Answer:
Complete the program as follows:
for(int i = 0; i<10; i++){
if(inCity == citiesInMichigan[i]){
foundIt = true;
break; } }
if(foundIt){ cout<<"It is a city"; }
else{ cout<<"Not a city"; }
Explanation:
Required
Complete the pre-written code in C++ (as indicated by the file name)
The pre-written code; though missing in this question, can be found online.
The explanation of the added lines of code is as follows:
This iterates through the array
for(int i = 0; i<10; i++){
This checks if the city exists in the array
if(inCity == citiesInMichigan[i]){
If yes, foundIt is updated to true
foundIt = true;
And the loop is exited
break; } } -- The loop ends here
If foundIt is true, print it is a city
if(foundIt){ cout<<"It is a city"; }
Print not a city, if otherwise
else{ cout<<"Not a city"; }
// MichiganCities.cpp - This program prints a message for invalid cities in Michigan.// Input: Interactive// Output: Error message or nothing#include <iostream>#include <string>using namespace std;int main(){ // Declare variables string inCity; // name of city to look up in array const int NUM_CITIES = 10; // Initialized array of cities string citiesInMichigan[] = {"Acme", "Albion", "Detroit", "Watervliet", "Coloma", "Saginaw", "Richland", "Glenn", "Midland", "Brooklyn"}; bool foundIt = false; // Flag variable int x; // Loop control variable // Get user input cout << "Enter name of city: "; cin >> inCity; // Write your loop here for (x = 0; x < NUM_CITIES; x++) { // Write your test statement here to see if there is // a match. Set the flag to true if city is found. if (inCity == citiesInMichigan[x]) { foundIt = true; cout << "City found." << endl; break; } else { foundIt = false; } } // Test to see if city was not found to determine if // "Not a city in Michigan" message should be printed. if (!foundIt) { cout << "Not a city in Michigan." << endl; } return 0; } // End of main()
Choose the item which best describes the free frame list. 1. a per process data structure of available physical memory 2. a global data structure of available logical memory 3. a global data structure of available physical memory 4. a global data structure of available secondary disk space
Answer:
A global data structure of available logical memory ( Option 2 )
Explanation:
A Free list is a data structure connecting unallotted regions in a memory together in a linked list (scheme for dynamic/logical memory allocation) , hence a free frame list is a global data structure of available Logical memory .
Plzz help will mark brainliest
Answer:
11. 3 dimensions
12. ( i believe its number 3)
13. 2 option
14. Natural Light
15. Development
Explanation:
Write functions to compute a subset, find member, union, and intersection of sets. Follow the steps below:
1. Read two integers from the user.
2. Suppose one of the integers is 2311062158. The binary equivalent of this integer stored in a register will be 1000 1001 1100 0000 0000 0010 1000 1110. This data should be regarded as bit strings representing subsets of the set {1, 2, … 32}. If the bit string has a 1 in position i, then element i is included in the subset. Therefore, the string: 1000 1001 1100 0000 0000 0010 1000 1110 corresponds to the set: {2, 3, 4, 8, 10, 23, 24, 25, 28, 32}.
3. Print out members of the set from smaller to larger. You can do a loop from 1 to 32. Load a masking bit pattern that corresponded to the position number of the loop counter (0x00000001 for 1). Isolate the bit in the operand by using the AND operation. If the result of the AND is not 0 then the loop counter is in the set and should be displayed. Increment the counter and shift the masking bit pattern to the left.
4. Read a number from the user. Determine if that element is a member of the given sets.
5. Determine the union of two sets.
6. Determine the intersection of two sets.
7. Implement a loop back to the main function. See the prompts below: "Enter the first number:" "Enter the second number:" "Members of Set 1:" "Members of Set 2:" "Enter an element to find:" "It is a member/ not a member of set 1" "It is a member/ not a member of set 2" "Union of the sets:" "Intersection of the sets:" "Do you want to compute set functions again?"
8. Test the program using the following data:
Enter the first number: 99999
Enter the second number: 111445
Members of set 1: 1 2 3 4 5 8 10 11 16 17
Members of set 2: 1 3 5 7 9 10 13 14 16 17
Enter an element to find: 7
It is not a member of set 1
It is a member of set 2
Union of the sets: 1 2 3 4 5 7 8 9 10 11 13 14 16 17
Intersection of the sets: 1 3 5 10 16 17
Explanation:
Suppose one of the integers is 2311062158. The binary equivalent of this integer stored in a register will be 1000 1001 1100 0000 0000 0010 1000 1110. This data should be regarded as bit strings representing subsets of the set {1, 2, … 32}. If the bit string has a 1 in position i, then element i is included in the subset. Therefore, the string: 1000 1001 1100 0000 0000 0010 1000 1110 corresponds to the set: {2, 3, 4, 8, 10, 23, 24, 25, 28, 32}.
Popular periodicals might include newspapers
True or false?
Answer:
False
Explanation:
Because there is no way that would be correct!
Answer:
True
Explanation:
It makes sense
~Plz tap the crown ~
~Thank you~
How to use the RANK Function in Microsoft Excel
Answer:
=RANK (number, ref, [order])
See Explanation
Explanation:
Literally, the rank function is used to rank values (i.e. cells) in a particular order (either ascending or descending).
Take the following instances:
A column used for total sales can use rank function to rank its cells from top sales to least.
A cell used for time can also use the rank function to rank its cells from the fastest time to slowest.
The syntax of the rank function is:
=RANK (number, ref, [order])
Which means:
[tex]number \to[/tex] The rank number
[tex]ref \to[/tex] The range of cells to rank
[tex]order \to[/tex] The order of ranking i.e. ascending or descending. This is optional.
Given positive integer n, write a for loop that outputs the even numbers from n down to 0. If n is odd, start with the next lower even number.
if(n % 2 == 0){
for(int i = n; i >= 0; i-=2){
System.out.println(i);
}
}
else{
for(int i = n - 1; i >= 0; i-=2){
System.out.println(i);
}
}
Sample output
Output when n = 12
12
10
8
6
4
2
0
Output when n = 21
20
18
16
14
12
10
8
6
4
2
0
Explanation:The above code is written in Java.
The if block checks if n is even by finding the modulus/remainder of n with 2. If the remainder is 0, then n is even. If n is even, then the for loop starts at i = n. At each cycle of the loop, the value of i is reduced by 2 and the value is outputted to the console.
If n is odd, then the else block is executed. In this case, the for loop starts at i = n - 1 which is the next lower even number. At each cycle of the loop, the value of i is reduced by 2 and the value is outputted to the console.
Sample outputs for given values of n have been provided above.
Landing pages in a foreign language should never be rated fully meets?
Answer:
if the landing page provides all kind information of information as to that site people usually like it or will most likely enjoy it
BRAINLIEST?????
Explanation:
A pharmaceutical company is going to issue new ID codes to its employees. Each code will have three letters followed by one digit. The letters and and the digits , , , and will not be used. So, there are letters and digits that will be used. Assume that the letters can be repeated. How many employee ID codes can be generated
Answer:
82,944 = total possible ID's
Explanation:
In order to find the total number of combinations possible we need to multiply the possible choices of each value in the ID with the possible choices of the other values. Since the ID has 3 letters and 1 digit, and each letter has 24 possible choices while the digit has 6 possible values then we would need to make the following calculation...
24 * 24 * 24 * 6 = total possible ID's
82,944 = total possible ID's
Which of the following describes a characteristic of organic light-emitting diodes (OLEDs) used in clothing?
uniform
flexible
transparent
sizeable
Answer:
Yes the answer is flexible.
Explanation:
I took the test and got it right.
pleaseeeeeeee tellllllllllllllllllllll
Answer:
visual communication
hope it helps
stay safe healthy and happy.Answer:
visual communication will be the correct answer
1. A bank customer invested $24 in a bank with 5 percent simple interest per year, write a program the construct a table showing how much money the bank customer would have at the end of each 20- year period starting in 2021 to 2041.
2. A programmer starts with salary of $65,000 and expect to receive $1500 raise each year. Write a program to compute and print the programmer's salary for each of the first 10 years and total amount of money the programmer would receive over the 10- year period.
Answer:
1.lettuce is 2021 to 2,000 4136 verse 2. that is 10 years to tell if your 10 years 20 years old point monthstate 4 basic operation performed by a computer
Answer:
The processes are input, output, storing,processing, and controlling.
Write a program second.cpp that takes in a sequence of integers, and prints the second largest number and the second smallest number. Note that in the case of repeated numbers, we really mean the second largest and smallest out of the distinct numbers (as seen in the examples below). You may only use the headers: and . Please have the output formatted exactly like the following examples: (the red is user input)
Answer:
The program in C++ is as follows:
#include <iostream>
#include <vector>
using namespace std;
int main(){
int n;
cout<<"Elements: ";
cin>>n;
vector <int>num;
int input;
for (int i = 1; i <= n; i++){ cin>>input; num.push_back(input); }
int large, seclarge;
large = num.at(0); seclarge = num.at(1);
if(num.at(0)<num.at(1)){ large = num.at(1); seclarge = num.at(0); }
for (int i = 2; i< n ; i ++) {
if (num.at(i) > large) {
seclarge = large;;
large = num.at(i);
}
else if (num.at(i) > seclarge && num.at(i) != large) {
seclarge = num.at(i);
}
}
cout<<"Second Largest: "<<seclarge<<endl;
int small, secsmall;
small = num.at(1); secsmall = num.at(0);
if(num.at(0)<num.at(1)){ small = num.at(0); secsmall = num.at(1); }
for(int i=0; i<n; i++) {
if(small>num.at(i)) {
secsmall = small;
small = num.at(i);
}
else if(num.at(i) < secsmall){
secsmall = num.at(i);
}
}
cout<<"Second Smallest: "<<secsmall;
return 0;
}
Explanation:
See attachment for explanation
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Answer:
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Code a Python program that uses a graphical user interface (GUI) to address a real-world problem. Within reason, you may choose to address any real-world problem that you would like; however, please only choose a real-world problem that is both safe and legal.
Answer:
Explanation:
The following is a simple GUI Python program that solves for the different variables in a Pythagorean theorem equation, which is a real-world problem that many students have to face on a daily basis. The output can be seen in the attached picture below. Due to technical difficulties, I have added the code as a txt file attachment.
state two ways of moving an icon from one location to another
Answer:
To arrange icons by name, type, date, or size, right-click a blank area on the desktop, and then click Arrange Icons.
Click the command that indicates how you want to arrange the icons (by Name, by Type, and so on).
If you want the icons to be automatically arranged, click Auto Arrange.
If you want to arrange the icons on your own, click Auto Arrange to remove the check mark.
Explanation:
In Python what are the values passed into functions as input called?