Answer:
A should be the swer n
Explanation:
what should i do the next time i see someone that i havent seen in a year and they said they want to kiss me
Answer:
Well if you want to kiss them go for it, but if you don't then say sorry but I don't feel comfortable with that.
Hope everything goes well <3
6. Which of the process would you use to remove salt
dissolved in water?
opicean .Filtration, evaporation, chlorination
Answer:
Evaporation
Explanation:
You can use evaporation to separate the salt from the water.
Which of the following can be calculated from the mass of the reactants used in a chemical reaction? (Select all that apply)
Theoretical yield of products
Amount of limiting reactant used in a reaction
Actual yield of products
Amount of excess reactant from a reaction
Answer:
Can you explain it more please
Explanation:
Which of the following methods is least likely to help Alisha determine the age of sedimentary rock layers in her backyard?
A. Apply radiometric dating to determine the amount of radioactive isotopes in each rock layer.
B.Identify index fossils in sedimentary rock that have lived in a particular time in Earth’s history.
C. Analyze seismic diagrams to determine how radioactive elements break down into stable elements.
D. Use relative dating techniques to determine how individual fossil groups are related to specific rock layers.
ILL GIVE BRAINLIEST!11
Answer:
i put c
Explanation:
Rocks' ages are determined through radiometric dating, which takes into account the ratio of two different isotopes in a sample. Geologists can use tools like these to assess the age of a material,Mass spectrometer for thermal ionization Thus, option C is correct.
What determine the age of sedimentary rock layers?How rocks are structured in strata and how they fit into the larger geological history are the main topics of stratigraphic study. This approach is best suited for studying sedimentary rocks. Cross dating is a method for using fossils to determine a rock's relative age.
Therefore, Index fossils are sought after by geologists in geological strata. Index fossils are useful because they show the relative dates of the rock layers in which they are discovered. Since radioactive isotopes deteriorate with known time intervals.
Learn more about sedimentary rock here:
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Should vaccinations be required for students to attend public school?
Answer:
I don't think so for now, there hasn't been much research done with the vaccine and children so we really don't know how children's bodies will react to it. Once more studies are done with the vaccine and children and is proven safe then yes, kids should use it in order to attend public school.
During electrolysis, where do reduction reactions occur?
A. in the anode of an electrolytic cell
B. in the cathode of an electrolytic cell
C. in the power source of an electrolytic cell
D. in the salt bridge of an electrolytic cell
Answer:
B)
Explanation:
HOPE IT WILL HELP YOU
WAITING FOR YOUR RESPONSE
Answer:
( : The correct option is, (a) anode
Explanation:
Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is: CO(g)C(s) 1/2 O2(g) We could also write this reaction three other ways, listed below. The equilibrium constants for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.
The question is missing some parts. Here is the complete question.
Carbon monoxide is a colorless, odorless gas that binds irreversibly to hemoglobin in our blood, causing suffocation and death. CO is formed during incomplete combustion of carbon. One way to represent this equilibrium is:
[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]
we could also write this reaction three other ways listed below. The equilibrium constant for all of the reactions are related. Write the equilibrium constant for each new reaction in terms of K, the equilibrium constant for the reaction above.
1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex] K₁ =
2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex] K₂ =
3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] K₃ =
Answer: 1) [tex]K_{1}=\frac{1}{K}[/tex]
2) [tex]K_{2}=\frac{1}{K^{1/2}}[/tex]
3) [tex]K_{3}=K^{1/2}[/tex]
Explanation: A chemical reaction can be reversible, i.e., can proceed in both directions: to the right of the arrow (forward) or towards the left of the arrow (backward).
When the rates of forward and backward reactions are the same, the reaction is in equilibrium. In that state, we can determine the equilibrium constant, [tex]K_{c}[/tex].
For the first way to represent equilibrium of CO formed, the [tex]K_{c}[/tex] is calculated
[tex]2CO_{(g)}[/tex] ⇄ [tex]2C_{(s)}+O_{2}_{(g)}[/tex]
[tex]K=\frac{[O_{2}]}{[CO]^{2}}[/tex]
in which the symbol [ ] is concentration of the compound.
In equilibrium constant, solids are not included.
Equilibrium constants for the other reactions:
1) [tex]2C_{(s)}+O_{2}_{(g)}[/tex] ⇄ [tex]2CO_{(g)}[/tex]
[tex]K_{1}=\frac{[CO]^{2}}{[O_{2}]}[/tex]
Comparing K₁ and K, the first one is the inverse of K, so writing in terms of K
[tex]K_{1}=\frac{1}{K}[/tex]
2) [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex] ⇄ [tex]CO_{(g)}[/tex]
[tex]K_{2}=\frac{[CO]}{[O_{2}]^{1/2}}[/tex]
In terms of K, K₂ is
[tex]K_{2}=\frac{1}{K^{1/2}}[/tex]
3) [tex]CO_{(g)}[/tex] ⇄ [tex]C_{(s)}+1/2O_{2}_{(g)}[/tex]
[tex]K_{3}=\frac{[O_{2}]^{1/2}}{[CO]}[/tex]
This constant in terms of K will be
[tex]K_{3}=K^{1/2}[/tex]
In conclusion, K₁, K₂ and K₃ in terms of K is [tex]\frac{1}{K}[/tex],[tex]\frac{1}{K^{1/2}}[/tex] and [tex]K^{1/2}[/tex], respectively.
Convert 75g of NaOH to moles
Answer:
75g and I no inglish I my espanish perfec
Explanation:
A 1 mL sample weighs 4 g, the density of the sample is
Please help me answer this I will mark brainliest
Answer:
A is brain, ND the fact that u don't know this stuff is a lil bit sad, u can so look it
Explanation:
Describe the patterns and atomic mass is an ion charges in the periodic table
Answer:
The atomic number increases across a period and down the group or family. The atomic mass generally increases with atomic number with a few exceptions.
Salt of a weak acid with strong base When
dissolved in water gives?
Answer:
it gives base, it is process of neutralization,when acid reacts with base it gives salt and water
which planet in are solar system haves most moons
Answer:
Jupiter
Explanation:
5.6 g of an organic compound on burning with excess
of oxygen gave 17.6 g of CO2, and 7.2 g of H,O. The
organic compound is :
Answer:organic compound is : C₄H₈
Explanation: The equation of the reaction of the organic compound burning with excess oxygen gives us the general equation as
C xHy + 1/2(x+ y/2 )O₂ → xCO₂ + y/2H₂O
We first find the number of moles of CO₂ and H₂O
Number of moles of CO₂= Mass/ molar mass
= 17.6g/ 44g/mol ( 12+ 16 x2)
=0.4 moles
Number of moles of H₂O= Mass/ molar mass
= 7.2g/ 18g/mol ( 1 X 2+ 16)
=0.4 moles
From the reaction , we can see that
x = 0.4
and [tex]\frac{y}{2}[/tex]= 0.4 such that y= 0.4 x 2= 0.8
Their ratios become
[tex]\frac{x}{y}[/tex] =[tex]\frac{0.4}{0.8}[/tex]= [tex]\frac{4}{8}[/tex]
Therefor the organic compound CxHy = C₄H₈
_______________ is the interaction between organisms in an ecosystem.
Which ecosystem likely has the lowest species diversity?
O a habitat with high rainfall and high sunlight
O a habitat with low rainfall and high sunlight
O a habitat with low rainfall and low sunlight
O a habitat with high rainfall and low sunlight
Answer:
a habitat with low rainfall and low sunlight
Explanation:
Because little to nothing grows in ground that is frozen year-round except for some forms of microscopic life
Which two statements about composite materials is true?
A. They're made up of more than one substance
B. They have the same or similar properties as the materials used to make them
C. They're always made of metal
D. They're readily available in nature
help as fast as u can please
In the compound aluminum oxide, which is the cation?
Answer:
-Aluminum Oxide: The cation is Al3+ and the anion is O2-. The sum of the charges for aluminum oxide is 2(3+) + 3(2-) = 0. Thus, the formula is Al2O3. An ionic compound is named using the name of the cation followed by the name of the anion, eliminating the word ion from each.
Explanation:
4 moles of monoatomic ideal gas is compressed adiabatically causing the temperature to increase from 300 K to 400 K. Calculate the work done on the gas in units of Joules (if the answer is negative, be sure to enter a negative sign in your answer).
Answer:
the work done on the gas is 4,988.7 J.
Explanation:
Given;
number of moles of the monoatomic gas, n = 4 moles
initial temperature of the gas, T₁ = 300 K
final temperature of the gas, T₂ = 400 K
The work done on the gas is calculated as;
[tex]W = \Delta U = nC_v(T_2 -T_1)[/tex]
For monoatomic ideal gas: [tex]C_v = \frac{3}{2} R[/tex]
[tex]W = \frac{3}{2} R \times n(T_2-T_1)[/tex]
Where;
R is ideal gas constant = 8.3145 J/K.mol
[tex]W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W = \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J[/tex]
Therefore, the work done on the gas is 4,988.7 J.
This is the chemical formula for the compound calcium chloride: CaCl2
In this compound, how many atoms are combined?
O1
02
O3
O4
Answer:
3
Explanation:
1 Calcium atom and two chlorine atoms
Is this answer correct
Answer:
Yes
Explanation:
Convert Fahrenheit temperature
to Kelvin scales
Answer:
K = (F – 32)5/9 + 273.15
Explanation:
You basically convert Fahrenheit to Celcius and then to Kelvin
Here's the entire formula:
K = (x °F – 32)5/9 + 273.15
. Carbamide (CH4N2O), can be synthesized by the reaction of ammonia (NH3) with carbon
dioxide (CO2):
2 NH3 (aq) + CO2 (aq) CH4N2O (aq) + H2O (l)
An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia
with 105 kg of carbon dioxide. Determine the limiting reactant, theoretical yield of urea and percent yeild for the reaction
Answer:
NH₃ is the limiting reactant.Theoretical yield = 120 kg% yield = 72.9 %Explanation:
2NH₃ (aq) + CO₂ (aq) → CH₄N₂O (aq) + H₂O (l)First we convert the given masses of reactants to moles, using their respective molar masses:
68.2 kg NH₃ ÷ 17 kg/kmol = 4.01 kmol NH₃105 kg CO₂ ÷ 44 kg/kmol = 2.39 kmol CO₂2.39 kmol of CO₂ would react completely with (2.39 * 2) 4.78 kmol of NH₃. There are not as many NH₃ kmoles so NH₃ is the limiting reactant.
We calculate how much urea would form with a 100% yield, using the moles of limiting reactant:
4.01 kmol NH₃ * [tex]\frac{1kmolCH_4N_2O}{2kmolNH_3}[/tex] = 2.00 kmol CH₄N₂OWe convert that amount to kg:
2.00 kmol CH₄N₂O * 60 kg/kmol = 120 kg CH₄N₂OFinally we calculate the percent yield:
87.5 kg / 120 kg * 100% = 72.9 %PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP
DUE IN 5 MINUTES CHEMISTRY DIMENSIONAL ANALYSIS
In 2009, Usain Bolt ran 100 meters in 9.58 seconds. What is this speed in km/hr? (!! DIMENSIONAL ANALYSIS!! NOT A REGULAR PROBLEM)
Arsenate (AsO43-) is structurally and chemically similar to inorganic phosphate (PO43-), and many enzymes that act on phosphate will also use arsenate as a substrate if it is available. However, unlike phosphates, organic compounds of arsenate are kinetically unstable. For example, acyl phosphates (such as 1,3-bisphosphoglycerate) require an enzyme to catalyze phosphate hydrolysis on a biologically relevant timescale, but acyl arsenates hydrolyze almost instantaneously in water without an enzyme.
a) Predict the effect on the net reaction catalyzed by glyceraldehyde 3-phosphate dehydrogenase if phosphate were replaced by arsenate.
b) Write a balanced overall equation for the conversion of glucose to pyruvate in the presence of ATP, ADP, NAD+, and arsenate.
c) Arsenate is extremely toxic to most organisms. Based on your answers above, explain why.
Answer:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is used mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Explanation:
A) The effect on the net reaction catalyzed by glyceraldehyde is that
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived
C ) Arsenate is very toxic to most organisms and it is mostly regarded as poisons during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells
Those structures that are similar in all behavior is called homologous structure.
The answer of the following question is as follows:-
The effect on the net reaction catalyzed by glyceraldehyde is that the 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase ) There will be no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived Arsenate is very toxic to most organisms and it is used mostly regarded as a poison during the formation of glycolysis, it forms 1-arsen0, 3-phosphoglycerate which hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of a cell.For more information, refer to the link:-
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P4 +502 — P4010
What is the limiting reactant if you are using 25.0 grams of phosphorus and 50.0 grams of oxygen?
A.) O2
B.) P4
C.) P4O10
D.) P4O2
Answer:
B.) P4
Explanation:
Step 1: Convert 25.0 grams of phosphorus into moles of phosphorous:
25 g P4 x 1 mol P4/123.90 g P4 = 0.202 mol P4
Step 2: Convert 0.202 mol P4 into moles of O2 using their stoichiometric ratios:
0.202 mol P4 x 5 mol O2/1 mol P4 = 1.01 mol O2
Step 3: Convert 1.01 mol O2 into grams of O2:
1.01 mol O2 x 31.98 g O2/1 mol O2 = 32.3 g O2
Because 25.0 grams of phosphorous only needs 32.3 grams of oxygen to react, phosphorous will be the limiting reactant, as after the 25.0 grams of phosphorous is used up, there will still be 17.7 grams of oxygen leftover (excess reactant).
Because the reaction cannot occur without more phosphorous to react with the 17.7 grams of oxygen remaining, P4 is the limiting reactant.
Answer: B.) P4
Explanation:
Step 1: Convert 25.0 grams of phosphorus into moles of phosphorous:25 g P4 x 1 mol P4/123.90 g P4 = 0.202 mol P4
Step 2: Convert 0.202 mol P4 into moles of O2 using their stoichiometric ratios:0.202 mol P4 x 5 mol O2/1 mol P4 = 1.01 mol O2
Step 3: Convert 1.01 mol O2 into grams of O2:1.01 mol O2 x 31.98 g O2/1 mol O2 = 32.3 g O2
Because 25.0 grams of phosphorous only needs 32.3 grams of oxygen to react, phosphorous will be the limiting reactant, as after the 25.0 grams of phosphorous is used up, there will still be 17.7 grams of oxygen leftover (excess reactant).
Because the reaction cannot occur without more phosphorous to react with the 17.7 grams of oxygen remaining, P4 is the limiting reactant.
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A sample of 523.1 mg of impure KBr is treated with an excess of AgNO3 and 814.5 mg of AgBr is obtained. What is the purity of KBr?
Answer:
98.68%
Explanation:
Step 1: Write the balanced equation
KBr + AgNO₃ ⇒ AgBr + KNO₃
Step 2: Calculate the moles corresponding to 814.5 mg (0.8145 g) of AgBr
The molar mass of AgBr is 187.77 g/mol.
0.8145 g × 1 mol/187.77 g = 4.338 × 10⁻³ mol
Step 3: Calculate the moles of KBr needed to produce 4.338 × 10⁻³ moles of AgBr
The molar ratio of KBr to AgBr is 1:1. The moles of KBr needed are 1/1 × 4.338 × 10⁻³ mol = 4.338 × 10⁻³ mol.
Step 4: Calculate the pure mass corresponding to 4.338 × 10⁻³ moles of KBr
The molar mass of KBr is 119.00 g/mol.
4.338 × 10⁻³ mol × 119.00 g/mol = 0.5162 g
Step 5: Calculate the purity of KBr
0.5162 g of KBr are in a 0.5231 g-sample. The purity of KBr is:
P = 0.5162 g/0.5231 g × 100% = 98.68%
Why do particles with different masses have the same kinetic energy when at the same temperature?
Answer: Because Kinetic energy depends on temperature and not mass
Explanation:
Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:
[tex]K.E=\frac{3RT}{2}[/tex]
where K.E = Kinetic energy
R= gas constant
T= temperature in kelvin
It is visible that kinetic energy is dependent on the temperature of the system and not on the mass of the system. Thus particles with different masses have the same kinetic energy when at the same temperature
For case 1, what happens when an electron jumps from energy level 1 to energy level 3 in an atom?
Answer:
Case 1 (energy level): In an atom, an electron jumps from energy level 1 to energy level 3. ... The energy will increase.
Explanation:
The vapor pressure of liquid octane, C8H18, is 40.0 mm Hg at 318 K. A sample of C8H18 is placed in a closed, evacuated container of constant volume at a temperature of 448 K. It is found that all of the C8H18 is in the vapor phase and that the pressure is 71.0 mm Hg. If the temperature in the container is reduced to 318 K, which of the following statements are correct?
a. The pressure in the container will be 42.8 mm Hg.
b. Liquid octane will be present.
c. Only octane vapor will be present.
d. Some of the vapor initially present will condense.
e. No condensation will occur.
Answer:
a, d
Explanation:
a. The pressure in the container will be 42.8 mm Hg.
d. Some of the vapor initially present will condense.