please help me figure this out!!

Answer:

Step-by-step explanation:

It depends on what level you are. Logs are most easily developed by using a series for the natural logarithms (instead of base 10, you use base e). Even that is a difficult process using a series that you won't be introduced to until your second calculus course..

For now, I'd be content to use a calculator. The series does not converge terribly quickly.

9514 1404 393

Answer:

  boat speed: (7t -95)/(6t² -110t +500)

  stream speed: (37t -345)/(6t² -110t +500)

Step-by-step explanation:

The relation between time, speed, and distance is ...

  time = distance/speed

The boat speed (b) is added to the stream speed (s) going downstream. The stream speed is subtracted going upstream. The given relations tell us ...

  25/(b-s) +44/(b+s) = t

  15/(b-s) +22/(b+s) = 5

This gives us 2 equations in 3 unknowns, so we can only provide a solution in terms of one of the unknowns. Since we are asked for the speeds, they will be provided in terms of t.

Subtracting the first equation from 2 times the second gives ...

  2(15/(b-s) +22/(b+s)) -(25/(b-s) +44/(b+s)) = 2(5) -(t)

  5/(b-s) = 10 -t

  5/(10 -t) = b -s

Substituting for b-s in the second equation gives ...

  15/(5/(10-t)) +22/(b+s) = 5

  30 -3t +22/(b+s) = 5

  22/(b+s) = 3t -25

  22/(3t -25) = b+s

Adding the equations for the sum and difference of speeds, we get ...

  (b-s) +(b+s) = 5/(10-t) +22/(3t -25)

  2b = (5(3t -25) +22(10 -t))/((10-t)(3t-25)) = (95 -7t)/((10-t)(3t-25))

  b = (7t -95)/(6t² -110t +500)

Subtracting the equations for sum and difference of speeds, we get ...

  (b+s) -(b-s) = 22/(3t -25) -5/(10 -t)

  2s = (22(10-t) -5(3t -25))/((10-t)(3t-25))

 s = (37t -345)/(6t² -110t +500)

__

The speed of the boat in still water is (7t -95)/(6t² -110t +500) km/h.

The speed of the stream is (37t -345)/(6t² -110t +500) km/h.

__

Note that these solutions only make sense for values of t between 25/3 and 345/37, approximately 8.33 < t < 9.32. For t=9 hours, the boat speed is 8 km/h and the stream speed is 3 km/h.

Answer:

1.9%.

Step-by-step explanation:

Answer: I think it’s False I’m not sure

Answer:

it's false because isosceles is convex quadrilateral with line of symmetry

Answer:

Hello.

The answer to this question is  

− √ 2 − √ 3 /2

And in Decimal Form: − 0.25881904

Step-by-step explanation:

Give brainliest :)

Answer:

By 2020, there will be 1,147 species of birds left

Step-by-step explanation:

The general model for an exponential decrease is;

y = I(1 - r)^t

where in this case;

y is the number of bird species at a particular decade from the initial

I is the number of birds initially at 1990

r is the decrease percentage which is 1.5% per decade ; 1.5% = 1.5/100 = 0.015

t in this case will be the number of decades after the initial

Mathematically, a decade is 10 years

The difference between 2020 and 1990 is 30

The number of decades in 30 years is 30/10 = 3

so t will be 3 here

Substituting these values into the equation, we have

y = 1200(1-0.015)^3

y = 1200(0.985)^3 = 1,146.8

To the nearest whole number, this is 1,147

Answer:

6chocolates

Step-by-step explanation:

Given

The total number of chocolate = 15chocolates

If it is divide into ratio 2:3

total ratio = 2+3

Total ratio = 5

Number of chocolate raju receives = 2/5 * 15

Number of chocolate raju receives = 2 * 3

Number of chocolate raju receives = 6chocolates

The number of chocolates that Raju received are; 6 chocolates

We are told that;

Number of chocolates distributed = 15

Ratio of sharing between Raju and sanju = 2:3

Thus, fraction to be received by both of them are;

Thus;

Amount of chocolates for Rajus = 2/5 × 15 = 6

In conclusion, Raju received 6 chocolates.

Read more about proportion at; https://brainly.com/question/1781657

Answer:

A.  when an action causes something to come into effect

Step-by-step explanation:

Mark as brainliest please. Hope the answer helps :)

Answer:

B. -2_x_4÷3 this answer are not sure

Answer:

D

Step-by-step explanation:

-5 < 6x +3

-8 < 6x

-(4/3) < x

I use < to represent 'no no smaller than'

Answer:

1.) Hypotenuse.

The hypotenuse is the longer side.

2.)Leg

Answer:

1.) Hypotenuse

2.) Leg

Step-by-step explanation:

The legs or bases of a triangle are the sides connected to the right angle.

The hypotenuse is the side across from the right angle and is always the longest side.

Answer:

Explanation:

you mean the hypotenuse* lol

the hypotenuse = √(11²+9²)

the hypotenuse = √(121+81)

the hypotenuse = √(202)

the hypotenuse ≈ 14.21 cm

Answer:

What’s the answer

Step-by-step explanation:

Step-by-step explanation:

find the area as if it was a rectangle so do 14x12 then subtract the area of half a circle with a diamater of 12

Answer:

12=4 3          4=2 2

Step-by-step explanation:

Answer:

49/64 yd²

Step-by-step explanation:

since where finding a square we do

A = bxh

A = 7/8×7/8

A = 49/64

[tex]\huge\red{\boxed{\tt{\colorbox{pink}{ANSWER:}}}}[/tex]

[tex] - 4(2w + 1)[/tex]

[tex]\huge\red{\boxed{\tt{\colorbox{pink}{Solution:}}}}[/tex]

[tex] - 8w - 4[/tex]

Bind the expression with the common factor -4

[tex] - 8w - 4[/tex]

Answer: −4(2w+1)

Step-by-step explanation: Hope this help :D

Answer:

infinite number of solutions

Answer:

it can have any about 3 and up as long as it is a 2d shape and it has to have straight lines

Answer:

They all vary. All a polygon needs is straight sides, two dimensions, and equal length sides.

Step-by-step explanation:

Hope this helps!

Answer:

8 is the length

Step-by-step explanation:

The length of AD is 9 units from the given right triangle ABC.

A right angled triangle is a triangle with one of the angles as 90 degrees. A 90-degree angle is called a right angle, and hence the triangle with a right angle is called a right triangle.

Given right triangle ABC with altitude BD drawn to hypotenuse AC.

Given that, AB = 18 and AC = 36

Using Pythagoras theorem

AC²=AB²+BC²

⇒ 36²=18²+BC²

⇒ BC²=1296-324

⇒ BC²=972

⇒ BC=31.18 units

We know that, area of a triangle =1/2 × Base × Height

= 1/2 × 31.18 × 18

= 280.62 square units

Now, area of a triangle ABC with base AC and height BD

That is, Area = 1/2 ×36×BD

⇒ 18BD=280.62

⇒ BD=280.62/18

⇒ BD=15.6

Consider ΔBDA

AB²=AD²+BD² (Pythagoras theorem)

18²=x²+15.6²

⇒ x²=18²-15.6²

⇒ x=9 units

Therefore, the length of AD is 9 units from the given right triangle ABC.

To learn more about the right angle visit:

https://brainly.com/question/3770177.

#SPJ2

Step-by-step explanation:

x+5Y=13...... 1

4x +7y=0..... 2

from eqn 1

x =13-5y

substitute into eqn 2

[tex]4(13 - 5y) + 7y = 0[/tex]

52-20y +7y=0

52-13y=0

52=13y

y=52÷13

y=4

substitute Y into eqn 2

x +5y=13

x + 5(4)= 13

x+ 20=13

x=13-20

x=-7

Answer: 5n = 35

Step-by-step explanation:

The product of a number n and the number 5 is 35. This statement can be formed into an equation as:

n × 5 = 35

5n = 35

The equation is 5n = 35

If we want to get the value of the number, it'll be:

5n = 35

n = 35/5

n = 7

The number is 7

Answer:

D.

Step-by-step explanation:

Hope this helps

~R3V0

Answer:i think D

Step-by-step explanation:

Answer:

The answer is the second one!

Have a wonderful day/night! <3

Answer:

24.75 percents

Step-by-step explanation:

-41.2 minus (-37.4) is -3.8.

If this is incorrect, please, don't refrain to tell me. Thank you.

Answer: -3.8

Hope this helps!

Answer:

0.00923077

Step-by-step explanation:

thats it

Answer:

Your answer is 0.000096 if your question was 0.96÷10 with a power of 4.

Answer:

[tex]b_1 \approx 7.2[/tex]

[tex]b_2 \approx 14.4[/tex]

Step-by-step explanation:

Given

[tex]Area = 65cm^2[/tex] --- Area of the triangle

[tex]b_2 = 2b_1[/tex] --- the bases of the trapezoid

The missing parameters is:

[tex]h=6 cm[/tex] --- Trapezoid height

Required

Determine b1 and b2

Since the areas of the trapezoid and the triangle are the same, then:

[tex]Area = \frac{1}{2}(b_1 + b_2) *h[/tex]

So, we have:

[tex]65 = \frac{1}{2}(b_1 +b_2) * 6[/tex]

Substitute[tex]b_2 = 2b_1[/tex]

[tex]65 = \frac{1}{2}(b_1 +2b_1) * 6[/tex]

[tex]65 = \frac{1}{2}(3b_1) * 6[/tex]

[tex]65 = 3b_1 * 3[/tex]

[tex]65 = 9b_1[/tex]

Solve for [tex]b_1[/tex]

[tex]b_1 = \frac{65}{9}[/tex]

[tex]b_1 \approx 7.2[/tex]

Substitute [tex]b_1 \approx 7.2[/tex] in [tex]b_2 = 2b_1[/tex]

[tex]b_2 \approx 2 * 7.2[/tex]

[tex]b_2 \approx 14.4[/tex]