The frictional force that acts on the puck is 0.5 N.
The given parameters;
coefficient of kinetic friction, μk = 0.1normal force of the puck, Fₙ = 5 NThe frictional force that acts on the puck is determined by taking the product of the normal force and the coefficient of kinetic friction.
The frictional force that acts on the puck is calculated as follows;
[tex]F_k = \mu_k F_n[/tex]
Substitute the given parameters in the above equation and solve the frictional force.
[tex]F_k = 0.1 \times 5\\\\F_k = 0.5 \ N[/tex]
Thus, the frictional force that acts on the puck is 0.5 N.
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Use the chemical reaction to answer the question.
Answer:
I believe this answer is -They maintain their properties-
Explanation:
Let's see what others say. :)
The blue mass in the image is 10kg.
The red mass in the image is 10kg.
The blue mass is currently 4 meters away from the red mass.
If we change each mass to 20kg, what will happen to the gravitational force each mass puts on the other?? You have to pick a answer through A,B,C! The force of gravity will increase as the masses increase.
The force of gravity will not change as the masses increase.
The force of gravity will decrease as the masses increase.