Please answer both it will really help

Answer:

[tex]\huge\boxed{\sf Slope = \frac{9}{7}}[/tex]

Step-by-step explanation:

The top and bottom points of the line are

(3,0) and (10,9)

[tex](x_1,y_1) = (3,0)\\\\(x_2,y_2) = (10,9)[/tex]

So,

[tex]\sf Slope = \frac{y_2-y_1}{x_2-x_1}\\\\Slope = \frac{9-0}{10-3} \\\\\boxed{\sf Slope = \frac{9}{7} }\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

B

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then

cos45° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{3}{c}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )

c = 3[tex]\sqrt{2}[/tex]

Answer:

1

X is equal to 10

10 plus 1 equals 11

2

y is equal to 6

30 minus 8

is equal to 22

3

m equals 3 and t equals 5

30 minus 27

is equal to 3

4 not written properly

5 not written properly

Answer:

Check pdf

Step-by-step explanation:

Answer:

35+28=31

Step-by-step explanation:

Answer:

Tom's weekly allowance is $16.

Step-by-step explanation:

With the information provided, first you have to subtract the amount he earned washing the family car from the total amount he had to determine the amount he had left from his allowance after going to the movies:

$15-$7=$8

Now, since the statement indicates that tom spent half of his allowance going to the movies, this means that the $8 represents the amount left after going to the movies and it is half of his allowance. So, you have to multiply this amount by 2 to find his weekly allowance:

$8*2=$16

According to this,the answer is that Tom's weekly allowance is $16.

Equations:

[tex]x+6=5+x[/tex]

[tex]-2(x-3)=-2x+6[/tex]

[tex]4-4x=3x+2[/tex]

[tex]4(x+1)=3(x+2)[/tex]

[tex]5-3x=-3x+4[/tex]

Answer:

[tex]x+6=5+x[/tex]

[tex]5-3x=-3x+4[/tex]

Step-by-step explanation:

Given

[tex]x+6=5+x[/tex]

[tex]-2(x-3)=-2x+6[/tex]

[tex]4-4x=3x+2[/tex]

[tex]4(x+1)=3(x+2)[/tex]

[tex]5-3x=-3x+4[/tex]

Required:

Which have no solution

[tex]x+6=5+x[/tex]

Subtract x from both sides

[tex]x -x+6 = 5 + x - x[/tex]

[tex]6 = 5[/tex]

[tex]x+6=5+x[/tex] has no solution because [tex]6 \ne 5[/tex]

[tex]-2(x-3)=-2x+6[/tex]

Open bracket

[tex]-2x + 6 = -2x + 6[/tex]

Both sides are equal.

Hence, there is an [tex]Infinite\ Number[/tex] of Solutions

[tex]4-4x=3x+2[/tex]

Collect like terms

[tex]-3x - 4x = 2 - 4[/tex]

[tex]-7x = -2[/tex]

Solve for x

[tex]x = \frac{-2}{-7}[/tex]

[tex]x = \frac{2}{7}[/tex] --- This has a solution

[tex]4(x+1)=3(x+2)[/tex]

Open brackets

[tex]4x + 4 = 3x + 6[/tex]

Collect like terms

[tex]4x-3x = 6 - 4[/tex]

[tex]x = 2[/tex] --- This has a solution

[tex]5-3x=-3x+4[/tex]

Add 3x to both sides

[tex]5 - 3x + 3x = -3x + 3x + 4[/tex]

[tex]5 = 4[/tex]

[tex]5-3x=-3x+4[/tex] has no solution because [tex]5 \ne 4[/tex]

Answer:

Sorry, I can't complete this without knowing the radius, or diameter.

Step-by-step explanation:

Answer:

I believe it will be 5 minutes for it to reach that.

Step-by-step explanation:

T=D/S

D=360m

S=12m/s

360m÷12m/s

Time=30s

Answer:

3

Step-by-step explanation:

Given:

Consider the given polynomial is:

[tex]x^3+4x^2+16x+64[/tex]

To find:

The complete factorization of the given polynomial.

Solution:

We have,

[tex]x^3+4x^2+16x+64[/tex]

Using grouping method, we get

[tex]=(x^3+4x^2)+(16x+64)[/tex]

[tex]=x^2(x+4)+16(x+4)[/tex]

[tex]=(x+4)(x^2+16)[/tex]

[tex]=(x+4)(x+4i)(x-4i)[/tex]         [tex][\because x^2+y^2=(x+iy)(x-iy)][/tex]

Therefore, the correct option is C.

Answer:

B

Step-by-step explanation:

C = πd = 3.14 * 32 = 100.48in

Answer:

b

Step-by-step explanation:

The domain is a set of input values so {x| x = –7, –6, 2, 11, 3} will be the domain of the relation therefore option (B) will be correct.

A function's range is the set of all values that the function accepts, and its domain is the set of all values for which the function is defined.

The domain is for the independent variable while the range is for the dependent variable.

For example f(x) = x²

Now if we put x = 1 then it is called as domain variable while the value of function at x = 1 its that f(1) = 1 called range variable.

The domain is the set of all input values where the function is defined.

Since in the given relation ;

All input values have an output so all input values will be the domain of the given relation.

Hence "{x| x = –7, –6, 2, 11, 3} will be the domain of the relation".

For more details about the range and domain of the function,

brainly.com/question/28135761

#SPJ2

Answer:

m = -1, b = 5.

Step-by-step explanation:

We can find the slope, m, by plugging in our coordinates into the slope formula: [tex]\frac{y2-y1}{x2-x1} =\frac{2-7}{3-(-2)}=\frac{-5}{5}=-\frac{5}{5}=-\frac{1}{1}=-1[/tex]. That gives us the slope. Now we can fill that in the slope intercept formula: [tex]y=-1x+b[/tex]. We know one of the coordinates and the slope, which allows to find the y-intercept. We know that for every 1 unit down on the line, we move 1 unit right, and vice versa. Meaning we can just count down (or up in this case), so, (-2, 7), (-1, 6), (0, 5). Therefore, our y intercept is 5.

Answer:

6

Step-by-step explanation:

The two small triangles are congruent by SAS.

By CPCTC, x = 6.

Answer: 6

-12 x 3 = -36

-6 x 6 = 36

-8 x 2 = -16

-4 x 4 = -16

Answer:

6.5

Step-by-step explanation:

Answer:

6.5 centimeters (proof below!)

Step-by-step explanation:

Given:

The vertices of a right triangle are:

[tex](-3,4),(3,4),(3,-4)[/tex]

To find:

The length of the hypotenuse of the given right triangle.

Solution:

Let the vertices of the right triangle are [tex]A(-3,4),B(3,4),C(3,-4)[/tex].

The distance formula is:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Using distance formula, we get

[tex]AB=\sqrt{(3-(-3))^2+(4-4)^2}[/tex]

[tex]AB=\sqrt{(3+3)^2+(0)^2}[/tex]

[tex]AB=\sqrt{(6)^2+0}[/tex]

[tex]AB=\sqrt{36}[/tex]

[tex]AB=6[/tex]

Similarly,

[tex]BC=\sqrt{(3-3)^2+(-4-4)^2}[/tex]

[tex]BC=\sqrt{(0)^2+(-8)^2}[/tex]

[tex]BC=\sqrt{64}[/tex]

[tex]BC=8[/tex]

And,

[tex]AC=\sqrt{(3-(-3))^2+(-4-4)^2}[/tex]

[tex]AC=\sqrt{(6)^2+(-8)^2}[/tex]

[tex]AC=\sqrt{36+64}[/tex]

[tex]AC=\sqrt{100}[/tex]

[tex]AC=10[/tex]

Now, taking sum of squares of two smaller sides, we get

[tex]AB^2+BC^2=6^2+8^2[/tex]

[tex]AB^2+BC^2=36+64[/tex]

[tex]AB^2+BC^2=100[/tex]

[tex]AB^2+BC^2=AC^2[/tex]

By the definition of the Pythagoras theorem, AC is the hypotenuse of the given triangle.

Therefore, the length of the hypotenuse is 10 units.

Answer: It's C=πr2

Step-by-step explanation: I took the test

Answer:

-5

Step-by-step explanation:

1*1=1

1-6= -5

Hope this helped!

Answer:

D

Step-by-step explanation:

D starts low on both sides but is highest in the middle

Answer:

m=3/2,y-int=5

Step-by-step explanation:

y=mx+b is the slope equation. since -10 is at the end of the equation and it does not have a variable next to it yk it is the y-intercept. if you want you draw this on a graph and you can see that you go up 3 and over 2

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Answer: 27528 ft^3

Explanation:

24 x 31 x 37 = 27528

I hope this helped!

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