Please do all of i will give you brainlest and thanks to best answer plz do it right

Answer: thanks for the point

Explanation:

The action and reaction law allows us to find that the reaction force, the weight of the cylinder, is:

Newton's third law or action and reaction law, establishes that if two bodies interact with each other the force that one applies to the other, is equal in magnitude to the force of the second on the first but in the opposite direction, that is, all forces act in pairs one in each body that interact.

Forces with these characteristics are called action and reaction.

In this case we have a hanging cylinder, with the cylinder it has mass so the weight is 12 N it acts on the table in a downward direction, let's say this is the action force.

In response to this force, the table exerts a force on the cylinder of equal magnitude but in the opposite direction, which is why it is directed upwards.

let's analyze the force diagram

In conclusion using theaction and reaction law we find that the answer for reaction force is:

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Answer: tectonic plates

Explanation:

Answer:A material that can dissolve in another material called Soluble

Explanation:

Answer:

Option 3.

Soluble is the correct/best answer choice.

Answer:

45 degrees

Explanation:

Given that the coefficient of friction, [tex]\mu=1.0[/tex]

Let the angle of the ramp be [tex]\theta[/tex].

The gravitational force acting downward [tex]=mg[/tex]

The normal reaction by the ramp on the box, [tex]N=mg\cos\theta[/tex]

So, the maximum frictional force that can act on the box, [tex]f= \mu N[/tex]

The force along with the plane in the direction of sliding, [tex]F = mg\sin\theta[/tex]

When the box begins sliding, the F must have to overcome the frictional force,f.

So, F=f

[tex]mg\sin\theta=\mu N \\\\mg\sin\theta=\mu mg\cos\theta \\\\\frac {\sin\theta}{\cos\theta}=\mu \\\\\tan\theta=\mu \\\\\theta=\tan^{-1}\mu \\\\[/tex]

Putting the value of \mu, we have

[tex]\theta=\tan^{-1}1[/tex]

[tex]\theta=45[/tex] degrees.

Hence, the angle of the ramp with respect to the ground when the box begins sliding is 45 degrees.

Answer:

80g

Explanation:

The half - life is the time taken for half of radioactive substance to decay to half of its original composition.

After 4 half lives, the carbon - 14 sample is 10grams

 Now let us trace the decay of this substance;

At the 3rd  half life, it will have double the amount at the 4th half life;

                 2 x 10  = 20g

At the 2nd half life, there will be double the amount at the 3rd half life;

                20 x 2  = 40g

Originally, we are going to have;

               40 x 2 = 80g

Answer:

The answer is "[tex]5.184 \times 10^{23}[/tex] kg"

Explanation:

Given:

[tex]g= 6.003 \ \frac{m}{s^2}\\\\G= 6.67 \times 10^{-11} \ \frac{N - m^2}{kg^2}\\\\M=?\\\\radius= 2,400 \ km\\\\[/tex]

Calculating diameter:

[tex]Diameter =radius \times 2[/tex]

                [tex]=24\times 10^5 \times 2\\\\=48 \times 10^5 \ m[/tex]

The formula for mass calculation:

[tex]\to g = G \times \frac{M}{(\frac{d^2}{4})}\\\\\to g=G\times \frac{4M}{d^2}\\\\\to 4M= \frac{g \times d^2}{G} \\\\\to M= \frac{g \times d^2}{4G} \\\\[/tex]

         [tex]=\frac{6.003 \times (48 \times 10^{5})^2}{4 \times 6.67 \times 10^{-11}}\\\\=\frac{6.003 \times 2,304 \times 10^{10}}{26.68\times 10^{-11}}\\\\=\frac{13,830.912 \times 10^{10}}{26.68\times 10^{-11}}\\\\=518.4 \times 10^{21}\\\\= 5.184 \times 10^{23}\\\\[/tex]

Answer:

Density of the ship :133.33 kg/m³

Mass of the ship :50,000,000 kg

Ships are able to float on water because they displace a volume that equals  their own weight

Explanation:

The formula for density is ;

Density = Mass/Volume

But the mass of  displaced fluid is give by the formula;

m=ρV where ρ is density of the fluid and V is volume of water displaced

Volume of liner= 375000 m³

Volume displaced = 50000 m³

The volume of the water displaced is equal to mass of the liner

I m³ = 1000 kg

50000 m³ = 50000*1000 =50,000,000 kg

50,000,000 kg ----------mass of the ship

So if ;

m= 50,000,000 kg

v= 375000 m³

ρ = m/V

ρ = 50,000,000/375000

ρ = 50,000,000/375000

ρ =133.33 kg/m³

Ships are able to float on water because they displace a volume that equals  their own weight. Additionally, the air contained in the spaces of the ship inside is much less dense than density of water aiding in the floating process.

Explanation:

It is given that,

A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)

i. Total distance = total path covered

= 14 km + 43 km

= 57 km

ii. Let east is positive and west is negative.

Displacement = final position-initial position

= 43-14

= 29 km

iii. If time taken in the entire trip = 3.2 hours

Average speed = distance/time

[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]

1 km/h = 0.2777 m/s

17.81 km/h = 4.94 m/s

iv. If time taken in the entire trip = 2.5 hours

Average velocity = displacement/time

[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]

1 km/h = 0.621 mph

11.6 km/h = 7.2 mph

Henc, this is the required solution.

Answer:

physical, social, and mental

Explanation:

Answer:

A,B,C

Explanation:

These three maintain the overall health of the person being. Take for instance an example a cake, it has layers that make the overall cake. So it is with the persons health, it takes all three of these feilds to make the overall health.

Answer:

Chemists classify chemical reactions in a number of ways: by type of product, by types of reactants, by reaction outcome, and by reaction mechanism. Often a given reaction can be placed in two or even three categories, including gas-forming and precipitation reactions.

Explanation:

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Answer:

The answer is D.

Explanation:

You have to apply distance formula :

[tex]distance = speed \times time[/tex]

[tex]let \: d = 200,t = 4[/tex]

[tex]200 = s \times 4[/tex]

[tex]4s = 200[/tex]

[tex]s = 200 \div 4[/tex]

[tex]s = 50 \: m {s}^{ - 1} [/tex]

An eagle travels 200 meters in 4 seconds

Speed of the eagle

Distance=d=200m

Time=t=4s

[tex]{\boxed{\sf Speed ={\dfrac{Distance{}_{(d)}}{Time{}_{(t)}}}}}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=\dfrac {200}{4}[/tex]

[tex]\qquad\quad {:}\longmapsto\sf Speed=50m/s [/tex]

[tex]\therefore{\underline{\boxed{\bf Speed\:of\:eagle=50m/s}}}[/tex]

Answer:

μ = 0.125

Explanation:

To solve this problem, which is generally asked for the coefficient of friction, we will use the conservation of energy.

Let's start working on the ramp

starting point. Highest point of the ramp

         Em₀ = U = m h y

final point. Lower part of the ramp, before entering the rough surface

        [tex]Em_{f}[/tex] = K = ½ m v²

as they indicate that there is no friction on the ramp

          Em₀ = Em_{f}

          m g y = ½ m v²

          v = [tex]\sqrt{2gy}[/tex]

we calculate

          v = √(2 9.8 0.25)

           v = 2.21 m / s

in the rough part we use the relationship between work and kinetic energy

          W = ΔK = K_{f} -K₀

as it stops the final kinetic energy is zero

          W = -K₀

The work is done by the friction force, which opposes the movement

          W = - fr x

friction force has the expression

          fr = μ N

let's write Newton's second law for the vertical axis

         N-W = 0

         N = W = m g

we substitute

            -μ m g x = - ½ m v²

           μ = [tex]\frac{v^{2} }{2 g x}[/tex]

Let's calculate

           μ = [tex]\frac{2.21^{2}}{2\ 9.8\ 2.0}[/tex]

           μ = 0.125

A 8.0 kg box is released from rest at a height y0 = 0.25 m on a frictionless ramp. The box slides from the ramp onto a rough horizontal surface. The box slides 2.0 m horizontally until it stops.

What is the friction coefficient of the horizontal surface?

Answer: 0.125

Answer:

Air moves from the areas of higher temperature to areas of lower temperature.

Explanation:

this is because hotter temperatures seek out colder temps.

hope this helped!

When a teacher opens a window on a cold day. the room starts to feel cooler because air moves from the areas of higher temperature to areas of lower temperature.

The transfer of heat between two bodies by currents of moving gas or fluid is known as convective heat transfer. In free convection, air or water rises and is replaced by a cooler parcel of air or water as it moves away from the hot body.

As air moves from the areas of higher temperature to areas of lower temperature, when the teacher opens a window on a cold day, the air in the room moves out side and cold air takes the position inside the room. So, it feels cooler then.

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Answer:

A

Explanation:

Trust me I just took it !

[tex]\huge\boxed{Option D}[/tex]

Radius of Mercury = [tex]R_m[/tex] = [tex]2.43x10^6m[/tex]

Mass of Mercury = [tex]M_m = 3.2x10^{23}m[/tex]

Distance Satellite above the surface of the Mercury = d = 265,000m

Gravitational Constant =  [tex]G = 6.67x10^{-11} \frac{N.m^2}{kg^2}[/tex]

Since the Satellite is orbiting around the Planet Mercury, due to the centripetal force, and Centripetal force is the force that acts towards the center of the circle, Whereas The gravitational force also acts towards the center of the circle thus we can say that Centripetal force is equal or same as centripetal force.  So,

                                             [tex]F_g =F_C[/tex]

Fg is Given by,

                                           [tex]F_g = \frac{GM_MM_S}{r^2}[/tex]

Fc is Given by,

                                           [tex]F_c=\frac{M_SV^2}{r}[/tex]

Where,

            G is Gravitational Constant

            [tex]M_e[/tex] is mass of Planet Mercury

            [tex]M_S[/tex] is Mass of Satellite

             r(small letter) is the distance between the center of the Planet Mercury and the satellite.

             V is velocity of satellite

Now,

                                 [tex]\frac{GM_MM_S}{r^2} =\frac{M_SV^2}{r}[/tex]

                                 [tex]V = \sqrt\frac{GM_M}{r}[/tex]

 r can also be written as,

                                  [tex]V = \sqrt\frac{GM_M}{R_M +d}[/tex]

Substitute the variables,

                                  [tex]V = \sqrt{\frac{(6.67x10^{-11})x(3.2x10^{23})}{2695000}[/tex]

Simplify the equation,

                                  V = 2814 [tex]\frac{m}{s}[/tex]

Approximately,

                                  V = 2800 [tex]\frac{m}{s}[/tex]

Answer:

125 m

Explanation:

i just did the edpuzzle

Answer:

im pretty sure its d

Explanation:

Answer:

Chemical energy transformations take place from the outlet charger to the ringing phone.

Explanation:

chemical energy

While charging the mobile electrical energy gets transformed into chemical energy. Most of the contemporary mobile phone batteries are lithium-ion batteries where the power is saved by the chemical transformations in the ionic structure of the battery.  When the power gets into the mobile phone it is transformed and collected as chemical energy inside of the battery and when we utilize the mobile the earlier saved chemical energy is again transformed into electrical energy.

The energy transformation that takes place from the outlet charger to the

ringing phone is electrical energy from the outlet is converted to chemical

energy and back to electrical energy and sound energy when the phone is

being used and ringing.

The charger provides a source of electrical energy which gets converted to

chemical energy stored in the battery. During use, the chemical energy gets

converted to electrical energy to power the phone and to sound energy

when it rings with heat energy being dissipated also.

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Answer:

The car is going 0 km/h more than the bike

Explanation:

Answer:

D

Explanation:

The decrease in potential energy is equal to the increase in kinetic energy.

mgh

250 x 9.8 x 30

=73, 500

Answer:

73,500 J

Explanation:

100% Correct

Explanation:

F=MA

F=1500 * 2

F=3000N

Answer:

The period is 0.54 seconds

Explanation:

Period (T)

Is the time required for a rotating object to make one complete revolution around a circular path.

If it takes a time t to complete n revolutions, the period is:

[tex]\displaystyle T=\frac{t}{n}[/tex]

The rotating object spins n=24 times in t=13 seconds, thus its period is:

[tex]\displaystyle T=\frac{13}{24}[/tex]

T = 0.54 sec

The period is 0.54 seconds

Biker 1's acceleration:

(25 mph) / (3 s) = ((25 mi/h) • (1/3600 h/s)) / (3 s) ≈ 0.00231 mi/s²

Biker 2's acceleration:

(85 mph) / (8 s) = ((85 mi/h) • (1/3600 h/s)) / (8 s) ≈ 0.00295 mi/s²

Biker 2 has the greater acceleration.

Answer:

Pressure on the narrow piston = 3100 [tex]N/m^2[/tex]

The wider piston can lift the weight up-to 6200 N

Explanation:

Given that the area of the narrow piston = 0.2 [tex]m^2[/tex]

Applied force on the narrow piston, [tex]F_{in}[/tex]= 620 N

Area of the larger piston  = 2.0 [tex]m^2[/tex].

As pressure = force/ area,

So. pressure exerted on the narrow piston, [tex]P= 620/0.2=3100 N/m^2[/tex]

There is liquid in between the narrow piston and the larger piston and according to Pascal's law, the pressure inside any liquid is uniformly distributed.

As the narrow piston is applying the pressure on the liquid which is equal to the external pressure applied on the narrow piston, i.e 3100 [tex]N/m^2[/tex].

So, the uniformly distributed pressure in the fluid is 3100 [tex]N/m^2[/tex].

Now, the liquids apply pressure on the larger piston,

as force = Area x pressure, so the applied on the larger piston, [tex]F_{out}[/tex], by the liquid is

[tex]F_{out} = 3100\times2=6200[/tex] N

Hence, the wider piston can lift the weight up-to 6200 N.

Answer: 20

Explanation:

If Jake pushes with 20 N of force, the force that he would feel backwards away from Amir is 20N

Force simply means the strength or energy that can later the position of an object. Force can also be described as a push or pull.

It should be noted that since Jake pushes with 20 N of force, the force that he would feel backwards away from Amir will be the exact force that was used in pushing.

This will therefore be 20 Newton as well.

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