Weathering is the process by which rocks break down in place to produce soils and sediments.
The breakdown or dissolving of rocks and minerals on the earth's surface is known as weathering. Carrier of weathering include water, ice, acids, plants, animals and variations in temperature.
Erosion is the movement of soil, rock, or dissolved material from one region of the earth's crust to another, where it is deposited. Weathering, which is a static process, is distinct from erosion.
Rocks break down by the process called weathering. The effect of weathering and erosion cannot be resisted by any rock on Earth due to its softness.
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The diagram below shows a 4.0-kilogram object accelerating
at 10. meters per second2 on a rough horizontal surface.
Acceleration = 10. m/s²
Frictional
force=F₁
m = 4.0 kg
O. 5.0N
Ob
10. N
Of 20.N
04 40.N
Applied
force = 50. N
(Not drawn to scale)
What is the magnitude of the frictional force Fr acting on
the object?
The magnitude of the frictional force Fr acting on the object is 10 N.
option B.
What is the magnitude of the frictional force?
The magnitude of the frictional force Fr acting on the object is calculated by applying the following formula.
F - Fr = ma
where;
Fr is the frictional forceF is the applied forcem is the mass of the objecta is the acceleration of the object50 N - Fr = 4 kg x 10 m/s²
50 N - Fr = 40 N
Fr = 50 N - 40 N
Fr = 10 N
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a softball is thrown off of a building that is 80 meters high at a velocity of 10 meters per second. its height, in meters, after t seconds is
When a softball is thrown from an 80-meter-high building at a velocity of 10 meters per second, the height after t seconds is 148 feet.
What is velocity?Velocity is a vector representation of an object's or particle's displacement with respect to time. The meter per second (m/s) is the standard unit of velocity magnitude (also known as speed). Alternatively, velocity magnitude can be expressed in centimeters per second (cm/s). The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change. Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number.
Here,
The maximum height the ball will reach is the vertex of the parabola s(t)=48+80t-16t2. first, we need to solve for t. The vertex of any parabola of the form f(x)=ax2+bx+c is found by using x=-b/2a. In this case, x=t, b=80 and a=-16. Substituting we get:
]t=-80/((2)(-16)--->t=-80/-32--->t=5/2
Putting this value of t in the original formula will give us the maximum height:
s(t)=48+80t-16t2
s(5/2)=48+80(5/2)-16(5/2)2
s(5/2)=48+200-16(25/4)
s(5/2)=248-100
smax=148 feet
It's height, in meters, after t seconds is 148 feet when softball is thrown off of a building that is 80 meters high at a velocity of 10 meters per second.
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in an experiment, students use a force sensor to apply a force of magnitude to an object of mass that is initially at rest. the force is exerted in the -direction for a time . the impulse exerted on the device is . which of following procedure changes would result in an impulse being exerted on an object? A Exert a force of magnitude on an object of mass m for a time t T. B Exert a force of magnitude on an object of mass 2m for a time t = 2T. 2 Exert a force of magnitude F on an object of mass 2m for a time t = 2T. D Exert a force of magnitude 2F on an object of mass m for a time t = 2T. E Exert a force of magnitude 2F on an object of mass m for a time t = .
Option D: Apply a force of magnitude 2F for a period of time t=2T to a mass m object. The impulse will rise as the force, the passage of time, or the object's mass increase.
The force times the length of time that the force is applied to an item results in the impulse. For a force to impose an impulse on an item, both the force applied and the time period during which it is applied must be non-zero. The scenario in which a force of magnitude 2F is applied to an item of mass m over a period of time t = 2T results in option D being the right response. This is so that, since the impulse is computed as the product of force and time, the impulse will not change if the force and time are both doubled. Alternatives like A, B, and C wouldn't cause an impulse to be applied to an object.
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Three charged particles are placed at each of three corners of an equilateral triangle whose sides are of length 3.1cm . Two of the particles have a negative charge: q1 = -8.4nC and q2 = -16.8nC . The remaining particle has a positive charge, q3 = 8.0nC . What is the net electric force acting on particle 3 due to particle 1 and particle 2?
1. Find the net force ?F? 3 acting on particle 3 due to the presence of the other two particles. Report you answer as a magnitude ?F3 and a direction ? measured from the positive x axis. Express the magnitude in newtons and the direction in degrees to three significant figures
2. Assume that particle 3 is no longer fixed to a corner of the triangle and is now allowed to move. In whatdirection would particle 3 move the instant after being released? Draw the velocity vector for particle 3 below. The orientation of your vector will be graded, but not its length
1. The net force is 79.1°
The angle between those two forces is 120 degrees (because the triangle is equilateral) so the net force on particle 3 is the vector sum of the two forces.
The direction of the force on particle 3 due to particle 1 is along the line joining particles 1 and 3. The direction of the force on particle 3 due to particle 2 is along the line joining particles 2 and 3.
To find the net electric force acting on particle 3 due to particles 1 and 2, we can use Coulomb's law, which states that the force between two point charges is given by the equation:
[tex]F = k * (q1 * q2) / r^2[/tex]
where F is the force, k is the Coulomb constant [tex](8.99 x 10^9 N * m^2/C^2)[/tex], q1 and q2 are the charges of the two particles, and r is the distance between the two particles.
In this case, we have three particles placed at the corners of an equilateral triangle, with a side length of 3.1 cm. Since the triangle is equilateral, all three sides are equal in length, so r1 = r2 = 3.1 cm
The net force on particle 3 is the vector sum of the two forces acting on it due to particles 1 and 2.
F3 = F31 + F32 where F31 is the force on particle 3 due to particle 1 and F32 is the force on particle 3 due to particle 2
[tex]F31 = k * (q3 * q1) / r1^2[/tex]
[tex]F32 = k * (q3 * q2) / r2^2[/tex]
[tex]F31 = 8.99 x 10^9 N * m^2/C^2 * (8.0 nC * -8.4 nC) / (3.1 cm)^2[/tex]
[tex]F32 = 8.99 x 10^9 N * m^2/C^2 * (8.0 nC * -16.8 nC) / (3.1 cm)^2[/tex]
[tex]F31 = -9.52 * 10^{-4 N}[/tex]
[tex]F32 = -1.93 * 10^{-3 N}[/tex]
[tex]F3 = F31 + F32 = -2.88 * 10^{-3 N}[/tex]
After solving, The net force = 79.1°
The direction of the force on particle 3 due to particle 1 is along the line joining particles 1 and 3. The direction of the force on particle 3 due to particle 2 is along the line joining particles 2 and 3.
The angle between those two forces is 120 degrees (because the triangle is equilateral) so the net force on particle 3 is the vector sum of the two forces
2. Particle 3 will move in the direction of the net force acting on it, which is the vector sum of the two forces acting on it due to particles 1 and 2.
Since the net force is [tex]-2.88 * 10^{-3 N}[/tex], and the angle between the direction of the forces on particle 3 due to particles 1 and 2 is 120 degrees, particle 3 will move in the direction of the angle bisector of the angle between those two forces.
The angle bisector of 120 degrees is 60 degrees, thus the net force is acting on particle 3 at 60 degrees with respect to the positive x-axis.
The instant after being released, particle 3 will move in the direction of the net force vector and it will have a velocity vector pointing in the same direction as the net force.
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Sally, Max, and William are on a camping trip in the forest. They are riding their bikes through the forest and come across a clearing. In the clearing, there are several trees and a small plane. Sally is curious about the physics of the plane, so she asks Max and William to help her measure the distance from the plane to the nearest tree. They use a measuring tape to find that the distance is 60 meters. They also measure the height of the plane to be 10 meters and the height of the tree to be 20 meters. Using the principles of physics, they calculate the angle at which the plane is flying relative to the tree. What is the angle?
Answer: The angle at which the plane is flying relative to the tree is 19.47 degrees.
Explanation:
To calculate the angle at which the plane is flying relative to the tree, we can use the principle of trigonometry and the Pythagorean theorem. Since we know the distance from the plane to the nearest tree (60 meters), the height of the plane (10 meters), and the height of the tree (20 meters), we can use these measurements to form a right triangle with the plane, the tree, and the ground.
Using the Pythagorean theorem, we can calculate the length of the hypotenuse of the right triangle. The length of the hypotenuse is the distance between the plane and the top of the tree. The hypotenuse is calculated by the square root of (distance^2 + height of the plane^2 + height of the tree^2)
The angle we are trying to calculate is opposite to the height of the tree, therefore we can use the tangent function:
tan(angle) = opposite/adjacent
opposite = height of the tree = 20m
adjacent = distance = 60m
angle = arctan(20/60) = arctan(1/3) = 19.47122063449069 degrees
The angle at which the plane is flying relative to the tree is 19.47 degrees.
the support bearings at a and b allow free turning of the shaft. (figure 1) figure1 of 1 part a determine the resultant internal torque acting on the cross section at points c and d . enter your answers in newton-meters to three significant figures separated by a comma.
The internal torque acting at point C is 800 lb-ft clockwise, and at point D is 1500 ft-lb anti-clockwise.
The shaft is bearing at a and b. As the shaft is at rest and not rotating in any direction. So the internal torque must be balancing the external torques acting on the shaft. Near the bearing A, the the external torque acting on the shaft is 1500 lb-ft clockwise, so at point D there must be an anti-clockwise torque. So the torque acting on the D is 1500 ft-lb.
Similarly, near the bearing B the external torque acting on the shaft is 800 lb-ft anti-clockwise, so there must be an equal and external clockwise torque working on point C to balance the 800 anti-clockwise torque. So the internal torque working on point C is 800 lb-ft.
--The given question is incomplete, the complete question is:
"the support bearings at a and b allow free turning of the shaft. (figure 1) figure1 of 1 part a determine the resultant internal torque acting on the cross section at points c and d . enter your answers in newton-meters to three significant figures separated by a comma."
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fill in the blank.the internal revenue service threatens chloe with a penalty if she fails to pay her back taxes. she pays, and the threat is withdrawn. in the future, she is more prompt in meeting her obligation. this is an example of the use of___to control behavior. group of answer choices
When a person or business avoids paying their tax responsibilities, it is a criminal violation that entails fines and penalties.
What do "tax avoidance" or "tax evasion" mean?If Chloe doesn't pay her overdue taxes, then Internal Revenue Service will impose penalties. The threat is removed after she makes a payment. Now, she will finish her work more swiftly. This illustrates the application of behavior control.
What is the name for legitimate tax avoidance?On the contrary hand, tax avoidance is entirely legal. Qualified taxpayers may claim a variety of deductions, credits, or income adjustments in accordance with IRS regulations. For instance, some homeowners are permitted to write off the interest they pay off their mortgage.
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Figure 9-53 shows an approximate plot of force magnitude F versus time t during the collision of a 58g Superball with a wall. The initial velocity of the ball is 34m/s perpendicular to the wall; the ball rebounds directly back with approximately the same speed, also perpendicular to the wall. What is F max,the maximum magnitude of the force on the ball from the wall during the collision?
The force applied by the ball on the wall is 3.994 Newton, if the mass of the ball is 58 gm, and initial velocity is 34 m/s.
Mass of the ball, m = 58 gm = 0.058 kg
Initial velocity of the ball, u = +34 m/s
Time of the applied force, t = 1 sec
Final velocity of the ball, after collision, v = -34 m/s [negative: as the direction is opposite]
Let the force applied by the ball on the wall is F. We know the rate of change of momentum of an object is equal to the force applied by the object. So,
F = (m₁v₁ - m₂v₂)/t
F = (0.058 × 34 - 0.058(-34))
F = 3.944 N
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Which of the following solutions contains the smallest total concentration of ions, assuming complete dissociation?
a) 2 M AI2(SO4)3
b) 2 M AICl3
c) 2 M NaCl
d) 2 M CaCl2
The solution with the lowest total ion concentration, assuming full dissociation, is 2 M aluminum sulphate.
What is concentration?Concentration in chemistry is defined as the abundance of an ingredient divided by the total volume of a combination. There are four sorts of mathematical descriptions: mass concentration, molar concentration, number concentration, and volume concentration. The amount of a material, such as salt, that is present in a certain amount of tissue or liquid, such as blood. When there is less water present, a material becomes more concentrated. When a person does not drink enough water, the salt in his or her urine may become more concentrated. A substance's concentration is the amount of solute contained in a given amount of solution. Molarity is the number of moles of solute in one liter of solution and is used to express concentrations.
Here,
The solution with the lowest total ion concentration, assuming full dissociation, is 2 M aluminum sulfate.
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the emotional atmoshere is very controlled and restricted for mom,jaja, and kambili due to how extremely controlling eugene, the father is. due to papas ways the children do not ever speak up, never laugh , never live a true childhood and never smile. they are also never allowed to fail or be themselves. papa is so strict because he did not have much in his own childhood and want his kids to not take what they are given for granted. he also is this way he justifies everything out of the bible and almost views himself as a god.
Due to Eugene's intense control, the emotional environment for mom, jaja, and kambili is very confined and controlled.
The children never laugh, speak up, truly experience childhood, or grin as a result of Papa's ways. Additionally, they are never permitted to make mistakes or be themselves. Papa is very severe because he did not have a lot growing up and wants his children to appreciate what they have. He is this way also because he virtually sees himself as a god and uses the bible to justify everything.
Eugene, the father, is incredibly controlling, which restricts and controls the emotional atmosphere for mom, jaja, and kambili. Due to papa's ways, the kids never speak up, laugh, or truly experience childhood. They also never smile. They're never let to make mistakes or be themselves, either. Papa is very severe because he did not have a lot growing up and wants his children to appreciate what they have. He too thinks this way; he uses the Bible to support all he does and almost considers himself to be divine.
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an olympic track runner starts from rest and has an acceleration of 1.6 m/s2 for 3.7 s, then has zero acceleration for the remainder of the race. find the runner's speed at the following times. (a) at time t = 1.3 s
m/s
(b) the end of the race
m/s
When an Olympic track runner begins at rest and has an acceleration of 1.6 m/s2 for 3.7 seconds, then has zero acceleration for the remainder of the race, the runner's speed at time t is 2.08 m/s.
What is velocity?Velocity is a vector representation of an object's or particle's displacement with respect to time. The meter per second (m/s) is the standard unit of velocity magnitude (also known as speed). Alternatively, velocity magnitude can be expressed in centimeters per second (cm/s). The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change. Speed is the pace at which an item moves along a route in time, whereas velocity is the rate and direction of movement. In other words, velocity is a vector, whereas speed is a scalar number.
Here,
put the values of Vi, a and t in first equation of motion
Vf = Vi + a×t
Vf = 0 + 1.6×1.3
Vf = 2.08 m/s
The runner's speed at time t as 1.3 seconds is 2.08 m/s when Olympic track runner starts from rest and has an acceleration of 1.6 m/s2 for 3.7 s, then has zero acceleration for the remainder of the race.
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the change in velocity between location d and location f: select an option unanswered the change in momentum between location d and location f: select an option unanswered the average net force between location
The change in the momentum is equal to the product of the mass and the change in the velocity.
what is change in momentum?
The change in momentum (Δp ) is defined as the change in the product of an object's mass and velocity. A force is required to change the momentum of an object. This applied force can increase or decrease the momentum or even change the object's direction.The change in momentum = m × (v – u). Here a = [(v - u)t ] is the acceleration, which is the rate of change of velocity. The quantity, k is a constant of proportionality. The SI units of mass and acceleration are kg and m s-2 respectively.Δ p = F net Δ t . F net Δ t F net Δ t is known as impulse and this equation is known as the impulse-momentum theorem. From the equation, we see that the impulse equals the average net external force multiplied by the time this force acts. It is equal to the change in momentum.To learn more about momentum refers to:
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at which of the following air temperatures will the speed of a sound wave be closest to 1,0001,0001, comma, 000 feet per second?
The speed of a sound wave will be closest to 1,000 feet per second at an air temperature of 0°C (32°F).
What is sound wave?Sound waves are waves of energy that travel through air, water, or other materials as vibrations. Sound waves form when an object vibrates in a medium like air.
The speed of sound in air is approximately 1,116 feet per second at sea level and decreases with increasing altitude. At an air temperature of 0°C (32°F), the speed of sound is about 1,010 feet per second.
Therefore, the speed of a sound wave will be closest to 1,000 feet per second at an air temperature of 0°C (32°F).
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Please answer the question.
The angle θ between P and Q vector is 18.43°.
What is vector quantity?In physics, a vector is a quantity that has both magnitude and direction. It is typically represented by an arrow with the same direction as the quantity and a length proportional to the magnitude of the quantity.
A vector, while having magnitude and direction, does not have position. A vector quantity is any physical quantity that has both directions and magnitude.
According to given parameters:
PQ sinθ = (1/3) PQ cosθ
tanθ = 1/3
θ = 18.43°
Hence, the angle θ between P and Q vector is 18.43°
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what is most nearly the force (in kips) in member cd in the truss shown, where tension is positive and compression is negative?
If the value is positive, the member is in tension; otherwise, the member is in compression if the value is negative.
What is force?A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction. The term "force" has a specific meaning in science. At this level, it is perfectly acceptable to refer to a force as a push or a pull. A force is not something that an object possesses or possesses. Another object applies a force to another. The concept of a force is not restricted to living or non-living things.
Here,
If the value is positive, the member is in tension; if it is negative, the member is in compression.
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A 3.0 g spider is dangling at the end of a silk thread. You can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every second. What is the spring constant of the silk thread?
The spring constant can be obtained as 0.12.
What is the spring constant?We know that in the question, we have been told that A 3.0 g spider is dangling at the end of a silk thread. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every second.
Thus using;
T = 2π√m/k
m = mass of the spider
k = spring constant
T = time in seconds
Then;
1 = 2 * 3.142√3 * 10^-3/K
1/2 * 3.142 = √3 * 10^-3/K
(1/2 * 3.142 )^2 = 3 * 10^-3/K
K = 3 * 10^-3/(1/2 * 3.142 )^2
K = 0.12
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If you could drive a Jetson's flying car at a constant speed of 160km/hr (100 mi/hr) across oceans and space, approximately how long would it take to drive to the nearest star, Alpha Centauri (4.4 light-years away)?
If you could drive a Jetson's flying car at a constant speed of 160km/hr (100 mi/hr) across oceans and space, approximately how long would it take to drive around Earth's equator?
If one could drive a Jetson's flying car at a constant speed of 160km/hr (100 mi/hr), the time it will take to drive around the Earth's equator is 250.47hours.
How to calculate time?The time it will take to cover a certain distance can be calculated using the following formula;
Speed = distance ÷ time
According to this question, one could drive a Jetson's flying car at a constant speed of 160km/hr (100 mi/hr) across oceans and space. The distance around Earth at the Equator, its circumference, is 40,075 kilometers (24,901 miles).
Time = Distance ÷ speed
Time = 40,075km ÷ 160km/hr
Time = 250.47hours
Therefore, 250.47hours is the time it will take to cover around the Earth's equator.
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(UPDATED) Please answer the following questions requested bellow ↓ (SIXTH PAGE)
≈≡ EACH QUESTION IS 5 POINTS WHICH IS 30 POINTS IN TOTAL ≡≈
**( + An extra 10 points)**
**Check previous question for other five pages Thank You**
During Stanford University's "Search for Isolated Fractionally Charged Particles," more than 100 million more oil droplets were measured, hence option A is correct.
What is the search for fractionally charged particles?Theoretically, every charge must be a multiple of the charge of an elementary particle or an electron.
Similar automated equipment to that of Millikan and Fletcher was employed. No droplet with a fractional charge was discovered.
Therefore, even if the quantity used today for the elementary charge differs slightly from what Millikan and Fletcher measured, it is generally agreed that all charge is made up of multiples of the elementary charge.
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which of the following correctly describes the meridian in your sky? group of answer choices the boundary between the portion of the celestial sphere you can see at any moment and the portion that you cannot see a half-circle extending from your horizon due north, through your zenith, to your horizon due south a half-circle extending from your horizon due east, through your zenith, to your horizon due west a half-circle extending from your horizon due east, through the north celestial pole, to your horizon due west the point directly over your head
The celestial meridian is a hypothetical line that passes through the NCP, the zenith, the north point on the horizon, and the south point on the horizon before ending at the south point.
What point in your sky is the Meridian?The zenith is the point immediately overhead, and the meridian is a fictitious half-circle running from the horizon's due south to its due north, passing through the zenith. The direction along the horizon and the height above the horizon of any object in the nearby sky can be used to identify it.The celestial meridian is a hypothetical line that passes through the NCP, the zenith, the north point on the horizon, and the south point on the horizon before ending at the south point. A western and an eastern half of the sky are separated by it.To learn more about celestial meridian refer to:
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a reactor operates at a power of 103 mw(t) for 1 year. calculate the power from decay heat a. 1 day following shutdown, b. 1 month following shutdown, c. 1 year following shutdown.
So the heat dacy can be calculated using the winger way formula
In one day ,[tex]P_{d}(t)=\\[/tex][tex]6.65\times 10^{-3}[/tex] GW(t), In one month =[tex]P_{d}(t)=\\[/tex][tex]1.946\times 10^{-3}[/tex] GW(t) , in one year , [tex]P_{d}(t)=\\[/tex][tex]2.29\times 10^{-4}[/tex] GW(t)
According to thermodynamics, heat is a type of energy that crosses a thermodynamic systems' boundary due to a temperature differential across the barrier Heat is absent in thermodynamic systems. However, the expression is also regularly used to describe the thermal energy that constitutes a system's internal energy and is reflected in the system's temperature. In all senses of the word, energy is a form of heat.
For the decay we have winger way formula as ,
[tex]P_{d} =0.0622P_{0}[t-0.2-(t_{0}-0.2(t_{0}+t)-0.2][/tex]
[tex]P_{0}=1.5GW(t)[/tex],[tex]t_{0}=31,536,000[/tex]
[tex]P_{d}(t)=\\[/tex]thermal power generation due to beta and gamma rays
[tex]t_{0}=[/tex]time in seconds , of thermal power level before shut down
t= rime , in seconds elapsed since the shutdown
a) In one day ,
Number of seconds ,t=86400s
so , P
[tex]P_{d}(t)=\\[/tex]0.0622 x 1.5 x [86,400-0.2-(31,536,000+86,400)-0.2]
[tex]P_{d}(t)=\\[/tex][tex]6.65\times 10^{-3}[/tex] GW(t)
b ) In one month
Number of seconds ,t=2629800s
[tex]P_{d}(t)=\\[/tex]0.0622 x 1.5 x [2629800-0.2-(31,536,000+2629800)-0.2]
[tex]P_{d}(t)=\\[/tex][tex]1.946\times 10^{-3}[/tex] GW(t)
c) In one year
Number of seconds ,t=2629800s
[tex]P_{d}(t)=\\[/tex]0.0622 x 1.5 x [31,536,000-0.2-(15,768,000+31,536,000)-0.2]
[tex]P_{d}(t)=\\[/tex][tex]2.29\times 10^{-4}[/tex] GW(t)
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Water flows through a pipe as shown in the figure. The pressure at points 1 and 2 respectively is 1.85 x 10ª Pa and 1.20 x105 Pa. The
radius of the pipe at points 1 and 2 respectively is 3.30 cm and 1.40 cm. If the vertical distance between points 1 and 2 is 2.75 m, determine
the following.
(1) The total pressure of the pipe at point 1 is 1.85 x 10⁵ Pa.
(2) The total pressure of the pipe at point 2 is 146,950 Pa.
What is the total pressure at position 1 and 2?
The total pressure at position 1 and 2 is calculated by applying Bernoulli's equation as shown below.
P (t) = P₀ + ρgh
where;
P₀ is the gauge pressureρ is the density of waterg is acceleration due to gravityh is the height of the pipeThe total pressure of the pipe at point 1 is calculated as follows;
P (t) = ( 1.85 x 10⁵ ) + ( 1000 x 9.8 x 0 )
P (t) = 1.85 x 10⁵ Pa
The total pressure of the pipe at point 2 is calculated as follows;
P (t) = ( 1.2 x 10⁵ ) + ( 1000 x 9.8 x 2.75 )
P (t) = 146,950 Pa
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The complete question is below:
Water flows through a pipe as shown in the figure. The pressure at points 1 and 2 respectively is 1.85 x 10ª Pa and 1.20 x105 Pa. The
radius of the pipe at points 1 and 2 respectively is 3.30 cm and 1.40 cm. If the vertical distance between points 1 and 2 is 2.75 m, determine
the following.
(1) the total pressure at point 1
(2) the total pressure at point 2
the mass of a glacier____when the accumulation of snow and ice during the winter months is larger than ice melt during summer months. fill in the blank with the best word choice from the list below.
When the accumulation of snow and ice during the winter months exceeds the ice melt during the summer months, the mass of a glacier increases.
How the mass of glacier increases?As summer temperatures rise, the higher glaciers melt to provide water later in the season.If the rate of melting across the glacier increases, the glacier will have a negative mass balance and shrink. If the glacier receives more snow or ice but the amount of melt remains constant, the glacier will expand.Glaciers gain and lose mass due to snowfall and melting and sublimation (when water evaporates directly from solid ice). Glaciers that end in a lake or the ocean lose mass due to iceberg calving.Increased marginal ablation (largely a function of summer temperature for land-based glaciers) overwhelms the mass supplied during climate warming, forcing a glacier margin to retreat.The complete question:
"the mass of a glacier ____ when the accumulation of snow and ice during the winter months is larger than ice melt during summer months. fill in the blank with the best word choice from the list below.
a. increases
b. decreases."
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If someone tells a friend that it is 75 degrees outside, that number represents the
Answer:
Temperature
Explanation:
Commonly when speaking about the temperature outside we will refer to it as --degrees Fahrenheit or Celsius. So if I were to tell my friend that it is currently 68 degrees outside, that would mean that the current temperature is 68 degrees Fahrenheit or Celsius outside.
-Hope this helped
which of the following can be used to organize large volumes of data into meaningful patterns and summaries?
Data mining can be used to organize large volumes of data into meaningful patterns and summaries.
Large data sets are sorted through in data mining in order to find patterns and relationships that may be used in data analysis to assist solve business challenges. Enterprises can forecast future trends and make more educated business decisions thanks to data mining techniques and technologies.
Data mining is a crucial component of data analytics as a whole and one of the fundamental fields in data science, which makes use of cutting-edge analytics methods to unearth valuable information in data sets. Data mining, at a more detailed level, is a step in the knowledge discovery in databases (KDD) procedure, a data science approach for obtaining, processing, and evaluating data. Although they are often used interchangeably, data mining and KDD are more frequently understood to be separate concepts.
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A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. IT starts from rest and is pulled up a mine shaft by a cable connected to a winch. The shaft is inclined at 30.0o above the horizontal The car accelerates uniformly to a speed of 2.20 m/s in 12.0 s and then continues at constant speed. What power must the winch motor provides when the car is moving at constant speed?
10.628 kW of power must the winch motor provides when the car is moving at constant speed at the slope of 30.0o at a speed of 2.20m/s for 12 s to keep of moving.
The maximum Force, with the maximum speed of the motor, gives maximum power Now we know
a = (vf-vi)/t = (2.20 - 0)/12 => 0.1853 m/s^2
The maximum force is when the car is accelerating so,
f = fa+fg
F = ma+ ma * sign 30o => 4831.035 N ( As shown in the Image attached how the perpendicular vector that is a signθ is taken)
So the force will be 4831.035 N
Hence the maximum power p = fxV
4831.035 * 2.20
P =10626.27 w
which results in 10626.27/1000 kW
So 10.628 Kw is the maximum power required for the slop of 30o.
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Model rocket engines are rated by their thrust force and by the impulse they provide. You can use this information to determine the time interval at which the engines fire. Two rockel engines provide the same impulse. The first engine provides 6 N of thrust for 2 s; the second provides 4 N of thrust. For how long does this second engine fire? A. 1 s B. 2 s C. 3 s D. 4 s
The answer is B. 2 s. The impulse provided by both engines is the same, so they must fire for the same amount of time in order to provide that amount of impulse.
What is engines?Engines are devices that convert energy into mechanical force, usually to power machines and vehicles. Engines come in a variety of forms and sizes, but all are based on the same basic principles of converting thermal energy into mechanical force via combustion.
Since the first engine fires for 2 s and provides 6 N of thrust,
the second engine must also fire for 2 s to provide 4 N of thrust (since 6N/2s = 4N/x, where x = 2s).
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ou have a lightweight spring whose unstretched length is 4.0 cmcm. first, you attach one end of the spring to the ceiling and hang a 1.4 gg mass from it. this stretches the spring to a length of 5.1 cmcm . you then attach two small plastic beads to the opposite ends of the spring, lay the spring on a frictionless table, and give each plastic bead the same charge. this stretches the spring to a length of 4.6 cmcm . Required:
What is the magnitude of the charge (in nC) on each bead?
The magnitude of the charge on each bead is 7.08nc.
What is the magnitude of charge?Given the following information:
Original length = 4.0 cm converted to m = 0.04 m
1.4 grams to kilograms = 0.0014
5.1 cm to m = 0.051 is the new length.
4.6 cm to m = 0.046 m is the final length.
e = 0.051 - 0.046
= 0.005m in length
Scientific evidence:
Gravitational acceleration = 9.8m/s²
Coulomb's constant is equal to 8.99 x 10⁹ Nm²/C²
We would use Coulomb's law to calculate the magnitude of the charge (in nC) on each bead:
First, we would calculate the spring constant of this lightweight spring
using the following formula:
W = mg = Ke
K = mg/e
K = 0.014 x 9.8 / 0.05
K = 2.744N/m
K, the spring constant, is 2.744N/m.
In terms of electrostatic force:
F = ke
F = 2.77 x 0.05
F = 0.1385
F equals 0.1385 Newton.
Coulomb's electrostatic force law.
The charge in an electric field can be calculated mathematically using the following formula:
q = √F/k x r
We get by substituting the given parameters into the formula;
q = √(0.1385/8.99 x 10⁹) x 0.046
q = √(1.54060 x 10⁻¹²) x 0.046
q = 7.08 x 10⁻⁸
Take note that 1 nC = 1 x 10⁻⁹ C
Charge, q = 7.08nc
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Help me pleaseee!!
Would appreciate ^^
**BRAINLIST, thanks and
points***
With steps pls so I can
understand
The battery has an internal resistance of 2.50
4.1 Show that the resistance of the 6.2 V, 4.5 W lamp at its working potential difference
(pd) is about 9.
Look at photo for more info
4.2 The terminal pd across the battery is 6.2 V.
Calculate the emf of the battery.
The resistance of working potential difference of the 6.2 V, 4.5 W lamp is 8.54 ohm. When terminal pd across the battery is 6.2 V, the emf of the battery is 8.01 V.
What is resistance?The opposition that a substance provides to the flow of electric current is referred to as resistance. The uppercase letter R represents it. The ohm is the standard unit of resistance, which is sometimes written as a word and sometimes represented by the uppercase Greek letter omega. Resistance is a measure of an electrical circuit's resistance to current flow. Resistance is measured in ohms, which is represented by the Greek letter omega ().
Here,
r=2.5 ohm
V= 6.2 volts
P=4.5 watt
P=V²/R
R=V²/P
R=6.2*6.2/4.5
R=8.54 ohm that is about 9 ohm.
I=V/R
I=0.726 A
EMF=V+Ir
=6.2+0.726*2.5
=6.20+1.81
=8.01 volts
The resistance of the 6.2 V, 4.5 W lamp at its working potential difference is 8.54 ohm. The emf of the battery when terminal pd across the battery is 6.2 V is 8.01 V.
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A pulley system has a mechanical advantage of 3, and an object weighing 9 Newtons must be lifted 15
meters. How much force must be applied to lift the object?
Use the following equation to find the answer.
MA= Fo/F i
(1 point)
A. 1.7 N
b. 0.3 N
c.27 N
d.3N
C. 27 N force must be applied to lift the object.
How much force must be applied to lift the object?The mechanical advantage of a pulley system is calculated by dividing the output force by the input force. In this case, the mechanical advantage is 3, meaning the output force is 3 times larger than the input force.To find the force required to lift the object, we can use the equation: Force = (Weight of Object x Distance) / Mechanical Advantage.Plugging in the given numbers, the force required to lift the object is (9 Newtons x 15 meters) / 3 = 45 Newtons. Therefore, 45 Newtons of force must be applied to lift the object. Using a pulley system to lift an object is advantageous because it reduces the amount of force needed to lift the object. The mechanical advantage of the pulley system multiplies the output force, allowing the user to lift the object with less effort.Pulley systems are often used to lift large or heavy objects, such as in cranes and construction sites.They are also useful in machines and everyday items, such as roller blinds and bicycles.
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A hummingbird averages a speed of about 45 km/hour (Cool facts: They visit up to 1000 flowers per day, and reach maximum speed, while diving, up to 160 km/hour!). Ruby-throated hummingbirds take a non-stop trip across Gulf of Mexico in which they fly for 18 hours straight! How far is the trip across the Gulf of Mexico at their average speed?
answer choices
810 km
2.5 km
3.6 km
360 km
It would take 18 hours to travel 18 x 45 = 810 km across the Gulf of Mexico.
What is average speed?Average speed is the measure of an object's overall rate of motion in a given direction. It is calculated by dividing the total distance traveled by the total time taken. Average speed can be calculated over a certain period of time, or it can be calculated over the entire duration of a journey.
At an average speed of 45 km/hour, a hummingbird would travel 45 km in one hour.
Therefore, it would take 18 hours to travel 18 x 45 = 810 km across the Gulf of Mexico.
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