One mole of silver has a mass of 107.9 grams. Approximately how many atoms of silver are present in one mole of silver?

A) 107 atoms
B) 108 atoms
C) 6 × 1023 atoms
D) 53 × 1023 atoms

Answers

Answer 1

Answer  C) 6 × 1023 atom

Answer 2

The number of silver atoms present in one mole of silver is 6.0 × 10²³ atoms. The correct option is C) 6 × 1023 atoms

Stoichiometry

From the question, we are to determine the number of silver atoms present in one mole of silver.

From the formula,

Number of atoms = Number of moles × Avogadro's constant

Number of atoms = 1 × 6.022 × 10²³

Number of atoms = 6.022 × 10²³

Number of atoms ≅ 6.0 × 10²³ atoms

Hence, the number of silver atoms present in one mole of silver is 6.0 × 10²³ atoms. The correct option is C) 6 × 1023 atoms

Learn more on Stoichiometry here: https://brainly.com/question/16505596


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Explanation:

1.0 °C = 274.15 K

2.0 °C = 275.15 K

3.0 °C = 276.15 K

4.0 °C = 277.15 K

5.0 °C = 278.15 K

6.0 °C = 279.15 K

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Using the balanced chemical equation:
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Determine the amount of grams of N2 is produced If 4.03 moles of NH3 react?

Answers

Your answer and workings are all mentioned in the picture below.

Taking into account the reaction stoichiometry, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Reaction stoichiometry

In first place, the balanced reaction is:

4 NH₃ + 3 O₂  → 2 N₂+ 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

NH₃: 4 molesO₂: 3 molesN₂: 2 molesH₂O: 6 moles

The molar mass of the compounds is:

NH₃: 17 g/moleO₂: 32 g/moleN₂: 28 g/moleH₂O: 18 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

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Mass of N₂ formed

The following rule of three can be applied: if by reaction stoichiometry 4 moles of NH₃ form 56 grams of N₂, 4.03 moles of NH₃ form how much mass of N₂?

[tex]mass of N_{2} =\frac{4.03 moles NH_{3} x56 grams of N_{2} }{4 moles NH_{3}}[/tex]

mass of N₂= 56.42 grams

Then, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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