Please help me solve this much appreciated

Explanation:

Let's say this school has 1000 seniors.

25% of this count is 0.25*1000 = 250 to indicate there are 250 seniors with blue eyes. Of this smaller count, 60% of them are girls with blue eyes. So there are 0.60*250 = 150 female seniors with blue eyes.

Divide that last number over the original value: 150/1000 = 0.15 = 15%

The probability that the senior selected randomly is a blue-eyed female is 15%.

It is given that 25% of the seniors class has blue eyes of the blue student 60% are females.

Probability refers to the occurrence of random events. Basically, it is the possibility to predict how likely events are to happen.

Probability of event = Number of favorable outcomes / Total number of outcomes.

Let's consider this school has 1000 seniors.

25% of this count

0.25 × 1000 = 250

Which shows that there are 250 seniors with blue eyes.

Similarly, 60% of them are girls with blue eyes.

So, there are 0.60 × 250 = 150

there are 150 female seniors with blue eyes.

Here, the probability that seniors selected randomly is a blue-eyed female

150/1000 = 0.15

                = 15%

Therefore, the probability that the senior selected randomly is a blue-eyed female is 15%.

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Answer:

k=8

Step-by-step explanation:

2k+5=21  (-5 on both sides to get rid of +5)

2k=16      (divide by 2 to get rid of that 2 in front of K)

k=8

Answer:

D) 83 is the answer. this is because it doest divide more then 2wice like the rule

Answer:

D TRUST ME

Step-by-step explanation:

Answer:

19 meters

Step-by-step explanation:

if he goes straight up at 90 degreed to the surface of water, it would be 19 metres

[tex]\text{Given that,}\\\\(x_1,y_1) = (0,0)~~ \text{and}~~ (x_2, y_2) = (-12,5)\\\\\text{Distance between two points,}\\\\d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\\\\implies d = \sqrt{(-12-0)^2 + (5-0)^2}\\\\\implies d = \sqrt{(-12)^2 +5^2}\\\\\implies d =\sqrt{144+25}\\\\\implies d=\sqrt{169}\\\\\implies d = 13\\\\\text{So, the answer is C.}[/tex]

Answer:

1/-0.5x

Step-by-step explanation:

1/2 = 0.5

-0.5x = -1/2x

Inverse function is the same as 1/fuction, so inverse of -0.5x = 1/-0.5x

Hope that helps

Answer:

c=400

Step-by-step explanation:

Use the perfect square formula:

ax^2+bx+c=0

x^2-40x+c=0

bring c to the other side

x^2-40x+___=-c

divide -40 by 2 then square it; 400

add 400 to each side

c=400

(x-20)(x-20)

The value of c that makes the trinomial a perfect square x²– 40x + c is 400.

A quadratic equation is a second-order polynomial equation in a single variable x , ax²+bx+c=0. with a ≠ 0 .

We have to find the  value of c that makes the trinomial a perfect square: x²– 40x + c

Lets use the perfect square formula:

ax²+bx+c=0

The given equation is given below.

x²-40x+c=0

Take the c term to the right hand side

x²-40x=-c

x²-40x+400=-c+400

c=400

Hence, the value of c that makes the trinomial a perfect square x²– 40x + c is 400.

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Answer:

x = 1

y = -4

Step-by-step explanation:

if you solve for y

y = -4x

plug this into the other equation

x - -4x = 5

simplify

5x = 5

x = 1

plug x into the fist equation

4(1)+y = 0

y = -4

Step-by-step explanation:

3 is ur answer

mmmmmmmmmmm

Answer: Refer to Step-by-step explanation

Step-by-step explanation:

To find the MAD

Step 1 Find the mean of the data.

Step 2 Find the distance between each data value and the mean.

Step 3 Add the distances together from Step 2

Step 4 Divide the sum in Step 3 by the total number of values in the data.

1) MAD = 21.36

2) Mean = 56

MAD = 3.75

3) Mean = 57

MAD = 16.67

Answer:

Use the coefficient of x as the slope and constant as the y-intercept

Step-by-step explanation:

Start by going to your graph and plotting your y-intercept. For example, if the y- intercept is -2, plot the point (0, -2). Then from there, you need to plot the slope (let's pretend that the slope is 2/3). From the intercept, you will go up two and right one. Then starting from that point, continue using the rise over run to plot your points and then draw your line.

Answer:

230/p = 23/100 You would need 1,000 g of snack mix.

Step-by-step explanation:

There are 1000 snack mix would be needed to get 230g of almonds.

Given that;

23% of a snack mix is almonds.

And, there are 230g of almonds.

Let us assume that;

The number of snacks = x

Hence, it can be written as,

23% of x = 230

23/100 × x = 230

23x = 23000

x = 23000/23

x = 1000

Therefore, The number of snacks = 1000 g

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Answer: 3

Step-by-step explanation:

V=whl

Answer:

huh Step-by-step explanation:

its really hard

Answer:

y = -x - 1

Step-by-step explanation:

(y - y1)/(x - x1) = (y1 - y2)/(x1 - x2)

(y - 4)/(x - (-3)) = (4 - (-1))/(-3 -2)

(y - 4)/(x + 3) = 5/-5

(y - 4)/(x + 3) = -1

y - 4 = -1(x + 3

y - 4 = -x - 3

y = -x - 1

Answer:

This is voluntary response bias because vocal supporters of later start times will be more likely to offer their opinion.

Step-by-step explanation:

Answer:

undercoverage bias

Step-by-step explanation:

Answer:

You could substitute the point (5,-4) into each equation

Step-by-step explanation:

x=5    y=-4

3x-2y=23

3(5)-2(-4)=23

15+8=23

23=23

2x+y=6

2(5)+(-4)=6

10-4=6

6=6

The points go into each equation which proves that the point (5,-4) is the solution.

(i don't know if I did this right, I apologize if I didn't

Answer:

b = [tex]\frac{7}{12}[/tex]

Step-by-step explanation:

b + [tex]\frac{2}{3}[/tex] = 1 [tex]\frac{1}{4}[/tex] ← change to an improper fraction

b + [tex]\frac{2}{3}[/tex] = [tex]\frac{5}{4}[/tex]

Multiply through by 12 ( the LCM of 3 and 4 ) to clear the fractions

12b + 8 = 15 ( subtract 8 from both sides )

12b = 7 ( divide both sides by 12 )

b = [tex]\frac{7}{12}[/tex]

Answer:

The value of b is 7/12.

Step-by-step explanation:

Question :

Solve for b.

[tex]{\implies{\sf{b + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]

Enter your answer as a fraction in simplest form in the box.

[tex]\implies{\sf{b = \square}}[/tex]

[tex]\begin{gathered}\end{gathered}[/tex]

Solution :

[tex]{\implies{\sf{b + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]

Converting the mixed fractions into improper fraction.

[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{(1 \times 4) + 1}{4}}}}[/tex]

[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{(4)+ 1}{4}}}}[/tex]

[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{4+ 1}{4}}}}[/tex]

[tex]{\implies{\sf{b + \dfrac{2}{3} = \dfrac{5}{4}}}}[/tex]

Now, transporting LHS to RHS.

[tex]{\implies{\sf{b= \dfrac{5}{4} - \dfrac{2}{3}}}}[/tex]

Taking LCM of denominators and subtracting.

[tex]{\implies{\sf{b= \dfrac{(5 \times 3) - (2 \times 4)}{12}}}}[/tex]

[tex]{\implies{\sf{b= \dfrac{(15) - (8)}{12}}}}[/tex]

[tex]{\implies{\sf{b= \dfrac{15 - 8}{12}}}}[/tex]

[tex]{\implies{\sf{b= \dfrac{7}{12}}}}[/tex]

[tex]{\star{\red{\underline{\boxed{\sf{b= \dfrac{7}{12}}}}}}}[/tex]

Hence, the value of b is 7/12.

[tex]\begin{gathered}\end{gathered}[/tex]

Verification :

[tex]{\implies{\sf{b + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]

Substituting the value of (b=7/12)

[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = 1 \dfrac{1}{4}}}}[/tex]

Converting mixed fractions into improper fraction

[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{(1 \times 4) + 1}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{(4) + 1}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{4 + 1}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{7}{12} + \dfrac{2}{3} = \dfrac{5}{4}}}}[/tex]

Taking LCM of denominators in LHS and adding.

[tex]{\implies{\sf{ \dfrac{(7 \times 1) + (2 \times 4)}{12} = \dfrac{5}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{(7) + (8)}{12} = \dfrac{5}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{7 + 8}{12} = \dfrac{5}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{15}{12} = \dfrac{5}{4}}}}[/tex]

Cutting the fraction to simplest form.

[tex]{\implies{\sf{ \cancel{\dfrac{15}{12}} = \dfrac{5}{4}}}}[/tex]

[tex]{\implies{\sf{ \dfrac{5}{4}= \dfrac{5}{4}}}}[/tex]

[tex]{\star{\red{\underline{\boxed{\sf{LHS = RHS}}}}}}[/tex]

Hence Verified!

[tex]\underline{\rule{220pt}{3.5pt}}[/tex]

Answer:

[4  -11   1   7   l  -17]

[0  1   -1   -7  l  0]

[3  0  -2   2   l  12]

[4   1   5   3   l   7]

Step-by-step explanation:

This is Finite Math, I got this hehe :)

To find the answer, first you need to understand what R means.

It stands for "row". So R1 means "Row 1".

So: -3R1 + R3 means that you need to multiply -3 by all of the numbers in row 1 and then add all of the numbers in row 3

[0   3   1   -1   l  6]

[0  1   -1   -7  l  0]

[3  0  -2   2   l  12]

[4  1    5   3   l   7]

Then use ^^THAT^^ and apply the next set of instructions.

-4R1 + R4 means that you multiply -4 by all of the numbers in row 1 and then add all of the numbers in row 4:

[4  -11    1   7   l  -17]

[0  1   -1   -7  l  0]

[3  0  -2   2   l  12]

[4   1   5   3   l   7]

Answer:

[tex]3\frac{3}{4}[/tex]

Step-by-step explanation:

[tex]\frac{6}{8} *\frac{5}{1}[/tex]

[tex]\frac{30}{8}[/tex] multiply across

[tex]\frac{15}{4}[/tex] simplify and convert into mixed number

[tex]3\frac{3}{4}[/tex]

Answer: 28/9 as a mixed number is 3 1/9

Step-by-step explanation:

Answer:

3 1/9

Step-by-step explanation:

3 times 9 is 27

27 plus 1 is 28

Answer:

2^21

Step-by-step explanation:

3+18=21

Answer:

2/27

Step-by-step explanation:

Here is me work:

Answer:

Step-by-step explanation:

The x component of a function is domain and the y component is range of a function . For example -                                                                                                   R1={(3,4),(5,6),(7,9)}                                                                                                                  The domain of R1 ={3,5,7}                                                                                                                                                                                                                                     The range of R1={4,6,9}

If we express  [tex]3x^2-6x-2[/tex] in the form  [tex]a(x-h)^2+k[/tex], then a + h + k = -1

The given quadratic expression is:

[tex]3x^2-6x-2[/tex]

To express [tex]3x^2-6x-2[/tex] in the form [tex]a(x-h)^2+k[/tex], follow the steps below

Rewrite [tex]3x^2-6x-2[/tex] as  [tex]3x^2-6x+3-5[/tex]

Factorize common terms

[tex]3(x^2-2x+1)-5[/tex]

This can be further simplified as:

[tex]3(x-1)^2-5[/tex]

Therefore, the vertex form of the equation  [tex]3x^2-6x-2[/tex] is [tex]3(x-1)^2-5[/tex]

Compare [tex]3(x-1)^2-5[/tex] with  [tex]a(x-h)^2+k[/tex]

a = 3, h = 1, k = -5

a  +  h  +  k  =  3  +  1 - 5

a  +  h  +  k  =  -1

Therefore if we express  [tex]3x^2-6x-2[/tex] in the form  [tex]a(x-h)^2+k[/tex], then a + h + k = -1

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