please help it’s due soon ): Find the slope of the line represented
by the data below.

Answer:

The 2-yard pièce of cotton cloth for $13.26

Step-by-step explanation:

2 yards is 6 feet then it would be $2.21 per foot.

The 17 foot piece would cost $3.29 per foot.

To answer this question, you need to determine which one has a lower price per unit.  In this scenario, you must divide the price of the cloths by their length in feet.

For the 2-yard piece of cotton cloth, first convert the length to feet.  There are three feet in a yard, so the cloth is 6 feet.  Then divide:

13.26/6=2.21

For the 17-foot piece of cotton cloth, simply divide:

55.93/17=3.29

The 2-yard piece of cotton cloth for $13.26 is the better buy because it has a lower unit price.

Hope this helps!!

Answer: The slope of the line can be determined from the gradient equation, rise (y axis)/ run (x-axis)

Hence let (-1, 8) be A and (2, -4) be B. The slope from A to B is (-4-8)/(2-(-1))= (-12)/3= -4

Hence the gradient/ slope of the line is -4.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given

Equation we need is

Answer:

D 9 softball tickets for $72

Step-by-step explanation:

72/9=8

Answer:

The answer is D.

Step-by-step explanation:

You divide 72 by 9. Hope this helps!!! Please mark me brainliest and have a good rest of your day!!!

Answer:

66

Step-by-step explanation:

Answer:

35

Step-by-step explanation:

No explanation bc due in 5 mins

Answer: 1/3

Step-by-step explanation:

Answer:

i use slope calculators for these type of problems :)

Step-by-step explanation:

Line 1. Vertical. Undefined slope.

Line 2. -4/3

Line 3. 4/3

Line 4. Vertical. Undefined slope.

Line 5. 7/3

Line 6. -7/3

Line 7. Horizontal line. Slope 0

Line 8. Horizontal line. Slope 0

Line 9. Vertical line. Undefined slope.

Line 10. Vertical line. Undefined slope.

Line 11. Horizontal line. Slope 0

Line 12. Vertical line. Undefined slope.

These slopes can be found using the rise and run method. All vertical lines are undefined and all horizontal lines are 0.

The slope of the line is -5/2

Slope m = -5/2

What is an Equation of a line?

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of the line be A

Now , the equation of line is expressed as

5x + 2y + 9 = 0

Now , the equation of line is expressed in the form y = mx + c

5x + 2y + 9 = 0

Subtracting 9 on both sides of the equation , we get

5x + 2y = -9

Subtracting 5x on both sides of the equation , we get

2y = -5x - 9

Divide by 2 on both sides of the equation , we get

y = ( -5/2 )x - 9/2

So , the slope of the equation is y = mx + c

The slope of the line is m

The slope is m = -5/2

Hence , The slope of the line is -5/2

To learn more about equations click :

https://brainly.com/question/14200719

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Step-by-step explanation:

let equation be y = mx + b.

m = (9-5)/(3-1) = 2

sub (1, 5):

5 = 2(1) + b

b = 3

therefore the equation: y = 2x + 3

Topic: coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

Answer:

Attachment given answer

Step-by-step explanation:

I gave you the answer but if you have any questions let me know.

Answer:

420 funny number

Step-by-step explanation:

Answer:

P = 100 centimeters (assuming you are asking for the perimeter)

Step-by-step explanation:

P = 2 (L + W) OR P =  2L + 2W where P equals the perimeter, L equals the length, and W equals the width.

Since the rectangle's length is 4 times its width and given we know the width is 10 centimeters, then the length is 40 centimeters. Now we can substitute these values in our formula, okay?  

P = 2 (L + W)  

P = 2 (40 + 10)  

P = 80 + 20  

P = 100 centimeters

Answer:

18e⁶

⁵/₁₂₈

Step-by-step explanation:

Rₙ(x) = f⁽ⁿ⁺¹⁾(c) / (n+1)! (x − a)ⁿ⁺¹, and a < c < x.

f(x) = eˣ, a = 0, and n = 1.  Thus R₁ is:

R₁(x) = f"(z)/2! x²

R₁(x) = eᶻ/2 x²

|R₁| is a maximum when |f"(z)| is a maximum.  On the domain 0 < z < 6, that maximum is e⁶.  At x = 6, the upper bound of |R₁| is:

|R₁| = 18e⁶

This time, f(x) = 1 / √(1 + x) = (1 + x)^-½.  a = 0, and n = 2.

R₂(x) = f⁽³⁾(z)/3! x³

Find f⁽³⁾(x):

f'(x) = -½ (1 + x)^-³/₂

f"(x) = ¾ (1 + x)^-⁵/₂

f⁽³⁾(x) = -¹⁵/₈ (1 + x)^-⁷/₂

On the domain -½ < z < 0, |f⁽³⁾(z)| is a maximum at z = 0.

|f⁽³⁾(z)| = ¹⁵/₈

Therefore, at x = -½, the upper bound of R₂ is:

|R₂| = (¹⁵/₈)/6 |(-½)³|

|R₂| = ⁵/₁₂₈

There are 49 ways to arrange the letters (if they aren't words)

Answer:y

y=−2x+2/3

SLOPE:-2

Y-INTERCEPT:2/3

Step-by-step explanation:

Answer/Step-by-step Explanation:

To determine if segment AB and CD are parallel, perpendicular, or neither, calculate the slope of each.

✍️If the slope of AB and CD are the same value, then they are parallel.✅

✍️If the slope of one is the negative reciprocal of the other, then they are perpendicular.☑️

✍️If their slopes are different, or the slope of one is not the negative reciprocal of the other, then they are neither.❌

1. AB formed by (-2, 13) and (0, 3)

CD formed by (-5, 0) and (10, 3)

Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 13}{0 -(-2)} = \frac{-10}{2} = -5 [/tex]

Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 0}{10 -(-5)} = \frac{3}{15} = \frac{1}{5} [/tex].

☑️-5 is the negative reciprocal of ⅕, therefore segments AB and CD are perpendicular

2. AB formed by (3, 7) and (-6, 1)

CD formed by (-6, -5) and (0, -1)

Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 7}{-6 - 3} = \frac{-6}{-9} = \frac{2}{3} [/tex]

Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 -(-5)}{0 -(-6)} = \frac{4}{6} = \frac{2}{3} [/tex].

✅Segment AB and CD have the same slope value of ⅔. Therefore, they are parallel.

3. AB formed by (-6, 2) and (-2, 4)

CD formed by (-1, 11) and (5, -7)

Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{4 - 2}{-2 -(-6)} = \frac{2}{4} = \frac{1}{2} [/tex]

Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{-7 - 11}{5 -(-1)} = \frac{-18}{6} = -3 [/tex].

❌The slopes of Segments AB and CD are not the same (½ and -3). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.

4. AB formed by (-3, 8) and (2, 3)

CD formed by (-4, 6) and (-8, 2)

Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 8}{2 -(-3)} = \frac{-5}{5} = -1 [/tex]

Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 6}{-8 -(-4)} = \frac{-4}{-4} = 1 [/tex].

❌The slopes of Segments AB and CD are not the same (1 and -1). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.

5. AB formed by (-8, -1) and (-4, 2)

CD formed by (0, -3) and (12, 6)

Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 -(-1)}{-4 -(-8)} = \frac{3}{4} [/tex]

Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 -(-3)}{12 - 0} = \frac{9}{12} = \frac{3}{4} [/tex].

✅Segment AB and CD have the same slope value of ¾. Therefore, they are parallel.

6. AB formed by (6, 5) and (3, -1)

CD formed by (2, -5) and (-4, 7)

Slope of AB = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{-1 - 5}{3 - 6} = \frac{-6}{-3} = 2 [/tex]

Slope of CD = [tex] \frac{y_2 - y_1}{x_2 - x_1} = \frac{7 -(-5)}{-4 - 2} = \frac{12}{-6} = -2 [/tex].

❌The slopes of Segments AB and CD are not the same (2 and -2). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.

To determine if the given equations are parallel, perpendicular, or neither, ensure both equations are in the slope-intercept form, y = mx + b, where m is the slope.

7. 3x + 2y = 6 and y = -³/2x + 5

Rewrite the first equation in slope-intercept form

3x + 2y = 6

2y = -3x + 6

y = -3x/2 + 6/2

y = -³/2x + 3

The slope of the first equation is -³/2.

The slope of the second equation is -³/2.

✅Both equations have the same slope value of -³/2. Therefore, they are parallel.

8. 3y = 4x + 15 and 9x + 12y = 12

Rewrite both equations in slope-intercept form.

3y = 4x + 15

y = 4x/3 + 15/3

y = ⁴/3x + 5

And

9x + 12y = 12

12y = -9x + 12

y = -9x/12 + 12/12

y = -¾x + 1

The slope of the first equation is ⁴/3.

The slope of the second equation is -¾..

☑️-¾ is the negative reciprocal of ⁴/3. Therefore both AB equations are perpendicular.

9. 8x - 2y = 4 and x + 4y = -12

Rewrite both equations in slope-intercept form.

8x - 2y = 4

-2y = -8x + 4

y = -8x/-2 + 4/-2

y = 4x - 2

And

x + 4y = -12

4y = -x - 12

y = -x/4 - 12/4

y = -¼x - 3

The slope of the first equation is 4.

The slope of the second equation is -¼..

☑️-¼ is the negative reciprocal of 4. Therefore both AB equations are perpendicular.

10. 3x + 2y = 10 and 2x + 3y = -3

Rewrite both equations in slope-intercept form.

3x + 2y = 10

2y = -3x + 10

y = -3x/2 + 10/2

y = -³/2x + 5

And

2x + 3y = -3

3y = -2x - 3

y = -⅔x - 1

The slope of the first equation is -³/2.

The slope of the second equation is -⅔.

❌The slopes of the first equation and second equation are not the same (-³/2 and -⅔). One is also not the negative reciprocal of the other. Therefore, they are neither parallel nor perpendicular.

11. -4y = -2x + 8 and 3x - 6y = 6

Rewrite both equations in slope-intercept form.

-4y = -2x + 8

y = -2x/-4 + 8/-4

y = ½x - 2

And

3x - 6y = 6

-6y = -3x + 6

y = -3x/-6 + 6/-6

y = ½x - 1

The slope of the first equation is ½.

The slope of the second equation is ½.

✅Both equations have the same slope value of ½. Therefore, they are parallel.

12. y = 8 and x = -1

The first equation is a horizontal line. The slope of am horizontal line is always zero.

The second equation is a vertical line. The slope of a vertical line is undefined.

❌Therefore, they are neither parallel nor perpendicular.

Answer:

Y-intercept = 0.4

X-intercept = 0.3

Step-by-step explanation:

Answer:

Step-by-step explanation:

1 × a = a

a² = a*a ; a³ = a*a*a .....

[tex](\frac{a}{b}) ^{n} = \frac{a^{n} }{b^{n} }[/tex]

(1).

(a). [tex]7^{5}[/tex]

(b). [tex](\frac{1}{7}) ^{6}[/tex] = [tex]\frac{1}{7^{6} }[/tex]

(c). [tex](9.3)^{9}[/tex]

(2).

(e). [tex](\frac{1}{2} )^{4} =\frac{1}{2^{4} }[/tex] = [tex]\frac{1}{2*2*2*2}[/tex] = [tex]\frac{1}{16}[/tex]

(f). [tex](\frac{1}{3} )^{2}[/tex] = [tex]\frac{1}{3}[/tex] × [tex]\frac{1}{3}[/tex] = [tex]\frac{1}{9}[/tex]

(3).

x² = 30² + 16² = 900 + 256 = 1156 = 34² ⇒ x = 34 units

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Answer:

-3 f

ithink

Step-by-step explanation:

We are told that x is -3. Based on the side conditions of this piecewise function, we evaluate the top portion only.

f(-3) = -1/2(-3) + 4

Take it from here.

Answer: C. The graph is positive on the intervals (-∞,-8) and (-4,3)

Step-by-step explanation: I guessed on my test and got it right. PLATO

Answer:

4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

Answer:

Systems of equations can be classified by the number of solutions. , . , . If a consistent system has an infinite number of solutions, it is dependent.

Answer:

f(t+1)= -4t+2

Step-by-step explanation:

Subsitute the given vaule into the function and evaluate.