If x = 1 and y = 2 is a solution to the simultaneous equation ax + by = 2 and bx + a^(2)y = 10, find the possible values of a and b.

Answer:

a = - 2, [tex]\frac{9}{4}[/tex] , b = 2, - [tex]\frac{1}{8}[/tex]

Step-by-step explanation:

Since x = 1, y = 2 is a solution to the equations , then substitute these values into the 2 equations and solve for a and b

a + 2b = 2 → (1)

b + 2a² = 10 → (2)

In (1) subtract 2b from both sides

a = 2 - 2b → (3)

Substitute a = 2 - 2b into (2)

b + 2(2 - 2b)² = 10 ← expand parenthesis using FOIL

b + 2(4 - 8b + 4b²) = 10 ( simplify left side )

b + 8 - 16b + 8b² = 10 ( subtract 10 from both sides )

8b² - 15b - 2 = 0

Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term

product = 8 × - 2 = - 16 and sum = - 15

The factors are - 16 and + 1

Use these factors to split the b- term

8b² - 16b + b - 2 = 0 ( factor first/second and third/fourth terms )

8b(b - 2) + 1(b - 2) = 0 ← factor out (b - 2) from each term

(b - 2)(8b + 1) = 0

Equate each factor to zero and solve for b

b - 2 = 0 ⇒ b = 2

8b + 1 = 0 ⇒ 8b = - 1 ⇒ b = - [tex]\frac{1}{8}[/tex]

Substitute these values into (3) and evaluate for a

b = 2 ⇒ a = 2 - 2(2) = 2 - 4 = - 2

b = - [tex]\frac{1}{8}[/tex] ⇒ a = 2 - 2(- [tex]\frac{1}{8}[/tex] ) = 2 + [tex]\frac{1}{4}[/tex] = 2 [tex]\frac{1}{4}[/tex] = [tex]\frac{9}{4}[/tex]

The possible values of a and b are 8, -3 or 9/4 , -1/8 respectively.

An equation is a combination of different variables, in which two mathematical expressions are equal to each other.

The given equations are,

ax + by = 2            (1)

and bx + a²y = 10        (2)

Also, x = 1 and y = 2 are the solution of the equation,

Substitute x = 1 and y = 2in equation (1),

a(1) + b(2) = 2

a + 2b = 2       (3)

Further substitute x = 1 and y = 2 in equation (2),

b(1) + a²(2)  = 10  

2a² + b = 10         (4)

By solving equation (3) and (4),

The possible values of a are 8 and 9/4.

And possible value of b are -3 and -1/8.

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