The evaluate value of integral
[tex]\int_{0}^{\infty}7xe^{-x²} dx[/tex], is equals to the [tex] \frac{ 7 }{2}[/tex]
and limit of integral is finite so, this integral converges.
Integral test is used to check the Integral convergence. Integral is converge whose limit exists and is finite, and integral divergence is defined as an integral whose limit is either ±∞ , or nonexistent. When evaluating an integral with one boundary at infinity, that is [tex]\int_{a}^{\infty} f(x) dx = \lim_{A→ ∞ }\int_{a}^{A} f(x) dx [/tex]. We have an integral say [tex]I =\int_{0}^{+ \infty}7xe^{- x²} dx [/tex]
[tex] =\int_{0}^{\infty} 7xe^{- x²} dx [/tex]
We have to evaluate it and check it converges or not. Now, put x² = z
=> 2xdx = dz
when x = 0 => z = 0 and x = ∞=> z = ∞
[tex]\int_{0}^{\infty}7xe^{-x²} dx = \int_{0}^{\infty}\frac{ 7 }{2}e^{ - z} dz [/tex]
[tex]= \frac{ 7 }{2}\int_{0}^{\infty}e^{ - z} dz [/tex]
Now, consider the limits of integral, [tex]= \frac{ 7 }{2}\lim_{ε → ∞}\int_{0}^{ε}e^{ - z} dz \\ [/tex]
[tex]= \frac{ 7 }{2}\lim_{ε → ∞}[ -e^{ - z} ]_{0}^{ε} \\ [/tex]
[tex]= \frac{ 7 }{2}\lim_{ε → ∞}( 1 -e^{ -ε} ) \\ [/tex]
[tex]= \frac{ 7 }{2}( 1 -e^{ - \infty} )[/tex]
[tex]= \frac{ 7 }{2}( 1 - 0 ) = \frac{ 7 }{2}[/tex]
which is a finite number. Hence, integral is converges.
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Complete question:
Evaluate the integrals that converge enter 'DNE' if integral Does Not Converge
[tex]I =\int_{0}^{ + \infty} 7xe^{- x²} dx [/tex]
Jump to Problem: [ 1 2 3 4 5 ,]
18,12,8,.
Find the 8th term.
What’s the answer
The 8th term in the sequence is -24.
To find the 8th term in the sequence 18, 12, 8, we need to first identify the pattern or rule that generates the sequence. From observing the sequence, we can see that each term is obtained by subtracting 6 from the previous term.
So, the sequence can be written as:
18, 12, 6, 0, -6, -12, -18, -24, ...
To find the 8th term, we need to apply the pattern 7 times (since we already have the first term).
Starting with 18, we subtract 6 seven times:
18 - 6 = 12
12 - 6 = 6
6 - 6 = 0
0 - 6 = -6
-6 - 6 = -12
-12 - 6 = -18
-18 - 6 = -24
It's important to note that the pattern we identified only applies to this specific sequence. To find the nth term of a sequence, we need to look for a more general pattern or rule that generates all the terms in the sequence.
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For the following frequency table, the (سؤال إضافي) median, mode and range respectively are Class f [3 – 10] 1 [11 – 18] 5 [19 – 26] 2 [27 – 34] 4 a. 18.5, 15.07 and 32 b. 19.5, 15.07 and 32.5 c. 19.5, 16.07 and 31 d. 12.1, 26.5 and 31 e. 12.1, 11.07 and 31
The answer is (b) 19.5, 15.07, and 32.5.
To find the median, we need to first calculate the cumulative frequency:
Class f Cumulative Frequency [3 – 10] 1 1 [11 – 18] 5 6 [19 – 26] 2 8 [27 – 34] 4 12
Since there are 12 observations in total, the median will be the average of the 6th and 7th values, which fall in the [11-18] class. Using the midpoint formula, we can find that the lower bound of the [11-18] class is 11 and the class width is 8. Therefore:
Median = 11 + [(6 - 1)/5] x 8 = 11 + 1.0 x 8 = 19
To find the mode, we need to identify the class with the highest frequency, which is the [11-18] class with a frequency of 5. The mode is then the midpoint of this class, which can be calculated as:
Mode = 11 + [(5 - 1)/2] x 8 = 11 + 2 x 8 = 27
To find the range, we subtract the smallest observation (3) from the largest observation (34):
Range = 34 - 3 = 31
Therefore, the answer is (b) 19.5, 15.07, and 32.5.
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Let a, b, c be positive natural numbers. Determine whether the following statement is true or false: If u > x and v > y then ged(u, v) > ged(x,y). O True O False
The statement is true, if u > x and v > y then ged(u, v) > ged(x,y).
First, let's define ged(u,v) as the greatest common divisor of u and v.
Assuming that u > x and v > y, we can express u and v as:
u = x + m
v = y + n
where m and n are positive natural numbers.
Now, let's assume that ged(x,y) = d, where d is a positive natural number that divides both x and y.
Therefore, we can express x and y as:
x = dp
y = dq
where p and q are positive natural numbers.
Now, we can express u and v in terms of d as well:
u = dp + m
v = dq + n
Since m and n are positive natural numbers, it follows that ged(u,v) is a positive natural number as well.
Now, we need to show that ged(u,v) > d.
Assume the contrary, i.e. ged(u,v) ≤ d.
This means that there exists a positive natural number k that divides both u and v, and k ≤ d.
Since k divides both u and v, it must also divide their difference:
u - v = (d * p + m) - (d * q + n) = d * (p - q) + (m - n)
Therefore, k must also divide (m - n).
But since m and n are positive natural numbers, we have:
|m - n| < max(m,n) ≤ max(u,v)
Therefore, k cannot divide both (m - n) and max(u,v), which contradicts the assumption that k divides both u and v.
Therefore, our initial assumption that ged(u,v) ≤ d must be false, which means that ged(u,v) > d.
Therefore, the statement is true.
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Student's Practice Question 2012
2. If |=|≤1, determine the maximum modulus (=) max
(a) ƒ(=)=z²-2=+3, (b) ƒ(z) =z²+= −1, (c) ƒ (z) z+1/2z-1 (d) cos(z)
The maximum modulus is the maximum value of |z| within the given domain.
To find the maximum modulus, we need to find the point(s) within the unit circle where the modulus is the highest.
(a) ƒ(z) = z² - 2z + 3
We can write ƒ(z) as ƒ(z) = (z - 1)² + 2, which is a parabola that opens upwards. The maximum modulus occurs at the vertex, which is located at z = 1, and the maximum modulus is ƒ(1) = 2.
(b) ƒ(z) = z² + z - 1
We can write ƒ(z) as ƒ(z) = (z + 1/2)² - 5/4, which is a parabola that opens upwards. The maximum modulus occurs at the vertex, which is located at z = -1/2, and the maximum modulus is ƒ(-1/2) = 1/4.
(c) ƒ(z) = (z + 1)/(2z - 2)
We can write ƒ(z) as ƒ(z) = 1/2 + 3/(2z - 2), which is a hyperbola that opens downwards. The maximum modulus occurs at the point where the real part of z is 1/2, and the imaginary part of z is 0, which is located at z = 1. The maximum modulus is ƒ(1) = 2.
(d) ƒ(z) = cos(z)
The maximum modulus of cos(z) occurs at z = 0 or z = π, where the modulus is 1.
Therefore, the maximum modulus for each function is:
(a) 2
(b) 1/4
(c) 2
(d) 1
Note: The modulus of a complex number z is defined as |z| = sqrt(x^2 + y^2), where x and y are the real and imaginary parts of z, respectively. The maximum modulus is the maximum value of |z| within the given domain.
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Factor. (6x+4)
A.2(3x+2)
B. 3x+2
C. 3(2x+1)
D. 2(x+2)
←
Complete the table shown to the right for the population growth model for a certain
country.
(Round to four decimal places as needed.)
2003 Population (millions)
58.8
Points: 0 of 1
Projected 2017 Population (millions) Projected Growth Rate, k
46.7
The projected growth rate (k) is equal to -1.632%.
How to determine the projected growth rate (k)?In Mathematics, a population that increases at a specific period of time represent an exponential growth rate. This ultimately implies that, a mathematical model for any population that decreases by r percent per unit of time is an exponential equation of this form:
[tex]P(t) = I(1 + r)^t[/tex]
Where:
P(t ) represents the population.t represents the time or number of years.I represents the initial population.r represents the exponential growth rate.Note: x = number of years = 2017 - 2003 = 14 years.
By substituting given parameters, we have the following:
[tex]46.7 = 58.8(1 +r)^{14}\\\\\frac{46.7}{58.8} = (1 + r)^{14}\\\\r=\frac{46.7}{58.8}^{\frac{1}{14}} -1[/tex]
Growth Rate, r = -0.01632 = -1.632%
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Suppose x has a distribution with = 30 and = 28.
(a) If a random sample of size n = 31 is drawn, find x, x and P(30 ≤ x ≤ 32). (Round x to two decimal places and the probability to four decimal places.)
x =
x =
P(30 ≤ x ≤ 32) =
(b) If a random sample of size n = 62 is drawn, find x, x and P(30 ≤ x ≤ 32). (Round x to two decimal places and the probability to four decimal places.)
x =
x =
P(30 ≤ x ≤ 32) =
(c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).)
The standard deviation of part (b) is ---Select--- larger than the same as smaller than part (a) because of the ---Select--- same smaller larger sample size. Therefore, the distribution about x is ---Select--- narrower the same wider .
a) P(30 ≤ x ≤ 32) = 0.3446.
b) P(30 ≤ x ≤ 32) = 0.2868.
c) The probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).
We have,
(a)
The mean of the distribution is = 30 and the standard deviation is = 28.
For a sample size n = 31, the sample mean x follows a normal distribution with mean = 30 and standard deviation = /√n = 28/√31 = 5.02 (approx.).
Therefore, x ~ N(30, 5.02).
The probability P(30 ≤ x ≤ 32) can be found by standardizing the values using the formula z = (x - ) / , where z is the standard normal variable.
z1 = (30 - 30) / 5.02 = 0
z2 = (32 - 30) / 5.02 = 0.40
P(30 ≤ x ≤ 32) = P(0 ≤ z ≤ 0.40) = 0.3446 (approx.)
Therefore, x = 30, x = 5.02, and P(30 ≤ x ≤ 32) = 0.3446 (approx.).
(b)
For a sample size n = 62, the sample mean x follows a normal distribution with mean = 30 and standard deviation = /√n = 28/√62 = 3.56 (approx.).
Therefore, x ~ N(30, 3.56).
The probability P(30 ≤ x ≤ 32) can be found using the same method as in part (a).
z1 = (30 - 30) / 3.56 = 0
z2 = (32 - 30) / 3.56 = 0.56
P(30 ≤ x ≤ 32) = P(0 ≤ z ≤ 0.56) = 0.2868 (approx.)
Therefore, x = 30, x = 3.56, and P(30 ≤ x ≤ 32) = 0.2868 (approx.).
(c)
The standard deviation of part (b) is smaller than part (a) because of the larger sample size.
Therefore, the distribution about x is narrower in part (b) than in part (a). This means that the sample mean x in part (b) is likely to be closer to the population mean than the sample mean x in part (a).
As a result, the probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).
Thus,
a) P(30 ≤ x ≤ 32) = 0.3446.
b) P(30 ≤ x ≤ 32) = 0.2868.
c) The probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).
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Sylvia is considering investing in one of two bond packages offered to her by different brokers. Broker U suggests that Sylvia buy two par value $1,000 bonds from Franklin County, three par value $500 bonds from Enam Telecom, and two par value $1,000 bonds from the city of Iligs.. Franklin County bonds are selling at 96.674, Enam Telecom bonds are selling at 109.330, and Iligs bonds are selling at 103.851. Broker V suggests that Sylvia buy four par value $500 bonds from Trochel Office Supplies, one par value $500 bond from Okaloosa county, and three par value $1,000 bonds from Globin Publishing. Bonds from Trochel Office Supplies are selling at 105.142, Okaloosa county bonds are selling at 85.990, and Globin Publishing bonds are selling at 97.063. If Broker U charges a commission of 2.8% of the market value of the bonds sold and Broker V charges a fee of $65 for each bond sold, which bond package will cost Sylvia less, and by how much? a. Broker V’s bond package will cost Sylvia $366.00 less than Broker U’s. b. Broker V’s bond package will cost Sylvia $205.77 less than Broker U’s. c. Broker U’s bond package will cost Sylvia $156.02 less than Broker V’s. d. Broker U’s bond package will cost Sylvia $361.79 less than Broker V’s.
Broker U's package costs $156.02 less money than Broker V's package. The Option C is correct.
How do we conclude that Broker U cost less money?Broker U: 2.8% commission
2 par value bonds $1,000 x 96.674% = $1,933.48
3 par value bond $500 x 109.330% = $1,639.95
2 par value bonds $1,000 x 103.851% = $2,077.02
Silvia's total investment:
= ($1,933.48 + $1,639.95 + $2,077.02) x 1.028
= $5,808.66
Broker V: $65 per bond plus
4 par value bonds $500 x 105.142% = $2,102.84
1 par value bond $500 x 85.990% = $429.95
3 par value bonds $1,000 x 97.063% = $2,911.89
Silvia's total investment:
= $2,102.84 + $429.95 + $2,911.89 + (8 x $65)
= $5,964.68
By how much of less that these bond package cost is:
= Broker V's offer - Broker U's offer
= $5,964.68 - $5,808.66
= $156.02
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ASAP PLSSS DUE TODAY I REALLY REALLY NEED HELP!!!!!!!!!!!!
1. A standard cereal box has roughly the following dimensions: 9 in. x 2 in. x 12 in. What is the volume of the box in cubic inches?
- 23
-216
-75
-144
-300
2. For the same cereal box with dimensions of 9 in. x 2 in. x 12 in, what is the surface area in square inches?
- 23
-216
-75
-144
-300
3. Calculate the cost of manufacturing this cereal box if cardboard costs $0.01 per square inch.
-3.00
- 2.16
- 0.75
- 1.44
- 2.86
4. A spherical container is designed to hold as much volume as the rectangular prism above. Its radius is 3.7 in. Find the surface area of the sphere rounded to the nearest square inch.
172 square inches
216 square inches
141 square inches
128 square inches
5. Using your answers from above, which design would cost less in packaging
The rectangular prism with dimensions of 9 in. x 2 in. x 12 in
the sphere with a radius of 3.7 in.
6. A family-size cereal box in the shape of a rectangular prism with dimensions of 13 in x 10 in x 3 in holds 390 cubic inches of cereal. If the packaging is redesigned to be a cylinder with a height of 5 inches, what would be the approximate radius so that it still holds the same volume of cereal?
7 inches
4 inches
6 inches
5 inches
7. A travel-size cereal box has dimensions of 3 in. x 1.5 in. x 4.5 in. If it is redesigned to be a cube with the same surface area, what would be the length of each side in the cube?
3.2 inches
6.4 inches
2.9 inches
2.2 inches
8. For the two designs in question #7, which one holds more volume?
the rectangular prism with dimensions of 3 in. x 1.5 in. x 4.5 in.
the cube with a side length from the answer in #7
9. What are some factors that a cereal company may consider in creating their packaging?
How well it stacks for shipping and storing on shelves
How easy it is to hold and pour
How much advertising space there is on the front of the design
All of the above
1. The volume of the box is given by:
Volume = length x width x height = 9 in. x 2 in. x 12 in. = 216 cubic inches
So, the answer is 216 cubic inches.
2. The surface area of the box is given by:
Surface Area = 2lw + 2lh + 2wh = 2(9)(12) + 2(9)(2) + 2(2)(12) = 216 + 36 + 48 = 300 square inches
So, the answer is 300 square inches.
3. The surface area of the cereal box is 300 sq. in.
If cardboard costs $0.01 per square inch, then the cost of manufacturing this cereal box would be:
300 sq. in. x $0.01/sq. in. = $3.00
Therefore, the correct answer is -3.00.
4. The volume of the rectangular prism is given by:
Volume = length x width x height = 9 in. x 2 in. x 12 in. = 216 cubic inches
To find the surface area of the sphere, use the formula:
A = 4πr²
Plugging in r = 3.7 in.:
A = 4π(3.7 in.)² ≈ 172.11 square inches
Rounding this to the nearest square inch gives us:
A ≈ 172 square inches
5. The rectangular prism with dimensions of 9 in. x 2 in. x 12 in. would cost less in packaging.
6. The volume of the cylinder is given by:
Volume = πr²h = 390 cubic inches
Solving for r:
r ≈ 4 inches
Therefore, the approximate radius of the cylinder should be 4 inches to hold the same volume of cereal as the rectangular prism.
7. The surface area of the travel-size cereal box is given by:
Surface Area = 2lw + 2lh + 2wh = 2(3)(1.5) + 2(3)(4.5) + 2(1.5)(4.5) = 9 + 27 + 13.5 = 49.5 square inches
To find the length of each side in the cube with the same surface area, we use the formula:
Surface Area of Cube = 6s²
49.5 = 6s²
s ≈ 2.2 inches
So, the length of each side in the cube would be approximately 2.2 inches.
8. The rectangular prism with dimensions of 3 in. x 1.5 in. x 4.5 in. holds more volume than the cube with a side length of approximately 2.2 inches.
9. Some factors that a cereal company may consider in creating their packaging include how well it stacks for shipping and storing on shelves, how easy it is to hold and pour, and how much advertising space there is on the front of the design.
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3) Find the simple interest.
Rafael borrowed $12,000 at 6% interest to be paid back in 7 years. How much interest will that cost him?
Please help asap
Step-by-step explanation:
Simple interest = prt÷100
Here,
Principle = 12000
Rate = 6
Time = 7
So to find the simple interest,
You just apply the formula.
[tex]\frac{p \times r \times t}{100} = \frac{12000 \times 6 \times 7}{100} = 5040[/tex]
Interest = 5040
Nick worked 6 hours today and earned a total of $54. What is Nick's hourly wage? Equation_______Nick earns______per hour.
The amount that is Nick's hourly wage would be = $9.
How to calculate tye amount of money that Nick earns hourly as a wage?The total number of hours that Nick works a day = 6 hours
The total amount of money that Nick earned for those hours = $54
That is;
6 hours = 54
1 hours = X
Mark X the subject of formula;
X = 54/6
= $9
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If you are comparing the difference between two separate populations, such as children who attend two different Elementary schools, you should use a(an) a. Within-groups design b. One-tailed t-test c. Repeated-measures design
d. Independent-measures design
A one-tailed t-test is used when the researcher has a specific directional hypothesis.
If you are comparing the difference between two separate populations, such as children who attend two different Elementary schools, you should use an independent-measures design. In an independent-measures design, two separate groups of participants are sampled, and each participant is only tested once. The purpose of this design is to compare the means of two independent populations to determine if there is a statistically significant difference between them. In contrast, a within-groups design would involve testing the same group of participants twice under different conditions, while a repeated-measures design would involve testing the same group of participants under all conditions. A one-tailed t-test is a specific type of statistical test that can be used in either an independent-measures or within-groups design to test a directional hypothesis.
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COM Question 7 of 8, Step 1 of 5 Consider the following data: 5 6 8 9 VO P(X = x) 0.2 0.2 0.2 0.2 0.2 Step 1 of 5: Find the expected value E(X). Round your answer to one decimal place.
The expected value E(X) is 5.6.
To find the expected value E(X) of the given data, we'll use the terms you provided: data points (5, 6, 8, 9), probabilities (0.2, 0.2, 0.2, 0.2), and the formula E(X) = Σ [x * P(X = x)].
Step 1: List the data points and their corresponding probabilities:
X: 5, 6, 8, 9
P(X = x): 0.2, 0.2, 0.2, 0.2
Step 2: Use the formula E(X) = Σ [x * P(X = x)] and plug in the values:
E(X) = (5 * 0.2) + (6 * 0.2) + (8 * 0.2) + (9 * 0.2)
Step 3: Calculate each term:
E(X) = 1 + 1.2 + 1.6 + 1.8
Step 4: Sum up the terms:
E(X) = 5.6
Step 5: Round your answer to one decimal place:
E(X) = 5.6
So, the expected value E(X) of the given data is 5.6.
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Edwin wrote the word MATHEMATICS on separate index cards. What is the probability of pulling out a “M” and then an “A”, If you do not replace the first letter?
Show all work.
Hi, can someone please help me with this math problem
Which function is represented by the graph?
please help
The function of the trigonometric graph plotted is
y = cos (x - π/4) - 2How to determine the equation graphedThe equation is written by the general formula
y = A cos (Bx + C) + D
where:
A = amplitude.
B = 2π/T, where T = period
C = phase shift.
D = vertical shift.
amplitude
A = (maximum - minimum) / 2
from the graph,
maximum = 1
minimum = -1
A = |-1 - (-3)| / 2 = 2/2 = 1
B = 2π/T
where T = 2π
B = 2π/(2π) = 1
C = phase shift
= 0 - π/4
= - π/4
D = vertical shift
= 0 - 2 = -2
plugging in the results of the parameters to the equation
y = 1 cos (1x + (-π/4)) + (-2)
this is written as
y = cos (x - π/4) - 2
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dude someone hurry up and help please
The proportion that can be used to find the length of the side y for the similar triangle DEF is y/16 = 38/32, which makes option C correct.
What are similar trianglesSimilar triangles are two triangles that have the same shape, but not necessarily the same size. This means that corresponding angles of the two triangles are equal, and corresponding sides are in proportion.
The side DE corresponds to AB, also the side DF corresponds to AC, so;
DE/AB = DF/AC
y/38 = 16/32
by cross multiplication;
y/16 = 38/32
Therefore, the proportion that can be used to find the length of the side y for the similar triangle DEF is y/16 = 38/32.
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(Competing patterns among coin flips) Suppose that Xn, n 2 1 are i.i.d. random variables with P(X1 = 1) = P(X1 = 0) = }. (These are just i.i.d. fair coin flips.) Let A = (a1, a2, a3) = (0,1, 1), B = (b1, b2, b3) = (0,0, 1). Let TA = min(n 2 3: {X,-2, Xn-1, Xn) = A} be the first time we see the sequence A appear among the X, random variables, and define Tg similarly for B. Find the probability that P(TA < TB). (This is the probability that THH shows up before TTH in a sequence of fair coin flips.)
The probability of A appearing before B is [tex]\frac{4}{7}[/tex].
To find the probability that TA < TB, we can use the fact that the probability of a certain pattern appearing in a sequence of coin flips is independent of the position in the sequence. In other words, the probability of A appearing at time n is the same as the probability of A appearing at time n+k for any k.
Using this fact, we can set up a system of equations to solve for the probability of TA < TB. Let p be the probability of A appearing before B, and q be the probability of B appearing before A. Then we have:
[tex]p = \frac{1}{2} + \frac{1}{2q}[/tex] (since the first flip can be either 0 or 1 with equal probability)
[tex]q= \frac{1}{4p} + \frac{1}{2q} + \frac{1}{4}[/tex] (if the first two flips are 0, the sequence B has appeared; if the first flip is 1 and the second is 0, the sequence is neither A nor B and we start over; if the first flip is 1 and the second is 1, we have a new chance for A to appear before B)
Solving for p, we get:
[tex]p=\frac{4}{7}[/tex]
Therefore, the probability of A appearing before B is [tex]\frac{4}{7}[/tex].
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Which segment is opposite to
The segment that is opposite ∠ E is C. UJ.
What are opposite segments ?A segments that could be formed through connecting the endpoints of the adjacent segments are called the opposite segments. This can also create an intersection in certain types of lines or segment configurations, depending on their individual set ups.
When looking at angle ∠ E, we can see that the segment opposite it is Segment UJ. This is because it was formed by connecting the endpoints of the adjacent segments of UE and JE.
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Mieko bought 2 gallons of paint. She used 1/4 of the paint on her bedroom, 3 quarts on the hallway, and the rest of the pain in the living room. How many quarts of paint did mieko use in the living room?
Therefore, she used 8 - 5 = 3 quarts of paint in the living room.
An English measurement of volume equal to one-quarter gallon is the quart. There are now three different types of quarts in use: the liquid quart, dry quart, and imperial quart of the British imperial system. One litre is about equivalent to each. It is split into four cups or two pints.
Legally, a US liquid gallon (sometimes just referred to as "gallon") is equal to 231 cubic inches, or precisely 3.785411784 litres. Since a gallon contains 128 fluid ounces, it would require around 16 water bottles, each holding 8 ounces, to fill a gallon.
Here 2 gallons is equivalent to 8 quarts (2 gallons x 4 quarts/gallon = 8 quarts).
Mieko used 1/4 of the paint on her bedroom, which is 1/4 x 8 = 2 quarts.
She used 3 quarts on the hallway, so she used a total of 2 + 3 = 5 quarts on the bedroom and hallway.
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Write an equation of the perpendicular bisector of the segment with the endpoints (2,1) and (6,3)
Answer:
Step-by-step explanation:
Answer
Equation of a straight line
y = -0.33x + 4.995
Answer:
Step-by-step explanation:
Find the midpoint of the segment by using the formula [(x1 + x2)/2, (y1 + y2)/2]. The midpoint is [(2 + 6)/2, (1 + 3)/2] = (4, 2).
Find the slope of the segment by using the formula (y2 - y1)/(x2 - x1). The slope is (3 - 1)/(6 - 2) = 1/2.
Find the negative reciprocal of the slope by flipping the fraction and changing the sign. The negative reciprocal is -2/1 or -2.
Find the equation of the perpendicular bisector by using the point-slope form y - y1 = m(x - x1), where m is the negative reciprocal and (x1, y1) is the midpoint. The equation is y - 2 = -2(x - 4).
Simplify the equation by distributing and rearranging. The equation is y = -2x + 10. This is the equation of the perpendicular bisector in slope-intercept form.
Find the area of the shaded region
The area of the shaded part is 100.48cm²
What is area of shape?Area is defined as the total space taken up by a flat (2-D) surface or shape of an object. The area of the shaded part can be expressed as;
area of shaded part = 4 × area of semi circle
Area of semi circle = 1/2 πr²
radius = diameter/2
radius = 8/2 = 4
= 1/2 × 3.14 ×4²
= 3.14 ×16×1/2
= 3.14 × 8
= 25.12 cm²
Since the shaded parts are semi circles
then the area of the shaded part = 4× 25.12
= 100.48cm²
therefore the area of shaded part is 100.48cm²
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Solve the equation by factoring. 4x² – 15x = 4
The solution to this equation 4x² – 15x = 4 include the following: D. x = 4, -1/4.
What is the general form of a quadratic function?In Mathematics and Geometry, the general form of a quadratic function can be modeled and represented by using the following quadratic equation;
y = ax² + bx + c
Where:
a and b represents the coefficients of the first and second term in the quadratic function.c represents the constant term.Next, we would solve the quadratic function by using the factorization method as follows;
4x² – 15x = 4
Subtract 4 from both sides of the quadratic function:
0 = 4x² – 15x - 4
0 = 4x² - 16x + x - 4
(4x + 1)(x - 4)
x = 4 or x = -1/4.
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4. Part A
James has a board that is foot long. He wants to cut the board into pieces
that are each foot long.
How many pieces can James cut from the board? Explain how James can use
the number line diagram to determine the number of pieces he can cut from
the board.
Enter your answer and your explanation in the space provided.
Part B
Write an equation using division that represents how James can find the
number of pieces he can cut from the board.
The number of pieces that James can cut from the board is 6 pieces.
How to get the number of piecesTo get the number of pieces that James can cut from the board, we will have to determine how many 1/8 divisions there are in a total of 3/4 foot long board. When the division is done, we will have:
3/4 ÷ 1/8
=3/4 × 8/1
= 6
So, James can hope to get 6 pieces of 1/8 foot long board pieces.
An equation using division that represents how James can find the number of pieces is 3/4 ÷ 1/8.
Complete Question:
4. Part A
James has a board that is 3/4 foot long. He wants to cut the board into pieces
that are each 1/8 foot long.
How many pieces can James cut from the board? Explain how James can use
the number line diagram to determine the number of pieces he can cut from
the board.
Enter your answer and your explanation in the space provided.
Part B
Write an equation using division that represents how James can find the
number of pieces he can cut from the board.
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The value of 8 dimes is ____% of the value of a dollar
Answer:
80%
Step-by-step explanation:
Solve for x:
x = ($0.80 / $1.00) * 100 x = 0.8 * 100 x = 80
So, the value of 8 dimes is 80% the value of a dollar.
Hope this helps :)
Pls brainliest...
Answer:
80%
Step-by-step explanation:
a dime is 10 cents and a dollar is 100 cents so 8times 10 is 80 so therefore 8 dimes is 80 cents so its 80% of a dollar
(5 MARKS) Prove that F (c)(A + B) → (Vx) A (3.c)B. 4. (5 MARKS) All the sets in this problem are subsets of N. For any ACN, let us use the notation ADES N-A
To prove F(c)(A + B) → (Vx) A (3.c)B, we need to show that if the union of sets A and B is finite, then there exists an element x in A such that for all elements y in B, (x, y) is in the relation C.
Assume F(c)(A + B) is true. Then for any (x, y) in C, x belongs to A + B, which means x belongs to either A or B. If x belongs to A, then we have found an element x in A such that for all elements y in B, (x, y) is in C, and we are done. If x belongs to B, then we need to find another element in A such that the condition holds.
Since A and B are finite, their union A + B is also finite. Let n be the size of A + B. Then there are n distinct elements in A + B, say a1, a2, ..., an. Since there are more elements in A than in B (or equal if they have the same size), there must be at least one element of A among a1, a2, ..., an. Call this element x.
Now, consider any element y in B. Since x belongs to A + B and y belongs to B, their sum x + y belongs to A + B as well. But we know that x + y cannot be equal to x, since y is not in A. Therefore, x + y must be equal to one of the remaining n-1 elements of A + B, say ai. But then ai - x = y, so (x, y) is in C.
Therefore, we have shown that F(c)(A + B) → (Vx) A (3.c)B is true.
For the second part of the question, we need to show that for any set A in N, there exists a set B in N such that A is a subset of B and B is infinite.
Let B be the set of all natural numbers greater than the maximum element in A. Then A is clearly a subset of B, and B is infinite since it contains all natural numbers greater than a certain number.
Therefore, we have shown that for any set A in N, there exists a set B in N such that A is a subset of B and B is infinite.
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An arch is in the shape of a parabola. It has a span of 280 meters and a maximum height of 28 meters.
Find the equation of the parabola.
Determine the distance from the center at which the height is 13 meters.
The equation of the parabola is given as follows:
y = -28/19600(x - 140)² + 28.
The distances from the center for a height of 13 meters are given as follows:
37.53 m and 242.47 m.
How to obtain the equation of the parabola?The equation of a parabola of vertex (h,k) is given by the equation presented as follows:
y = a(x - h)² + k.
In which a is the leading coefficient.
It has a span of 280 meters, hence the x-coordinate of the vertex is given as follows:
x = 280/2
x = 140 -> h = 140.
The maximum height is of 28 meters, hence the y-coordinate of the vertex is given as follows:
y = 28 -> k = 28.
Hence the equation is:
y = a(x - 140)² + 28.
When x = 0, y = 0, hence the leading coefficient a is obtained as follows:
19600a = -28
a = -28/19600
Hence:
y = -28/19600(x - 140)² + 28.
The distance from the center at which the height is 13 meters is obtained as follows:
13 = -28/19600(x - 140)² + 28.
28/19600(x - 140)² = 15
(x - 140)² = 15 x 19600/28
(x - 140)² = 10500.
Hence the distances are obtained as follows:
x - 140 = -sqrt(10500) -> x = -sqrt(10500) + 140 = 37.53 m.x - 140 = sqrt(10500) -> x = sqrt(10500) + 140 = 242.47 m.More can be learned about quadratic functions at https://brainly.com/question/1214333
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1.Which of these statement true or false? Clearly explain your answer.
a. The series
[infinity]
Σ5n/2n³ + n² + 1
n=1
diverges by the nth test.
b. Comparing the series
[infinity]
Σ5n/2n³ + n² + 1
n=1
With the Harmonix series shoes that it diverges bybthe comparison test.
2. Determine convergence of the series
[infinity]
Σn/√n²+1
n=1
The limit comparison test, we can conclude that the series Σ(n/√(n²+1)) also converges.
(a) To determine if the series Σ(5n/2n³ + n² + 1) from n=1 to infinity diverges, we can use the nth term test for divergence.
The nth term test for divergence states that if the limit of the nth term of a series as n approaches infinity is not zero, then the series diverges.
Let's evaluate the limit of the nth term of our series:
lim (n → ∞) (5n/2n³ + n² + 1)
As n approaches infinity, the term 5n/2n³ becomes 0 because the exponential term in the denominator grows much faster than the numerator. However, the terms n² and 1 remain constant.
Therefore, the limit of the nth term is 0.
Since the limit of the nth term is 0, the nth term test for divergence does not provide conclusive evidence, and we cannot determine whether the series converges or diverges.
(b) To compare the series Σ(5n/2n³ + n² + 1) from n=1 to infinity with the harmonic series, we need to show that it diverges by the comparison test.
The comparison test states that if 0 ≤ aₙ ≤ bₙ for all n, and the series Σbₙ diverges, then the series Σaₙ also diverges.
Let's compare the given series with the harmonic series Σ(1/n) from n=1 to infinity:
0 ≤ 5n/2n³ + n² + 1 ≤ 5n/2n³ + n² + n²
Simplifying the inequality:
0 ≤ 5n/2n³ + n² + 1 ≤ 5/2n + 2
Now, let's consider the harmonic series Σ(1/n):
The harmonic series Σ(1/n) is a well-known divergent series. It can be proven that Σ(1/n) diverges.
By comparison, since we have shown that 0 ≤ 5n/2n³ + n² + 1 ≤ 5/2n + 2, and the harmonic series diverges, we can conclude that the series Σ(5n/2n³ + n² + 1) also diverges by the comparison test.
Therefore, both (a) and (b) conclude that the series Σ(5n/2n³ + n² + 1) from n=1 to infinity diverges.
To determine the convergence of the series Σ(n/√(n²+1)) from n=1 to infinity, we can use the limit comparison test.
Let's consider the series Σ(1/√n) from n=1 to infinity, which is a well-known series with known convergence.
First, we need to check if the terms of the series Σ(n/√(n²+1)) are positive for all n. Since both n and √(n²+1) are positive for positive values of n, the terms n/√(n²+1) are also positive.
Now, let's evaluate the limit of the ratio of the nth term of the given series and the corresponding term of the series Σ(1/√n):
lim (n → ∞) (n/√(n²+1)) / (1/√n)
= lim (n → ∞) (n/√(n²+1)) * (√n/1)
= lim (n → ∞) √(n³)/(√(n²+1))
= lim (n → ∞) √(n)
As n approaches infinity, the limit √(n) also approaches infinity.
Since the limit of the ratio is not a finite positive value, but instead approaches infinity, the series Σ(n/√(n²+1)) and the series Σ(1/√n) have the same convergence behavior.
The series Σ(1/√n) is a harmonic series with a known convergence. It can be shown that Σ(1/√n) converges.
Therefore, by the limit comparison test, we can conclude that the series Σ(n/√(n²+1)) also converges.
In summary, the series Σ(n/√(n²+1)) from n=1 to infinity converges.
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a program exists to encourage more middle school students to major in math and science when they go to college. the organizers of the program want to estimate the proportion of students who, after completing the program, go on to major in math or science in college. the organizers will select a sample of students from a list of all students who completed the program. which of the following sampling methods describes a stratified random sample?
The sampling method that describes a stratified random sample is (D) Randomly select 25 names from the female students on the list and randomly select 25 names from the male students on the list. The correct option is D.
Stratified random sampling involves dividing the population into strata or subgroups based on some characteristics, such as gender in this case, and then randomly selecting a sample from each stratum to ensure representation from all groups in the population.
Option (A) only selects one subgroup, while option (B) and (E) are simple random samples that do not involve dividing the population into strata.
Option (C) is systematic sampling, which involves selecting every nth individual from the population after randomizing the order of the list.
Option D is the correct option.
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Complete question:
A program exists to encourage more middle school students to major in math and science when they go to college. The organizers of the program want to estimate the proportion of students who, after completing the program, go on to major in math or science in college. The organizers will select a sample of students from a list of all students who completed the program. Which of the following sampling methods describes a stratified random sample? (A) Select all female students on the list. (B) Randomly select 50 students on the list. (C) Randomize the names on the list and then select every tenth student on the randomized list. (D) Randomly select 25 names from the female students on the list and randomly select 25 names from the male students on the list. (E) Randomly select 50 students on the list who are attending college.
A coin is loaded so that the probability of heads is 0.7 and the probability of tails is 0.3. Suppose that the coin is tossed ten times and that the results of the tosses are mutually independent. a. What is the probability of obtaining exactly seven heads? b. What is the probability of obtaining exactly ten heads? c. What is the probability of obtaining no heads? d. What is the probability of obtaining at least one head?
The probability of obtaining exactly seven heads can be calculated using the binomial probability formula: P(X=7) = (10 choose 7) * (0.7)^7 * (0.3)^3 = 0.2668, where (10 choose 7) represents the number of ways to choose 7 heads out of 10 tosses.
The probability of obtaining exactly ten heads is also calculated using the binomial probability formula: P(X=10) = (10 choose 10) * (0.7)^10 * (0.3)^0 = 0.0282, where (10 choose 10) represents the number of ways to choose all 10 heads out of 10 tosses.
The probability of obtaining no heads can be calculated by using the complement rule: P(no heads) = 1 - P(at least one head). Since there are only two outcomes (heads or tails) for each toss, the probability of obtaining no heads is simply (0.3)^10 = 0.000005904.
=The probability of obtaining at least one head can also be calculated using the complement rule: P(at least one head) = 1 - P(no heads) = 1 - (0.3)^10 = 0.999994096.\
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