Answers
Answer:
3.69 m/s²
Explanation:
weight = mass × Acceleration of gravity
479.96 = 129.72 × Acceleration of gravity
Acceleration of gravity = 479.96/129.72 = 3.69 m/s²
Related Questions
1.00 x 100 kg of clear liquid (specific heat
capacity = 5.11 x 102 J/kg•°C) at a temperature
of 15.0°C gains 3.33 x 10 J of heat. What is the
final temperature of the liquid? (Assume the
melting point is less than 15.0°C and the boiling
point is greater than 62.0°C.)
Answers
Answer:
No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a ... to change 1 kg of liquid water at the normal boiling point (100ºC at atmospheric pressure) to steam (water vapor).
The melting point of lead is 327.3o C. Assume the final temperature of the system is T. Then the amount of energy released by the lead as it solidifies is. ΔQ = mleadLlead = 0.09 kg*(2.45*104 J/kg) = 2205 J
A 45.0-kg girl is standing on a 168-kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.55 m/s to the right relative to the plank.
Required:
What is the velocity of the plank relative to the surface of the ice?
Answers
Answer:
The speed of the plank relative to the ice is:
[tex]v_{p}=-0.33\: m/s[/tex]
Explanation:
Here we can use momentum conservation. Do not forget it is relative to the ice.
[tex]m_{g}v_{g}+m_{p}v_{p}=0[/tex] (1)
Where:
m(g) is the mass of the girlm(p) is the mass of the plankv(g) is the speed of the girlv(p) is the speed of the plankNow, as we have relative velocities, we have:
[tex]v_{g/b}=v_{g}-v_{p}=1.55 \: m/s[/tex] (2)
v(g/b) is the speed of the girl relative to the plank
Solving the system of equations (1) and (2)
[tex]45v_{g}+168v_{p}=0[/tex]
[tex]v_{g}-v_{p}=1.55[/tex]
[tex]v_{p}=-0.33\: m/s[/tex]
I hope it helps you!
The Hydrogen Spectrum
When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the atoms will emit electromagnetic radiation and visible light can be observed. If this light passes through a diffraction grating, the resulting spectrum appears as a pattern of four isolated, sharp parallel lines, called spectral lines. Each spectral line corresponds to one specific wavelength that is present in the light emitted by the source. Such a discrete spectrum is referred to as a line spectrum
By the early 19th century, it was found that discrete spectra were produced by every chemical element in its gaseous state. Even though these spectra were found to share the common feature of appearing as a set of isolated lines, it was observed that each element produces its own unique pattern of lines. This indicated that the light emitted by each element contains a specific set of wavelengths that is characteristic of that element.
The first quantitative description of the hydrogen spectrum was given by Johann Balmer, a Swiss school teacher, in 1885, By trial and error, he found that the correct wavelength λ of each line observed in the hydrogen spectrum was given by
1/λ = R ( 1/2^2-1/n^2)
where R is a constant, later called the Rydberg constant, and n may have the integer values 3, 4, 5, If λ is in meters, the numerical value of the Rydberg constant (determined from measurements of wavelengths) s R= 1.097x10^7 m-1
Balmer knew only the four lines in the visible spectrum of hydrogen. Thus, the original formula was written for a limited set of values of T. However, as more techniques to detect other regions of the spectrum were developed, it became clear that Balmer's formula was valid for all values of n. The entire series of spectral lines predicted by Balmers formula is now referred to as the Balmer series
Part A) What is the wavelength of the line corresponding to n =4 in the Balmer series? Express your answer in nanometers to three significant figures .
Part B) What is the wavelength of the line corresponding to n =5 in the Balmer series?
Answers
Answer:
a) λ = 4.862 10⁻⁷ m, b) λ = 4.341 10⁻⁷ m
Explanation:
The spectrum of hydrogen can be described by the expression
[tex]\frac{1}{\lambda} = R_H ( \frac{1}{n_o^2} - \frac{1}{n^2} ) \ \ \ \ n>n_o[/tex]
in the case of the initial state n = 2 this series is the Balmer series
a) Find the wavelength for n = 4
let's calculate
[tex]\frac{1}{ \lambda}[/tex] = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{4^2}[/tex])
\frac{1}{ \lambda} = 1.097 10⁷ 0.1875 = 0.2056 10⁷
λ = 4.862 10⁻⁷ m
b) n = 5
\frac{1}{ \lambda} = 1,097 10⁷ ([tex]\frac{1}{2^2} - \frac{1}{5^2}[/tex])
\frac{1}{ \lambda} = 1.097 10⁷ 0.21 = 0.23037 10⁷
λ = 4.341 10⁻⁷ m
A negatively charged rod briefly touches a neutral metal ball. The metal ball will now be ____________
Answers
Answer:
let say it will be positive
Astronomy Question
Who thinks Venus is the hottest planet instead of the lava planet?
say aye or nay
Answers
Answer:
AYE
Explanation:
A player kicks a football from ground level with an initial velocity of 27.0 m/s, 30.0° above the Horizontal. Find the distance the ball travels before it hits the ground.
Answers
Answer:
The horizontal distance traveled by the ball before it hits the ground is 64.42 m.
Explanation:
Given;
initial velocity, u = 27.0 m/s
angle of projection, θ = 30⁰
The horizontal distance traveled by the ball before it hits the ground is known as Range;
[tex]Range = \frac{u^2 sin(2\theta)}{g} \\\\Range = \frac{(27^2)sin(2 \times 30)}{9.8} \\\\Range = 64.42 \ m[/tex]
Therefore, the horizontal distance traveled by the ball before it hits the ground is 64.42 m.
The vector matrix [6 -2] is rotated at different angles. Match the angles of rotation with the vector matrices they produce.
Answers
Answer:
Hello your question is incomplete hence I will give you a general answer as regards rotation of vector matrix assuming angle of rotation = [tex]\frac{\pi }{4}[/tex]
answer :
angle of rotation = [tex]\frac{\pi }{4}[/tex]
vector matrix produced = attached below
Explanation:
lets assume the vector matrix [ 6, -2 ] is rotated clockwise by an angle of [tex]\frac{\pi }{4}[/tex]
The resultant matrix = attached below
Result of the rotation = attached below
attached below is the detailed solution
Answer: I got it right on Edmentum
Explanation: Answers attached below
PLEASE HELP ME IN THE QUESTION ALSO!
Answers
Answer:
467
Explanation:
Black holes result from
Answers
Answer:
supernova explosion or death of massive star
Explanation:
"Most black holes form from the remnants of a large star that dies in a supernova explosion."
A piece of irregularly shaped metal weighs 300N in air. When the metal is completely submerged in water, it weighs 232.5N. Find the volume and specific gravity of the metal.
Answers
Answer:
Volume of metal piece = 0.0069 m³ (Approx.)
Explanation:
Given:
Weight of metal in air = 300 N
Weight of metal in water = 232.5 N
Find:
Volume of metal piece
Specific gravity of metal
Computation:
We know that;
Density of water = 1,000 kg/m³
Buoyant force applied on metal piece = Weight of metal in air - Weight of metal in water
Buoyant force applied on metal piece = 300 N - 232.5 N
Buoyant force applied on metal piece = 67.5 N
Buoyant force = Volume of metal x Density of water x Gravitational force
67.5 = Volume of metal x 1,000 x 9.8
Volume of metal piece = 0.0069 m³ (Approx.)
What do the different colors of stars tell us?
A. The size of the stars
B. The shape of the stars
C. The temperatures of the stars
Answers
Answer:
It would Be C The temperatures of the stars
Explanation:
Which of the following is an example of charging by friction?
Answers
Answer: where is the examples?
Explanation:
Which of the following is NOT a geological event caused by the movement of tectonic plates?
A) Sand Dunes
B) Mountain forming
C) Earthquakes
D) Volcanoes
Answers
Help please due tomorrow
Answers
sorry i was gone hope you dident mess me hers a question
Identify the organ that brings oxygen into the body.
brain
chest
heart
lungs
Answers
Answer:
lungs
Explanation:
lungs bring oxygen
Answer:
lungs
Explanation:
i took the quiz
8.
A
2.0 m
A 1.0 kg box slides without friction around the
loop-the-loop apparatus as shown in the
diagram. If the object starts from rest at point A,
and the radius of the loop is 0.75 m, what is the
speed of the box at point B?
Answers
Answer:
6.26 m/s
Explanation:
From the given information:
Using the conservation of Energy;
M.E at A =M.E at B
[tex]\dfrac{1}{2}mv_A^2 + mgh _A = \dfrac{1}{2}mv_B^2 + mgh_B[/tex]
Replacing the values given in the equation:
[tex](1) (9.8) (2 \ m) +\dfrac{1}{2}(0)^2 = 1 \times 9.8 \times 0 + \dfrac{1}{2}(1) \times v_B^2 \\\\ 19.6 + 0 = 0 + 0.5v_B^2\\ \\ v_B^2 = \dfrac{19.6}{0.5} \\ \\ v_B^2 = 39,2 \\ \\ v_B = \sqrt{39.2} \\ \\ \mathbf{v_B = 6.26 \ m/s}[/tex]
A star that is one of the coolest,
about 3,200°C, is going to be which
of the following colors?
Resourcos
A. greenish
Help
B. bluish
C. yellowish
D. reddish
Answers
A ray of light is incident from air on the surface of a block of clear ice (nice=1.31) at an angle of 45.0° with the normal. Part of the light is reflected and part is refracted. Find the angle between the reflected and refracted light.
Answers
Answer:
A ray of light is incident from air on the surface of a block of clear ice (nice=1.31) at an angle of 45.0° with the normal. Part of the light is reflected and part is refracted. Find the angle between the reflected and refracted light.
what happens to the work done when a force is doubled and the distance moved remain the same?
Answers
Answer:
It is doubled
Explanation:
f2=2f1
x1=x2=x
W1=f1*x1=f1*x
W2=f2*x2=f2*x=2*(fi*x)=2*W1
How do home computer scanners generally use electromagnetic waves?
O A. They change information received from sound waves into electromagnetic waves.
OB. They gather information from reflected and absorbed waves.
O C. They receive microwaves that are emitted by natural objects.
O D. They use X-rays that penetrate most objects. SUBMIT
Answers
Answer:
they gather information from reflected and absorbed waves.
Explanation:
Since water is much denser than air, deep-sea divers experience a much higher ambient pressure underwater. Each 10 meters of depth underwater adds another 1 atm to the ambient pressure experienced by the diver. (Note: this is in addition to the 1 atm ambient pressure at the surface of the water!) What pressure, in psi, is experienced by a diver 50.0 meters below the surface of the water
Answers
Answer:
If you are at sea level, each square inch of your surface is subjected to a force of 14.6 pounds. The pressure increases about one atmosphere for every 10 meters of water depth. At a depth of 5,000 meters the pressure will be approximately 500 atmospheres or 500 times greater than the pressure at sea level.
Explanation:
At sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.
What is pressure?Pressure is defined as the force applied perpendicularly to an object's surface divided by the surface area over which it is applied.
Pressure is the physical amount of force exerted on a particular area.
Pressure can be expressed as
Pressure = Force / area
There are three types of pressure.
Absolute pressureGauge pressureDifferential pressureThus, at sea level, a force of 14.6 pounds is applied to every square inch of your surface. For every 10 meters of sea depth, the pressure rises by approximately one atmosphere. The pressure will be about 500 atmospheres, or 500 times more than the pressure at sea level, at a depth of 5,000 meters.
To learn more about pressure, refer to the link below:
https://brainly.com/question/15170210
#SPJ2
3. A ball thrown vertically upward returns to its starting point in 4s. Find its initial speed. [4]
Answers
Answer:
9.8 ×4 equal 39.2 m/s This is v intial
Acceleration is rate of change of
A-Position
B-Time
C-Velocity
D-Speed
Answers
Two long current-carrying wires run parallel to each other and are separated by a distance of 5.00 cm. If the current in one wire is 1.65 A and the current in the other wire is 3.25 A running in the opposite direction, determine the magnitude and direction of the force per unit length the wires exert on each other.
Answers
Answer:
The magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Explanation:
Given;
distance between the parallel wires, r = 5.0 cm = 0.05 m
current in the first wire, I₁ = 1.65 A
current in the second wire, I₂ = 3.25 A
The magnitude of the force per unit length between the two wires is calculated as follows;
[tex]\frac{F}{l} =\frac{\mu_0 I_1 I_2}{2\pi r} \\\\\frac{F}{l} =\frac{4\pi \times 10^{-7} \times 1.65 \times 3.25}{2\pi \times 0.05} \\\\\frac{F}{l} = 2.145 \times 10^{-5} \ N/m[/tex]
Therefore, the magnitude of the force per unit length is 2.145 x 10⁻⁵ N/m and the direction of the force is outward or repulsive since the current in the two parallel wires are flowing in opposite direction.
Priscilla is driving her car on a busy street and Harvey passes her on his motorcycle. What will happen to the sound from his motorcycle after it passes her car?
A.
The frequency of the sound will decrease.
B.
The amplitude of the sound will increase.
C.
The intensity of the sound will increase.
D.
The wavelength of the sound will decrease.
E.
The velocity of the sound will increase.
Answers
Answer:
the correct answer is A
Explanation:
This is a doppler effect exercise which is the change in frequency due to the relative movement of the sound source and the observer.
[tex]f' = f_o \ \frac{v+v_o}{v-v_s}[/tex]
where v₀ is the speed of the observer and v_s the speed of the source, the signs correspond when the two are closing in
with this expression let's analyze the different answers
A) True. The observed change is in the frequency, in this case the two are moving away, so the expression that describes the phenomenon is
[tex]f'= f_o \ \frac {v-v_o}{ v+v_s}[/tex]
In this case, the speed of the source is greater than the speed of the observer, so when the denominator increases faster than the numerator, consequently the frequency must decrease
B) False. The amplitude does not depend on the relative velocity
C) False. The intensity depends on the distance, by or which when increasing the distance the intensity should decrease
D) False. The speed of sound is a constant, if the frequency decreases the wavelength must increase to maintain equality
E) False. The speed of sound depends on the properties of the propagating medium, not on the relative speed of the source and the observer.
Consequently the correct answer is A
A heat pump with a COP of 3.0 is used to heat air contained in a 1205.4 m3 of well-insulated, rigid tank. Initially the pressure and the temperature inside the gas tank are 100 kPa and 7 oC, respectively. When running, the heat pump consumes 5 kW of electric power. How long does it take for the heat pump to raise the temperature of air in the tank to 22 oC
Answers
Answer:
ffff
Explanation:
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A wheelbarrow full of bricks is lifted to the top of a wall. If the mass of the loaded wheelbarrow is 3000.0 g and the height of the wall is 0.45 meters, what is its GPE?
Answers
Answer:
the Gravitational potential energy is 13.23 J
Explanation:
The computation of the GPE is shown below:
GPE stands for Gravitational potential energy
The following formula should be used for the same
= mass × gravity × height
= 3000 g × 9.8m/sec^2 × 0.45 m
= 13.23 J
Hence, the Gravitational potential energy is 13.23 J
We simply applied the above formula so that we can easily determine the GPE
528 nm light passes through a single slit. the second (m=2) diffraction minimum occurs at an angle of 3.48 degrees. what is the width of the slit
Answers
Answer:
1.74
Explanation:
right on acellus
Answer:
1.74
Explanation:
acellus
a 0.1 kg object oscillates as a simple harmonic motion along x axis with a frequency f=3.185 hz. At a position x1 , the object has a kinetic energy of o.7 j and a potential energy 0.3 J.The amplitude of oscillation A is:
Answers
Answer:
The total energy must be .7 J + .3 J = 1 J for a particle at the endpoint or midpoint of motion.
Also, omega = (k / m)^1/2
f = omega / (2 * pi)
omega^2 = 4 pi^2 * f^2 = k / m
k = 4 * pi^2 * f^2 * m = 40.05
Max KE or PE = 1/2 k A^2
A^2 = 2 * E / k = 2 * 1 / k = .0499
A = .223 meters
Help answer question in licture
Answers
Answer:
D
Explanation:
D is high pitch c is low pitch
Answer:
D creo que esa es la nota mas alta, la segumda