If z = 1 + StartRoot 3 EndRooti, what is z5? 16 + 16StartRoot 3 EndRoot i –16 + 16StartRoot 3 EndRoot i –16 – 16StartRoot 3 EndRoot i 16 – 16StartRoot 3 EndRoot i

Answers

Answer 1

Answer:

The answer is C

Step-by-step explanation:

Correct answer shown on edge

Answer 2

The power of 5 of complex number z is (-16√3 + 16) + 4(-√3 + 3)i

What is a complex number?

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have:

z = 1 + √3i

We have to find: z⁵

z⁵ = (1 + √3i)(1 + √3i)(1 + √3i)(1 + √3i)(1 + √3i)

z⁵ = (-2 + 2√3)(1 + √3i)(1 + √3i)(1 + √3i)

[tex]\rm z^5=\left(2\sqrt{3}-2\right)+2\left(3-\sqrt{3}\right)i(1+\sqrt{3}i)(1+\sqrt{3}i)[/tex]

[tex]\rm =\left(-4\sqrt{3}+4\right)+4\left(3-\sqrt{3}\right)i(1+\sqrt{3}i)[/tex]

z⁵ = (-16√3 + 16) + 4(-√3 + 3)i

Thus, the power of 5 of complex number z is (-16√3 + 16) + 4(-√3 + 3)i

Learn more about the complex number here:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation: I think

Answer:

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Step-by-step explanation:

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https://brainly.com/question/13101306

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