] - Posiciones horizontales iniciales y finales, medidas en metros.
[tex]t[/tex] - Tiempo, medido en segundos.
Si tenemos que [tex]x_{o} = 0\,m[/tex], [tex]x = 2,5\,m[/tex] y [tex]t = 0,4\,s[/tex], entonces el componente horizontal de la velocidad inicial es:
[tex]v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}[/tex]
[tex]v_{o,x} = 6,25\,\frac{m}{s}[/tex]
La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.
help please asap due 20 minutes please help me