How do you know square root c is a right angle?

Answer:

They are used to share something among friends , Like if there are four friends and they want to divide a cake equally among themselves , then the quantity of cake that each friend will get will be one-fourth of the cake , That is a rational number 1/4.

Step-by-step explanation:

short answer it won't trust me

Answer:

(20,0)

Step-by-step explanation:

I think that's it sorry if I am wrong:(

Answer:

-4.515

Step-by-step explanation:

3.5 times 5.8 is 20.3 and then 3.5 times -7.09 is -24.815 added together to get -4.815 so technically its none of those but they might have miss typed so i think probably -4.515

one solution i think it has one solution

Answer:

p = 1

Step-by-step explanation:

Δ JKH ≅ Δ JIH

therefore KJ corresponds with IJ so you can set both sides equal to each other

10p = p+9

9p = 9

p = 1

Given :

Some angles in degree.

To Find :

1) Complement of 75 degree

2) Complement of 40 degree

3) Complement of 71 degree

4) Complement of 101 degree ​

Solution :

We know, two angles are complement when their sum is 90 degree.

1) Complement of 75 degree is, 90 - 75 = 15 degree.

2) Complement of 40 degree is, 90 - 40 = 50 degree.

3) Complement of 71 degree is, 90 - 71 = 19 degree.

4) Complement of 101 degree is, 90 - ( -101 ) = 191 degree.

Hence, this is the required solution.

Answer:

[tex]\frac{9}{16}[/tex]

Step-by-step explanation:

[tex]\frac{1 \frac{1}{2} * \frac{3}{4}}{2}=\frac{9}{16}[/tex]

Expressions can be expressed as equations or as inequalities.

The difference is that the variables in a system of equation have one solution each, while in a system of inequalities, the variables have a range of values.

Let the system of equation be:

[tex]\mathbf{ax + by = c}[/tex]

[tex]\mathbf{dx + ey = f}[/tex]

Let the system of inequality be:

[tex]\mathbf{ax + by < c}[/tex]

[tex]\mathbf{dx + ey > f}[/tex]

Both systems can be solved using the same method, such as: graphs, substitution and elimination.

However, the difference is that:

In a system of equation, the variables can have one solution each, while in a system of inequalities, the variables have a range of values.

Read more about system of equations and inequalities at:

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Answer:

21 cubic inches (or cu. in)

Step-by-step explanation: Multiply 7 by three

Answer:

I have no idea sorry :c

Step-by-step explanation:

Answer:

Acute

Obtuse

Right

Acute

Step-by-step explanation:

To see if a triangle is acute, right, or obtuse, you use something similar to the pythagorean theorem:

Let a and b be the shorter sides, c be the longest side.

If a^2+b^2 > c^2, then the triangle is acute.

If a^2+b^2 = c^2, then the triangle is right.

If a^2+b^2 < c^2, then the triangle is obtuse.

Answer: B.1 2/5 − a fraction less than 2/5

Step-by-step explanation:

Question was not formatted properly and in the proper format, the above is the answer.

1²/₅ - ²/₅ = 1

Any number therefore that is lower than ²/₅ will when subtracted from 1²/₅ give an answer greater than 1 because when ²/₅  was subtracted from  1²/₅, it gave 1 as an answer.

Answer:

Step-by-step explanation:

they're the same figure but turned 90 deg

congruent sides:

AD and RQ

BA and SR

BC and SP

PQ and CD

congruent angles:

D and Q

R and A

B and S

C and P

haven't done this in a minute sorry if this is wrong

Answer:

[tex]y = - 1x + 9[/tex]

Step-by-step explanation:

Remmeber:

[tex]Slope = \frac{rise}{run} [/tex]

Answer:

subtracting both equations

3x-10y=14

3x-9y=15

- - =-

_________

0-y=-1

y=1

then putting the value of y in first eqn

3x-10×1=14

3x=24

x=8

so x is 8and y is 1

Answer:

its A because it can't be B or D obviously, and since there are the least amount of elephants, its gonna be the one will less of a percentage. So its A.

Step-by-step explanation:

jabsbabsbavvsbabs

Answer:

fhyedGFYUSEGCFUEGFCYU

Step-by-step explanation:

pay back

Answer:

49m^4 - 25

Step-by-step explanation:

The simpler expression can simply be found by expanding

The kind of expansion we have here is the difference of two squares

(a + b)(a-b) = a^2 - b^2

Thus, we have it that;

(7m^2-5)(7m^2 + 5)

=

49m^4 - 25

Answer:

We have the angles as;

8.9 and 72.2

Step-by-step explanation:

When two angles are complementary, they add up to 90

Let the first angle be x , the second angle is 72.2 degrees less and it is x-72.2

Thus, mathematically;

x + x - 72.2 = 90

2x = 90+ 72.2

2x = 162.2

x = 81.1

x = 81.1

The other will be

81.1 - 72.2 = 8.9

Answer:

isosceles

Step-by-step explanation:

Answer:

An isosceles

Answer:

3.75 as a decimal

Step-by-step explanation:

Answer

when 2 triangle scales are similar the ration reduces and become a scale factor

Answer:

The scale factor is 2

Step-by-step explanation:

Answer:

[tex]\displaystyle \frac{d}{dx} \Big [ \frac{3}{x^2} \Big ]=-\frac{6}{x^3}[/tex]

Step-by-step explanation:

We can use either the Power Rule or the Quotient Rule to find the derivative of 3/x².

Rewrite [tex]\displaystyle \frac{3}{x^2}[/tex] as [tex]\displaystyle 3\cdot \frac{1}{x^2}[/tex] which is equivalent to [tex]3\cdot x^-^2[/tex].

Now we can apply the power rule to 3x⁻². Subtract 1 from the exponent and multiply the coefficient by -2.

This can be rewritten as [tex]\displaystyle -\frac{6}{x^3}[/tex].

Substituting 3 for f(x) and x² for g(x), we get:

Simplify.

Using exponent rules, we can rewrite this as:

This can be rewritten as [tex]\displaystyle -\frac{6}{x^3}[/tex], which is the same as what we got using the product rule.

Answer:

[tex]\displaystyle \frac{d}{d x}\left[\frac{3}{x^2}\right] = -\frac{6}{x^{3}}[/tex].

Step-by-step explanation:

Let [tex]f(x)[/tex] and [tex]g(x)[/tex] denote two functions of [tex]x[/tex]. Assume that [tex]g(x) \ne 0[/tex]. The quotient rule states that:

[tex]\displaystyle \frac{d}{d x}\left[\frac{f(x)}{g(x)}\right] = \frac{{f}^\prime(x) \cdot g(x) - f(x) \cdot g^{\prime}(x)}{{(g(x))}^2}[/tex].

In this question:

Find [tex]{f}^{\prime}(x)[/tex] and [tex]{g}^{\prime}(x)[/tex].

Notice that the value of [tex]f(x)[/tex] is constantly [tex]3[/tex] regardless of the value of [tex]x[/tex]. By the constant rule, [tex]{f}^{\prime}(x) = 0[/tex].

For [tex]{g}^{\prime}(x)[/tex], consider the power rule:

if [tex]m[/tex] represents a rational number (such as [tex]2[/tex],) then by the power rule, [tex]\displaystyle \frac{d}{d x}\left[{x}^{m}\right] = m\, {x}^{m-1}[/tex].

Apply this rule to find [tex]{g}^{\prime}(x)[/tex].

[tex]\begin{aligned}{g}^{\prime}(x) &= \frac{d}{d x} \left[x^{2}\right] \\ &= 2\, x^{2 - 1} \\ &= 2\, x\end{aligned}[/tex].

Substitute [tex]f(x) = 3[/tex], [tex]{f}^{\prime}(x) = 0[/tex], [tex]g(x) = x^{2}[/tex], and [tex]{g}^{\prime}(x) = 2\, x[/tex] into the quotient rule expression to find [tex]\displaystyle \frac{d}{d x}\left[\frac{3}{{x}^{2}}\right][/tex]:

[tex]\begin{aligned}&\; \frac{d}{d x}\left[\frac{3}{{x}^{2}}\right] \quad \genfrac{}{}{0em}{}{\leftarrow f(x) = 3}{\leftarrow g(x) = {x}^{2}} \\ =&\; \frac{d}{d x}\left[\frac{f(x)}{g(x)}\right]\\ =&\; \frac{{f}^\prime(x) \cdot g(x) - f(x) \cdot g^{\prime}(x)}{{(g(x))}^2} \\ =& \; \frac{0 \, x^2 - 3\, (2\, x)}{\left({x}^{2}\right)} \\ =&\; -\frac{6}{x^{3}}\end{aligned}[/tex].

Therefore, [tex]\displaystyle \frac{d}{d x}\left[\frac{3}{{x}^{2}}\right] = -\frac{6}{x^{3}}[/tex].

Answer: (9x^2)^2 -1^2

Step-by-step explanation:

Jake rewrite the expression as,

⇒ (3x - 1) (3x + 1) (9x² + 1)

Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.

Given that;

The expression is,

⇒ 81x⁴ - 1

And, Jake rewrites the expression as a difference of squares so he can factor it.

Now, We can rewrite the expression as;

⇒ 81x⁴ - 1

⇒ (9x²)² - 1²

⇒ (9x² - 1) (9x² + 1)

⇒ ((3x)² - 1²) (9x² + 1)

⇒ (3x - 1) (3x + 1) (9x² + 1)

Learn more about the mathematical expression visit:

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Answer:

3(3x−2)

Step-by-step explanation:

Answer:

We get [tex]\mathbf{(f-g)(x)= -x^2-3x-8}[/tex]

Step-by-step explanation:

We are given:

[tex]f(x) = -3x - 3\\ g(x) = x^2 + 5[/tex]

We need to find (f-g)(x) (assuming there is x in the bracket, i.e. (f - g) () should be (f-g)(x))

We would simply subtract f(x) and g(x)

[tex](f-g)(x)\\= -3x-3-(x^2+5)\\Multiply\:minus\:sign\:with\:terms\:inside\:the\:bracket\\=-3x-3-x^2-5\\Combining\:like\:terms:\\=-x^2-3x-3-5\\=-x^2-3x-8[/tex]

So, We get [tex]\mathbf{(f-g)(x)= -x^2-3x-8}[/tex]