need help Define population.

Question 1 options:

A group of all living things in a given area


A group of organisms that are the same species interacting with each other in a given area.


All of the living and non-living organisms in a given area


Areas with similar climate and flora and fauna

Question 2 (2 points)
What does the x-axis represent?

Question 2 options:

Time


Starting population of Fog Beetles


The number of organisms in the population


exponential growth

Question 3 (2 points)
What does the y-axis represent?

Question 3 options:

Time


Starting population of Fog Beetles


The number of organisms in the population


exponential growth

Question 4 (2 points)
Move the growth rate r slider to its lowest value of 0.1, then gradually increase it. What happens to the population size as you increase the growth rate (the r slider)?



Question 4 options:

As the growth rate increases, the population size moves up and down rapidly.


As the growth rate increases, the population size stays the same.


As the growth rate increases, the population size decreases more rapidly. The slope flattens out.


As the growth rate increases, the population size increases more rapidly. The slope becomes steeper.

Question 5 (2 points)
Set the growth rate at r = 0.5, and make N0 = 500 individuals. What is N when t = 8? To answer this question, you will have to rescale the graph so that you can see the higher values of N: Click on the gear icon and change the Max value of Pop. (N0) to 30,000.

Question 5 options:

12,182


30,000


27,299


500

Question 6 (2 points)
The initial values for the fog beetle population are as follows:

Initial # of fog beetles (N0) = 2,000,

birth rate=.88 (b)

death rate= .05 (d)



What is the calculated population growth rate (r) for the beetles?

Growth Rate(r) = birth rate (b)- death rate (d)

Question 6 options:

.88


.05


.83


.94

Question 7 (2 points)
After 5 years, what would be the total population of fog beetles?

**write the number in the following format xxx,xxx** Don't include a label

Question 7 options:
Question 8 (2 points)
The growth rate you entered into the model predicts that the population growth of fog beetles will start to slow down and decline as time continues.

Question 8 options:
True
False
Question 9 (2 points)
What are two possible limiting factors that might cause the population of fog beetles to level off?

Question 9 options:

Disease and predators


habitat loss and more beetles immigrating to the desert


Natural disasters and more beetles immigrating to the desert


None of the above

Question 10 (2 points)
If a parasite began attacking the fog beetles increasing their death rate to .12, how would this change alter the growth rate of the fog beetles (remember r=b-d, use the information from the initial question about fog beetles)?

Question 10 options:

An increase in death rate would cause the growth rate to decrease to .76


An increase in death rate would cause the growth rate to increase to .98


An increase in death rate would not cause a change to the growth rate

Question 11 (2 points)
How would this new growth rate influence the population size at time t = 10?

(The old growth rate was .83 )

Question 11 options:

The new growth rate would result in a decrease of 2 million fog beetles over the course of 10 years.


The new growth rate would result in an increase of 4 thousand fog beetles over the course of 10 years.


The new growth rate would result in a decrease of about 4 million fog beetles over the course of 10 years.


There would be no change to the population after 10 years.

Question 12 (2 points)
The kudu population will reach its carrying capacity right around the 35 year mark (You may need to change the max value of t and adjust the max value of k to optimize the graph display).

Question 12 options:
True
False
Question 13 (2 points)
Assume a new plot of land is added to the park, increasing the carrying capacity to 350 kudu. How will the population size change?

Question 13 options:

The population would continue to grow at the same rate until it hit 200 and then it would grow at a slower rate until it reached 350 kudu


The population would continue to grow until it hit the new carrying capacity.


It would provide more space for the trophy hunters to move in and hunt the kudu.

Question 14 (2 points)
Reset the carrying capacity back to 200. Trophy hunters move into the area, leading to an increased death rate, which decreases the growth rate r to 0.15. How would this impact the population size? (Hint: Look at when the population reaches its carrying capacity, look at the T value)

Question 14 options:

The kudu would grow at a very slow rate for 30 years and then the growth rate would slow down.


It would take about 25 more years for the kudu to reach their carrying capacity.


The population would reach its peak in the first 10 years


none of the above

Answer: factors that limit a population size are limiting factors. Biotic potential is the amount of organisms that could be supported in an ecosystem if plenty of resources were available. Factors that cause a population to increase are 1)births: the number of births in a population in a certain period of time. 2) immigration: when organisms move INTO a population.

Explanation:

some examples of limiting factors are natural hazards, amount of food, amount/quality of water and air, predators deforestation.

competition plays a very important role in ecology and evolution. The best competitors are the ones who survive and get to pass on their genes.

Answer:

d

Explanation:

please give brainlest need 2 more

Bacteria that require oxygen to grow are called "obligate aerobic bacteria". Without oxygen they generally die since these bacteria require oxygen to grow.

Their methods of energy production and respiration depend on the transfer of electrons to oxygen.

Answer:

Myelinated axons utilize fewer voltage-gated channels than unmyelinated axons of the same length and diameter.

Myelinated axons are more energy efficient than unmyelinated axons.

Explanation:

Neurons are cells that specialize in transmitting messages to each other using a type of electrical signal. These signals carry information from outside your body to the brain, while others are the instructions for the various organs, glands and muscles to carry out functions.

Neurons receive these signals from other neighboring neurons through their dendrites. The signal then travels to the soma of the neuron, which is the main body of the cell, and finally travels down the axon to the synapse (space between the end of a neuron and another cell). The axon is a neuronal extension through which the electrical signal travels, extending from the soma to other neurons.

There may be layers of myelin, which consist of a layer of fat, covering the axons and where they have the function of acting as insulators to help keep the electrical signal inside the cell, which makes it move faster increasing the speed of transmission of the nerve impulse.

1) Myelinated axons transmit nerve impulses via continuous conduction. FALSE. In the axon, nodes of Ranvier are found at regular intervals along the length of the axon in the myelin sheath that surrounds it. These are small spaces that expose the axon membrane to the extracellular fluid and serve to allow the nerve impulse to travel faster, in a jumping manner and with less chance of error.

2) Myelinated axons transmit nerve impulses in the same manner as unmyelinated axons. FALSE. In an unmyelinated axon, the movement of voltage across the membrane is due to ion flux that is limited by the time it takes for sodium ions to diffuse into the axon. Myelinated axons conduct faster because they are shorter than unmyelinated axons. In the latter, transmission is continuous but slower.

3) Myelinated axons utilize fewer voltage-gated channels than unmyelinated axons of the same length and diameter. TRUE. The action potential conduction jumps from node to node, thereby they need fewer voltage-gated channels. Unmyelinated axons need voltage-gated channels in along the entire axon.

4) Myelinated axons are more energy efficient than unmyelinated axons. TRUE. The rate at which sodium input through one node can depolarize the axon at the next node is related to the current and capacitance across the membrane. Myelinated axons have faster action potential conduction because it jumps from node to node, thereby they use less energy because they don't have to travel the entire length.

5) Myelinated axons would be unaffected by diseases that attack the CNS. FALSE. For example, Multiple sclerosis (MS) is a demyelinating disease of the CNS in which the immune system attacks the myelin sheath or the cells.

The correct statements are:

Myelinated axons are nerve fibers that are protected by a covering called myelin. In both the central nervous system (CNS) and peripheral nervous system (PNS), oligodendrocytes and specialized cells known as Schwann cells work together to generate the myelin sheath. This sheath is composed of several layers of lipids, which are fatty substances that wrap around the axon in segments, leaving small spaces known as nodes of Ranvier.

Therefore, the correct options are A, C and D.

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Your question is incomplete, most probably the complete question is:

Check all that apply as characteristics of myelinated axons. Check All That Apply

Answer:

chemical energy

Explanation:

we get this from food which pur bodies use as fuels to do things like running,talking,etc

Answer:

fvgvurhufv

Explanation:

Answer and Explanation:

Due to technical problems, you will find the complete answer and explanation in the attached files

Answer:

I think the answer is colour

Answer:

The binding of carbon monoxide (CO) with hemoglobin leads to an R state even in conditions that should produce the release of oxygen. In consequence, CO-hemoglobin binding shifts the oxygen dissociation curve to the left.

Explanation:

Hemoglobin is a globular protein containing four heme groups that can bind to one oxygen each. This protein (hemoglobin) has two conformational states: the T-state, also known as deoxyhemoglobin (a tense state, where lacks O species), and the R-state, also known as oxyhemoglobin (a relaxed, fully oxygenated state). When carbon monoxide binds to hemoglobin, the protein can not release oxygen, shifting the oxygen dissociation curve -which expresses the percentage of oxygen saturation against the partial pressure of oxygen- to the left. Therefore, under CO-hemoglobin binding, the oxygen level in the tissues is reduced.

Out of the options given, the density-independent factor is: A. Forest fire. A density-independent factor is a factor that affects a population regardless of its size and density.  

A cell is the basic unit of life that makes up all living things, including animals, plants, fungi, and bacteria. It is the smallest structural and functional unit of an organism that is capable of performing all the functions of life, including metabolism, growth, reproduction, and responding to stimuli. A typical cell is composed of a cell membrane, cytoplasm, and a nucleus (in eukaryotic cells), or a nucleoid region (in prokaryotic cells). The cell membrane is a selectively permeable membrane that surrounds the cell and separates it from the environment, regulating the exchange of materials between the cell and its surroundings. The cytoplasm is a gel-like substance that fills the cell and contains all the organelles and structures necessary for the cell's functions. The nucleus contains the cell's genetic material, including DNA, which controls the cell's activities and is responsible for inheritance.

Here,

A forest fire can have a significant impact on a population, regardless of its size or density. Forest fires can destroy habitats, reduce food sources, and alter the physical environment, which can have a significant impact on the population. A forest fire does not depend on the size or density of a population, so it is considered a density-independent factor.

The other options, such as food source, shelter, and water supply, are density-dependent factors that can impact a population based on its size and density. As the population increases, the availability of these resources can become limited, which can affect the population's growth and survival.

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Compaction and Cementation They are compacted, reducing the available pore space and expelling much of the pore-water. Dissolved minerals in the ground water precipitate (crystallize) from water in the pore spaces forming mineral crusts on the sedimentary grains, gradually cementing the sediments, thus forming a rock.

Through compaction and cementation, minerals form a crusts on the sedimentary rocks which are no longer just a loose pile of sand and rocks.

Sedimentary rocks are formed from the pre-existing rocks or pieces of or fossils of living organisms. They form from the deposits which accumulate on the surface of Earth. Sedimentary rocks often have distinctive layering or bedding over Earth.

Dissolved minerals present in the ground water precipitates from the water surface present in the pore spaces forming mineral crusts on the sedimentary grains, which gradually undergo cementing the sediments, which thus lead to formation of a rock.

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Answer:  it would be natural selection

Explanation:

Answer:

The correct answer is ''forms a channel in the target cell membrane that causes cytolysis.''

Explanation:

The membrane attack complex (MAC) has the essential effect of producing a notable osmotic imbalance in the microorganism that leads to its cytolysis (in Gram-negative bacteria it inserts into the outer membrane, favoring the entry of lysozyme, and in Gram-positive ones insert into the cytoplasmic membrane, destroying the electrochemical gradients). The lytic pathway corresponds to the final reactions of the complement system. It begins when the C5 convertase enzymes formed either in the classical pathway, MBL or the alternative, fix the factor C5 and fragment it into C5a (anaphylatoxin) that passes into the fluid medium and C5b, which binds non-covalently to C3b. The C5b fraction captures C6 and C7 from the fluid phase, forming a stable C5b67 complex with chemotaxic activity and membrane-binding capacity, which when joining the C8 fraction is cytolytic, and acquires the ability to interact with C9 molecules, forming the complex C5b6789. The C9 molecules then undergo conformational changes, enhance and accelerate the penetration of this membrane attack complex (MAC), giving rise to the formation of channels that allow the free exchange of sodium and water with the outside of the cell, causing the consequent  osmotic lysis (cytolysis)of the attacked cell, since C9 is structurally homologous to perforin, a protein released by cytotoxic T lymphocytes and NK cells, and which is also responsible for the formation of pores in the membrane of the target cells.

Hiii!! I believe the answer is False. The temperature of an object is a measure of the average kinetic energy of the particles in an object. ((:

a transform fault or transform boundary is a fault along a plate boundary where the motion is predominantly horizontal. it ends abruptly where it connects to another plate boundary, either another transform, a spreading ridge, or a subduction zone.

Answer:

The correct answer is -

The phenotype of offspring (first cross or F1): 100% tall

The genotype of offspring (first cross or F1 - 100% Tt or heterozygous)

The phenotype of offspring in F2 (F1 × F1) - 3:1 (3 tall: 1 dwarf)

The genotype of offspring in F2 (F1 × F1) - 1:2:1 (One dominant tall: two heterozygous tall: one dwarf)

Explanation:

In this experiment of Mendel, Mendel selected the pea plant as it has various characters, short life span, and easy to breed. For this, he used two true breed lines, tall plants that had dominant allele TT and dwarf plant tt (recessive). In presence of the dominant allele, recessive alleles do not show their characteristics and only express if both alleles are recessive.

In the first cross of TT and tt

Gametes: T and t

offspring: Tt

the offsprings are all tall and heterozygous which means one dominant and one recessive allele.

second cross or F1 × F1

Tt × Tt

gametes: T, t and T, t

offspring: TT, Tt, Tt, tt

Thus,

The phenotype of offspring (first cross or F1): 100% tall

The genotype of offspring (first cross or F1 - 100% Tt or heterozygous)

The phenotype of offspring in F2 (F1 × F1) - 3:1 (3 tall: 1 dwarf)

The genotype of offspring in F2 (F1 × F1) - 1:2:1 (One dominant tall: two heterozygous tall: one dwarf)

Explanation:

The city's water supply shortage seems to be the result of a combination of physical, social, and political factors. Well below-average rainfall patterns, the increasing unpredictability of weather conditions due to anthropogenic climate change impacts, population growth, and government mismanagement have produced one of the worst urban water crises in recent memory.

here is the reason your explanation from the water shortage now just figure out what the factors are in your answers I would say it's naturally occurring drought conditions because it says on here well below average rainfall patterns and climate change

Water shortage can occur as a result of mismanagement practices by humans or as a result of natural occurrences such as droughts.

Water shortage refers to a situation in which there is not enough water to meet the daily water needs of the human, animal and plant population in a particular area.

The water shortage issue in Cape Town, South Africa could have been as a result of:

Therefore, water shortage can occur as a result of mismanagement practices by humans or as a result of natural occurrences such as droughts.

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Answer:

Explanation:

there is a positive side and a negitive side to magnets two of the same side of the magnet will repel oppisites will attract

positive+positive=repel

positive+negitive=atract

Answer:

attract: when two magnets will attract, S and N will be facing each other

repel: when two magnets will repel, S and S or N and N will face each other

both: when two magnets will attract and repel, the magnets won't be placed in the same way. N will be facing the middle of both S and N or S will be facing the middle of N and S

Explanation:

this is what i learned i hope it's right if not i didn't say nothing

Answer:

7

Explanation:

"Seven natural body openings or orifices providing access to an internal cavity through a natural passage called a canal, duct or meatus."

Answer:

caseous necrosis

Explanation:

The pathologic process that most likely occurred to this nodule would be caseous necrosis. This occurs at the time of death of a some cells but it is a very unique scenario in which the cell maintains a soft and white proteinaceous dead cell mass, just like in this scenario. This type of cell death usually occurs in lymph nodes but can occur in any cell in the body including in the lung.

Answer: In ecosystems, matter and energy are transferred from one form to another. Matter refers to all of the living and nonliving things in that environment. Nutrients and living matter are passed from producers to consumers, then broken down by decomposers. Decomposers break down dead plant and animal matter.

Explanation:

Answer:

According to Chargaff’s rule, the amount of adenine is always equal to that of thymine and the amount of guanine is always equal to that of cytosine. A = T(120), G = C(120) The total number of nucleotides would be 120 × 4 = 480.

I think yes, because from what i knew. When the DNA replicate, it will be same as the original/mother DNA. so it will both have radioactive DNA.

Just think, if only one DNA have radioactive then it wont be dangerous, but it affect the replication DNA, then its different case and will be dangerous for the body. You must've heard that radioactive can be dangerous for the body.

Sorry if im wrong

Answer:

I would say one..

Explanation:

It says the new strands take u non-radioactive bases.. if he only used the radioactive to label one of them then I would say one..

Explanation:

a. cell . . . . . . . .......

Answer:

cell

Explanation:

Answer/Explanation:

Recall:

Volume of a sphere = ⁴/3πr³

Surface Area = 4πr²

✔️For radius (r) = 1 mm:

Volume = ⁴/3 × π × 1³ = 4.19 mm³

Surface Area = 4 × π × 1² = 12.57 mm²

Ratio of volume to surface area = 4.19 : 12.57 = 1:3

✔️For radius (r) = 3 mm:

Volume = ⁴/3 × π × 3³ = 113.1 mm³

Surface Area = 4 × π × 3² = 113.1 mm²

Ratio of volume to surface area = 113.1 : 113.1 = 1:1