If a nonzero net force is acting on an object, then the object is definitely _____.
a. at rest
b. being accelerated
c. moving with a constant velocity
d. losing mass.
An object is definitely being accelerated when a nonzero net force is acting on it: Option B.
A net force refer to the vector sum of all the forces that are acting on an object or physical body. Thus, a net force is a single force that substitutes the effect of all the forces acting on an object or physical body.
According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass.
This ultimately implies that, an object is definitely being accelerated when a nonzero net force is acting on it.
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what is the unit of measurement for expressing the intensity of sound
What is the control group
Answer: the group in an experiment that doesn’t get treatment
Explanation:
Please I need help with this ❤️ ?
Answer:
Compound 'A' C5H12 does not react with phenyl hydrazine. Oxidation of 'A' with K2Cr2o7,/H" gives B' (c5H10o). Compound 'B' reacts with phenyl hydrazine but does not give Tollen's test. The
3) A 14 kg object is sitting at the top of a hill that is 100 m high. What is the potential energy of the
object?
Answer:
13,720 joules
Explanation:
Epotential = mgh
mass x gravity x height
Ep= 14 x 9.8 x 100
Ep=13,720 joules
batman recharges his bat taser with 2500 joules of energy in 15 minutes. how much power does it draw from the mains
help omg
An object, moving with a constant velocity, travels 400 m in 25 s. What is its velocity?
A balloon is rubbed against a sweater. Which of the following describes the result of this interaction?(1 point)
The outer shell electrons move from the balloon to the sweater.
The fibers of the sweater lose electrons.
The balloon becomes positively charged.
The free electrons in the balloon decreases.
Answer:
The fibers of the sweater lose electrons.
moving east with a constant velocity of 30 m/s for 5 seconds. What is the object's
acceleration?
a. O m/s/s
C. 30 m/s/s
b. 6 m/s/s
d. 150 m/s/s
When traveling north from the United States into Canada, you'll see the North Star (Polaris) getting _________. lower in the sky higher in the sky dimmer brighter
When traveling north from the United States into Canada, you'll see the
North Star (Polaris) getting higher in the sky .
This is because the polaris which is also known as North Star is located
very close to the north celestial pole. When an objects moves towards the
north , the polaris gets higher due to its upward northern location.
This is the major reason why when traveling north from the United States
into Canada, you'll see the North Star (Polaris) getting higher.
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Answer:
Higher
Explanation:
As you go further north, the Star Polaris rises in the sky. This is due to it being circumpolar meaning that the star doesn't move in the night sky (Often)
Send right answers plzzzz plz
Answer:
I think A
Explanation:
Anyone please.??????
Answer:
468.42572 Wavelength In Metres
Explanation:
Answer:
[tex]\huge\boxed{\sf Wavelength= 470\ m}[/tex]
Explanation:
Given Data:
Speed of light = c = 3 × 10⁸ m/s (Constant)
Frequency = f = 640 kHz = 6.4 × 10² × 10³ Hz = 6.4 × 10⁵ Hz
Required:
Wavelength = λ = ?
Formula:
λ = c / f
Solution:
λ = 3 × 10⁸ / 6.4 × 10⁵
λ = 0.47 × 10³
λ = 4.7 × 10² m
λ = 470 m
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH18074) What is the kinetic energy of a 5 kg object moving ot a velocity of 25 m/s?
Help me please I’m confused
A 100kg diver jumps off a 40m cliff. Ignoring the affects of air resistance, determine the
time it would take for the diver to reach the water.
Answer:2.86seconds
Explanation:
H=gt^2/2
t=2h/g
A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?
The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
The given parameters:
Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 NThe net force on the pail of water at the top of the vertical circle is calculated as follows;
[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]
Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s
We are given;
Mass of the pail of water; m = 2000 g = 2kg
Radius of the circle; r = 1 m
Tension exerted by string; T = 25 N
To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;
W - T = ma
Where;
W is weight = mg
T is tension on the string
Now, in circular motion, we know that;
Acceleration is; a = v²/r
Thus;
mg - T = m(v²/r)
Making v the subject of the formula gives us;
v = √[(r(T + mg)/m)
Plugging in the relevant values gives;
v = √[(1(25 + (2 * 9.8))/2)
v = 4.722 m/s
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define the unit of work
[tex]\text{The unit of work is same as energy. Newton-meters(Nm) or Joules(J).}\\[/tex]
what two properties change when light is refracted
Answer:
Refraction is merely one of several possible boundary behaviors by which a light wave could behave when it encounters a new medium or an obstacle in its path. The transmission of light across a boundary between two media is accompanied by a change in both the speed and wavelength of the wave.
Explanation:
From one point on the ground, the
angle of elevation of the peak of a
mountain is 10.38°, and from a
point 15,860 ft closer to the
mountain, the angle of elevation is
14.67º. Both points are due south of
the mountain. Find the height of the
mountain.
10.38°
一企一
14.67°
15,860 ft
Trigonometry allows to find the result for the question about the height of the mountain is:
The height mountain is: y = 9674.4 ftTrigonometry allows finding relationships between the angles of a right triangle.
[tex]tan \theta = \frac{y}{x}[/tex]
Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).
In the attachment we can see a diagram of the system. They indicate that for x distance the angle is 14.67º
tan 14.67 = [tex]\frac{y}{x}[/tex]
At the other point the angle is 10.38º.
tan 10.38 = [tex]\frac{y}{x+15860}[/tex]
We look for the horizontal distance (x) with these equations.
x tan 14.67 = (x + 15860) tan 10.38
x tan 14.67 / tan 10.38 = x + 15860
x 1,429 = x + 15860
x 0.429 = 15860
x = [tex]\frac{15680}{0.429}[/tex]
x = 36955.3 ft
We calculate for the height.
y = x tan 14.67
y = 36955.3 tan 14.67
y = 9674.4 ft
In conclusion using trigonometry we can find the result for the height of the mountain is:
The height is y = 9674.4 ftLearn more about trigonometry here: https://brainly.com/question/8120556
how many types Of Ornital does the atomic orbital have ?
Answer:
There are four types of orbitals that you should be familiar with s, p, d and f (sharp, principle, diffuse and fundamental). Within each shell of an atom there are some combinations of orbitals
Which element forms more com-
pounds than all the other elements
combined?
Answer:
Terms in this set (7) Which element forms more compounds than all the other elements combined? Carbon.
Explanation:
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a galaxy that is a featureless spherical ball of stars would be called a type
Answer:
E0
Explanation:
Yes. The "0" indicates that it is spherical
An eagle flying at a constant 120 km/h and has kinetic energy of 2,800 J. What is the mass of the eagle?
Answer:
The mass of the eagle is about 5 Kg
Explanation:
1/2 M= Ke/V^2
120 km/h = 33.3333m/s
1/2 M = 2,800/33.3333^2
1/2 M = 2,800/ 1111.10888889
1/2 M = 2.52000504001
(2) 1/2 M = (2) 2.52000504h001
= M = 5.04001008002
About 5 Kilograms
A car starts with a velocity of 16 m/s and slows at a constant rate of -2m/s2, what is its velocity after 3 s?
After 3 seconds, the car slows down to
16 m/s + (-2 m/s²) (3 s) = 16 m/s - 6 m/s = 10 m/s
Say you were at mission control on
Earth. You use radio waves to say "Hello" to an
astronaut on Mars when Mars is 84,000,000
km from Earth. The astronaut hears your "Hello"
280 seconds after you spoke the word. How do
you explain this time lag?
Answer:
because mars is far
Explanation:
so if he shouts louder than he will hear it quicker
find the quotient 3^15 × 3^3
Answer:
3^15 / 3^3 = 3^12 * 3^3 / 3^3 = 3^12
The Law of Exponents applies here
3^15 x 3^3 is a product, not a quotient
3^15 x 3^3 = 3^18
What is an example of bad energy efficiency but good energy conservation?
Answer:
Energy conservation relies on people cutting back on activities that consume energy—by turning off lights or driving less or using appliances less often.
Explanation:
hope this helps
How does production and possibilities curve show efficiency grouth and opportunity cost
Answer:
The Production Possibilities Curve (PPC) is a model that captures scarcity and the opportunity costs of choices when faced with the possibility of producing two goods or services. Points on the interior of the PPC are inefficient, points on the PPC are efficient, and points beyond the PPC are unattainable.
Explanation:
write the resistivity of gold, iron ,Mercury, silver,copper? which is bad conductor?
Answer:
Mercury is a bad conductor of heat but a fair conductor of electricity
By the way PURE SILVER is the best conductor of electricity
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A rocket consists of a shuttle and a fuel tank. The rocket flies through the air with a momentum of 180000kgm/s at a velocity of 120m/s. If the fuel tank has a mass of 500kg, what is the mass of the shuttle?
Answer:
Answer is 1000kg
Hope it help
A 30.4-newton force is used to slide a 40.0-newton crate a distance of 6.00 meters at constant speed along an incline to a vertical height of 3.00 meters. Calculate the work done by a friction force on the crate as it slides 6.00 m along the incline.
Hi there!
Since the crate is being slid at a constant speed, the forces sum to 0 N. In this instance, the following forces occur in the axis of interest:
Wsinθ = downward acceleration along incline due to gravity (N)
Fκ = kinetic friction force along incline (N)
A = applied force (N)
The acceleration due to gravity and friction force act in the same direction, so:
Wsinθ + Fκ = A
Solve for sinθ using right triangle trigonometry:
sinθ = O/H = 3/6 = 0.5
Rearrange the equation for the force of kinetic friction and solve:
Fκ = A - 0.5W
Fκ = 30.4 - 20 = 10.4 N
Now, recall that:
Work = Force × displacement (W = F × d)
Since the box's displacement is in the same axis as the force but OPPOSITE direction, we must use:
W = Fdcosθ
Angle between displacement and friction force is 180°.
cos(180) = -1
Work done by friction = -Fd = -10.4(6) = -62.4 J