These periods are named as ones, thousands, lakhs, and so on. The one's period consists of the first three digits of the large number, starting from the right.
Everyone learns how to count numbers at a very young age starting from a single digit up to seven digits. This is done with the help of the place value system.
While writing large numbers, we always keep the place value system in mind to ensure that it is written correctly. According to the Indian place-value system, when a number is written in the standard form, each group of digits separated by a comma is called a period.
These periods are named as ones, thousands, lakhs, and so on. The one's period consists of the first three digits of the large number, starting from the right. The thousands period consists of the next two digits. The lakhs period consists of the next two digits and it continues.
Some other large numbers are read and written as follows:
1,000,000,000 = one billion
1,000,000,000,000 = one thousand billion
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Hannah can spend up to $40 on snacks and drinks at the movie theater. A snack costs $5 and a drink costs $3.50.
Use for the number of snacks
Use for the number of drinks
Which inequality represents this situation?
Answer:
5s + 3.50d < 40
Step-by-step explanation:
if you were to total up the costs of a snack and drink together you'll end up with $8.50
-multiply $8.50 until you reach $40 mark
i.e 8.50×2(means 2 of each item) = $17
8.50×3 = $25.5
8.50×4 = $34
8.50×5= $42.5
-if you look at it, the calculation for 5, the pricing is now over the budget therefore the answer is then 5s + 3.50d < 40 because she can only spend up to $34 at most
I really need help, I might get a grade detention
Answer:
Step-by-step explanatio
from up to down
12
30
10
In the segment below, QV = 23. QT =8. TR = RS = SV.
Answer: RS=5
QS=18
TS=10
TV=15
Step-by-step explanation:
QV = 23. QT =8. TR = RS = SV.
QV=QT+TR+RS+SV
23=8+RS+RS+RS
23=8+3*RS
3*RS=15
RS=5 ==> TR=5 and SV=5
QS=QT+TR+RS
QS=8+5+5
QS=18
TS=TR+RS
TS=5+5
TS=10
TV=TS+SV
TV=10+5
TV=15
Answer:
RS=5
QS=18
TS=10
TV=15
Step-by-step explanation:
The whole thing is 23. A part of it (QT) is 8 parts of that line as a whole. And if you subtract 8 from 23, that’s what’s left over for the rest of the parts to split amongst themselves. And if you read the question carefully, you’ll realize those last three parts are equal to eachother. Take that information, and after doing 23-8, you should get 15. Take that number and divide by the number of parts left over of the whole line. (Three leftover parts) divide 15 by 3 and that’s the length of each of those parts. From there we just label those parts and add what goes together to get our answers.
For RS: the length of R to S we already know since we just did the math for that. It’s 5.
For QS: from Q to S we have a few parts, but since they should be labeled, this should be easy because it’s just adding! (8+5+5=18)
For TS: since both parts are worth 5, no complicated math needed, just add 5+5 to get the answer, 10!
For TV: we know all parts are worth 5, so again, easy adding and you get! 15!
Congruence: Mastery Test
4
Select the correct answer.
pair 1
pair 3
Which pairs of polygons are congruent?
OA pairs 1, 2, and 3
OB. pairs 1, 2, 3, and 4
OC. pairs 2 and 3
OD. pairs 1 and 3
ANYONE GOT THE AWNSERRRRR???
From the given polygons, the pairs of polygons that are congruent are D. pairs 1 and 3.
What are congruent polygons?When two or more polygons are said to be congruent, it means that they have the same shape and that the lengths of their sides are the same.
The orientation of the shape is irrelevant if the above requirements are met.
The pair of polygons in Pair 1 are congruent because they have the same shape and are the same length. The same is true of the polygons in pair 3.
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Suppose that 24 inches of wire costs 72 cents. At the same rate, how much (in cents) will 49 inches of wire cost?
Answer:
147 cents
Step-by-step explanation:
If 24 inches of wire cost 72 cents then each inch cost 3 cents. 49*3=147
Marshall pours 1/2 gallon of lemonade into 8 glasses. He pours the same amount of lemonade into each glass. How much lemonade, in gallons, does Marshall pour into each glass?
Find the p-value for a left tailed hypothesis test with a test statistic of z = - 1.81. decide whetehr to reject
According to the given data The value of p is[tex]0.0351<0.1[/tex](alpha) so reject H₀
What does it mean to have a left-tailed hypothesis?A left-tailed test is used when the alternative hypothesis claims that the true value of the parameter suggested by the null hypothesis is lower than the null hypothesis implies. If the sample being tested is within the one-sided critical zone, the alternative hypothesis will be accepted rather than the null hypothesis.
Financial analysts employ the one-tailed test to confirm an investment or portfolio hypothesis.
If our statistical analysis finds that the significance level is smaller than the set cut-off value, we reject the null hypothesis and accept the alternative hypothesis (for example, either 0.05 or 0.01).
z = -1.81alpha
= 0.1p [tex]( z < -1.81 )p ( z < -1.81 )[/tex]
= 0.0351 ( from z table )P <
alpha, reject H₀
When the p-value is less than or equal to alpha, hypothesis H0 is rejected;
however,
if the p-value is greater than alpha, hypothesis H0 is not rejected.
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find the LCM of 2 and 3
Answer:
6
Step-by-step explanation:
If you multiply both together once that will be the lowest it gets
Answer: 6
Step-by-step explanation: compare the multiplication tables ig
In the segment below, QV = 23. QT = 8. TR = RS = SV.
Answer:
Step-by-step explanation:
Question 2 (Essay Worth 10 points)
(03.03)
How does the graph of f(x) = (x + 2)4 + 6 compare to the parent function g(x) = x4?
Is this how you solve this (finding the inverse)
There are a couple ways to go about this.
By definition of inverse function, if [tex]j^{-1}[/tex] exists, then
[tex]j\left(j^{-1}(x)\right) = x[/tex]
All this means is that if you provide some input [tex]x[/tex], plug it into [tex]j^{-1}(x)[/tex], then plug that into [tex]j(x)[/tex], you end up recovering the original input [tex]x[/tex] that you started with.
We can also do this in the opposite direction, so
[tex]j^{-1}(j(x)) = x[/tex]
So now if [tex]j(x)[/tex] is invertible, then
[tex]j(x) = -\dfrac23 x - 9 \implies j\left(j^{-1}(x)\right) = -\dfrac23 j^{-1}(x) - 9 = x[/tex]
Solve for [tex]j^{-1}[/tex].
[tex]-\dfrac23 j^{-1}(x) - 9 = x[/tex]
[tex]\dfrac23 j^{-1}(x) = -x - 9[/tex]
[tex]j^{-1}(x) = -\dfrac32 (x+9)[/tex]
[tex]\boxed{j^{-1}(x) = -\dfrac32 x - \dfrac{27}2}[/tex]
Another way to do it is by algebraically substituting [tex]x[/tex] within the definition of [tex]j(x)[/tex]
Starting with the given definition
[tex]j(x) = -\dfrac23 x - 9[/tex]
we replace [tex]x[/tex] with some new expression in a new variable [tex]y[/tex] that makes the right side reduce to just [tex]y[/tex]. To demonstrate, if we multiply [tex]-\frac23 x[/tex] by [tex]-\frac32[/tex], we end up with a coefficient of 1. So let [tex]x=-\frac32 y[/tex]. Then
[tex]j\left(-\dfrac32 y\right) = -\dfrac23 \left(-\dfrac32 y\right) - 9 = y - 9[/tex]
As you can see, this doesn't completely reduce to [tex]y[/tex], so we're not done. To adjust for this, we just add 9 to [tex]y[/tex], so our ultimate substitution is [tex]x=-\frac32(y+9)[/tex]. Then
[tex]j\left(-\dfrac32 (y+9)\right) = -\dfrac23 \left(-\dfrac32 (y+9)\right) - 9 = (y+9) - 9 = y[/tex]
Now applying [tex]j^{-1}[/tex] to both sides,
[tex]j^{-1}\left(j\left(-\dfrac32 (y+9)\right)\right) = j^{-1}(y)[/tex]
[tex]\implies \boxed{j^{-1}(y) = -\dfrac32 y - \dfrac{27}2}[/tex]
(we can freely swap out [tex]y[/tex] for [tex]x[/tex] at this point)
Yet another way, since the function here is quite simple, we can just think about the action of [tex]j[/tex] on a given number [tex]x[/tex] - multiply it by -2/3, and subtract 9.
[tex]x \mapsto -\dfrac23 x \mapsto -\dfrac23x - 9 = j(x)[/tex]
The inverse operation undoes this, so given some number [tex]j(x)[/tex], we recover [tex]x[/tex] by adding the additive inverse of -9, or 9, then multiplying the whole result by the multiplicative inverse of -2/3, or -3/2.
[tex]j(x) \mapsto j(x) + 9 \mapsto -\dfrac32(j(x) + 9) \mapsto -\dfrac32 j(x) - \dfrac{27}2 = x[/tex]
You seem to be using some version of this method. You made the mistake of thinking the "multiply by -3/2" step applies only to [tex]j(x)[/tex], and not [tex]j(x) + 9[/tex].
is |-10| greater than
|6|?
Answer:
Yes
Step-by-step explanation:
The value of |-10| is,
→ |-10| = 10
The value of |6| is,
→ |6| = 6
Now the greater value is,
→ 10 > 6
→ |-10| > |6|
Yeah, |-10| greater than |6|.
Answer:
No, it's not
Step-by-step explanation:
Hope it helps you
PLS RATE AS BRAINLIEST ANSWER
solve for t
(pls help me im struggling)
Step-by-step explanation:
Solve for what?.......
What is the remainder when 17^77 is divided by 35?
The remainder when 17^(77) is divided by 35 is 12
How can the remainder of dividing a large number be found?The number being divided = 17^(77)
The number by which 17^(77) is divided = 35
Using a graphing calculator as follows, we have;
Enter the value 17^(77) in the calculatorEnter the value 35 in the calculatorPress the divide by '÷' buttonUse the 'Display as proper fraction' button on the calculator, to display the result as proper fraction, [tex] a \frac{b}{c} [/tex]Use the left arrow button to move to the fraction part of the result displayed as proper fraction The remainder is the numerator of the fraction part of the proper fraction, which is 12[tex] \frac{17^{77}}{35} = V+ \frac{12}{35} [/tex]
Where V is a very large number quotient
From the above fraction, we have;
17⁷⁷ ÷ 35 = V + 12/35Expressing the above result using long division gives;
__V___ (Quotient)
35 (17⁷⁷)
____
12 (Remainder)
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How many digits are there in one period?
three digits hope this helped
Which expression is equivalent to (a^8)^4
Answer:
Brainliest pls
Step-by-step explanation:
a^32
simplify each expression 9(7k-2)+6k
Answer:
= 69k - 18
Step-by-step explanation:
9(7k-2) + 6k
= (9*7k + 9*-2) + 6k
= (63k - 18) + 6k
= 63k + 6k - 18
= 69k - 18
this is pain need help and to be explained
Answer:
Equation is 0.5 gal × (0.1) + x gal × (0.35) = (0.5 + x) × (0.15)
0.125 gallons of the 35% acid solution Eli should add.
Step-by-step explanation:
Given: Eli wants to combine 0.5 gallon of a 10% acid solution with some 35% acid solution to make a 15% acid solution.
To find: Equation can you use to determine how many gallons of the 35% acid solution Eli should add?
Solution:
Let x be the gallons of the 35% acid solution.
According to question,
For 0.5 gallon of a 10% acid solution = 0.5×0.1
For x gallon of a 35% acid solution = x×0.35
For (0.5+x) gallon of a 15% acid solution = 0.5 + x × 0.15
The equation form is
0.5 gal × (0.1) + x gal × (0.35) = (0.5+x) × (0.15)
Solving the above equation,
0.05 + 0.35x = 0.075 + 0.15x
0.2x = 0.025
x = 0.025/0.2
x= 0.125
Therefore, 0.125 gallons of the 35% acid solution Eli should add.
Therefore, 0.125 gallons of the 35% acid solution Eli should add.The equation is 0.5 gal × (0.1) + x gal × (0.35) = (0.5 + x) × (0.15)
PLS HELPPPPPP MEEE!!
What is the slope of line m?
Answer:-1/2
Step-by-step explanation:rise 1 run back 2
When working on homework, Jen spends 5 minutes reading for every 10 minutes spent on writing, Andy spends 2 minutes reading for every 5 minutes of writing, and Noor spends 10 minutes reading for every 15 minutes of writing.
When working on homework, Jen spends 5 minutes reading for every 10 minutes spent on writing, Andy spends 2 minutes reading for every 5 minutes of writing, and Noor spends 10 minutes reading for every 15 minutes of writing .
Many teachers and parents believe that homework helps students build study skills and review concepts learned in class. Others see homework as disruptive and unnecessary, leading to burnout and turning kids off to school. Decades of research show that the issue is more nuanced and complex than most people think: Homework is beneficial, but only to a degree. Students in high school gain the most, while younger kids benefit much less.
The National PTA and the National Education Association support the “10-minute homework guideline”—a nightly 10 minutes of homework per grade level. https://brainly.com/question/28529831 #SPJ9
What is the area, in square meters, of the Polygon?
16,608 square cm
2760 Square meters
2091.6 square inches
12,480 square inches
Answer:The answer would be the second one since he question is saying square meters.
Step-by-step explanation:Please give brainliest if right.
state the domain and range of the following function: {(-3,4),(0,6),(2,-2),(1,-3),(6,-7),(3,2)} domain: {-7,-3,-2,2,4,6} range: {-3,0,1,2,3,6} domain: {0,1,2,3,4,6} range: {-7,-3,-2} domain: {-3,0,1,2,3,6} range: {-7,-3,-2,2,4,6} domain: {-7,-3,-2} range: {0,1,2,3,4,6}
The domain and range of the given function are: domain: {-7,-3,-2,2,4,6} range: {-3,0,1,2,3,6}. (Option A).
What is domain and range?The terms Domain and Range describe the input values and the function's output values, respectively.In terms of coordinates, domain is the x-coordinate and range is the y-coordinate of a function.Now,
In the given function {(-3,4),(0,6),(2,-2),(1,-3),(6,-7),(3,2)},
the x- coordinates are: {-3, 0, 2, 1, 6, 3} and the y-coordinates are: {4, 6, -2, -3, -7, 2}.Thus, According to the definition of domain and range,
the domain is {-3, 0, 2, 1, 6, 3} and the range is {4, 6, -2, -3, -7, 2}.Hence, Option A is correct, i.e., the domain and range of the given function are: domain: {-7,-3,-2,2,4,6} range: {-3,0,1,2,3,6}.
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What percent is represented by the diagram below?
Alternative text
A. 13%
B. 65%
C. 130%
D. 650%
Answer:
I think it's will be C
Step-by-step explanation:
C I psomes
Answer: C 130%
Step-by-step explanation:
Jordan knits a square blanket that has an area of 1,500 square inches. What is the approximate length of each side of the blanket?
O 16 inches
O 27 inches
O 39 inches
O 42 inches
The highest elevation in the world is 29,029 feet and the lowest is -35,994 feet. What is
the difference between the two?
Answer:
Question: Mt. Everest, the highest elevation in Asia, is 29,028 feet above sea level. The Dead Sea, the lowest elevation, is 1,312 feet below sea level.
Hana has some blue paint. She wants to lighten the shade, so she mixes in 1 cup of white paint. The color is still too dark, so Hana keeps mixing in 1 cup of white paint at a time. After adding 4 cups, she decides the color is too light.
A. Explain in words how much paint Hana should have added initially to get the shade she wants.
Enter your answer.
B. Model With Mathematics Represent your answer to part A with one or more inequalities.
Enter your answer.
C. Hana decides that she likes the shades of blue that appear in between adding 1 cup and 4 cups of white paint. How can you represent the number of cups of white paint that yield the shades Hana prefers?
Enter your answer.
Answer:
e, so she mixes in 1 cup of white paint. The color is still too dark, so Hana keeps mixing in 1 cup of white paint at a time. After adding 4 cups, she decides the color is too light.
A. Explain in words how much paint Hana should have added initially to get the shade she wants.
Enter your answer.
B. Mod
Step-by-step explanation:
The diameter of a single strand of human hair varies depending on its color. The average diameter of a strand of
black hair is 2.4 x 10-3 inch. The average diameter of a strand of red hair is 0.001 inch. What is the difference, in
inches, in the diameters of a strand of black hair and a strand of red hair?
O
3.4 x 10-3
The diameters of a strand of black hair and a strand of red hair is found to be 1.4×10⁻³.
What is defined as the scientific notations?Scientific notation is a method of expressing extremely large or extremely small numbers.
When a quantity between 1 & 10 is multiplied by a power of 10, it is composed in scientific notation. 650,000,000, for example, can be composed in scientific notation as 6.5× 10⁸. The scientific notation system relies on powers of ten. The coefficient is the first number, 1.23.For the given question;
Diameter of the black hair is 2.4×10⁻³ inch.Diameter of the red hair is 0.001 inch.Convert the decimal value 0.001 in scientific notations;
= 0.001 inch
= 1×10⁻³ inch
Now, calculate the difference;
Difference in diameter = Black hair diameter - Red hair diameter
Difference in diameter = 2.4×10⁻³ - 1×10⁻³
Difference in diameter = 1.4×10⁻³
Therefore, the value of the difference in the diameter of red and black hair is found as 1.4×10⁻³.
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7. Rob wants to purchase a $5,000 drum set. The music store offers him a 2-year installment agreement requiring $800 down and monthly payments of $202.50. Rob has
a poor credit rating.
a. What is his interest on this installment agreement?
The interest on this installment agreement that Rob pays is $660.00
What the loan?In short, the loan is an amount that the bank or financial institution makes available to you for a certain period. Basically, every time you apply for credit, whether it's a loan or even a credit card, you're taking out a type of loan.
The amount borrowed to purchase the drum set is the cost price of $5000 minus the down payment of $800
amount borrowed=$5000-$800amount borrowed=$4,200total monthly payments= $202.50*24total monthly payments=$4,860.00 interest on this installment agreement=$4860-$4200 interest on this installment agreement=$660.00Find out more about loan on: brainly.com/question/2865739
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One diagonal of a rhombus is three times as long as the other diagonal. If the area of the rhombus is 54 square millimeters, what are the lengths of the diagonals?
Answer:
Assume one diagonal of 2x and other of x inches. and sides of length =L inches.
Area of rhombus = 2*2x*x/2=2x^2 = 81 x=9/sqrt.2 and 2x=9*sqrt 2.
Diagonals are x=6.365 inch 2x=12.73 inch check area =12.73*6.365= 81.026 sq.inch.
Step-by-step explanation:
Element X decays radioactively with a half life of 14 minutes. If there are 160 grams
of Element X, how long, to the nearest tenth of a minute, would it take the element to
decay to 11 grams?
loudy
y = a(.5)^t/h
[tex]\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\dotfill &11\\ P=\textit{initial amount}\dotfill &160\\ t=\textit{elapsed time}\\ h=\textit{half-life}\dotfill &14 \end{cases} \\\\\\ 11=160\left( \frac{1}{2} \right)^{\frac{t}{14}}\implies \cfrac{11}{160}=\left( \cfrac{1}{2} \right)^{\frac{t}{14}}\implies \log\left( \cfrac{11}{160} \right)=\log\left[ \left( \cfrac{1}{2} \right)^{\frac{t}{14}} \right][/tex]
[tex]\log\left( \cfrac{11}{160} \right)=\cfrac{t}{14}\log\left[ \left( \cfrac{1}{2} \right)\right]\implies \cfrac{\log\left( \frac{11}{160} \right)}{\log \left( \frac{1}{2} \right)}=\cfrac{t}{14} \\\\\\ 14\left( \cfrac{\log\left( \frac{11}{160} \right)}{\log \left( \frac{1}{2} \right)} \right)=t\implies {\LARGE \begin{array}{llll} \stackrel{mins}{54.1}\approx t \end{array}}[/tex]