ILL GIVE BRAINLEIST THIS WAS DUE YESTERDAY!! 5. Use the following information to answer the questions.
.
A survey asked 75 people if they wanted a later school day start time.
.
45 people were students, and the rest were teachers.
.
50 people voted yes for the later start.
• 30 students voted yes for the later start.
.
a) Use this information to complete the frequency table. (5 points: 1 point for
each cell that was not given above)
Students
Teachers
Total
Vote YES for
later start
Vote NO for later
start
Total
b) Use the completed table from Part a. What percentage of the people surveyed
were teachers? (2 points)

The number 6.34 repeating is an irrational number because it can be expressed as a fraction of two integers.

The number 6.34 repeating is irrational.

An irrational number cannot be expressed as the ratio of two integers, and it has an infinite number of non-repeating decimal places.

In this case, 6.34 repeating can be expressed as 6.34343434..., where the digits "34" repeat infinitely.

This cannot be expressed as a ratio of two integers because there is no repeating pattern that can be represented by a fraction.

Therefore, 6.34 repeating is irrational.

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The larger can price is proportional to the price of

smaller can in relation to its volume.

A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface.

The volume of a cylinder is expressed as;

V = πr²h

Volume of the small cylinder = πr²h

= 3.14 × 2² × 3

= 3.14 × 4 × 3

= 37.68 in²

The volume of big cylinder

= πR²h

= 3.14 × 6² × 9

= 3.14 × 36 × 9

= 1017.36 in³.

price of the big can = 2 × price of small

Therefore the volume of the big can is thrice the volume of the small cylinder and the price of the

big can is twice of the price of the small can.

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The 95% confidence interval for the true mean weight, H, of all packages received by the parcel service is (21.2 pounds, 22.8 pounds), which corresponds to option b) 21.2 to 22.8 pounds

To calculate the 95% confidence interval for the true mean weight, H, of all packages received by the parcel service, we will use the following terms and steps:

1. Sample mean (x): 22.0 pounds
2. Sample size (n): 43 packages
3. Standard deviation (σ): 2.7 pounds
4. Confidence level: 95%

Step 1: Calculate the standard error (SE) by dividing the standard deviation (σ) by the square root of the sample size (n). [tex]SE= \frac{σ}{\sqrt{n} }[/tex]

[tex]SE=\frac{2.7}{\sqrt{43} } = 0.4114[/tex]

Step 2: Determine the critical value (z) for the 95% confidence level. For a 95% confidence interval, the z-value is 1.96.

Step 3: Calculate the margin of error (ME) by multiplying the standard error (SE) by the critical value (z). ME = SE × z

ME = 0.4114 × 1.96 = 0.806

Step 4: Calculate the lower and upper bounds of the confidence interval using the sample mean (x) and margin of error (ME).

Lower bound = x - ME = 22.0 - 0.806 = 21.2 pounds
Upper bound = x + ME = 22.0 + 0.806 = 22.8 pounds

So, the 95% confidence interval for the true mean weight, H, of all packages received by the parcel service is (21.2 pounds, 22.8 pounds), which corresponds to option b) 21.2 to 22.8 pounds.

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In the given triangle, the measure of side c is approximately 39 m

From the question, we are to calculate the measure of side c in the given triangle.

To determine the measure of side c, we will use SOH CAH TOA

sin (angle) = Opposite / Hypotenuse

cos (angle) = Adjacent / Hypotenuse

tan (angle) = Opposite / Adjacent

In the given diagram,

Angle = 29°

Opposite = 19 m

Hypotenuse = c

Thus

sin (29°) = 19 / c

0.4848 = 19 / c

c = 19 / 0.4848

c = 39.1914

c ≈ 39 m

Hence,

The measure of c is 39 m

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The area of the figure is 23.5 in².

Given is shape we need to find the area of the same,

For finding the same,

We will find the area of the rt. triangle with height 9 in and base 7 in.

Then we will subtract the area of the rectangle with dimension 2 x 4.

So,

The required area = (1/2 x 9 x 7) - (2 x 4) = 23.5 in²

Hence, the area of the figure is 23.5 in².

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The ending balance of the money that was invested would be =$1150

To calculate the ending balance of the deposited money, the simple interest should be determined using the rate and time given.

The formula for simple interest = principal×time×rate/100

principal = $1,000

time = 5 years

rate = 3%

simple interest = 1000×5×3/100

= 15000/100

=$150

Therefore the end balance = 1000+150 = $1150

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Answer:

16/22, 24/33, and 40/55

or

72.7272...% = Percentage form

0.7272... = Decimal form

Hope this helps :)

Pls brainliest...

Answer:

72 cm

Step-by-step explanation:

24cm x 3 = 72cm

A= 72cm

Answer:

27cm

Step-by-step explanation:

24=p w=x         L=3x

x+x+3x+3X=24

8X=24

X=3

w=3

L=9

3*9=27

A=27

We first need to clarify a few terms and the question itself. It seems like you are asking about a codeword in polynomial form and finding the third circular shift of the codeword. Let's express the codeword in polynomial form:

Let u(x) be the original polynomial codeword, and let n = 4. Based on the information provided, assuming that q(x) = u(x)n(x) = u(x)(1 + x^4).

To find the third circular shift of the codeword, follow these steps:

1. Express the original codeword u(x) in polynomial form, for example, u(x) = a_0 + a_1x + a_2x^2 + a_3x^3 (where a_i are coefficients).
2. Perform the first circular shift by moving the last term to the front: a_3x^3 + a_0 + a_1x + a_2x^2.
3. Perform the second circular shift: a_2x^2 + a_3x^3 + a_0 + a_1x.
4. Perform the third circular shift: a_1x + a_2x^2 + a_3x^3 + a_0.

The third circular shift of the codeword u(x) is given by the polynomial a_1x + a_2x^2 + a_3x^3 + a_0.

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The percent of area under a normal curve between the mean and −1.18 standard deviations is 38.10% and between z=−1.6 and z = 0.7 is 70.32% and the​ z-score that best satisfies the condition is z=−0.4.

To find the percent of area under a normal curve between the mean and −1.18 standard deviations from the mean, we need to use a standard normal distribution table or calculator.

The area to the left of −1.18 standard deviations is 0.1190, and the area to the left of the mean is 0.5000. To find the area between them, we subtract the smaller area from the larger area:

0.5000 - 0.1190 = 0.3810

Therefore, the percent of area under a normal curve between the mean and −1.18 standard deviations is 38.10%.

To find the percent of the total area under the standard normal curve between z=−1.6 and z = 0.7, we again need to use a standard normal distribution table or calculator.

The area to the left of −1.6 is 0.0548, and the area to the left of 0.7 is 0.7580. To find the area between them, we subtract the smaller area from the larger area:

0.7580 - 0.0548 = 0.7032

Therefore, the percent of the total area between z=−1.6 and z = 0.7 is 70.32%.

To find the​ z-score that best satisfies the condition that 36% of the total area is to the left of z, we need to use a standard normal distribution table or calculator.

We look for the z-score that corresponds to a cumulative probability of 0.36. This is approximately −0.4, which means that 36% of the total area under the standard normal curve is to the left of z=−0.4. Therefore, the​ z-score that best satisfies the condition is z=−0.4.

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The cost per widget based on the given data is decreasing by $0.616 for every one-unit increase in volume, and the predicted cost when volume is zero is $36.94.

To determine the cost per widget based on the given data, we need to find the slope of the regression line. The slope of the regression line represents the change in cost for a one-unit change in volume.

We can use the formula for the slope of the regression line:

slope = r(Sy/Sx)

where r is the correlation coefficient, Sy is the standard deviation of Y (cost), and Sx is the standard deviation of X (volume).

From the given data, we can calculate the following:

r = -0.75 (negative correlation between cost and volume)

Sy = 4.5 (standard deviation of cost)

Sx = 5.5 (standard deviation of volume)

Substituting these values into the formula for slope, we get:

slope = -0.75(4.5/5.5) = -0.616

Therefore, the cost per widget is decreasing by $0.616 for every one-unit increase in volume.

To find the actual cost per widget, we need to look at the intercept of the regression line. The intercept represents the predicted cost when volume is zero.

We can use the formula for the intercept of the regression line:

intercept = y - slope(x)

where y is the mean of Y (cost), slope is the slope of the regression line, and x is the mean of X (volume).

From the given data, we can calculate the following:

y = $10.50 (mean of cost)

x = 40 (mean of volume)

Substituting these values into the formula for intercept, we get:

intercept = 10.50 - (-0.616)(40) = $36.94

Therefore, the cost per widget is approximately $36.94 when volume is zero.

In summary, the cost per widget based on the given data is decreasing by $0.616 for every one-unit increase in volume, and the predicted cost when volume is zero is $36.94.

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The input x = 6 is mapped to different values, thus, the relation is not a function.

A relationship is a function only if all the inputs are mapped to a single output (this means that each value of the domain is mapped into only one of the values of the range)

Now, the given relation is the following one:

(6, 3), (5, 6), (-1, 1), (6, 9), (8,8)

If you look at the first and the fourth coordinate pairs, you can see that in both cases the inputs are 6.

And the outputs are different, then that input is being mapped to two different values, thus, the relation is not a function.

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The given example of rings A = Q and B = Q(ζ) demonstrates that B is integral over A, but not finite over A, as required by the problem.

To give an example of rings A⊂B such that B is integral over A, but not finite over A, we can use the hint provided.

Consider the following rings:
- A = Q (the field of rational numbers)
- B = Q(ζ) (the field obtained by adding all roots of unity to Q)

B is integral over A because every element in B can be expressed as a root of a monic polynomial with coefficients in A. Specifically, any root of unity ζ^n, where n is a positive integer, is a root of the monic polynomial x^n - 1 with coefficients in Q.

However, B is not finite over A because there are infinitely many roots of unity. Each root of unity generates a different extension field, and the union of all these fields is B. If B were finite over A, it would mean that there exists a finite set of elements {b_1, b_2, ..., b_n} in B such that every element in B can be written as a linear combination of these elements with coefficients from A. But, since there are infinitely many roots of unity, we can always find a new root that cannot be expressed as a linear combination of the others, which contradicts the finiteness assumption.

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Given a significance level (alpha) of 0.05, we can conclude that the P-value of 0.097 is greater than the alpha. Therefore, we fail to reject the null hypothesis and conclude that zip code and diet are independent of one another.

Since the P-value (0.094) is greater than the significance level of 0.05, we fail to reject the null hypothesis that zip code and diet are independent of one another. Therefore, the conclusion is that Zip code and diet are independent of one another.
We need to first calculate the degrees of freedom for the chi-square test statistic. For a contingency table with R rows and C columns, the degrees of freedom (df) is calculated as follows:
The degree of freedom of the x statistic is calculated as (number of rows - 1) times (number of columns - 1), which in this case is (4-1) times (3-1) = 6.
df = (R - 1) * (C - 1)
In this case, the table has 4 rows (zip codes) and 3 columns (diets), so:
df = (4 - 1) * (3 - 1) = 3 * 2 = 6
The test statistic (x^2) is 10.78, and the degrees of freedom is 6. To find the P-value, we need to refer to a chi-square distribution table or use statistical software. For this example, we'll round the P-value to 3 decimals.
P-value ≈ 0.097
Therefore, we need to use a chi-square distribution table with 6 degrees of freedom. Looking up the value of 10.78 in the table, we find that the P-value is approximately 0.094.
Given a significance level (alpha) of 0.05, we can conclude that the P-value of 0.097 is greater than the alpha. Therefore, we fail to reject the null hypothesis and conclude that zip code and diet are independent of one another.

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There is enough evidence to show that the mean carbon dioxide emission is now lower than it was in 2004.

To test whether the mean carbon dioxide emission is now lower than it was in 2004, we need to conduct a one-sample t-test.

We are given a random sample of carbon dioxide emissions from a recent study. Let's assume that this sample is representative of the population of interest. The null hypothesis is that the true population mean of carbon dioxide emissions is equal to or greater than the mean in 2004 (4.87 metric tons per capita). The alternative hypothesis is that the true population mean is less than the mean in 2004.

We can set up the hypotheses as follows:

H0: μ >= 4.87

Ha: μ < 4.87

where μ is the true population mean of carbon dioxide emissions.

We are given the sample data in a table, but we don't know the population standard deviation, so we will use the sample standard deviation to estimate it. The sample mean is calculated as:

x = (4.28 + 3.94 + 3.27 + 3.81 + 3.43 + 3.09 + 2.52 + 2.98 + 3.23 + 3.36) / 10 = 3.43

The sample standard deviation is calculated as:

s = √(((4.28 -x)² + (3.94 - x)² + ... + (3.36 - x)²) / 9) = 0.659

The sample size is n = 10.

We can calculate the t-statistic as:

t = (x- μ) / (s / √(n)) = (3.43 - 4.87) / (0.659 / √(10)) = -4.26

The degrees of freedom for this test are df = n - 1 = 9. We can use a t-distribution table or a calculator to find the p-value associated with this t-statistic and degrees of freedom.

Using a t-distribution table with df = 9, we find that the p-value for a one-tailed test at the 3% level is less than 0.001. This means that the probability of observing a t-statistic as extreme as -4.26, assuming the null hypothesis is true, is less than 0.001.

Since the p-value is less than the significance level of 0.03, we reject the null hypothesis and conclude that there is enough evidence to show that the mean carbon dioxide emission is now lower than it was in 2004 at the 3% level.

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The angle between lines L and L2 is approximately 33.23 degrees.

To find the angle between the two lines, we can use the dot product formula:

where L1 and L2 are the direction vectors of the two lines.

For line L1, the direction vector is <1, 3, 0>. For line L2, the direction vector is <8, 6, 0>. We can calculate the dot product and the magnitudes:

Plugging in these values to the formula, we get:

cos(θ)= 26 / (√(10) * 10) = 0.818

θ = acos(0.818) = 33.23 degrees

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The shipping fee is given as follows:

C. $6.00.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

When the number of books increases by 5, the costs increase by $15, hence the slope m is given as follows:

m = 15/5

m = 3.

Hence:

y = 3x + b.

When x = 5, y = 21, hence the intercept b, representing the shipping fee, is obtained as follows:

21 = 3(5) + b

b = $6.00.

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The equation of the plane tangent to the surfacer=3u2i+(5u−v2)j+3v2kr=3u2i+(5u−v2)j+3v2kat the point P that is P(12,9,3).z(x,y)=z(x,y)= 90x + 1296y + 810z = 14218.

To find the equation of the plane tangent to the surface at point P(12, 9, 3), we first need to find the partial derivatives of the surface with respect to u and v:

∂r/∂u = 6ui + 5j

∂r/∂v = -2vj + 6vk

Next, we can evaluate these partial derivatives at the point P(12, 9, 3) to get:

∂r/∂u = 6(12)i + 5j = 72i + 5j

∂r/∂v = -2(9)j + 6(3)k = -18j + 18k

Using these partial derivatives, we can find the normal vector to the tangent plane at point P by taking their cross product:

n = (∂r/∂u) x (∂r/∂v) = (72i + 5j) x (-18j + 18k)

= -90i - 1296j - 90k

Since the tangent plane passes through point P, its equation can be written in the form:

-90(x - 12) - 1296(y - 9) - 90(z - 3) = 0

Simplifying this equation gives:

-90x + 12960 - 1296y - 810z + 1458 = 0

or

90x + 1296y + 810z = 14218

Therefore, the equation of the plane tangent to the surface at point P is 90x + 1296y + 810z = 14218.

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There are 36 integers from 1 to 100 that are multiples of 4 or multiples of 7, and there are 64 integers that are neither multiples of 4 nor 7.

The group of counting numbers that can be written without a fractional component includes zero and both positive and negative integers. An integer can, as was already established, be either positive, negative, or zero.

To find how many integers from 1 to 100 are multiples of 4 or multiples of 7, we can use the principle of inclusion-exclusion. We start by counting the number of integers that are multiples of 4 and the number of integers that are multiples of 7:

- There are 25 multiples of 4 from 1 to 100 (4, 8, 12, ..., 96, 100).

- There are 14 multiples of 7 from 1 to 100 (7, 14, 21, ..., 91, 98).

However, we have double-counted the integers that are multiples of both 4 and 7 (i.e., multiples of 28). There are 3 such integers from 1 to 100 (28, 56, 84). So, the total number of integers that are multiples of 4 or multiples of 7 is:

25 + 14 - 3 = 36

To find how many integers are neither multiples of 4 nor 7, we can subtract the number of integers that are multiples of 4 or 7 from the total number of integers from 1 to 100:

100 - 36 = 64

Therefore, there are 36 integers from 1 to 100 that are multiples of 4 or multiples of 7, and there are 64 integers that are neither multiples of 4 nor 7.

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Total cost without items 2 and 4 = Sum(new price vector * adjusted quantity vector)

To get the average price of the items, sum the elements in vector p and divide by the number of elements (5 in this case).
Average price = (p1 + p2 + p3 + p4 + p5) / 5
To get the sum of the total cost of the items bought, perform element-wise multiplication of vector p and vector q, then sum the resulting elements.
Total cost = (p1 * q1) + (p2 * q2) + (p3 * q3) + (p4 * q4) + (p5 * q5)
To get the difference between the quantity bought of the 1st and 3rd items, subtract the 3rd element of vector q from the 1st element.
Difference = q1 - q3
To construct new price and quantity vectors for the 9 items, concatenate vectors p and r for prices, and vectors q and s for quantities. Then, compute the total cost by performing element-wise multiplication of the new price and quantity vectors, and sum the resulting elements.
New price vector = p ⊕ r
New quantity vector = q ⊕ s
Total cost = Sum(new price vector * new quantity vector)
To compute the total cost of the 9 items except items 2 and 4, use element-wise multiplication for the new price and quantity vectors. Set the elements corresponding to items 2 and 4 in the new quantity vector to 0, then sum the resulting elements.
Adjusted quantity vector = new quantity vector with 2nd and 4th elements set to 0
Total cost without items 2 and 4 = Sum(new price vector * adjusted quantity vector)

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The selling price of the computer was $8507.52.

We have,

If the businessman incurred a loss of 21% on the cost price, then the selling price (SP) must have been 79% of the cost price (CP), since:

SP = CP - Loss

SP = CP - 0.21 x CP

SP = 0.79 x CP

We know that the cost price was $10768, so we can substitute this value into the equation above to find the selling price:

SP = 0.79 x CP

SP = 0.79 x $10768

SP = $8507.52

Therefore,

The selling price of the computer was $8507.52.

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The circumference of the circle is 26.38 inches and the area of the circle is 55.39 square inches, both rounded to the nearest hundredth.

The diameter of a circle is the distance across the circle passing through its center. In this problem, the diameter of the circle is given as 8.4 inches. We can use the formula for the circumference and the area of a circle in terms of its diameter to find the solutions.

First, we can find the radius of the circle by dividing the diameter by 2. So, the radius is 8.4/2 = 4.2 inches.

To find the circumference of the circle, we can use the formula:

C = πd

where d is the diameter. Substituting the value of d = 8.4 inches and π = 3.14, we get:

C = 3.14 x 8.4 = 26.376

Therefore, the circumference of the circle is 26.38 inches (rounded to the nearest hundredth).

To find the area of the circle, we can use the formula:

A = πr²

where r is the radius. Substituting the value of r = 4.2 inches and π = 3.14, we get:

A = 3.14 x (4.2)² = 55.3896

Therefore, the area of the circle is 55.39 square inches (rounded to the nearest hundredth).

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The probability of randomly selecting a park that neither allows camping nor has a playground is 31/77.

We have,

We know that there are 59 parks that allow camping, 76 parks that have playgrounds, and a total of 154 parks.

Number of parks that allow camping only = 59 - 14 = 45

Number of parks that have playgrounds only = 76 - 14 = 62

Number of parks that have both camping and playgrounds = 14

The number of parks that neither allow camping nor have a playground.

= Total number of parks - (number of parks that allow camping only + number of parks that have playgrounds only - number of parks that have both camping and playgrounds)

= 154 - (45 + 62 - 14)

= 61

Now,

The probability of randomly selecting a park that neither allows camping nor has a playground.

= 61/154

= 31/77

Thus,

The probability of randomly selecting a park that neither allows camping nor has a playground is 31/77.

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Answer:

6 mph

Step-by-step explanation:

Let’s call the speed of the ferry in still water v. Then, we can use the formula:

distance = rate × time

to set up two equations for the trip upriver and downriver:

24 = (v - 6) × t1

24 = (v + 6) × t2

where t1 is the time it takes to travel upriver and t2 is the time it takes to travel downriver.

We also know that the total time for the round trip is 8 hours:

t1 + t2 = 8

We can solve this system of equations by first solving for t1 and t2 in terms of v:

t1 = 24 / (v - 6)

t2 = 24 / (v + 6)

Substituting these expressions into the equation for total time gives:

24 / (v - 6) + 24 / (v + 6) = 8

Multiplying both sides by (v - 6)(v + 6) gives:

24(v + 6) + 24(v - 6) = 8(v - 6)(v + 6)

Simplifying this equation gives:

48v = 288

So v = 6.

Therefore, the speed of the ferry in still water is 6 mph.

I hope this helps! Let me know if you have any other questions.

A) The length MN of the given wooden block is: 12

B) The total surface area in square inches of the wooden blocks to be painted is, 80400 in²

1) The formula for volume of a cuboid is:

Volume = Length * Width * Height

Thus: We get;

427 = (MN x 7 x 3) + (5 x 5 x 7)

427 = 21MN + 175

21MN = 252

MN = 252/21

MN = 12

2) Surface area of entire object is:

TSA = 2(12 x 3) + 2(12 x 7) - (5 x 7) + 2(7 x 3) + 3(5 x 7) + 2(5 x 5)

TSA = 402 in²

Hence, For 200 blocks:

TSA = 200 x 402

TSA = 80400 in²

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The radius of the sphere is approximately 5.22. The equation of the sphere is x^2 + y^2 + z^2 - 7x + 3y - 2z = 14.6784.

To find the centre of the sphere, we first need to find the midpoint of the diameter. Using the midpoint formula, we have:
Midpoint = ((5+2)/2, (-1-2)/2, (6+(-4))/2) = (3.5, -1.5, 1)
Therefore, the centre of the sphere is (3.5, -1.5, 1).
To find the radius of the sphere, we need to find the distance between the centre and one of the endpoints of the diameter. Using the distance formula, we have:
r = √[(5-3.5)^2 + (-1-(-1.5))^2 + (6-1)^2] = √[(1.5)^2 + (0.5)^2 + (5)^2] = √(27.25) ≈ 5.22
Therefore, the radius of the sphere is approximately 5.22.
The standard equation of a sphere with centre (h,k,l) and radius r is:
(x-h)^2 + (y-k)^2 + (z-l)^2 = r^2
Plugging in the values we found, we have:
(x-3.5)^2 + (y-(-1.5))^2 + (z-1)^2 = (5.22)^2
Expanding and simplifying, we get:
x^2 - 7x + 12.25 + y^2 + 3y + 2.25 + z^2 - 2z + 1 = 27.3284
Rearranging and simplifying further, we get:
x^2 + y^2 + z^2 - 7x + 3y - 2z = 14.6784
Therefore, the equation of the sphere is x^2 + y^2 + z^2 - 7x + 3y - 2z = 14.6784.

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The consumers' surplus if the market price is set at $6/disc is  $2,167.2.

The consumer's surplus is calculated from the quantity demanded as shown below;

-0.01x² − 0.2x + 54 = 6

-0.01x² - 0.2x + 48 = 0

solve the quadratic equation using formula method as follows;

x = -80 or 60

So we take only the positive quantity demanded.

Integrate the function from 0 to 60;

∫-0.01x² − 0.2x + 54 = [-0.0033x³ - 0.1x² + 54x]

= [-0.0033(60)³ - 0.1(60)² + 54(60)] - [-0.0033(0)³ - 0.1(0)² + 54(0)]

= -712.8 - 360 + 3,240

= $2,167.2

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The angle subtended by an arc 1.60 m in length on the circumference of a circle of radius 2.50 m is approximately 115.2°.

To find the angle subtended by an arc of 1.60 m in length on the circumference of a circle with a radius of 2.50 m, you can follow these steps:

Recall the formula for the length of an arc: Arc Length = (Central Angle × Radius)/180°, where the central angle is in degrees and the radius is in meters.

Rearrange the formula to solve for the central angle: Central Angle = (Arc Length × 180°) / Radius

Plug in the given values: Central Angle = (1.60 m × 180°) / 2.50 m

Calculate the result: Central Angle = (1.60 × 180) / 2.50 ≈ 115.2°

The angle subtended by an arc 1.60 m in length on the circumference of a circle of radius 2.50 m is approximately 115.2°.

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The correct number line that can be used to find the distance between the given points (4, -1) and (8, -1) is a number line going from negative 2 to positive 8 in increments of 1, with the points at 4 and 8.Option (A)

The reason for this is that the two points have the same y-coordinate, which means they lie on a horizontal line. To find the distance between them, we simply need to measure the difference between their x-coordinates, which is 8 - 4 = 4. On the given number line, the distance between points 4 and 8 is also 4 units, so we can directly read off the distance as 4 units.

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a)the probability that a single student randomly chosen from all those taking the test scores 558 or higher is approximately 0.4251.

b) the mean of the sampling distribution for x¯ is 552.9, and the standard deviation of the sampling distribution for x is approximately 4.507.

c)the probability that the mean score x¯ of these 35 students is 558 or higher is approximately 0.0943.

(a) Using the given mean and standard deviation, we can standardize the score of 558 as:

z = (558 - 552.9) / 26.7 = 0.1925

Using a standard normal table or calculator, we can find the probability of getting a z-score of 0.1925 or higher:

P(Z ≥ 0.1925) ≈ 0.4251

Therefore, the probability that a single student randomly chosen from all those taking the test scores 558 or higher is approximately 0.4251.

(b) The mean of the sample mean score x is the same as the population mean μ, which is 552.9. The standard deviation of the sample mean score x¯, also known as the standard error, is given by:

σ / sqrt(n) = 26.7 / sqrt(35) ≈ 4.507

Therefore, the mean of the sampling distribution for x¯ is 552.9, and the standard deviation of the sampling distribution for x is approximately 4.507.

(c) To find the z-score corresponding to the mean score x¯ of 558, we can standardize using the standard error:

z = (558 - 552.9) / (26.7 / sqrt(35)) ≈ 1.315

(d) Using the z-score of 1.315 and a standard normal table or calculator, we can find the probability of getting a sample mean score of 558 or higher:

P(Z ≥ 1.315) ≈ 0.0943

Therefore, the probability that the mean score x¯ of these 35 students is 558 or higher is approximately 0.0943.

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