Mike has a certain amount of money and is given $25.25 more money. Anthony has three times the total that mike has plus $5.48 extra dollars. Their combined total is $261.23. Write an equation and solve it to determine how much each of them has.

Answers

Answer 1

Answer:

Mike has =$63.94

Anthony = $197.3

Step-by-step explanation:

Step one:

let the certain amount that Mike has be x

so

in all Mike has = (x+25.25)

Anthony has

3(x+25.25)+5.48

we are told that the total amount for both Mike and Anthony is

$261.23

so

(x+25.25)+3(x+25.25)+5.48=261.23

open bracket

x+25.25+3x+75.75+5.48=261.23

collect like terms

x+3x+25.25+75.75+5.48=261.23

4x+106.48=261.23

4x=261.23-106.48

4x=154.75

divide both sides by 4

x=154.75/4

x=38.69

Hence,in all

Mike has = (38.69+25.25)

Mike has =$63.94

Anthony has

=3(38.69+25.25)+5.48

=3(63.94)+5.48

=191.82+5.48

=$197.3


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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Hi there!

[tex]\large\boxed{x = \frac{24z}{(18 + yz)} }[/tex]

We can begin solving by creating a common denominator:

x · 3 · z = 3xz. This is the denominator that all of the numerators must have in order to work with the fractions.

Multiply each numerator by the missing parts of the common denominator:

[tex]\frac{8 * 3 * z}{3xz} - \frac{y * x * z}{3xz} = \frac{6 * 3 * x}{3xz}[/tex]

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[tex]\frac{24z}{3xz} - \frac{yxz}{3xz} = \frac{18x}{3xz}[/tex]

Move all the fractions involving x in the numerator to the right-hand side of the equation:

[tex]\frac{24z}{3xz} = \frac{18x}{3xz} + \frac{yxz}{3xz}[/tex]

Combine fractions:

[tex]\frac{24z}{3xz} = \frac{18x + yxz}{3xz}[/tex]

Multiply both sides by 3xz:

[tex]24z = 18x + yxz[/tex]

Factor out "x" from the terms on the right-hand side:

[tex]24z = x(18 + yz)[/tex]

Divide both sides by (18 + yz)

[tex]\frac{24z}{(18 + yz)} = x[/tex]

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