If the rate of formation of ammonia gas in haber bosch 2.5x10-4 mol/l-1/s-1 then rate of consumption of n2 gas during process equals... mol/l-1/s-1

A)-2.5x10-4
B) -1.25x10-4
C)-3.75x10-4
D)-5x10-4
Can somebody help me out i am stressed

Answers

Answer 1

Rate of  consumption of  N₂ = - 1.25 x 10⁻⁴

Further explanation

The reaction rate (v) shows the change in the concentration per unit time.  

[tex]\tt rate=\dfrac{concentration(M)}{time(s)}[/tex]

The rate reaction for Haber Bosch :

N₂(g)+3H₂(g)⇒2NH₃(g)

From equation, mol ratio N₂ : NH₃ = 1 : 2, so

the rate of formation of ammonia = 2 x the rate of consumption of nitrogen.

Given

the rate of formation of ammonia gas : 2.5x10⁻⁴ M/s

the rate of consumption of nitrogen :

[tex]\tt \dfrac{2.5\times 10^{-4}}{2}=1.25\times 10^{-4}[/tex]

The sign negative for consumption : -1.25 x 10⁻⁴ M/s

or we can use another way:

Rate of formation of  NH₃  = reaction rate x coefficient of  NH₃

2.5 x 10⁻⁴ = reaction rate x 2

reaction rate = 1.25 x 10⁻⁴

Rate of  consumption of  N₂  = reaction rate x coefficient of N₂

Rate of  consumption of  N₂ =  1.25 x 10⁻⁴ x 1

Rate of  consumption of  N₂ =  1.25 x 10⁻⁴


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Question 20 (1 point)
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Answers

Answer:

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Explanation:

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Answer:

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Answer: A. The greater the pressure, the more of gas that will dissolve.

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Answers

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Explanation:

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On the pereiodic table.

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Explanation:

consider this equation S + 3O₂ → 3O₃ Is this equation balanced? why or why not?

Answers

Answer:

This equation is not balanced because you don't have the same amount of each element on each side of the chemical reaction. The balanced equation is:

2 S + 3  ⇒ 2

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

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By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

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Right side: 1 sulfur S and 3 oxygen O (subindice value)

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A simple way is to balance the equation is to multiply the product by 2, that is, add a coefficient 2 in front of the SO3 molecule, the reaction being as follows:

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Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

The oxygen is now balanced, but the amount of sulfur on both sides of the reaction varies. To balance the quantities of sulfur, as now on the right side you have an amount of 2, you can add the coefficient to sulfur. The chemical equation is as follows:

2 S + 3  ⇒ 2

Now the amount of elements on each side of the equation is:

Left side: 2 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

Finally you have the same amount of sulfur and oxygen on both sides of the reaction. So the chemical equation is finally balanced.

Explanation:

Brainliest please?

Answer:

it is balenced beacuse both sides have the same ammount of particals

Explanation:

lonic bonds tend to form between
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d. all of these

Answers

The correct answer is B
The correct answer is B
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