Answer:
A. Original energy source is converted to AC power, then transported through conductors to your house.
Explanation:
The correct option is - A. Original energy source is converted to AC power, then transported through conductors to your house.
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How can adding electricity to possible solutions of a problem help generate better outcomes?
i don't want to see any link
If i do you will be reported
Answer:
I hot u
Explanation:
it makes things function better and more fluently than a manual version of the certain object
Answer:
l m a o
Explanationl
A system that captures incoming solar radiation, stores it, and distributes it throughout a building is called
active solar heating
photoelectric heating
cell heating
passive solar heating
Answer: Active solar heating
Explanation:
Active solar heating is a design which is used for the purpose of storage of solar heat for household purposes. The solar heat is used for heat up the liquid and the energy is transferred to the interior space of the house for later use. It distributes the heat throughout the building. Passive solar heating used for heating and cooling of the building but not reliable for storage purposes. Photoelectric heating convert the incident solar heat into electrical energy. Cell heating is a technology in which the thermal energy in a cell is converted into mechanical energy and it is used in machines.
Do the lands in our
country have similar use?
What is most abundant
use of the land in the
Philippines? How are
these affecting the lives of
the Filipinos on this
certain area?
Answer:
sheosjos widhoe window
Explanation:
A 25mm square cross-section bar of length 300mm carries an axial compressive
load of 50kN. Determine the stress set up in the bar and its change of length when the
load is applied. For the bar material E = 200 GN/m
^2
Answer:
The correct answer is "299.88 mm".
Explanation:
The given values are:
Length,
[tex]l_o=300 \ mm[/tex]
Load,
[tex]P=50 \ kN[/tex]
i.e.,
[tex]=50\times 10^3 \ N[/tex]
[tex]E=200 \ GN/m^2[/tex]
[tex]=2\times 10^5 \ M/mm^2[/tex]
Now,
Stress,
⇒ [tex]\sigma=\frac{P}{A}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{50\times 10^3}{25\times 25}[/tex]
⇒ [tex]=80 \ N/mm^2[/tex]
The change in length will be:
⇒ [tex]\Delta l=\frac{Pl}{AE}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{50\times 10^3\times 300}{25\times 25\times 2\times 10^5}[/tex]
⇒ [tex]=\frac{15000\times 10^3}{1250\times 10^5}[/tex]
⇒ [tex]=0.12 \ mm[/tex]
hence,
⇒ [tex]L=l_o-\Delta l[/tex]
[tex]=300-0.12[/tex]
[tex]=299.88 \ mm[/tex]
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