Solution :
import [tex]$\text{java}.$[/tex]util.*;
public [tex]$class$[/tex] currency{
public static [tex]$\text{void}$[/tex] main(String[tex]$[]$[/tex] args) {
Scanner input [tex]$=$[/tex] new Scanner(System[tex]$\text{.in}$[/tex]);
System[tex]$\text{.out.}$[/tex]print("Enter [tex]$\text{number of}$[/tex] quarters:");
int quarters = input.nextInt();
System.out.print("Enter number of dimes:");
int [tex]$\text{dimes =}$[/tex] input.nextInt();
System[tex]$\text{.out.}$[/tex]print("Enter number of nickels:");
int nickels = input.nextInt();
System[tex]$\text{.out.}$[/tex]print("Enter number of pennies:");
int [tex]$\text{pennies = }$[/tex] input.nextInt();
// computing dollors
double dollars = (double) ((quarters*0.25)+(dimes*0.10)+(nickels*0.05)+(pennies*0.01));
System[tex]$\text{.out.}$[/tex]format("You have : $%.2f",dollars);
}
}
Combinations of velocity and acceleration
Answer:
acceleration=change in velocity/ time
Explanation:
The velocity of an object is its speed in a particular direction. Velocity is a vector quantity because it has both a magnitude and an associated direction. To calculate velocity, displacement is used in calculations, rather than distance.
calculate the radius of a circular orbit for which the period is 1 day
Answer:
(T²/D³)sys1 = (T²/D³)sys2
sys1 = earth-moon
sys2 = earth-sat
(27.33day)²/(3.8e8m)³ = (1day)²/D³
D = cbrt(7.3e22m³) = 4.2e7 m
Explanation:
exchange in capacity whilst a satellite tv for pc differences altitude How plenty paintings could be executed to flow the satellite tv for pc into yet another around orbit it is bigger above the outdoors of the Earth? satellite tv for pc exchange in capacity with top Assuming the satellite tv for pc is to be boosted to a clean top r? Gravitational capacity capacity (to center of earth) new orbit(2) has a greater robust PE than old one(a million), so exchange is helpful PE = G m?m?/r earth GM = 3.98e14 ?PE = (GM)(m)(a million/r? – a million/r?) KE additionally differences. Get speed at each and every top. New orbit(2) has decrease speed, so exchange is damaging v = ?(GM/R) V? = ?(GM/r?) V? = ?(GM/r?) ?KE = –½m(V?² – V?²) ?KE = –½mGM(a million/r? – a million/r?) including the two ?E = (GM)(m)(a million/r? – a million/r?)– ½mGM(a million/r? – a million/r?) ?E = ½mGM(a million/r? – a million/r?) ?E = ½(3.98e14)(7500) [a million/(0.5e7) –a million/(3.3e7) ] ?E = ½(3.98e14)(7500)(1e-7) [a million/(0.5) –a million/(3.3) ] ?E = ½(3.98e7)(7500) [2 – 0.303 ] ?E = ½(3.98e7)(7500)(a million.70) ?E = 2.04e11 Joules edit, corrected .
The radius of a circular orbit will be "[tex]\frac{V}{2 \pi} \ km[/tex]".
According to the question,
The orbit period of satellite,Time = 1 day
Total distance will be equal to the orbit's circumference, thenDistance = [tex]2 \pi r[/tex]
Let,
The velocity be "V km/day".As we know,
→ [tex]Distance = Velocity\times time[/tex]
By substituting the values, we get
→ [tex]2 \pi r = V\times 1[/tex]
→ [tex]r = \frac{V}{2 \pi} \ km[/tex]
Thus the above is the right answer.
Learn more about radius of orbit here:
https://brainly.com/question/12859535