How much work does an elephant do while moving a circus wagon 60 meters with a pulling force of 240N

Answers

Answer 1

Answer:

14,400

Explanation:

You need to do 240x60 and you would get the answer as 14,000


Related Questions

write the function of alcohol in a alcohol thermometer.​

Answers

Answer:

Ethanol-filled thermometers are used in preference to mercury for meteorological measurements of minimum temperatures and can be used down to −70 °C (−94 °F). The physical limitation of the ability of a thermometer to measure low temperature is the freezing point of the liquid used.

Which statement best describes wavelength?
wavelength is the speed at which a wave travels
wavelength is the height vertically of a wave
wavelength is the length of wave per sec
wavelength is the horizontal length of one complete wave cycle

Answers

Answer:

B

Explanation:

Wave length is the height perpendicular verically of a wave

Answer:

b

Explanation:

makes the most sense to me

2. A ray of light is incident at 60° in the air on an air glass plane surface find the angle of refraction in the glass. (mew for glass=1.5)
[tex] [/tex]

Answers

Answer:

35.2644

I suppose mew is refractive index

Explanation:

( sin i ) / (sin r) = refractive index

( sin 60) / (sin r) = 1.5

( sin 60) / 1.5 =sin r

r=35.844

sorry if I'm wrong

Please help

According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:

A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.

B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.

C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.

D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.

Answers

Answer:

don't know ....?

Explanation:

Please help

According to the seismograph recording of an earthquake shown above, we can conclude the following about this particular earthquake:

A.) The P-waves arrived at 24 min, the S- waves arrived at 27 min, the P-waves had a larger amplitude than the S- waves, and therefore the P- waves carried more energy than the S-waves.

B.) The P-waves arrived at 24 min, the S-waves arrived at 27 min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.

C.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27 min, the P-waves had a larger amplitude than the S-waves, and therefore the P- waves carried less energy than the S-waves.

D.) The P-waves arrived at 9hrs 24min, the S-waves arrived at 9hrs 27min, the S-waves had a larger amplitude than the P-waves, and therefore the S-waves carried more energy than the P-waves.

Answer This!!!!!!
I'll give brainliest to whoever gets it right.

Answers

Answer:

yes the answer is C. 32.16

The answer is c 32.16 days

a heavy jar sits on top of a 3.4 m shelf with a gravitational potential energy of 180 j. What is the mass of the jar?

Answers

Answer:

5.2941176471 kg or 5294.1 grams

Explanation:

g.p.e= mgh

g.p.e/gh=m

180j/10×3.4= m

180/34= m

5.2941 kg= m

A 70 kg hunter, standing on frictionless ice, shoots a 42 g bullet horizontally at a speed of 650 m/s . Part A What is the recoil speed of the hunter

Answers

Answer:

Explanation:

momentum is conserved. Initial momentum was zero, so final total momentum must also be zero

0.042(650) + 70v = 0

v = -0.39 m/s

|v| = 0.39 m/s

A 60.0 kg person jumps onto the floor from a height of 3.0m. Find
the KE of the jumper when she hits the ground.

Answers

Answer:

1800 J

Explanation:

GPE= mgh

60*3*10

=1800 J

how long does it take to reach the moon?

Answers

Over the past few decades man has always embarked on different space exploration by traveling to the moon. A typical Journey to the moon from Earth will take about 3 days in recent times.

It takes about 3 days for a spacecraft to reach the Moon. During that time a spacecraft travels at least 240,000 miles

In the year 1969 the first man (Neil Armstrong ) landed on the moon, the journey took him 8 days, 3 hours, 18 minutes, 35 seconds, on 16 July.

Research on space exploration is still growing and expanding, with large amount of funding and support globally.

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An action that has the ability to change an object’s state of motion is

Answers

Answer:

An unbalanced force

Explanation:

Answer:

Force

Explanation:

Trust me

An object accelerates at a rate of -3.2 m/s^2 to a velocity of 8 m/s over a time of 14 s. What was its initial velocity?

Answers

[tex]\text{Given that,}\\\\\text{Acceleration, a = -3.2 m s}^{-2}\\\\\text{Time, t = 14 sec}\\\\\text{Velocity, v = 8 m s}^{-1}\\\\\text{Initial velocity, v}_0 = ?\\\\\\v = v_0 +at\\\\\implies v_0 = v -at = 8 -(-3.2)(14) = 8 + 44.8 =52.8~ \text{m s}^{-1}[/tex]

Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each other during the pouring process, one piece of grain picks up a charge of 6.0 E -10 C and another piece of grain picks up a charge of 2.3 E -15 C. What is the electric force between them if the pieces of grain are 2 cm apart?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.

Answers

Answer:

3.1×10⁻¹¹ N is

Explanation:

is the answer

Suppose a cannon is sitting on top of a 50.0 m high hill and a 5.00 kg cannon ball is fired with a velocity of 30.0 m/s at some unknown angle. What is the velocity of the cannon ball when it strikes the earth?

Answers

The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

The given parameters:

Height of the hill, h = 50 mMass of the cannon, m = 5 kgVelocity of the ball, v = 30 m/s

The final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;

[tex]P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s[/tex]

Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

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Which of the following is the equation for acceleration?

Answers

Answer:

A

Explanation:

acceleration = velocity / time

Hope that helps

Answer:

D

Explanation:

Average acceleration = final velocity- initial velocity, divided by elapsed time.

ā = V - Vo/t

= change in velocity ÷ change in time

PLSSS HELP WILL MARK AS BRIANLIEST
The atomic mass is equal to the number of ______.
A.Protons
B.Electrons and neutrons
C.Neutrons and protons
D.neutrons

Answers

The answer is C : Neutrons and Protons

Best way to demonstrate that waves transfer energy

Answers

Answer:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

Explanation:

Magma usually stays below the Earth's
under great pressure.
o mantle
Inner core
outer core
Crust

Answers

Answer:

In the inner vote part of the earth

2) A traffic light of weight 100 N is supported by two ropes as shown. Let T1 and T2 are the tensions.
a. Resolve the vectors into its components and find their values [ 4 marks]
b. Find sum of the x-components [1 mark]
c. Find sum of the y-components [1mark]
d. Use the above equations to find the tensions in the ropes?
the two angles on x and y are both 37 I cant upload the diagram

Answers

Hi there!

a.

We know that:

[tex]\Sigma F_y = 0 \\\\\Sigma F_x = 0[/tex]

Begin by determining the forces in the vertical direction:

W = weight of traffic light

T₁sinθ = vertical component of T₁

T₂sinθ = vertical component of T₂

b.

The ropes provide a horizontal force:

T₁cosθ = Horizontal component of T1

T₂cosθ = Horizontal component of T2

Thus:

0 = T₁cosθ  - T₂cosθ

T₁cosθ = T₂cosθ

T₁ = T₂

c.

Since the angles for both ropes are the same, we can say that:

T₁ = T₂

Sum the forces:

ΣFy = T₁sinθ + T₁sinθ - W = 0

2T₁sinθ = W

d.

Now, we can begin by solving for the tensions:

2T₁sinθ = W

[tex]T_1 = T_2 = \frac{W}{2sin\theta} = \frac{100}{2sin(37)} = \boxed{83.08 N}[/tex]

1. In Newton's cannonball experiment, if the velocity is larger than the orbital velocity the Cannon
ball will
1. stay in orbit
2. fall to the earth
3. escape the earth
4. none of the above

Answers

Answer:

escape the earth I think

In Newton's cannonball experiment, is the velocity is larger than the orbital velocity the Cannon ball will escape the Earth. Thus, the correct option is 3.

What was Newton's Cannonball experiment?

In this experiment, Newton visualizes a stone that is a cannonball which is being projected on top of a very high mountain. And, if there were no gravitational force or air resistance in that area, the body should follow a straight line path away from the Earth, in the direction in which it was projected.

If the cannonball is launched at a velocity that matches the orbital velocity of the planet, then it will not be able to be drawn in by gravitational force due to the Earth which results into moving away from the cannonball at the same speed at which the cannonball itself is falling.

If the velocity of the cannonball is larger than the orbital velocity than the ball will escape the Earth.

Therefore, the correct option is 3.

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An apple is falling from its tree. While falling, its acceleration changes
but not direction. Explain.

Answers

it changes ever 9.8 m/sec2.

9.8m/sec 2 that’s the answer for your question :)

. Prior to Remy's trip to Cleveland, his uncle tells him about this amazing barbecue restaurant there and raves about
the food and live music. Remy looks it up once he gets to Cleveland, and he finds that there are a number of
negative reviews about it. Nevertheless, he focuses on the few positive reviews he comes across, convinces himself
they are probably more valid than the negative ones, and decides to go to the restaurant after all. Remy has likely
been influenced by:
the availability heuristic.
confirmation bias.
O the representativeness heuristic.
oming

Answers

whats the restraunt called

Based on the scenario, Remy has likely been influenced by framing effect.

What is framing effect?

In Psychology, framing effect can be defined as a cognitive bias wherein a person's choice from a group of options is primarily influenced by the positive or negative connotations pertaining to the options.

In this scenario, Remy did a research on the barbecue restaurant and finds that there are a number of both negative and positive reviews about it. However, he convinced himself by relying on the positive reviews and decides to go to the restaurant.

In conclusion, we can deduce that Remy has likely been influenced by framing effect.

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True or False If the mass of the object increases, then the potential energy of the object decreases.​

Answers

Answer:

The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases.

Explanation:

Answer:

Explanation:

It depends on where your reference frame for potential energy is chosen.

If a mass is above the reference origin and mass increases, potential energy will increase so the statement is FALSE

If the mass is at the reference origin and the mass increases, the potential energy stays constant at zero so the statement is FALSE

If the mass is below the reference origin and the mass increases, then the potential energy goes from a negative value to an even lower negative value so the statement in this case is TRUE

You are investigating how objects move when they are dropped from different heights. To collect your data, you drop a 1 kg weight from different heights and record the time it takes for the object to hit the ground when dropped from different heights. The data you collect is shown below:

Height dropped (m)

Time to fall (s)

1.0

0.45

2.0

0.63

3.0

0.78

4.0

0.89



Next, you plan to drop a 5 kg weight from the same heights. How will your time values in your new data table for the 5 kg weight compare to the time values in the old data table for the 1 kg weight?

Answers

The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

The given parameters;

Mass of the first object, m1 = 1 kg

Mass of the second object, m2 = 5 kg

The final velocity of the objects during the downward motion is calculated as follows;

[tex]v_f = v_0 + gt\\\\v_f = 0 + gt\\\\\v_f = gt[/tex]

The time of motion of the object from the given height is calculated as;

[tex]h = v_0 t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} }[/tex]

The time of motion of each object is independent of mass of the object.

Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

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is it true that playing badmenton help you to become a better person?

Answers

Answer:

There is no scientific evidence that playing specifically l badminton makes you a better person, but sport and exercise in general release hormones which can make you feel more happy therefore making you nicer to the people around you and 'a better person'.

Answer:

It's true because playing any sport makes a person happy. So a happy person is a better person.

Please Mark as brainliest.

How might "Roller Coaster Physics" have been different if the author's purpose had been to warn
readers of the dangers of roller coasters?
Use at least two details from the passage to support your answer.

Answers

Answer: The answer is hupa loopa

Explanation:

The slope of a line on a distant-time graph is
A. distance
B. time
C. speed

Answers

Answer:

c. speed

Explanation:

In a distant-time graph the x value is usually the time and the y value is usually the distance.

If slope is the change in y over the change in x, on a distant time graph the slope would be the change in time over the change in distance

Or time / distance.

Time / distance happens to calculate speed.

Thus, the slope of a line on a distant-time graph is speed.

[tex]\huge\textbf{Hey there!}[/tex]

[tex]\large\textbf{The formula for Slope of a line is: }\mathbf{m = \dfrac{rise}{run}}\large\textbf{ whereas it is}\\\large\textbf{equal to/equivalent to }\mathbf{ \dfrac{y_2 - y_1}{x_2- x_1} \ .}\\\\\large\textbf{Basically, the slope of the line is measured with its }\\\large\textbf{\underline{steepness}. The word steepness simply means a}\\\lage\textbf{very sharp slope.}[/tex]

[tex]\large\textbf{On slope of a line on distant-time graph is basically how }\\\large\textbf{ \boxed{\bf FAST} a particular object is.}[/tex]

[tex]\large\textbf{Now, that we got that information out of the way we}\\\large\textbf{can find out our answer.}[/tex]

[tex]\large\textbf{The formula for distance is: }\mathbf{d= \sqrt{(x_2 - x_1)^2 + (y_2 +y_1)^2}}}[/tex]

[tex]\large\textsf{We cannot say that OPTION A isn't your answer because you}\\\large\textsf{cannot calculate slope of a line on a distant-time graph. You}\\\large\textsf{cannot calculate the speed of the object by using that formula.}\\\large\textsf{So, this eliminates Option A. as your answer.}[/tex]

[tex]\large\textbf{The formula of time is: }\mathbf{time = \dfrac{distance}{speed}}[/tex]

[tex]\large\textsf{Yes, it calculates the distance but it doesn't calculate how fast a(n)}\\\large\textsf{object is going. So this eliminates Option B. as your answer.}[/tex]

[tex]\large\textsf{The formula for speed is: }\mathbf{s = \dfrac{d}{t}}\large\textbf{ whereas s = \underline{speed}, }\\\large\textsf{d = \underline{distance} you have \underline{traveled}, \& t = \underline{time} that has}\\\large\textsf{been \underline{elapsed}.}\\\large\textsf{Option C. could possibly be your answer}[/tex]

[tex]\large\textbf{Option C. seems to be the closes to your result than the}\\\large\textbf{to your answer.}[/tex]

[tex]\large\boxed{\text{Therefore, your answer should be: \boxed{\textbf{Option C. Speed}}}}\huge\checkmark[/tex]

[tex]\huge\textbf{Good luck on your assignment \&}\\\huge\textbf{enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

A ball is launched from ground level at 30 m/s at an angle of 35° above the horizontal. how far does it go before it is at ground level again

Answers

Answer:

Explanation:

Ignoring air resistance

Initial vertical velocity is 30sin35 = 17.2 m/s

Gravity reduces this velocity to zero in a time of

t = v/g =17.2 / 9.8 = 1.755 s

it takes the same time to come back down to ground level for a total flight time of 2(1.755) = 3.51 s

The horizontal velocity is 30cos35 = 24.57 m/s

the distance traveled horizontally is

d = vt = 24.57(3.51) = 86.298... = 86 m

In Newton's cannonball experiment, if the velocity is equal the orbital velocity the Cannon ball
will
O stay in orbit
O fall to the earth
O escape the earth
O none of the above

Answers

In Newton's cannonball experiment, if the velocity is equal to the orbital velocity then the cannonball will stay in Orbit.

Newtons cannonball experiment stated that the distance that a cannonball will travel, before being drawn into the Earth by the forces of gravity, is dependent on the initial velocity.

Therefore, if the cannonball is launched at a velocity that matches the orbital velocity, then it will not be able to be drawn in by gravity due to the Earth moving away from the cannonball at the same speed at which the cannonball itself is falling.

This means that the cannonball will continue to fall without reaching the Earth, therefore staying in orbit, much like that of the moon or planets around the sun.

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What is an ellipse?

a plane that slices between orbits

an oval-shaped orbit

a circular orbit

the center of gravity between orbiting objects​

Answers

Answer:

i think it's C thx correct me if wrong

A 30-cm-tall, 4.0-cm-diameter plastic tube has a sealed bottom. 250 g of lead pellets are poured into the bottom of the tube, whose mass is 30 g, then the tube is lowered into a liquid. The tube floats with 5.0 cm extending above the surface. What is the density of the liquid

Answers

The density of the liquid will be equal to   [tex]\rho=0.892 \ \dfrac{g}{cm^3}[/tex]

What is density?

The density of an object is defined as the ratio of the mass of an object to the volume of the object.

Volume of tube = 2^2 * pi * 30 = 377 cm^3

Volume of tube submerged = 25* 377 / 30 = 314 cm^3

Buoyancy = weight of liquid displaced

Volume of liquid displaced = 314 cm^3

Mass of tube and lead = 250 + 30 = 280 g

Now from the mass density by definition

[tex]\rho = \dfrac{m}{v}[/tex]

[tex]m=\rho \times v[/tex]

Mass of liquid displaced = Mass being supported

[tex]314 \times \rho = 280 g[/tex]

[tex]\rho= \dfrac{280}{ 314 } = .892 \frac{g}{cm^3}[/tex]

Thus the density of the liquid will be equal to   [tex]\rho=0.892 \ \dfrac{g}{cm^3}[/tex]

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The density of the liquid is 1.67 g/[tex]cm^3[/tex].

The volume of the tube is

30 * 4 * 3.14 * 0.25 = 94.2 [tex]cm^3[/tex].

The mass of the lead pellets and the plastic tube is

30 + 250 = 280 g.

The volume of the lead pellets is

250 / 11.34 = 22 [tex]cm^3[/tex].

The volume of the liquid that the tube displaces is

94.2 - 22 = 72 [tex]cm^3[/tex].

The density of the liquid is

280 / 72 = 1.67 g/ [tex]cm^3[/tex].

Therefore, the density of the liquid is 1.67 g/ [tex]cm^3[/tex].

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