Hi pls help me if you know the answer pls ASAP thank you

Answer:

Savanna regions have two distinct seasons - a wet season and a dry season. There is very little rain in the dry season. In the wet season vegetation grows, including lush green grasses and wooded areas.

Savannas are grasslands found in Africa, Australia, South America, and India. The climate is warm or hot. Savannas experience both dry and rainy seasons. Each year, savannas receive about 20 to 50 inches of rain in a span of six to eight months. The other months are dryer. There’s also a threat of wildfires because of the severe dryness during these months. Grasslands are true to their name because their vegetation is mostly grass. Savannas are home to a wide range of animals, including different species of beetles and insects, which many creatures consume. Squirrels, mice, elephants, gazelles, and antelopes are the plant-eating animals that live in the savanna. Hyenas, lions, and leopards are some of the meat-eating animals in these areas. Some of the nonliving components of the system include very porous soil that allows water to drain easily.

Answer:

1-butene

Explanation:

In this case, the problem is already stating and saying the reaction involved here.

1-bromobutane undergoes a dehydrohalogenation in presence of a base. This will cause an elimination reaction forming a product.

As this is an elimination product, this can be done in two ways.

The first way is with an unimolecular reaction where the halide is eliminated from the starting reactant in a two step reaction involving a carbocation formation. This is known as E1 reaction. However, the conditions for this reaction is to be in acid medium.

The second way is with a bimolecular reaction where the halide is eliminated from the starting reactant in just one step, and no carbocation is formed. This is known as E2 reaction and is commonly used with bases.

In the case of this problem, we are undergoing an E2 reaction, therefore, the mechanism of reaction is just one step, and when this happens, the base substract the hydrogen from Carbon 2, eliminates the bromide and forms a double bond, giving the 1-butene.

You can see the mechanism in the following picture.

Hope this helps

1-butene is the organic byproduct of 1-bromobutane's dehydrohalogenation in the presence of a base.

In the process of dehydrohalogenation, a molecule loses both a hydrogen and a halogen atom (such as a halogen from chlorine, bromine, or iodine) to create an unsaturated compound. The production of alkenes or alkynes, which are crucial in organic chemistry, is frequently accomplished using this reaction. Eliminating a hydrogen halide (HX) from a halogenoalkane or alkyl halide is the most important step in dehydrohalogenation. The E1 and E2 reactions are the two basic processes that can be used to do this. There are two steps in the E1 reaction. The halogenoalkane first passes through ionisation and creates a carbocation intermediate.

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The daughter isotope  : Radon-222 (Rn-222).

Given

Radium (Ra-226) undergoes an  alpha decay

Required

The daughter nuclide

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same

Radium (Ra-226) : ₈₈²²⁶Ra

Alpha particles : ₂⁴He

So Radon-226 emits alpha α particles ₂He⁴  , so the atomic number decreases by 2, mass number decreases by 4

The reaction :

₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn

Answer:

juvn hgf   jb ujvi i  junk food sux

Explanation:

Answer:

b. Ni, Fe, Ti, K

Explanation:

The given elements are present in period 4 of periodic table. Now we will discuss the trend of atomic radius along period.

Atomic radius:

" It is the smallest distance from nucleus to the outer most valance shell of an atom"

When we move from left to right in the periodic table the number of valance electrons in an atom increase. The atomic size goes to decrease in same period because of edition of electron with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. In this way positive charge is also going to increase and this charge is greater in effect than the charge of electrons. This effect causes the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell come closer to the nucleus.

As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.

Ni ∠ Fe ∠ Ti ∠ K

Explanation:

Mole ratio of NH3 to NaNH2 = 2 : 2.

Moles of NaNH2 produced

= 4.3mol * (2/2) = 4.3mol.

Answer:

atoms

Explanation:

i hope that help you

Answer:

atoms

Explanation:

Answer:  

I think F

Explanation:

Answer: Decrease in size

Explanation:

Electronegativity is defined as the property of an element to attract a shared pair of electron towards itself.

On moving across a period from left to right,   the size of an atom decreases because the electrons get added to the same shell and the nuclear charge keeps on increasing. Thus the electrons get more tightly held by the nucleus.

As, the size of an element decreases, the valence electrons come near to the nucleus. So, the attraction between the nucleus and the shared pair of electrons increases. Thus electronegativity increases.

Answer:

C. It may act as an insulator or a conductor.

Explanation:

Group B are the metalloids, so they have properties of both metals and nonmetals.

The statement which is most likely true for an element present in section B is: C. It may act as an insulator or a conductor.

A periodic table can be defined as an organized tabular array of all the chemical elements, which is typically arranged in order of increasing atomic number or number of protons (in rows).

In this diagram, the chemical element that is present in section B of the periodic table is a metalloid.

A metalloid can be defined as a chemical element that are typically intermediate between those of semiconductors, non-metals and metals.

In this context, the statement which is most likely true for an element present in section B is that it may act as an insulator or a conductor because it is a metalloid.

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Answer:

3rd

Explanation:

Answer: [tex]4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2[/tex]

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for reaction of potassium superoxide  with carbon dioxide to produce oxygen and potassium carbonate will be:

[tex]4KO_2+2CO_2\rightarrow 2K_2CO_3+3O_2[/tex]

Answer:

The process is called Puberty.

Answer:

Magenta.

Explanation:

Color absorption is a process that occurs when a light wave strikes an object. When a light wave strikes an object it either absorbs color or transmits the color, or reflects the color. When a light wave strikes a green object, it absorbs a magenta color.

Magenta is a combination of red and blue light, therefore, the colors that the green object will absorb is red. blue, or magenta light.

Answer: B. The rate goes down

Explanation:

Answer:

Easy, the flame is smaller but burns hotter.

Explanation:

The question is incomplete, the complete question is;

Suppose 1.87g of nickel(II) bromide is dissolved in 200.mL of a 52.0mM aqueous solution of potassium carbonate. Calculate the final molarity of nickel(II) cation in the solution. You can assume the volume of the solution doesn't change when the nickel(II) bromide is dissolved in it. Be sure your answer has the correct number of significant digits. The answer is needed in M.

Answer:

0.0428 M

Explanation:

The equation of the reaction is;

NiBr2 + K2CO3 → NiCO3 + 2KBr

Number of moles of NiBr2 = mass/molar mass = 1.87 g/218.53 g/mol =

8.557 *  10^-3 moles

Now, we know that the Ni^2+ comes from the NiBr2. Also, the concentration of Ni^2+ in NiBr2 = concentration of Ni^2+ in NiCO3

So,

Concentration of Ni^2+ = 8.557 *  10^-3 moles/0.2 L = 0.0428 M

Answer:

law of multiple proportions

Explanation:

The law of multiple proportions states that, if two elements A and B, combine to form more than one chemical compound. Then the various masses of one element A, which combine separately with a fixed mass of element B are in  simple multiple ratio.

We can see that the ratio of oxygen that combines with carbon in the two compounds( A and B) is 1:2. This demonstrates the law of multiple proportions.

The substances A and B must be CO and CO2 respectively.

Answer:

[tex]8.876\times 10^{18}\ km^2[/tex]

Explanation:

In this problem, we need to convert [tex]8.876 \times 10^{12}\ m^2[/tex] to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

[tex]8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2[/tex]

So, [tex]8.876 \times 10^{12}\ m^2[/tex] is equal to [tex]8.876\times 10^{18}\ km^2[/tex].

Answer:

the answer is 64 moths are dark

[OH⁻]= 2.7 x 10⁻¹³

pH = 1.431

Given

[H3O+] = 3.7x10⁻² M.

Required

the [OH-] and pH

Solution

pH = - log [H⁺]

pH = 2 - log 3.7

pH = 1.431

pOH = 14 - 1.431

pOH = 12.569

pOH = - log [OH⁻]

[OH⁻]= 2.7 x 10⁻¹³

or

[OH-][H3O+]=10⁻¹⁴

[OH-]=10⁻¹⁴ : 3.7 x 10⁻²

[OH-] = 2.7 x 10⁻¹³

 Answer:

I live in the USA so the questions have been answered to reflect that accordingly.

1. The letter which represents summer where I live is Letter C

Explanation:

Letter C represents the June solstice which usually takes place between June 20 and June 21.

2. The letter which represents winter where I live is letter A.

Explanation:

Letter A represents the December solstice. Another name for this is Winter Solstice. This usually takes place in December for those living in the Northern Hemisphere like me. It is projected that this will take place on Tuesday, 21 December 2021.

Another name for this is Northern Hemisphere Winter Solstice as it marks the first day of winter.

3. The correct seasons for June Solstice are:

Northern Hemisphere: Summer Solstice

This projected to occur on Sunday, 20 of June 2020. It will be characterized by 1 hour of twilight and approximately 10 hours each of daylight and night time.

4. Southern Hemisphere: Summer solstice

This is anticipated on Tuesday, 21 December 2021. It will also be characterized by 1 hour of twilight and approximately 10 hours each of daylight and night time.

5. Northern Hemisphere: Autumnal (Fall) Equinox  

6. Southern Hemisphere:  Spring (Vernal) equinox  

7. December Solstice - Northern Hemisphere: Winter Solstice is the Day of the Year with the shortest amount of sunlight

8. December Solstice - Southern Hemisphere: Summer Solstice. This is the day of the year with the longest amount of sunlight

9. March Equinox - Northern Hemisphere: Spring (Vernal) Equinox. This is the start of spring.

10. March Equinox - Southern Hemisphere: Autumnal (Fall) Equinox. This is the start of Fall.

Cheers!

Answer:

If coal and petroleum will get exhausted it will be very difficult for us to transport because most vehicles depends on petroleum, Transport on Earth will became complicated, and if coal will get exhausted we will lose an unique fossil fuel. Coal is used in various domestic and industrial purposes.

Answer:

See explanation

Explanation:

If we desire to recrystallize the given compound then we must do the following;

1) Add the compound to ethanol and heat the system

2) As the solute dissolves, the solution is allowed to cool

3) The solution may be seeded or the vessel scratched to aid crystallization.

4) The pure crystals are now filtered out, washed and dried.

Remember that recrystallization has to do with dissolving a solute in a solvent in which it is only soluble at high temperature but insoluble at low temperature.

The solvent dissolves the impure solute while pure crystals emerges as the temperature decreases.

Answer: We see constellations at different times of the year - spring, summer, fall, & winter. This occurs because the Earth is orbiting the Sun.

Explanation:

Answer:

D

Explanation:

I just did it on Edge

Answer:It’s D

Explanation: It was in my test

Answer:

where is diagram. sorry.

Answer:

1.57 × 10^-4

one point five seven times ten to the power of negative four

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.