How many atoms are in 14 moles of I? Watch your significant figures.
A. 8.4 x 10^24 atoms of l
B. 8.43 x 10^24 moles of l
C. 8.4 x 10^23 atoms of I
D. 8.43 atoms of l

Answer:

sry i don't know that language

Answer:

Using dimensional analysis:

3.01x1022 molecules CO2 x 1 mol CO2/6.02x1023 molecules x 44. g CO2/mole = 2.20 g CO2

Explanation:

Answer:

581 Joules.

Explanation:

Using the formula;

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

According to the information provided in this question;

Q = ?

mass of ice = 15.9g

initial temperature = -4°C

final temperature = 14°C

Hence, ∆T = 14 - (-4) = 14 + 4 = 18°C

specific heat capacity (c) of ice in J/g°C = 2.03 J/g°C

Using Q = m × c × ∆T

Q = 15.9 × 2.03 × 18

Q = 32 × 18

Q = 581 Joules.

Answer:

A. light energy is used in photosynthesis and created by respiration

Answer:

Correct answer-C 5.3g

Explanation:

Molarity = no. of moles of solute/ volume of of solution in litre

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,

olarity = no. of moles of solute/ volume of of solution in litreno of moles of solute = 0.125×0.25=0.03125one mole AgNO3 weighs 169.87 gm,so the mass of 0.03125 moles of AgNO3 = 0.03125×169.87= 5.3084g

The grams of AgNO₃ are needed to prepare 0.125 M solution in 250 mL of water is 5.3 grams.

Moles is a unit which is used to define any amount and it is calculated as:

n = W/M, where

W = required mass

M = molar mass

Given molarity of AgNO₃ = 0.125 M

Volume of water = 250mL = 0.25L

moles (n) from the molarity (M) will be calculated as:

n = M × V

n = (0.125)(0.25) = 0.0312 moles

Now we calculate the mass of AgNO₃ by using the above formula as:

W = (0.0312mol)(169.87g/mol)

W = 5.30 g

Hence option (c) is correct.

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Answer:

D 8.8

Explanation:

To solve this question you must know that, using the kw equation:

Kw = 1x10⁻¹⁴ = [H⁺] [OH⁻]

-log 1x10⁻¹⁴ = -log ([H⁺] [OH⁻])

14= -log [H⁺] + -log [OH⁻]

As pH = -log[H⁺] and pOH = -log [OH⁻]

we can obtain the equation:

pH = 14 - pOH

As the pOH of the solution is 5.2:

pH = 14 - 5.2

pH = 8.8

Right option is:

Answer:

It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...

Explanation:

It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...

Answer: ...

Explanation:

Sodium, chlorine

Answer:

2Na = 2 Sodium [has 2 atoms]

Cl2 = Dichlorine (Chlorine) [has 2 atoms]

Is this what you wanted?? I'm not entirely sure if this is the answer you were looking for.

Answer:

A) chlorine

Explanation:

To solve this question we can use:

PV = nRT

In order to solve the moles of the gas. With the moles and the mass we can find the molar mass of the gas to have an idea of its identy:

PV = nRT

PV / RT = n

Where P is pressure: 603mmHg * (1atm / 760mmHg) = 0.7934atm

V = 100mL = 0.100L

R is gas constant = 0.082atmL/molK

T is absolute temperature = 14°C + 273.15 = 287.15K

0.7934atm*0.100L / 0.082atmL/molK*287.15K = n

3.37x10⁻³ moles of the gas

In 0.239g. The molar mass is:

0.239g / 3.37x10⁻³ moles = 70.9g/mol

The gas with this molar mass is Chlorine, Cl₂:

Answer:

0.208333 M

Explanation:

M2=M1V1/V2=(0.25 M)(125mL)/(125mL+25 mL)= 0.208333 M

Answer: The value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]

Explanation:

[tex]CH_3COOH\rightarrow H^+CH_3COO^-[/tex]

 cM              0             0

[tex]c-c\alpha[/tex]        [tex]c\alpha[/tex]          [tex]c\alpha[/tex]  

So dissociation constant will be:

[tex]K_a=\frac{(c\alpha)^{2}}{c-c\alpha}[/tex]

Give c= 0.85 M and [tex]pH[/tex] = 2.4

[tex]pH=-log[H^+][/tex]

[tex][H^=}=c\times \alpha=10^{-2.4}=3.98\times 10^{-3}[/tex]

[tex]K_a=?[/tex]

Putting in the values we get:

[tex]K_a=\frac{(3.98\times 10^{-3})^2}{(0.85-3.98\times 10^{-3})}=1.87\times 10^{-5}[/tex]

Thus the value of acid ionization constant [tex]K_a[/tex] for acetic acid is [tex]1.87\times 10^{-5}[/tex]

Answer:

30.26 grams of N₂O₃

Explanation:

Divide by Avogadro's number. This leaves you with the number of moles. Then, multiply by the molar mass of N₂O₃

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, the correct option is option C.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound.  Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

Since phosphorus is a nonmetal, we need a metal. Out of given option the only element that is metal is Magnesium while others are non metal.

Therefore, the correct option is option C.

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Answer:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

190.14 mL of the NaOH solution would be required.

Explanation:

The balanced reaction is:

Now we calculate how many H₂SO₄ moles are there in 25.00 mL of a 5.400 M solution, using the definition of molarity:

Now we convert H₂SO₄ moles into NaOH moles, using the stoichiometric coefficients of the balanced reaction:

Finally we calculate the volume of a 1.420 M solution that would contain 270 mmoles:

Answer:

≅ 4.88 grams (3 sig. figs.)

Explanation:

to convert from ...

grams to moles => divide by formula wt.

moles to grams => multiply by formula wt.

this problem:

mass in grams = 488moles / 100.09g/mol = 4.875612 grams (calculator)

≅ 4.88 grams (3 sig. figs.)

. Consider a sample of oxygen gas at 27° C with a volume of 9.55L at a pressure

Answer:620 k

Explanation:

Answer:

sorry po

indi ko po maintindihan

Answer:

the volume of a give gas simple is directly propotional assolute temperature at constant pressure .the volume of a gavi. amount of gass is inversely propotional ot Its pressure when temperature is help constant

Answer:

energy

Explanation:

Answer:

The difference is due to the fact that one water molecule has two hydrogen atoms to one oxygen atom, as explained above. This means it takes two water molecules (2 H2O) to make one oxygen molecule (O2)

Explanation:

Answer:

In H20 does the 2 apply to Hydrogen

Explanation:

In H₂O there is two atoms of hydrogen and 1 atom of Oxygen

Hence, In H20 does the 2 apply to Hydrogen

-TheUnknownScientist

Answer:

Explanation:

molecules NH3 = 1.47 moles x 6.02x1023 molecules/mole = 8.9x1023 molecules of NH3

Answer:

Hydroelectric pumped storage can be used to eliminate the conditional nature of wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.

Explanation:

Pumped-storage hydroelectricity is a type of hydroelectric energy storage used by electric power systems to store excess electrical power during periods of low demand for later release at periods when demand for energy rises again. It stores energy in the form of gravitational potential energy of water, pumped from a lower level reservoir to a higher level reservoir.

At times of low electrical demand, excess generated energy is used to pump water into the upper reservoir. When there is higher demand, water is released back into the lower reservoir through a turbine, generating electricity.

This form of energy storage is useful in circumventing the conditional nature of renewable energy sources such as wind and solar energy. At times of peak production of energy from either solar or wind (during summer and windy days), the excess electrical energy produced can be stored using hydroelectric pumped storage methods. When conditions no longer favour energy production from either wind or solar sources, these stored energy can then be regenerated for use.

Answer:

nope its a myth don't worry :)

Answer:

A

Explanation:

Answer:

they help to calm the bees when the person keeping the bees inspects there hives.