Please help due today

The mean exam score of the first group is [tex]35.3[/tex]

The mean exam score for the second group is [tex]34.1[/tex]

but [tex]35.3[/tex] is greater than [tex]34.1[/tex]

Standard deviation of the first group is [tex]3.6[/tex]

Standard deviation of the second group is [tex]0.5[/tex]

but [tex]3.6[/tex] is greater than [tex]0.5[/tex].

(a) We can draw a conclusion that the score of the second group is more evenly distributed.

(b) The second group has more people get in - person interviews because  [tex]3.6\geq 0.6[/tex], so the scores of the exam for the second group are all close to 34.1. On the contrary, the score of exams for the first group is extreme polarization.

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Answer: The answer is b

Step-by-step explanation:  Simplify and expand it to determine it

Using the midpoint concept, the other endpoint of the segment is: G(18,-9).

The problem asks for the coordinates of the other endpoint, given by point G.

The midpoint between two points is the halfway point between them, and is found using the mean of the coordinates.

Hence the x-coordinate of G is found as follows:

8 = (x - 2)/2

x - 2 = 16

x = 18.

The y-coordinate of G is found as follows:

0 = (y + 9)/2

y + 9 = 0

y = -9.

The other endpoint of the segment is: G(18,-9).

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The output value of (y) will be 1 .

We have given an exponential function [tex]y=10.5^x[/tex]     ......(1)

It is given that input value is 0 which means that replace the x with the input value in the given function.

Putting x = 0 in the equation (1) , we get

  [tex]y=10.5^0[/tex]

Value of any number raised to power zero is always one .

   [tex]y=1[/tex]

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Answer:

awsome

Step-by-step explanation:

565

The complete compound inequality is 9 <= 1.5x <= 12

From the given figure, we have'

Height = x

Base = 3

The area of a triangle is

Area = 0.5 * Base * Height

So, we have

A = 0.5 * 3 * x

Evaluate

A = 1.5x

The compound inequality is given as

9 <= A <= 12

Substitute A = 1.5x in 9 <= A <= 12

9 <= 1.5x <= 12

Hence, the complete compound inequality is 9 <= 1.5x <= 12

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The direction cosines and direction angles will be - [tex]\frac{x}{r},\frac{y}{r},\frac{z}{r}[/tex] and

cos⁻¹([tex]\frac{x}{r}[/tex]), cos⁻¹([tex]\frac{y}{r}[/tex]),cos⁻¹([tex]\frac{z}{r}[/tex]) respectively.

The direction cosines of a specified vector, m = xi + yj + zk, are the cosines of the angles it makes well with x, y, and z axes.

The direction cosines of m are cos a, cos b, and cos c  in the x, y, and z axes, respectively, if a forms the angles a,b and c (which are the direction angles) with the x, y, and z axes, respectively.

Let us consider equation as =  [tex]xi + yj +zk[/tex]

vector of the equation will be - (x,y,z)

r = length of vector = [tex]\sqrt{x^{2} +y^{2} +z^{2} }[/tex]

The direction cosines will be -

[tex]\frac{x}{r},\frac{y}{r},\frac{z}{r}[/tex]

angles will be - cos⁻¹([tex]\frac{x}{r}[/tex]), cos⁻¹([tex]\frac{y}{r}[/tex]),cos⁻¹([tex]\frac{z}{r}[/tex])

Let us consider an example,

If we have vector as (1,2,3)

= i + 2j + 3k

= r = [tex]\sqrt{1^{2} +2^{2} +3^{2} }[/tex]

= [tex]\sqrt{14}[/tex]

Direction cosines will be -

[tex]\frac{1}{\sqrt{14} } , \frac{2}{\sqrt{14} }, \frac{3}{\sqrt{14} }[/tex]

Angles will be -

cos⁻¹([tex]\frac{1}{\sqrt{14} }[/tex]), cos⁻¹([tex]\frac{2}{\sqrt{14} }[/tex]),cos⁻¹([tex]\frac{3}{\sqrt{14} }[/tex])

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Let [tex]n=0[/tex]. Then [tex]0^3 = 0[/tex] but 0 > 0 is a false statement.

The equation for the parallel street that passes through (2, -3) is: B. y = 3x - 9.

Two lines that lie parallel to each other will have a slope (m) that is of the same value. The equation can be written as y = mx + b in slope-intercept form.

Find the slope of the line that passes through (4, 5) and (3, 2):

Slope (m) = change in y / change in x = (5 - 2)/(4 - 3)

Slope (m) = 3/1

Slope (m) = 3

The slope of a parallel line would also be 3.

Substitute (a, b) = (2, -3) and m = 3 into y - b = m(x - a):

y - (-3) = 3(x - 2)

y + 3 = 3x - 6

Subtract 3 to both sides of the equation

y + 3 - 3 = 3x - 6 - 3

y = 3x - 6 - 3

y = 3x - 9

Therefore, the equation for the parallel street that passes through (2, -3) is: B. y = 3x - 9.

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Answer:

Step-by-step explanation:

In 6 years, because I subtracted 3 from 259 6 times and added 20 to 362 6 times.

Answer: - 10

Step-by-step explanation: -2 to the 2nd power is - 4. And 3 * - 2 is -6. So -4 + -6 = - 10.

I hope I have helped and I hope you have a wonderful day!

Thus 3 bushels of pears can be acceptable term of trade for bushels of pears.

Opportunity cost of 1bushel of apple for Carlos=2pears    

Opp. Cost of 1 bushles of apple for Donna=4pears

Thus ,

Term of trade acceptable to both for one bushels of apple is 2-4 bushels of pears

a. The required equations are  6a+9p = 9.75 and 4a+5p = 5.75 .

b. The solution is given in the attached picture.

c. Apples are 1/2 and Peaches are 0.75

d. Solving the equations by putting the values

Let's take equation 1

6a+9p = 9.75

6 (1/2) + 9 (0.75) = 9.75

So equation satisfies both sides

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Step-by-step explanation:

1500÷75= 20

30×20= 600 seconds

600÷60= 10 minutes

Two possible lengths for CD if C, D, and E are collinear, CE 17.9 cm, and DE = 8.2 cm is 12.3cm and 19.3cm.

In space, a point is a precise position or location. It is possible to depict it in relation to a coordinate system and its origin. It has no length and is a zero-dimensional entity.

A line is made up of an unlimited number of points that form a straight line. One-dimensional objects like lines lack both thickness and width. It stretches forever in both directions. An endpoint and a beginning point define a line segment, which is a component of a line. A linear equation can be used to depict a line.

D is between C and E

_   _   _

C  D   E

CD =CE-DE

CD=15.8-3.5cm

CD=12.3 cm

E is between D and C

_  _  _

D  E C

CD=CE+DE

CD=15.8+3.5cm

=19.3cm

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The approximation of 2798.01 to 2 significant figures is 2800

The expression is given as

2798.01

The approximation is given as

2 significant figures

The above means that we approximate the given expression such that only 2 significant figures are left

In this case, the 2 significant figures in the expression 2798.01 are 2 and 7

So, we start the approximation from 9

When 9 is approximated, the expression becomes

2798.01 = 2800

Hence, the approximation of 2798.01 to 2 significant figures is 2800

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Answer:

The answer is 1

Step-by-step explanation:

On a graph, it would be at the plot point (3,1)

Answer:

32/40

Step-by-step explanation:

First divide 40 by 15

to check denominator, calculate 15 * the ans and for numerator as well

Answer:

15*2/3=10

10*2/3=20/3

20/3*2/3=40/9

40/9*2/3=80/27

80/27*2/3=160/81

160/81*2/3=480/243

480/243*2/3=960/729

960/729*2/3=1920/2187.

=1920/2187

The 9th term of the geometric sequence will be 1280 / 2187.

A series of non-zero integers where every term after the first is obtained by increasing the one before it by a constant, non-zero value known as the scale factor.

Let a₁ be the first term and r be the common ratio. Then the nth term of the geometric sequence is given as,

aₙ = a₁ · (r)ⁿ⁻¹

The sequence is given below.

15, 10, 20/3

The first term is 15. And the common ratio is given as,

r = 10 / 15

r = 2 / 3

The 9th term of the geometric sequence is given as,

a₉ = 15 · (2/3)⁹⁻¹

a₉ = 15 · (2/3)⁸

a₉ = 15 · 256/6561

a₉ = 1280 / 2187

The 9th term of the geometric sequence will be 1280 / 2187.

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Answer:

x = 16

Step-by-step explanation:

[tex]\frac{3x}{4}[/tex] + 3 = 15 (subtract 3 from both sides )

[tex]\frac{3x}{4}[/tex] = 12 ( multiply both sides by 4 to clear the fraction )

3x = 48 ( divide both sides by 3 )

x = 16

that is

subtraction / multiplication / division

Answer: ( not totally sure but I hope this helps)

Step-by-step explanation:

1. Given

2. Multiplication property of equality

3.  Subtraction

4. Division property of equality

We must deposit (B) $6,301.70 today to withdraw $10,000 in 6 years.

To find the amount:

Given -

Estimate the initial deposit required to obtain $10,000 in 6 years:

Therefore, we must deposit (B) $6,301.70 today to withdraw $10,000 in 6 years.

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The correct question is given below;
You can earn 8 percent interest, compounded annually. How much must you deposit today to withdraw $10,000 in 6 years?

A. $5,402.69

B. $6,301.70

C. $6,756.76

D. $8,432.10

E. $9,259.26

Andrew has 7 dimes and 15 quarters, as obtained from the system of linear equations so formed.

A system of linear equations is a set of two or more linear equations. Linear equations refer to the equations that involve two or more variables in the form of "ax + b".

Given:

To find: Number of dimes and quarters.

Finding:

=> By unitary method, $4 = 4(100) = 400 cents

d + q = 22 (Number of coins) => d = 22 - q (eqn1)

and 10d + 25q = 400 (amount of coins)

=> 10 ( 22 - q ) + 25q = 400

=> 220 - 10q + 25q = 400

=>  15q = 400 - 220 = 180

=> q = 12, i.e., number of quarters = 22 upon the solving of this system of linear equations.

On substituting the value of q in eqn1, we get: d = 22 - 15 = 7, i.e., number of dimes = 7.

Hence, Andrew has 7 dimes and 15 quarters, as obtained from the system of linear equations so formed.

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Answer:

(-1)=10

(10)= -54

(5)= -26

Step-by-step explanation:

h(-1)=4-6(-1)

h(-1)=4 (-6*-1)

h(-1)=4+6

h(-1)=10

h(10)=4-6(10)

h(10)=4 (-6*10)

h(10)=4-60

h(10)=-54

h(5)=4-6(5)

h(5)=4 (-6*5)

h(5)=4-30

h(5)=-26

Hope this helps.

The answer for the following algebraic expression [tex]10y-3(y+5)[/tex] is Option C [tex]7y-15[/tex].

According to the given question statement, We are supposed to simplify the given algebraic expression [tex]10y - 3(y + 5)[/tex]

Solution is as follows:

[tex]10y - 3(y + 5)\\= 10y-3(y)-3(5)\\\[/tex]

[tex]=10y-3y-15[/tex]

[tex]=7y-15[/tex]

Hence [tex]7y-15[/tex] is our final answer.

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Answer: y<3x-4

Step-by-step explanation:

[tex](0,-4) \ \ \ \ \ \ (1,-1)[/tex]

                           The equation of the line

                                 [tex]\displaystyle\\\boxed {\frac{x-x_1}{x_2-x_1}=\frac{y-y_1}{y_2-y_1} }[/tex]

[tex]\displaystyle\\x_1=0\ \ \ \ x_2=1\ \ \ \ y_1=-4\ \ \ \ y_2=-1\\Hence,\\\frac{x-0}{1-0} =\frac{y-(-4)}{-1-(-4)} \\\\\frac{x}{1} =\frac{y+4}{-1+4} \\x=\frac{y+4}{3}[/tex]

Умножьте обе части уравнения на 3:

[tex]3x=y+4\\3x-4=y+4-4\\3x-4=y[/tex]

Thus, y<3x-4

The fraction of those who were cast and got major roles is 1/5.

The number of the students who were cast out of the Ninety students auditioned  for the school play is calculated as follows;

Total number of students = 90

Number of students who were cast = ¹/₃ x 90 = 30

Number of students who go major role = 6

The fraction of those who were cast and got major roles is calculated as follows;

fraction of students who got major role = 6/30

fraction of students who got major role =  1/5

Thus, the fraction of those who were cast and got major roles is 1/5.

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Answer:

Total number of students = 90

Number of students who were cast = ¹/₃ x 90 = 30

Number of students who go major role = 6

fraction of students who got major role = 6/30

fraction of students who got major role = 1/5

1/5 = 0.2

Answer:

0.125

Step-by-step explanation: