Answer:
[tex] \boxed{(i).... 40cm}\\ \boxed{(ii).... 18cm}\\ \boxed{(iii).... 7.5N
}\\ [/tex]
Explanation:
[tex](i).... \\ the \: weight \: of \: the \: rod \: acts \: at \: the \: center \\ which \: is \: the \: half \: of \: 80cm = 40cm \\ (ii).... \\ let \: the \: distance \: be \: \boxed{d}...then \: 22 + d = 40 \\ d = 40 - 22 = 18cm \\ (iii).... \\let \: the \: weight \: of \: the \: metal \: rod \: be \: \boxed{ w} \\ taking \: the \: moment \: about \: the \: string \to \\ 15 \times (22 - 13) = 18w \\ 18w = (9)(15) \\ 2w = 15 \\ w = 7.5N[/tex]
♨Rage♨
Which could most likely describe the three surfaces?
Surface 1 is ice, Surface 2 is gravel, and Surface 3
is blacktop.
Surface 1 is gravel, Surface 2 is ice, and Surface 3
is blacktop.
Surface 1 is blacktop, Surface 2 is gravel, and
Surface 3 is ice.
Surface 1 is blacktop, Surface 2 is ice, and Surface
3 is gravel.
Answer:
Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.
Explanation:
Hope this helps! :]
Answer:
C. Surface 1 is blacktop, Surface 2 is gravel, and
Surface 3 is ice.
Explanation:
A tennis ball is beaten downward with an initial speed of 5 m/s.
How fast, in m/s, is the ball falling after 3 seconds (neglect air
friction, so g = 9.8 m/s2)?
a 34.4
b 34.4
C 9.8
d 9.8
e 5
Answer:
34.4m/sExplanation:
Step one:
given data
initial speed u= 5m/s
time t= 3seconds
acceleration due to gravity g= 9.8m/s^2
Required:
the final velocity v
Step two:
applying the first equation of motion
v=u+gt-----------we used + because the ball is falling with gravity
v=5+9.8*3
v=5+29.4
v=34.4
The final velocity is 34.4m/s
Answer:
-34.4
Explanation:
the person above had the right approach but it would be negative as it is in a downwards motion
can somone pls help me??!! i’m very stuck
Answer:
b
Explanation:
Jorge conducted an experiment,and included the graph shown below as part of his lab report.
Jorges experiment involved which if the following?
-A Chemical change.
-A change in the chemical properties of a substance.
-A physical change.
-the formation of a new substance.
The correct answer is A physical change
Explanation:
Jorge's experiment shows water at different temperatures; in this experiment, it is expected at low temperatures such as -20°C water is in solid-state (ice), at medium temperatures such as 40°C water is in a liquid state (liquid water), and at high temperatures such as 120°C water is in gaseous state (water vapor). This implies during this experiment the changing factor is the physical state (solid, gas, or liquid), and this is a physical change because only the physical properties of water change but not its composition or identity. According to this, the correct answer is physical change.
how can you show that pressure increases with the increase of force?
Answer:
...........................
State the career function of production engineering
Answer:
Production Engineering defines and works out how the product will be manufactured and/or assembled on the production line including design of packaging, ensuring the right quantity of components/products are delivered and aligned to support the speed of the production line.
Explanation:
Answer:
Production Engineers are responsible for supervising and improving production at plants and factories. They support engineering teams, draw up safety protocols, report issues to the Manager, and develop strategies to improve efficiency and profit.
Explanation:
a motorcycle starts from rest covers 200 meter distance in 6 second calculate final velocity and acceleration
Explanation:
s = ut + 1/2 a t^2
200 = 0 * 6 + 1/2 * a * (6)^2
200 = 1/2 * a * 36
200 = 18 a
a = 200/18
a= 11.1m/sec^2
v = u + at
v = 0 + 11.1 * 6
v = 66.6m/s
hope it helps you
Desde un rascacielos de 300 m de altura se lanza un objeto con una velocidad inicial de 50 m/s. Calcula el tiempo que transcurre hasta que llega al suelo y con qué velocidad llega en cada uno de los casos: a) Si se lanza verticalmente hacia arriba. b) Si se lanza verticalmente hacia abajo. c) Si se lanza horizontalmente (En este caso calcular también la distancia al edificio cuando llega al suelo) d) Si se lanza con un ángulo de 30o (Calcular también distancia al edificio)
Answer:
a) t = 14.2 s , v = -92 m / s , b) v = - 59.16 m / s , t = 0.916 s
c) t = 7.75 s , x = 387.5 m
d) t = 10.64 s , x = 463.9 m , v = 92.2 m / s
Explanation:
This is an exercise in kinematics, suppose we take the upward direction as positive
a) is thrown up vertically.
Let's use the equation
y = y₀ + v₀ t - ½ g t²
When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²
0 = y₀ + v₀t - ½ g t²
½ 10 t² - 50 t - 300 = 0
Let's solve the quadratic equation
t² - 10 t - 60 = 0
t = [10 ±√ (10² + 4 60)] / 2
t = [10 ± 18.4] / 2
t₁ = 14.2 s
t₂ = -4.2 s
since time must be a positive quantity, the correctors result t = 14.2 s
the speed at this point is
v = v₀ - g t
v = 50 - 10 14.2
v = -92 m / s
the sign indicates that the body is going down
b) in this case the initial velocity is vo = -50 m / s
let's calculate the velocity on the ground
v² = v₀² - 2g (y-y₀)
v² = 50 2 - 2 10 ((0- 300)
v² = 3500
v = + - 59.16 m / s
as the body is going down the correct sign is the negative
v = - 59.16 m / s
the time it takes to arrive is
v = v₀ - g t
t = (v₀ - v) / g
t = (-50 + 59.16) / 10
t = 0.916 s
c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0
y = y₀ + v₀ t - ½ g t²
0 = 300 + 0 - ½ 10 t²
t = √ (2 300/10)
t = 7.75 s
the horizontal displacement at this time is
x = v₀ₓ t
x = 50 7.75
x = 387.5 m
d) as it is thrown with an angle let's find each component of the velocities
v₀ₓ = v₀ cos 30
[tex]v_{oy}[/tex] = v₀ sin 30
v₀ₓ = 50 cos 30 = 43.3 m / s
v_{oy} = 50 sin 30 = 25 m / s
we look for the time of descent
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + v_{oy} t - ½ g t²
0 = 300 + 25 t - ½ 10 t²
t² - 5t - 60 = 0
we solve the second degree equation
t = [5 ±√ (5² + 4 60)] / 2
t = [5 ± 16.28] / 2
t₁ = 10.64 s
t₂ = -5.64 s
since the time must be positive the result is t = 10.64 s
the range on the x axis is
x = v₀ₓ t
x = 43.6 10.64
x = 463.9 m
the ground speed is
v_{y} = [tex]v_{oy}[/tex] - g t
v_{y} = 25 - 10 10.64
v_{y} = -81.4 m / s
speed is
v = √ (v₀ₓ² + v_{y}²)
v = √ (43.3² + 81.4²)
v = 92.2 m / s
Pitch describes how high or low a sound is. The pitch of a sound is most dependent upon the of the sound wave.
A.
amplitude
B.
rarefaction
C.
frequency
D.
wavelength
Answer:
The answer is C
Explanation:
A space vehicle is coasting at a constant velocity of 22.4 m/s in the y direction relative to a space station. The pilot of the vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.206 m/s2 in the x direction. After 40.5 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the y direction.
Answer:
a. 23.9 m/s b. 69.58°
Explanation:
a. Since the space vehicle is moving at a constant velocity of 22.4 m/s in the y direction relative to the space station, its initial vertical velocity v = 22.4 m/s.
Also, since the space vehicle moves in the y direction, its initial horizontal velocity u = 0 m/s.
Since its acceleration a = 0.206 m/s² for time, t = 40.5 s, we find the final horizontal velocity u' from u' = u + at.
Substituting the values of the variables into the equation, we have
u' = u + at
u' = 0 m/s + 0.206 m/s² × 40.5 s
= 8.343 m/s
≅ 8.34 m/s
The resultant velocity relative to the space station V = √(v² + u'²)
= √[(22.4m/s)² + (8.34 m/s)²]
= √[501.76 m²/s² + (69.56 m²/s²]
= √[571.32 m²/s²]
= 23.9 m/s
b. The direction of the vehicle's velocity relative to the space station is thus θ = tan⁻¹(v/u')
= tan⁻¹(22.4 m/s/8.34 m/s)
= tan⁻¹(2.6959)
= 69.58°
can y’all please help me with this 3 part question?
Answer:
Vf = 210 [m/s]
Av = 105 [m/s]
y = 2205 [m]
Explanation:
To solve this problem we must use the following formula of kinematics.
[tex]v_{f} =v_{o} +g*t[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0 (released from the rest)
g = gravity acceleration = 10 [m/s²]
t = time = 21 [s]
Vf = 0 + (10*21)
Vf = 210 [m/s]
Note: The positive sign for the gravity acceleration means that the object is falling in the same direction of the gravity acceleration (downwards)
The average speed is defined as the sum of the final speed plus the initial speed divided by two. (the initial velocity is zero)
Av = (210 + 0)/2
Av = 105 [m/s]
To calculate the distance we must use the following equation of kinematics
[tex]v_{f} ^{2} =v_{o} ^{2} +2*g*y\\\\(210)^{2} = 0 + (2*10*y)[/tex]
44100 = 20*y
y = 2205 [m]
Explain why when a firefighter rescues a dog that has fallen through ice on a
lake, they put their ladder on the ice first and then crawl out to the dog on the
ladder.
Answer:
This can spread their weight.
Explanation:
The ladder has a much larger surface area than the firefighter. Hence, his weight is spread out much more than usual, decreasing the pressure on the ice, preventing the ice from breaking/cracking.
Hope this helped!
b) A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to
buy the watch?
indir
Answer:
rs 900
Explanation:
the process is given
Select all the correct answers.
Which situations describe an elastic collision?
(A) Two glass marbles bounce off each other.
(B) Rodrick flops onto his sofa and sinks into the cushion.
(C) A tossed water balloon flattens when it lands on the grass.
D) A bowling ball knocks over five pins.
A grapefruit falls from a tree and hits the ground 0.72 s later.
How far did the grapefruit drop?
What was its speed when it hit the ground?
Answer:
The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2.[/tex]
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The distance traveled by a dropped object is:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:
[tex]\displaystyle y=\frac{9.8\cdot 0.72^2}{2}[/tex]
y = 2.54 m
The final speed is computed below:
[tex]vf=9.8\cdot 0.72[/tex]
vf = 7.06 m/s
The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s
Question 1) For resonance to occur, the object must experience a frequency equal to its what?
natural frequency
period
wavelength
amplitude
Question 2) What variable affects the natural frequency of an organ pipe?
pipe width
pipe length
pipe area
pipe use
Question 3) Resonance in air columns is used in which of these musical instruments?
violin
trumpet
drums
guitar
Question 4) Which term describes the number of crests that pass a point in a given amount of time?
wave speed
frequency
wavelength
period
Queston 5) Which of the following is the human ear able to detect?
dog whistle
sonar
ultrasound
musical note
Explanation:
Note that resonance can only occur when the natural frequency is greater than the damping rate, multiplied by the square root of 2. If the damping is too large, then resonance cannot occur.
what was the temperature changes in Celsius degrees if it is
changed from 44°F to -56°F?
Answer:
so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)
Explanation:
(formula, idk it is wrong or right) °C =°F - 32 then / 1.8000
44°F = 6.6666666667°C
-56°F = -48.888888889°C
So, if u want whole number as the answer
it is something like 6.6666666667°C + 48.888888889°C = 55.5555555557 °C
so, so, the answer is 56 whole number if round it, or 55.6(round it to 10th decimal)
1. An electric lamp a marked 240V, 6A. What
its resistance when it is operated at the correct
voltage?
Answer:
The resistance of the lamp is 4Ω.
Explanation:
You have to apply voltage formula :
V = I × R
R = V ÷ I
R = 240 ÷ 60
R = 4 Ω
a sheet of metal is 2mm wide 10cm tall and 15cm long. it was 4g. what is the density?
Answer:
Ro = 133 [kg/m³]
Explanation:
In order to solve this problem, we must apply the definition of density, which is defined as the relationship between mass and volume.
[tex]Ro = m/V[/tex]
where:
m = mass [kg]
V = volume [m³]
We will convert the units of length to meters and the mass to kilograms.
L = 15 [cm] = 0.15 [m]
t = 2 [mm] = 0.002 [m]
w = 10 [cm] = 0.1 [m]
Now we can find the volume.
[tex]V = 0.15*0.002*0.1\\V = 0.00003 [m^{3} ][/tex]
And the mass m = 4 [gramm] = 0.004 [kg]
[tex]Ro = 0.004/0.00003\\Ro = 133 [kg/m^{3}][/tex]
- An impulse is equivalent to
a. the change in mass of an object.
b. the change in volume of an object.
c. a force applied to an object for a period of time.
d. the original momentum of the object.
Answer:
c
Explanation:
impulse Is the product of force and distance so it's generally formula
The impulse should be equivalent to the option c. a force applied to an object for a period of time.
What is an impulse?Impulse of force represent the product of the resultant force ΣF and also the duration of the force Δt when the force should be constant. Also it should be lead to the changed to motion and changes to momentum
Therefore, The impulse should be equivalent to the option c. a force applied to an object for a period of time.
Learn more about force here: https://brainly.com/question/3398162
Deforestation invites natural disasters. Give reason.
Answer:
In addition to depleting resources for forest-dependent communities, deforestation is contributing to an increase in small-scale natural disasters.“That means when there's heavy rainfall, forest soil can absorb water underground and disburse it to streams.
Answer: Deforestation invites natural disasters by the following reasons:-
i) Soil erosion
ii)Landslides due to soil erosion
iii) Forest fire
iv) Flooding due to soil erosion
Hope it helped u,
pls mark this as brainliest
and put thanks
^_^
Which two elements have similar properties and 8 electrons in their outermost shells?
A. Chlorine and bromine
B. Calcium and strontium
C. Nitrogen and phosphorus
D. Argon and krypton
** THE ANSWER IS D **
Answer:
D
Explanation:
their octet is complete they don't react with any thing
Argon and krypton have similar properties, and they have a complete octet, which means that they do not react with anyone. Hence, option D is correct.
What are inert gases?The phrase "inert gas" is a bit misleading because, in some circumstances, these gases can really be reactive. As a result, these gases are typically referred to as noble gases in the context of chemistry and materials science.
The term "noble" has historically been used in chemistry (and earlier in alchemy) to characterize the resistance of some metals to chemical reaction, and the term "noble gas" denotes the same resistance.
Helium (He)Neon (Ne)Argon (Ar)Krypton (Kr)Xenon (Xe)Radon (Rn)These are the inert gases which are mentioned in the periodic table.
To get more information about inert gases :
https://brainly.com/question/14234951
#SPJ5
Which refers to the ratio of output work to input work of a machine expressed as a percent?
total work
wattage
efficiency
power
Answer: C.) Efficiency
Explanation: Edge 2020 good luck ^__^
PLZ HELP!!! the moon umbriel orbits uranus (mass = 8.68 x 10^25 kg) at a distance of 2.66 x 10^8 m. what is umbriels orbital speed? (In hours)
Answer:
99.48
Explanation:
99.48
Can any kind soul help me
Answer:
2917.4 m/s
Explanation:
From the question given above, the following data were:
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
Radius (r) of the Moon = 1737 Km
Escape velocity (v) =?
Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:
Gravitational acceleration of the earth = 9.8 m/s²
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
= 0.25 × 9.8 = 2.45 m/s²
Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:
1 Km = 1000 m
Therefore,
1737 Km = 1737 Km × 1000 m / 1 Km
1737 Km = 1737000 m
Thus, 1737 Km is equivalent to 1737000 m
Finally, we shall determine the escape velocity of the rocket as shown below:
Gravitational acceleration of the Moon (g) = 2.45 m/s²
Radius (r) of the moon = 1737000 m
Escape velocity (v) =?
v = √2gr
v = √(2 × 2.45 × 1737000)
v = √8511300
v = 2917.4 m/s
Thus, the escape velocity is 2917.4 m/s
How long does it take to travel a distance of 672km at a speed of 95km/h?
Answer:
7.07 hours
Explanation:
divide the distance by the speed
so in this case, divide 672 by 95
A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what is the range of the projectile?
Answer:
The range of the projectile is 60 meters
Explanation:
To determine the range/distance of the projectile, the formula for velocity is used;
velocity = distance/time
where velocity is 15 m/s
time is 4 seconds
distance is unknown
From the formula above, distance is made the subject and thus
distance = velocity × time
distance = 15 × 4
distance = 60 m
The range of the projectile is 60 meters
PLEASE HELP ASAP WILL GIVE BRAINLIEST!!!!
compare and contrast the strength of the forces between two objects with a mass of 1 kg each, a charge of 1 C, and at a distance of 1 m from each other.
Explanation:
Please mark me as the brainliest answer
Answer:
The electrostatic force is larger by a factor of 8.988E9 / 6.674E-11 = 1.35E20
Explanation:
William gave you all the ingredients, but not the answer. Being both 1/r^2 forces (resulting from massless mediators in QFT), and with unit charges in the problem (1 coulomb, 1 Kg), separated by unit distance (1m), the only nontrivial numerical values in the problem are the constants of proportionality: Coulomb's constant (k) and Newton's gravitational constant (G). So to "compare and constrast": the ratio of the forces is simply the ratio of these constants. The electromagnatic force is 1.35 X 10^20 times stronger than the gravitational force. Assuming positive charge on both objects (the problem is ambiguous on this), they are repelled, whereas the much weaker gravitational force is attractive. (Gravity only has one kind of "charge" - it's unsigned - and the force is always attractive).
The problem doesn't say the objects are pointlike: if they have some extent and are either conductive or made of some dielectric, then things get messy because the charge distribution on the object won't be uniform then, but save that for grad school. :-)
How much net force is needed to accelerate a 200 kg satellite 9.8 m/s2 ?
Answer:
1960 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 200 × 9.8
We have the final answer as
1960 NHope this helps you
what is displacement and distance
Answer:
Displacement is how far you are between your initial and finishing position.
Distance is how far you went.
Explanation:
For example, using a baseball field... if the sides are each 100 m..
A batter runs to third base... what is his displacement and distance?
Since the batter ran to 3rd base, it means he ran 300 m to get to 3rd base but his displacement is 100 m becuase that's how far they are from home plate. (which was their starting position)
So the answer to my example above would be:
Distance: 300 m
Displacement: 100 m
I hope this helped you.