Explanation:
There are 6.022x1023 molecules in 1 mole of SO3 (Avogadro's number) so in 0.25 moles, there are (0.25)(6.022x1023) molecules in the 0.25 moles of SO3. or 1.506x1023 molecules per 0.25 moles of SO3.
There is one atom of sulfur in each molecule of SO3. So there are 1.506x1023 atoms of sulfur in 0.25 moles of SO3.
According to the concept of Avogadro's number there are 0.7525 ×10²³ atoms of sulfur in 0.125 moles of sulfur.
What is Avogadro's number?Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.
It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .
According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.
Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number
In the given example, number of atoms of sulfur are calculated as, Avogadro's number×number of moles, that is,6.022×10²³ ×0.125=0.75275×10²³ atoms
Therefore, there are 0.75275×10²³ atoms in 0.125 moles of sulfur.
Learn more about Avogadro's number,here:
https://brainly.com/question/11907018
#SPJ2
A bottle labeled 0.01 M HCl is found in the laboratory. Assuming that the HCl is completely ionized calculate the [H+], [OH-] and the pH of the solution.
Answer:
[H⁺] = 0.01 M[OH⁻] = 1x10⁻¹² MpH = 2Explanation:
The assumption that the HCl is completely ionized means that the original concentration of the acid is equal to [H⁺].
[H⁺] = 0.01 MWith [H⁺], we can calculate [OH⁻], by using the following formula:
[H⁺] * [OH⁻] = 10⁻¹⁴0.01 M * [OH⁻] = 10⁻¹⁴[OH⁻] = 1x10⁻¹² MFinally we calculate the pH of the solution:
pH = -log[H⁺]pH = 28
What happens to solid waste in the circulatory system?
A it's expelled through the lungs
B
It pumps into the coronary circulation
C
It's dropped off in the kidneys
D
It's deposited in the aorta
Answer:c it’s dropped off in the kidneys
Explanation:
I took the quiz
The solid wastes are from the circulatory system is expelled to the kidney where, the nitrogenous wastes like urea and uric acid is excreted as urine from the body.
What is circulatory system ?A circulatory system is an organ system, where the blood is purified and oxygenation of blood takes place. Through circulatory system, the blood reaches throughout the body pumped from the heart through veins.
The organs included in circulatory system are lungs, heart, aorta, veins, blood vessels etc. There are various kinds of blood vessels each having specific functions.
There is a network of blood vessels including arteries and large veins, capillaries that join the venules and other veins. All the nutrients and ions are circulated throughout the body through blood and solid wastes are then expelled to kidney.
Kidney function as a sieve to clean the good fluid from waste products. Uric acid and urea along with water excreated as urine then. Thus, option C is correct.
To find more about circulatory system, refer the link below:
https://brainly.com/question/10103458
#SPJ6
Why is a wire used to connect the electrodes in an electrochemical cell?
O A. To provide the metal that is the oxidizing agent
B. To prevent the flow of protons from electrodes
C. So ions can flow from one electrode to another
D. So electrons can flow from one electrode to another
Answer:
D. So electrons can flow from one electrode to another
Explanation:
An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.
An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.
Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.
The enthalpy of formation of water is -285.8 kJ/mol. What can be inferred from this statement? O The enthalpy of the products is equal to the enthalpy of the reactants. O Heat is absorbed during the process. O Heat is released during the process. The enthalpy of the products is more than the enthalpy of the reactants.
Answer:
the answer is c
Explanation:
i did the test
The enthalpy of the formation of water is -285.8 kJ/mol. The information that can be made by the statement is heat is released during the process. The correct option is C.
What is enthalpy?Enthalpy is the volume times the pressure times the internal energy of the system. It is an entity of thermodynamics. It is the measurement of the energy in a thermodynamic system. The enthalpy totals the internal energy plus pressure and volume.
The statement that is given here is given that enthalpy is -285.8 kJ/mol. The value is negative, so the energy is released here. When energy is gained the energy will be positive and when the energy is released it is negative.
Thus, the correct option is C, heat is released during the process regarding the given statement of enthalpy.
To learn more about enthalpy, refer to the link:
https://brainly.com/question/24136717
#SPJ6
Use the equations below to calculate the enthalpy of formation for propane gas, C3H8, from its elements, hydrogen gas and solid carbon. Please hurry!!
Answer: I got -4542.9kg/mol
Explanation:
Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol
[tex] △H_{f} = Product [/tex]Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :
Product = [tex] 3CO_{2} + 4H_{2}0[/tex] Product = 3(-393.5) + 4(-285.8) = - 2323.70Reactant = [tex] C_{3}H_{8} + 5H_{2}0[/tex] Water, H20 has △H = 0Reactant = [tex] C_{3}H_{8} + 0[/tex]
Enthalpy of formation = product - Reactant
2219.2 = -2323.70 - (propane + 0)
2219.2 = - 2323.70 - propane
Propane = - 2323.70 - 2219.2
[tex] C_{3}H_{8} = - 4542.9 [/tex]
Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.
Learn more :https://brainly.com/question/1261360
Which of the following would result in being able to dissolve a greater amount of gas in a solution?
Answer:
Lower the temperature of the solution
10 ml of a 0.25M solution is diluted to make exactly 250 ml of solution. What's the concentration of the diluted solution?
Answer:
0.01 M
Explanation:
As this problem deals with a dilution process, we can solve it by using the following formula:
C₁V₁=C₂V₂Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.
That means that in this case:
C₁ = 0.25 MV₁ = 10 mLC₂ = ?V₂ = 250 mLWe input the given data:
0.25 M * 10 mL = C₂ * 250 mLC₂ = 0.01 M200.0g of a 3.0% NaF solution, how much distilled water do we weigh out?
197g of distilled water
194g of distilled water
140g of distilled water
170g of distilled water
Answer:
194g of distilled water.
Explanation:
Hello there!
In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:
[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]
And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:
[tex]m_w=200g-6g=194g[/tex]
Therefore, the answer is 194g of distilled water
Regards!
What [H3O+] in a solution of a PH of 0.60 is
Determine the hydroxide ion concentration in
a solution that is 0.00034 M Ca(OH)2.
Answer in units of M.
Answer:
[tex]0.00068M[/tex]
Explanation:
Hello there!
In this case, according to the ionization of calcium hydroxide, a strong base:
[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]
Thus, since there is a 1:2 mole ratio of calcium hydroxide to hydroxide ions, we apply the following proportional factor to obtain:
[tex]0.00034\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\=0.00068\frac{OH^-}{L}\\\\=0.00068M[/tex]
Regards!
Study the reaction.
CH4 + 2O2 → CO2 + 2H2O
If 7.4 moles of carbon dioxide (CO2) form at the end of the reaction, how many moles of methane (CH4) and oxygen gas (O2) entered the reaction?
? moles of methane and
? moles of oxygen gas
7.4 moles of methane (CH₄)
14.8 moles of oxygen gas (O₂)
At 27.0°C, the volume of a gas is 630 L. At the same pressure, its volume is 92,0 mL at a temperature of
Answer:
–272.96 °C
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 27.0 °C
Initial volume (V₁) = 630 L.
Final volume (V₂) = 92.0 mL
Final temperature (T₂) =?
Next, we shall convert 27.0 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 27.0 °C
Initial temperature (T₁) = 27.0 °C + 273
Initial temperature (T₁) = 300 K
Next, we shall convert 92.0 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
92 mL = 92 mL × 1 L / 1000 mL
92 mL = 0.092 L
Next, we shall determine the final temperature.
Initial temperature (T₁) = 300 K
Initial volume (V₁) = 630 L.
Final volume (V₂) = 0.092 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
630 / 300 = 0.092 / T₂
2.1 = 0.092 / T₂
Cross multiply
2.1 × T₂ = 0.092
Divide both side by 2.1
T₂ = 0.092 / 2.1
T₂ = 0.04 K
Finally, we shall convert 0.04 K to celsius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
Final temperature (T₂) = 0.04 K
Final temperature (T₂) = 0.04 – 273
Final temperature (T₂) = –272.96 °C
How are tadpoles and larvae similer
Answer: Tadpole, also called polliwog, aquatic larval stage of frogs and toads. Compared with the larvae of salamanders, tadpoles have short, oval bodies, with broad tails, small mouths, and no external gills. The internal gills are concealed by a covering known as an operculum.
Explanation:
What would the products be for the reaction between Na3PO4 + MgSO4?
MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2
Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2
Explanation:
QUESTION 29 The PH of a solution whose Hydroxide ion concentration is 0.45M is:
A. 0.071
B. 0.347
C. 13.65
D. 12.48
E. 12.7
Answer:
C. 13.65.
Explanation:
With the given hydroxide ion concentration [OH⁻] we can calculate the pOH of the solution, using the following formula:
pOH = -log[OH⁻]pOH = 0.35Then, with the pOH we can proceed to calculate the pH of the solution, with the formula:
pH + pOH = 14pH = 14 - pOHpH = 13.65The correct answer is option C. 13.65.
PLEASE HELP!! ORGANIC CHEMISTRY
A sample of a diatonic gas is loaded into an evacuated bottle at STP. The 0.25 L bottle contains 1.76 grams of the unidentified gas. Calculate the molar mass of the gas. What is the identity of the diatomic gas?
Answer:
(a) 157.7 g
(b) 7.04 g/dm³
Explanation:
(a) From the question,
According to Avogadro's Law,
1 mole of every gas at STP occupies a volume of 22.4 dm³
But mass of 1 mole of the diatomic gas = molar mass of the gas.
This Implies that,
The molar mass of the gas at STP occupies a volume of 22.4 dm³
From the question,
If,
0.25 L bottle contain 1.76 g of the gas,
Therefore,
Molar mass of the gas = (1.76×22.4)/0.25
Molar mass of the gas = 157.7 g.
(b) Density of the gas = mass/volume
D = m/v
Given: m = 1.76 g, v = 0.25 L = 0.25 dm³
Therefore,
D = 1.76/0,25
D = 7.04 g/dm³
Calculate the molarity of the two solutions.
The first solution contains 0.200 mol of NaOH in 2.00 L of solution.
The second is 15.5G of NaCl in 671mL of solution
Answer:
a) 0.100 M
b) 0.395 M
Explanation:
a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution
We will use the following expression for molarity.
[NaOH] = moles of solute / liters of solution
[NaOH] = 0.200 mol/2.00 L = 0.100 M
b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution
We will use the following expression for molarity.
[NaCl] = mass of solute / molar mass of solute × liters of solution
[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M
[H+] [OH-] =
NEED HELP ASAP!!!
What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe reacts with 2.1 g of O2?
4 Fe + 3O2 —> 2Fe2O3
Answer:
Fe is limiting reactant and 3.00g of Fe2O3 will be produced
Explanation:
To solve this question we must convert the mass of each reactant to moles and, using the reaction we can find limiting reactant. With moles of limiting reactant we can find moles of Fe2O3 and its mass as follows:
Moles Fe -Molar mass: 55.845g/mol-
2.1g * (1mol / 55.845g) = 0.0376 moles
Moles O2 -Molar mass: 32g/mol-
2.1g * (1mol / 32g) = 0.0656 moles
For a complete reaction of 0.0656 moles of O2 are needed:
0.0656moles O2 * (4mol Fe / 3 mol O2) = 0.0875 moles Fe
As there are just 0.0376 moles,
Fe is limiting reactant
The mass of Fe2O3 is:
Moles:
0.0376 moles Fe* (2mol Fe2O3 / 4mol Fe) = 0.0188 moles Fe2O3
Mass:
0.0188 moles Fe2O3 * (159.69g / mol) =
3.00g of Fe2O3 will be produced
1. Which individuals are most likely to die before reproducing, those with adaptive traits or
nonadaptive traits? Why? (Hint: You may use the newt population as an example in your
explanation.)
What is one movement that liquid water CANNOT do while on or at the Earth's surface? (GIVE RIGHT ANSWER OR I DELETE 100 POINTS)
Answer:
One movement that i can't do is float in mid air
Explanation:
Hl Weakly dissociates in water according to the chemical equation below. H20+ Hl <-> H3O^+ + l- What is a conjugate acid-base pair in this reaction?
Answer:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
Explanation:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?
Answer:
32.5 moles of O2(g) are necessaries for a complete reaction
Explanation:
Based on the reaction of combustion of C4H10(g):
C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)
1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.
That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:
5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =
32.5 moles of O2(g) are necessaries for a complete reaction
If 3.13 mol of an ideal gas has a pressure of 2.33 atm and a volume of 72.31 L, what is the temperature of the sample in degrees Celsius?
Answer:
382.49 C degree Celsius
Explanation:
Hello,
This problem deals with understanding the ideal gas law which hopes to predict how ideal gases might behave in any given condition. I listed the formula below and we are basically just going to solve for temperature by rearranging the equation as seen on the picture (there's also other rearranged ones in case you need to solve for those).
Universal gas constant R has a value of 0.0821 L * atm/(mole * K) when working with these given units so it will be part of this equation. R value changes based on what units you have.
T = PV/nR
= (2.33) (72.31) / (3.13)(0.0821)
= 655.64 K
Question is asking temperature in celsius so we employ the formula attached below:
C = K - 273.15
= 655.64-273.15
= 382.49 degree Celsius
382.49 degree Celsius is the answer!
What does pressure measure
Answer:
Pressure measurement is the analysis of an applied force by a fluid (liquid or gas) on a surface. Pressure is typically measured in units of force per unit of surface area.
hope this helps! mark as brainlist! :D
Answer:
THIS IS YOUR ANSWER I HOPE IT IS HELPFUL PLZ MARKS ME BRANILYHow are solutions and compounds similar?
Answer:
hope you liked it!!!!!!
A compound is a pure substance that is composed of elements chemically bonded in definite proportions. A compound can be broken down into simpler substances only by chemical reactions, such as electrolysis.
A solution is a homogeneous mixture, meaning that it is the same throughout. A solution is composed of one or more solutes dissolved in a solvent. The proportions of the solute(s) can vary, as the components of a solution are not chemically bonded. The components of a mixture can be separated by physical means, such as filtration and distillation
Every cell is surrounded by a thin membrane. What is the main function of this cell membrane?
A.
to protect the cell from invasion by bacteria and viruses
B.
to allow each cell to form connections with other cells
C.
to limit the size of the cell and keep the shape of the cell the same
D.
to separate the inside of the cell from the outside environment
Answer:
The main function of the cell membrane is to protect the cell from the outer environment.
Answer: The answer is D.) to separate the inside of the cell from the outside environment
Explanation:
A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is contained in a 0.200-kg aluminum calorimeter cup. The final temperature of the system is 30.5 Celsius. What is the specific heat of the metal alloy in J/Kg.Celsius
Answer:
[tex]C_{alloy}=0.497\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:
[tex]Q_{allow}=-(Q_{water}+Q_{Al})[/tex]
Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:
[tex]m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})[/tex]
Then, we solve for specific heat of the metallic alloy to obtain:
[tex]C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}[/tex]
Thereby, we plug in the given data to obtain:
[tex]C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}[/tex]
Regards!
If the pH of a solution is 6.96, then the solution is a
Answer:
acid
Explanation:
solution with pH less than 7 is acid
those with more that 7 is base
those equal to 7 is neutral
what is the most metallic item on the pterotic table
Answer:
francium or cesium