How many moles are in 8.7 x 104 atoms of oxygen?

.Answer:

2kclo3 --> 2kcl + 3o2 is a decomposition reaction because it is breaking apart (thinks decompose- to break apart/down)

H2 + I2 --> 2HI is a synthesis reaction because synthesis is like creation/ building

think DNA synthesis or the book of genesis in the bible about creation

2 Na + 2 H20 --> NaOH + H2 --- not balanced at all

other one is a balanced equation- the Zn + 2HCl one

Explanation:

Answer:

d. NaOH Sodium hydroxide soluble

First, make sure to balance your equation.

3H2(g) + N2(g) ⇄ 2NH3(g)

Now, you can write your Kc expression. Remember that Kc is products over reactants, and the exponent for each product or reactant is based on its coefficient.

Kc = [NH3]^2 / [H2]^3[N2]

The reaction between nitrogen and hydrogen is called the Haber process. Kc for the reaction is the ratio of the concentration of ammonia to nitrogen and hydrogen.

An equilibrium constant, kc is the concentration proportion of the products to the concentration of the reactants raised by their respective coefficients.

The balanced chemical Haber process is given as:

[tex]\rm 3H_{2}(g) + N_{2}(g) \leftrightharpoons 2NH_{3}(g)[/tex]

Now, the equilibrium constant for the reaction can be given as:

[tex]\rm Kc = \rm \dfrac{[NH_{3}]^{2}}{[H_{2}]^{3}[N_{2}]}[/tex]

Therefore, the ratio of the concentration of ammonia to hydrogen and nitrogen gives the equilibrium constant.

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Answer: a. 50 kJ

Explanation: good luck

Answer:

mark me as brainliest plsss

Hence in the Sodium hydroxide, methyl orange will turn into yellow color and in Sulfuric acid shows red color. Red litmus will turn into blue color in the Sodium hydroxide solution.

Litmus paper is a paper which is used to identify the acidity or basicity of any solution.

Hence, the effect of red litmus & methyl orange is explained above.

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Answer:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)[/tex]

Explanation:

Hello there!

In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI+H_2O[/tex]

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

[tex]HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)[/tex]

Which is also balanced as the number of atoms of all the elements is the same at both sides.

Best regards!

Answer:

1 K

2 P

3 P

4 P

5 K

6 K

7 K

8 P

9P

10 K

Answer:

A -  Nitrile compound

B-   AlkylAmine

C-   Alcohol

D -  Alkene

Explanation:

(A) undergoes reduction to form alkylamine.

(B) is a primary alkyl amine which on carbylamine test gives a foul smell.

(B) reacts with NaNO2 + HCl undergoes diasotisation following which alcohol is produced.

(C) being a alcohol undergoes hydrolysis to give alkene.

(D) On further reaction with H2S04 by the rule of Markownikoff rule it forms a isomer of (C).

Answer:

For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively

Explanation:

The computation of the mass of each element is given below:

As we know that

A1 mole of ammonium nitrate i.e. 2 mol N, 4 mol H, 3 mol

Now we multiply each of above  by the molar masses

For N

= 14.0 g/mol × 2

= 28.0 gN

For H

= 1.0 g/mol × 4

= 4.0 gN

ANd, for O

= 16.0 g/mol × 3

= 48.0 gN

Hence, For Mass N, Mass H, and Mass O, the mass is 28.0 g N, 4.0 g H, and 48.0 g respectively

Answer:

Energy is transferred between trophic levels when one organism eats another and gets the energy-rich molecules from its prey's body.

Explanation:

The flow of energy in an ecosystem is always linear ie uni direction. At each energy step in food chain, the energy received by the organisms is used for its own metabolism and maintenance. The left over energy is passed to next higher trophic level. Thus the energy flow decreases with successive trophic level.

Answer:

63.25 grams of CO₂

Explanation:

To convert from liters to grams, we first need to convert from liters to moles. To do this, we divide the liters by 22.4, the amount of liters of a gas per mole.

32.2 / 22.4

= 1.4375 moles of CO₂

Now we want to convert from moles to grams. To do this, we multiply the moles by the molar mass of CO₂. The total molar mass can be found on the periodic table by adding up the molar mass of carbon (12) and two oxygen (32).

12 + 32 = 44

Now we want to multiply the moles by the molar mass.

1.4375 • 44

= 63.25 grams of CO₂

This is your answer.

Hope this helps!

Answer:

[tex][NO_2]=0.112M[/tex]

Explanation:

Hello there!

In this case, since the second-order integrated law is given by the following equation:

[tex]\frac{1}{[NO_2]} =\frac{1}{[NO_2]_0}+kt[/tex]

Thus, given the initial concentration of the nitrogen dioxide gas, the rate constant and the elapsed time, we obtain:

[tex]\frac{1}{[NO_2]}= \frac{1}{0.477M} +0.54M^{-1}s^{-1}\\\\\frac{1}{[NO_2]}=8.933M^{-1}[/tex]

[tex][NO_2]=\frac{1}{8.933M^{-1}} =0.112M[/tex]

Best regards!

Answer:

k

Explanation:

Answer:28 g

Explanation:

Answer:

the correct answer is D

Explanation:

Basically, melting ice is an endothermic reaction because the ice absorbs (heat) energy, which causes a change to occur.

Answer:

1 - D) friction

2- B) rough

3- B) gravity

4- A)smooth

5- C)gravity pulls you down

Answer

PubChem CID/molecular formula

Explanation:

Cesium bromide

PubChem CID 24592

Molecular Formula CsBr or BrCs

Synonyms CESIUM BROMIDE 7787-69-1 Caesium bromide Cesiumbromide Cesium bromide (CsBr) More...

Molecular Weight 212.81 g/mol

Component Compounds CID 260 (Hydrogen bromide) CID 5354618 (Cesium)

have a good day /night

may i please have a branllist

Yes it is an cleaning product

Answer:

yes

Explanation:

it cleans in the house

Answer:

[H⁺] = 2.57x10⁻⁶ M

Explanation:

This problem can be solved using the definition of pH:

pH = -log[H⁺]

Now we isolate [H⁺] in the equation:

-pH = log[H⁺]

[tex]10^{-pH}[/tex]=[H⁺]

As we are given the pH by the problem, we can now proceed to calculate the [H⁺]:

[H⁺] = [tex]10^{-5.59}[/tex]

[H⁺] = 2.57x10⁻⁶ M

Thus, when the pH of a solution is 5,59; the molar concentration of H⁺ species is 2.57x10⁻⁶.

Answer:

2c11h21

Explanation:

Answer:

x = 3/6.02 = 0.50.

Explanation:

1 mole of CO2 has 6.02 x 10^23 molecules of CO2.

Say x moles of CO2 has 3.0x10^23 molecules of CO2.

Therefore x = 3/6.02 = 0.50.

Complete question is;

When the concentrations of reactant molecules are increased, the rate of reaction increases. The best explanation for this phenomenon is that as the reactant concentration increases,

A)the average kinetic energy of molecules increases.

B)the frequency of molecular collisions increases.

C)the rate constant increases.

D)the activation energy increases.

E)the order of reaction increases.

Answer:

B) The frequency of molecular collisions increases.

Explanation:

When we increase number of reactant molecules, the effective collision between the reactant molecules will form a product which also increases. As a result, the overall rate of the reaction will also increase which means the frequency of the molecular collision will also increase as well.

Thus, the correct answer is Option B

Answer:

C. Methane

Explanation:

Hopefully this isnt too late!

Answer:

C. Methane

(Photo for proof at the bottom.)

Explanation:

All amino acids contain an amino group, a carboxyl group, and an R group. An amino group consists of NH2. A carboxyl group consists of COOH. And an R group usually consists of a hydrogen or carbon atom bonded to the amino acid. Methane only consists of CH4, which clearly does not meet the criteria of an amino acid.

Here's a photo of Edge incase you're doubtful.

Please click the heart if this helped.

Answer:

breathed in air contains oxygen while breathed out air contains higher percentage of CO2

Answer:

see calculations below

Explanation:

Given:     HOAc     ⇄    [H⁺]     +    [OAc⁻]            

C(i)          0.12M             0M           0.15M

mix  => 5.55ml(0.092M NaOH) / (50ml + 5.55ml)

            = 0.00555(0.092)mole NaOH / 0.0555 L Soln

            = 0.0092M in NaOH is added into the initial buffer solution

            = 0.0092M in OH⁻ (NaOH is a strong base => 100% ionized)

Rxn => Addition of 0.0092M OH⁻ will react with 0.0092M H⁺ shifting buffer            .           equilibrium to the right decreasing [HOAc] and increasing [OAc⁻] by    .           0.0092M each.

Therfore ...

Given:           HOAc      ⇄    [H⁺]     +       [OAc⁻]            

C(i)                0.12M             0M               0.15M

ΔC           - 0.0092M           +x            +0.0092M

C(f)             0.1108M             x                0.1592M  =>  New Concentrations            .                                                                                     after adding 0.0092M             .                                                                                     NaOH

Substituting new acid and ion concentrations into Ka expression ...

Ka = [H⁺][OAc⁻]/[HOAc] = (x)(0.1592M)/(0.1108M) = 1.75 x 10⁻⁵M

=> x = [H⁺](new) = (1.75 x 10⁻⁵M*)(0.1108M)/(0.1592M) = 1.22 x 10⁻⁵M in H⁺ ions

*units of Ka are Molar

FYI => Adding a strong base to a buffer solution will shift pH to more basic.

          Adding a strong acid   to a buffer solution will shift pH to more acidic.

=> (such is a good way to check that your buffer calculations are correct.)

NOTE => Question asks for moles of HOAc, Na⁺OAc⁻ & NaOH after adding base. Giving answers in terms of Molarity (moles/Liter) is same as moles. Therefore ...

[HOAc] = 0.1108M

[NaOAc] = 0.1592M

[NaOH] = ∅M (from rxn of H⁺ + OH⁻ => H₂O, all NaOH was consumed in acid/base reaction.  Remaining are only Na⁺ as a spectator ion and OH⁻ as a function of the new concentration of H⁺ => [OH⁻] = Kw/[H⁺] = 1 x 10⁻¹⁴/1.22 x 10⁻⁵ = 8.2 x 10⁻¹⁰M.

Hope this helps. :-)

Answer:

he total mechanical energy E of a particle is defined as the sum of the kinetic and potential energies

Explanation:

Answer:

thermal energy

Explanation:

Having a greater volume definitely means a lower concentration (molarity) of solution. So, the statement is true.

Molarity of a solution is defined as the number of moles of solute present per unit volume of solution.

Here,

Since, the number of moles of solute in one litre of solution is known as the molarity, we can say that the change in volume of the solution will affect the molarity of the solution.

Molarity, M = n/V

where n is the number of moles of solute and V is the volume of solution

From the equation, we can say that the molarity of the solution is inversely proportional to its volume.

We know that, molarity of a solution is a temperature dependent parameter.

As the volume of the solution increases, the temperature also increases( Volume [tex]\alpha[/tex] Temperature). When the temperature increases, it affects the molarity of the solution such that the number of moles remains constant and as a result of the increasing volume, the molarity decreases.

Hence,

Having a greater volume definitely means a lower concentration (molarity) of solution.

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