If a car is able to accelerate a 500kg truck at 50m/s^2 what is the force applied by the engine on the car? Please show work

Answers

Answer 1

Answer:

The answer is 25,000 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 500 × 50

We have the final answer as

25,000 N

Hope this helps you

Answer 2

Answer:

Force applied by the engine on the car = 25 kN

Explanation:

Mass (m) = 500 kg

Acceleration (a) = 50 m/s²

The force (F) is equated to the product of the mass times the acceleration.

[tex] \boxed{ \bf{F = ma}}[/tex]

By substituting values, we get:

[tex] \longrightarrow [/tex] F = 500 × 50

[tex] \longrightarrow [/tex] F = 25000 N

[tex] \longrightarrow [/tex] F = 25 kN


Related Questions

One atomic mass unit is defined as 1.66 x 10^-27 kg. If a proton has a mass of one atomic mass unit and a density of approximately 5.8 x 10^27 kg/m3^ . What is the diameter of a proton if we assume it is a sphere?

Answers

Answer:

The diameter is [tex]d = 8.18*10^{-19} \ m[/tex]

Explanation:

From the question we are told that

   The value of one atomic mass unit is [tex]u = 1.66 *10^{-27} \ kg[/tex]

    The density of the proton is  [tex]\rho = 5.8 *10^{27} \ kg/m^3[/tex]

Generally the volume of the proton (sphere)is mathematically represented as

     [tex]V = \frac{4}{3} * \pi * r^3[/tex]

Generally this volume can also be evaluated as

      [tex]V = \frac{u}{\rho}[/tex]

=>   [tex]V = \frac{1.66 *10^{-27}}{5.8*10^{27}}[/tex]  

=>   [tex]V = 2.862 *10^{-55} \ m^3[/tex]

So

[tex]2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3[/tex]

=>   [tex]r^3 = 6.832 *10^{-56}[/tex]

=>  [tex]r = 4.088 *10^{-19} \ m[/tex]

Now the diameter is mathematically represented as

    [tex]d = 2 * r[/tex]

=> [tex]d = 2 * 4.088 *10^{-19}[/tex]

=> [tex]d = 8.18*10^{-19} \ m[/tex]

A 1400 kg car traveling in the positive direction takes 11.0 seconds to slow from 25.0 meters per second to 12.0 meters per second. What is the average force on the car during this time?

Answers

Answer:

–1652 N. The negative sign indicate that the force is in opposite direction to car.

Explanation:

The following data were obtained from the question:

Mass (m) of car = 1400 kg

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Force (F) applied on the car =?

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Time (t) = 11 s

Initial velocity (u) = 25 m/s

Final velocity (v) = 12 m/s

Acceleration (a) =?

a = (v – u) /t

a = (12 – 25) /11

a = –13/11

a = –1.18 m/s²

Finally, we shall determine the force on the car as follow:

Acceleration (a) = –1.18 m/s²

Mass (m) of car = 1400 kg

Force (F) applied on the car =?

F = ma

F = 1400 × –1.18

F = –1652 N

Thus, the force on the car is –1652 N. The negative sign indicate that the force is in opposite direction to car.

PLS HURRY!!!! 15 PTS!!! The pictures represent three different states of matter.
Which order of pictures places molecules with the most
amount of motion to the least amount of motion?
O X Y Z
O ZYX
O Y Z
O Y - X - Z

Answers

Xyz I think!
I’m so sorry if I’m wrong!!!

An automobile traveling 88.0 km/h has tires of 72.0 cm diameter. (a) What is the angular speed of the tires about their axles

Answers

Answer:

angular speed = 67.91 rad/s

Explanation:

Given that,

The diameter of a tire, d = 72 cm

The radius of a tire, r = 36 cm = 0.36 m

Linear speed of an automobile, v = 88 km/h = 24.45 m/s

We need to find the angular speed of the tires about their axles. The relation between angular speed and angular speed is given by :

[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{24.45 }{0.36}\\\\\omega=67.91\ rad/s[/tex]

So, the angular speed of the tire is 67.91 rad/s.

Which state of matter does this model represent?

Image of particles tightly packed

Solid
Liquid
Gas
Plasma

Answers

Answer:

gas

Explanation:

it is gas because the particles are floating up none of the above would be floating up.

Answer:

Solid

Explanation:

A: Solid- Solids have the particles tightly packed. They have a definite shape and volume

B: Liquid- Liquids have particles not to tightly packed but kind of loose. They have an indefinite shape but a definite volume

C: Gas- Gas has particles freely all around. Indefinite shape and volume

D: Plasma- Plasma is different and should be explained with an example; think of lighting....

Since the image shows tightly packed particles, it is clear the answer is a solid.

What kind of food would you expect a turtle with a hard, sharp beak and short neck to eat?

Answers

Ummmmmmmmmmm earthworms, grubs , snails , beetle and caterpillars
Leaves, grass, bugs, worms,

who plays adopt me on rob.lox!! plz answer people only if you play though tell me your best pet and your user name so we can play!!

Answers

Answer: I don't  do   adopt me   but I do have a Ro.blox username its  Nvm i cant but my user name

Explanation:

Answer:

adopt me sucks but my best pet was an albino monkey I think or a king monkey

Explanation:

An arrow in a bow has 357 J of elastic potential energy How much Winette enere
Will the arrow have after it has been shot assuming there is no sir restoran

Answers

Answer:

357 J

Explanation:

The elastic potential energy of arrow in the stretched bow is 357 J.

The kinetic energy of the arrow after it has been shot is given by half of the product of the arrow's mass and velocity of the arrow.

Here there are no other forms of energy at play here. Only potential and kinetic energy.

As we know that in any system the energy is conserved accordingly the elastic potential energy of the arrow will be equal to the kinetic energy of the bow after it is released i.e., 357 J.

Two balls collide in a head-on elastic collision and rebound in opposite directions. One ball has velocity 1.2 m/s before the collision, and −2.3 m/s after. The other ball has a mass of 1.1 kg and a velocity of −4.2 m/s before the collision. (a) What is the mass of the first ball? (b) What is the velocity of the second ball after the collision?

Answers

Answer:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

Explanation:

Mark me as brainliest and follow me

What do you do abt onion eyes (MY EYES ARE BURNING BADDD)

Answers

Answer:

Leave onions in cold water for about 15 minutes! Takes out the chemical reaction in the onion's defense system.

Explanation:

This is what people NEED to know for cooking... Lol :)

If you can answer my last post ill give you 75 points pls its very important and please make sure it correct!!!!!!!

Answers

Answer:

I can't see the post :/

Explanation:

Answer:

ok

Explanation:

ok how many points is this?????

Doing specific exercises to improve a particular skill or type of health fitness is called training? True or false

Answers

the statement is true

Bru challenge with the physics.

Answers

I don’t like school :(

Answer:

WHATATATATTAT

Explanation:

Which kind of wave interaction is shown?

Answers

Answer:

where?

Explanation:

ill edit my answer when see it

You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
30°
110
34°
120
38°
128
42°
133
46°
127
50°
119
54°
109
At which angle will the performer travel the shortest distance?
A. 44°
B. 54
Ο Ο Ο Ο
C. 32
D. 50°

Answers

Answer:

128

Explanation:

Answer:

54 degrees

Explanation:

Suppose that the space shuttle Columbia accelerates at 14.0 m/s2 for 8.50 minutes after takeoff.
A. What will be the speed of the shuttle at the end of 8.50 minutes?
B. How far will the shuttle have traveled during this time?

Answers

Answer:

A. speed = 7.14 Km/s

B. distance = 1820.7 Km

Explanation:

Given that: a = 14.0 m/[tex]s^{2}[/tex], t = 8.50 minutes.

But,

t = 8.50 = 8.50 x 60

  = 510 seconds

A. By applying the first equation of motion, the speed of the shuttle at the end of 8.50 minutes can be determined by;

v = u + at

where: v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

u = 0

So that,

v = 14 x 510

 = 7140 m/s

The speed of the shuttle at the end of 8.50 minute is 7.14 Km/s.

B. the distance traveled can be determined by applying second equation of motion.

s = ut + [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

where: s is the distance, u is the initial velocity, a is the acceleration and t is the time.

u = 0

s = [tex]\frac{1}{2}[/tex]a[tex]t^{2}[/tex]

  = [tex]\frac{1}{2}[/tex] x 14 x [tex](510)^{2}[/tex]

 = 7 x 260100

 = 1820700 m

The distance that the shuttle has traveled during the given time is  1820.7 Km.

Describe the difference between simply taking measurements and doing a scientific experiment.
In 2-3 sentences

Answers

Taking measurements might be something more of planning an experiment and a guess of how the experiment might end up! While doing an experiment is watching the action that was planned to happen or guessed to happen! Was this what you were looking for? Sorry if I’m like totally off

When scientists make models of dynamic physical events, they will normally choose to have values that may change as time progresses. What are these values called?

boundary conditions
initial conditions
outputs
gravity

Answers

Answer:

1. Initial conditions

2. The speed of a character at the moment of contact

3. The hardness of the sidewalk where the mug landed

4. The location where potential energy is zero

5. Aerodynamic properties

Explanation:

100%

The values that may change over time in a model are called initial conditions.

Scientists use models to represent actual conditions. A model is always a representation of real life situations and are very useful for explanatory and predictive purposes.

When scientists make models of dynamic physical events, they will normally choose to have values that may change as time progresses. These values are called initial conditions.

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Why are continental rocks much older than oceanic crust?
A. Oceanic crust is continually recycled through convection in the earth's mantle
B. Oceanic crust is made out of much less dense material than continental crust
C. Continental crust is continually renewed through convection in the earth's mantle
D. Continental crust eats oceanic crust for breakfast

Answers

Answer:

A. Oceanic crust is continually recycled through convection in the earth's mantle

Explanation:

The oceanic plate is constantly being recycled through the forces of convection within the earth's mantle.

New oceanic plate are formed mid-oceanic ridge for example. As the magma cools and solidifies, they are moved away continually.

This is not the case for the continental curst.

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OF CLAIMING
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B R A I N L I E S T

Which statement best explains why two flowers of the same species have different colored petals?:

A. exposure to sunlight

B. expression of an inherited trait

C. expression of an acquired trait

D. photosynthesis

You will get brainliest just for trying because i could use the help.

Answers

Answer:

B

Explanation:

it could be because they have a difference in genes

a steel is 40cm long at 20c.the coefficient of linear expansivity for steel is 0.000012.find the increase in length at 70C

Answers

Answer:

janakajnakanabjjiaj yav good day for you to everyone else to do with my family is it just doesn't want me and I am

What is the difference in
momentum between a 0.216 kg bird
flying 5.87 m/s and a 7.29 kg baby
crawling 0.234 m/s?

Answers

Answer:

0.438kg/ms-¹

Explanation:

Momentum, denoted by p, can be calculated by using the formula;

p = mv

Where;

m = mass (kg)

v = velocity (m/s)

Momentum (p) of bird = 0.216 kg × 5.87 m/s = 1.268kg/ms-¹

Momentum (p) of crawling baby = 7.29 kg kg × 0.234 m/s = 1.706kg/ms-¹

Having calculated the momentum of the bird to be 1.268kg/ms-¹, and the momentum of the baby to be 1.706kg/ms-¹, the difference in momentum between the flying bird and the crawling baby is:

{1.706kg/ms-¹ - 1.268kg/ms-¹} = 0.438kg/ms-¹

A student made a model of an onion skin cell she viewed using a microscope. The scale is 500:1. The student's cell model has a length of 15 cm. How many centimeters is the cells length

Answers

I feel like I'm in a city

Answer:

0.03 cm

Explanation: If the scale is 500:1, you have to divide 500 by 15 to get 0.03. You do not multiply 500 times 15 because the cells are smaller than the scale representation so you divide.


MULTIPLE CHOICE
Newton’s first law of motion is also known as the law of ______ while the Newton’s 2nd law of motion is known as the law of _____ and Newton’s third law is also known as the law of ______

Answers

Answer:

1st law known as low of inertial

2nd law of acelaration and force relationship

3rd law of action and reaction

A piece of wood from a nearby construction site floats near the shore of a lake. It floats in very calm water with half of its volume just above the surface. What is the density of this piece of wood

Answers

Answer:

Explanation:

The density of a substance can be described as the mass per volume of the substance. The density of the piece of wood described in the question can be calculated as the mass of the wood divided by the volume of the water the wood displaced (which was referred to in the question as making half of the wood's volume i.e half of the thickness of the wood was in the water).

The rotational inertia of a thin rod about one end is 1/3 ML2. What is the rotational inertia of the same rod about a point located 0.40 L from the end

Answers

Answer:

The value is  [tex]I = 0.0932 ML ^2[/tex]  

Explanation:

From the question we are told that

  The rotational inertia about one end is [tex]I_R = \frac{1}{3} ML^2[/tex]

   The location of the axis of rotation considered is [tex]d = 0.4 L[/tex]

Generally the mass of the portion of the rod from the axis of rotation considered to the end of the rod is  [tex]0.4 M[/tex]

Generally the length of the rod from the its beginning to the axis of rotation consider is

      [tex]k = 1 - 0.4 L = 0.6L[/tex]

Generally the mass of the portion  of the rod from the its beginning to the axis of rotation consider is

    [tex]m = 1- 0.4 M = 0.6 M[/tex]

Generally the rotational inertia about the axis of rotation consider for the first portion of the rod is

     [tex]I_{R1} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]

    [tex]I_{R1} = \frac{1}{3} (0.6 M )L^2 0.6^2[/tex]

Generally the rotational inertia about the axis of rotation consider for the second  portion of the rod is

     [tex]I_{R2} = \frac{1}{3} (0.6 M )(0.6L)^2[/tex]

=> [tex]I_{R2} = \frac{1}{3} (0.4 M )(0.4L)^2[/tex]

=>  [tex]I_{R2} = \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]

Generally by the principle of superposition that rotational inertia of the rod at the considered axis of rotation is

  [tex]I = \frac{1}{3} (0.6 M )L^2 0.6^2 + \frac{1}{3} (0.4 M )L^2 0.4^2[/tex]

=>   [tex]I = \frac{1}{3} ML ^2 [0.6 * (0.6)^2 + 0.4 * (0.4)^2 ][/tex]

=>   [tex]I = 0.0932 ML ^2[/tex]  


Electricity is produced in a hydroelectric plant when moving water turns a turbine.
Which describes this energy transformation from the turning turbine to electricity?
A
kinetic energy into electric energy
B
nuclear energy into electrical energy
С
thermal energy into electric energy
chemical energy into electric energy

Answers

Answer:

It involves both energy transformation and energy transfer.

Explanation:

In the hydroelectric power plant, the energy is transformed from kinetic energy to electricity. Therefore, option (A) is correct.

How is the energy transformed in the hydroelectric power plant?

In the hydroelectric power plant, electric energy is generated using water from a turbine. The moving water is used to propel the turbines. At first, a large amount of the flowing water is stored across the dams. The kinetic energy of moving water is stored as potential energy in the dams.

Then the stored water will fall on the turbines and rotate the turbines which causes the potential energy of water to be used to turn the turbines which is mechanical energy.

Therefore, the potential energy of water is converted into mechanical energy. Then the rotating turbines generate electricity and the mechanical energy is converted into electrical energy.

Therefore, the hydroelectric power plant converts the kinetic energy of water into electrical energy.

Learn more about the hydroelectric power plant, here:

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NEED HELP ASP
WILL GIVE POINTS OR WHATEVER

Answers

Answer:

you need to multiply the momentum and the mass

PLEASE PROVIDE AN EXPLANATION.

THANKS!!!

Answers

Answer:

(a) A = 0.0800 m, λ = 20.9 m, f = 11.9 Hz

(b) 250 m/s

(c) 1250 N

(d) Positive x-direction

(e) 6.00 m/s

(f) 0.0365 m

Explanation:

(a) The standard form of the wave is:

y = A cos ((2πf) t ± (2π/λ) x)

where A is the amplitude, f is the frequency, and λ is the wavelength.

If the x term has a positive coefficient, the wave moves to the left.

If the x term has a negative coefficient, the wave moves to the right.

Therefore:

A = 0.0800 m

2π/λ = 0.300 m⁻¹

λ = 20.9 m

2πf = 75.0 rad/s

f = 11.9 Hz

(b) Velocity is wavelength times frequency.

v = λf

v = (20.9 m) (11.9 Hz)

v = 250 m/s

(c) The tension is:

T = v²ρ

where ρ is the mass per unit length.

T = (250 m/s)² (0.0200 kg/m)

T = 1250 N

(d) The x term has a negative coefficient, so the wave moves to the right (positive x-direction).

(e) The maximum transverse speed is Aω.

(0.0800 m) (75.0 rad/s)

6.00 m/s

(f) Plug in the values and find y.

y = (0.0800 m) cos((75.0 rad/s) (2.00 s) − (0.300 m⁻¹) (1.00 m))

y = 0.0365 m

What famous equation describes the energy of stars?

Answers

Answer:

E=mc2

Explanation:

It explains that in their interiors, atoms fuse together, creating energy.

To solve this we must be knowing each and every concept related to energy and its different types. Therefore, the famous equation that describes the energy of stars is E=mc².

What is energy?

In physics, energy is the capacity to accomplish work. It can be potential, kinetic, thermal, electric, chemical, radioactive, or in other forms.

There is also heat and work—energy inside the process of being transferred by one body to the other. Energy is always classified according to its type once it has been transmitted. As a result, heat transported could become thermal energy, whereas labor done may emerge as mechanical energy. The famous equation that describes the energy of stars is E=mc²

Therefore, the famous equation that describes the energy of stars is E=mc².

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