Pls awnser I will mark brainliest math

Pls Awnser I Will Mark Brainliest Math

Answers

Answer 1
It’s 34....!!!! i did this before
Answer 2

Answer:

2788 or 116

Explanation:


Related Questions

Write a C console application that will be used to determine if rectangular packages can fit inside one of a set of spheres. Your program will prompt the user for the three dimensions that define a rectangular box; the length, the width, and the height. The interior diameter of a sphere is used to identify its size. Spheres are available in the following five sizes: 4- inch, 6-inch, 8-inch, 10-inch, and 12-inch. Your program will execute repeatedly until the user enters a value of zero for one or more of the rectangular box dimensions. After obtaining the dimensions of the rectangular box, your program will call a function named getSphereSize that determines if the box will fit inside one of the five spheres. The formula for calculating the diagonal of a rectangular box is:

Answers

Answer:

#include <cmath>

#include <iostream>

using namespace std;

int getSphereSize(double length, double breadth, double height) {

   double diagonal = sqrt(length * length + breadth * breadth + height * height);

   if (diagonal <= 4)

       return 4;

   if (diagonal <= 6)

       return 6;

   if (diagonal <= 8)

       return 8;

   if (diagonal <= 10)

       return 10;

   if (diagonal <= 12)

       return 12;

   return 0;

}

int main() {

   double length, breadth, height;

   int sphereCounts[5] = {0};

   int sphereSize;

   while (true) {

       // Get dimensions of the box

       cout << "Enter the dimensions of the box:\n";

       cout << "Length: ";

       cin >> length;

       cout << "Breadth: ";

       cin >> breadth;

       cout << "Height: ";

       cin >> height;

       if (length <= 0 || breadth <= 0 || height <= 0)

           break;

       sphereSize = getSphereSize(length, breadth, height);

       if (sphereSize == 0)

           cout << "The box cannot fit in any of the spheres";

       else

           cout << "The box can fit in the " << sphereSize << "-inch sphere";

       // Increment the counter

       if (sphereSize == 4)

           sphereCounts[0]++;

       else if (sphereSize == 6)

           sphereCounts[1]++;

       else if (sphereSize == 8)

           sphereCounts[2]++;

       else if (sphereSize == 10)

           sphereCounts[3]++;

       else if (sphereSize == 12)

           sphereCounts[4]++;

       cout << "\n\n";

   }

   cout << "\nNumber of 4-inch spheres: " << sphereCounts[0];

   cout << "\nNumber of 6-inch spheres: " << sphereCounts[1];

   cout << "\nNumber of 8-inch spheres: " << sphereCounts[2];

   cout << "\nNumber of 10-inch spheres: " << sphereCounts[3];

   cout << "\nNumber of 12-inch spheres: " << sphereCounts[4];

   cout << endl;

   return 0;

}

Explanation:

The "cmath" library is included in the c++ program. The getSphereSize function is used to return the sphere size the rectangle dimension can fit into. It program continuously prompts the user for the length, breadth, and height of the rectangle and passes the values to the getSphereSize function in the while but breaks if any or all of the variable value is zero.

The sizes of the sphere objects in inches are collected in an array of five integer values of zeros and are incremented by one for every match with a rectangle.

What is the correct order for writing the 3 dimensions for a 3D object? Here are the 3 dimensions:


Width


Height


Length


They need to be written in this format: ___________X___________X___________


Fill in the blanks.
for my sibling.

Answers

Answer:

Length x Width x Hight

Explanation:

The objective of this task is to use Scapy to estimate the distance, in terms of number of routers, between your VM and a selected destination. This is basically what is implemented by the traceroute tool. In this task, we will write our own tool. The idea is quite straightforward: just send an packet (any type) to the destination, with its Time-To-Live (TTL) field set to 1 first. This packet will be dropped by the first router, which will send us an ICMP error message, telling us that the time-to-live has exceeded. That is how we get the IP address of the first router. We then increase our TTL field to 2, send out another packet, and get the IP address of the second router. We will repeat this procedure until our packet finally reach the destination. It should be noted that this experiment only gets an estimated result, because in theory, not all these packets take the same route (but in practice, they may within a short period of time). The code in the following shows one round in the procedure. a = IP() a.dst = ’1.2.3.4’ a.ttl = 3 b = ICMP() send(a/b) If you are an experienced Python programmer, you can write your tool to perform the entire procedure automatically. If you are new to Python programming, you can do it by manually changing the TTL field in each round, and record the IP address based on your observation from Wireshark. Either way is acceptable, as long as you get the result.

Answers

Answer:

answer b

is correct

Match the data type to the given data.
1. float
2. array
3. Boolean
4. character

false
с
c, o, m, p, u, t, er
26.2

Answers

Float: 26.2
Array: c, o, m, p, u, t, er
Boolean: false
Character: c
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