If the net force acting on an object is zero, its inertia is also zero.
True or false

Answer:

5.17 x 10^5

Explanation

The correct answer is (b) [tex]5.17*10^{5}m[/tex]

Let us consider an object of mass m on the planet Q.

On planet Q, let the acceleration due to gravity be g = 2.24 m/[tex]s^{2}[/tex]

Mass of the planet is M = [tex]8.96*10^{21} kg[/tex]

Let its radius be R

and the universal gravitational constant G = [tex]6.67*10^{-11} m/kg[/tex]

Gravitational Force acting on the object:

[tex]mg=\frac{GMm}{R^{2} }[/tex]

[tex]R=\sqrt{\frac{GM}{g} } \\R=\sqrt{\frac{6.67*10^{-11}*8.96*10^{21} }{2.24} }\\R=5.17*10^{5} m[/tex] is the radius of the planet Q.

Learn more about gravitational force:

https://brainly.com/question/17531377

Answer:

[tex]A_{1}[/tex] = 0.2 [tex]m^{2}[/tex]

Explanation:

The pressure on the pistons is given as;

Pressure = [tex]\frac{Force}{Area}[/tex]

So that,

Pressure on the small piston = [tex]\frac{F_{1} }{A_{1} }[/tex] and Pressure on the large piston = [tex]\frac{F_{2} }{A_{2} }[/tex]

Thus,

[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]

Given that: [tex]F_{1}[/tex] = 100 N, [tex]F_{2}[/tex] = 2000 N, [tex]A_{2}[/tex] = 4 [tex]m^{2}[/tex].

[tex]\frac{100}{A_{1} }[/tex] = [tex]\frac{2000}{4}[/tex]

[tex]A_{1}[/tex] = [tex]\frac{100*4}{2000}[/tex]

    = [tex]\frac{400}{2000}[/tex]

    = 0.2

[tex]A_{1}[/tex] = 0.2 [tex]m^{2}[/tex]

The area of the small piston is 0.2 [tex]m^{2}[/tex].

Answer:

Both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement.

Explanation:

The main reason why people and bears, slip and fall on ice/snow is that both ice and snow have a lower coefficient of friction in comparison with grass, wood or pavement. We present below a comparative chart of coefficients of friction associated with different materials:

Material       Coefficient of Friction - Static                  

Ice/Snow                   0.05 - 0.3

Wood                          0.2 - 0.6

Asphalt                        0.5 - 0.7

Grass                            0.3 - 0.5

Explanation:

(1) Given that,

A charge, [tex]q=3\times 10^{-7}\ C[/tex]

Electric field, E = 27 N/C

We need to find the force acting on the charge. The force on the charge is given by :

[tex]F=qE\\\\F=3\times 10^{-7}\times 27\\F=8.1\times 10^{-6}\ N[/tex]

So, the force acting on the charge is [tex]8.1\times 10^{-6}\ N[/tex]

(b) Charge, [tex]q=5\times 10^{-6}\ C[/tex]

Force, [tex]F=2\times 10^{-4}\ N[/tex]

Let E be the electric field.

[tex]E=\dfrac{F}{q}\\\\E=\dfrac{2\times 10^{-4}}{5\times 10^{-6}}\\\\E=40\ N/C[/tex]

So, the electric field is 40 N/C.

Coulomb's Law says that the forces between any two charges depends directly on the size of the charges and inversely on the square of the distance between the charges. The correct option is D. A & B

From the question, we are to determine the correct option.

First, we will state Coulomb's law.

Coulomb's law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects

That is,

[tex]F \propto \frac{Q_{1} Q_{2} }{r^{2} } [/tex]

Where F is the electrical force

[tex]Q_{1} \ and \ Q_{2}[/tex] are the charges

r is the distance between the objects

From the law, we can observe that the forces depends directly on the size of the charges - Option A

and the forces also depends inversely on the square of the distance between the charges - Option B

Hence, the correct option is D. A & B

Learn more on Coulomb's law here: https://brainly.com/question/16033085

Answer:

The quadriceps consists of four muscles: the skinny rectus femoris and the three huge “vasti” — vastus lateralis/intermedius/medialis. The vasti are only elongated by knee flexion, which is limited to about 120˚ when the calf hits the hamstrings. The vasti cannot be stretched strongly.

Answer:Masseter and temporalis

Why it’s unstretchable: The jaw can only open so far.

Why it’s a dang shame: Jaw tension is epidemic, and trigger points in these muscles cause a wide array of strange face and head pains, including toothaches, headaches, and earaches.

Answer:

- 42

Explanation:

m = 6kg

vi = 17 m/s

vf = 10 m/s

delta mv = ?

Formula

delta mv = m*(vf) - m(vi)

delta mv = 6(10 - 17)

delta mv = 6(-7)

delta mv = - 42 kg m/s

Answer:

6.44pie

Explanation:

[tex]2\pirh[/tex]