HELP PLS
Which technologies have made global communication instant and more effective? Choose THREE answers.

social media
wireless devices
smart phones
automobiles
printed newspapers

Answer:

The answer is below

Explanation:

Suppose end system A wants to send a large file to end system B, the large file is first divided into smaller chunks. Each chunk is then assigned a header forming a packet. Multiple packets are being generated with each of the packet containing a unique destination address in its header.

When a packet arrives at the packet switch, the switch uses the unique destination address that is attached in the header of the packet to determine the link onto which the packet is to be forwarded.

Answer:

B

Explanation:

Your kidneys are fist-sized organs shaped like beans that are located at the back of the middle of your trunk, in the area called your flank. They are under the lower part of your ribcage on the right and left sides of your backbone.

Answer:

2788 or 116

Explanation:

Answer: you have to check your email and click on the microsoft email they sent you and enter the code in the email.

Explanation: plz mark brainliest

Answer:

Benefits of Virtualization

Reduced capital and operating costs.

Minimized or eliminated downtime.

Increased IT productivity, efficiency, agility and responsiveness.

Faster provisioning of applications and resources.

Greater business continuity and disaster recovery.

Simplified data center management.

Answer:

Program  - Array Sorting

Author   - Vishal Solanki

Language - C Language

Date     - 03/02/2018 (dd/mm/yyyy)

*/

//IDE used for this code is "Visual Studio 2017"

#include <stdio.h>              //including stdio.h for printf and other functions

#include<conio.h>

int main()                        //default function for call

{

int a[100],n,i,j;

printf("Array size: ");

       scanf("%d",&n);

       printf("Elements: ");

     for(i=0;i<n;i++)

   {

       scanf("%d",&a[i]);

   }

for (int i = 0; i < n; i++)                     //Loop for ascending ordering

{

 for (int j = 0; j < n; j++)             //Loop for comparing other values

 {

  if (a[j] > a[i])                //Comparing other array elements

  {

   int tmp = a[i];         //Using temporary variable for storing last value

   a[i] = a[j];            //replacing value

   a[j] = tmp;             //storing last value

  }  

 }

}

printf("\n\nAscending : ");                     //Printing message

for (int i = 0; i < n; i++)                     //Loop for printing array data after sorting

{

 printf(" %d ", a[i]);

}

for (int i = 0; i < n; i++)                     //Loop for descending ordering

{

 for (int j = 0; j < n; j++)             //Loop for comparing other values

 {

  if (a[j] < a[i])                //Comparing other array elements

  {

   int tmp = a[i];         //Using temporary variable for storing last value

   a[i] = a[j];            //replacing value

   a[j] = tmp;             //storing last value

  }

 }

}

printf("\n\nDescending : ");                    //Printing message

for (int i = 0; i < n; i++)                     //Loop for printing array data after sorting

{

 printf(" %d ", a[i]);                   //Printing data

}

return 0;          //returning 0 status to system

getch();

}

//Ouput

/*

Array size: 10

Elements :  3  4  7  6  5  1  2  8  10  9

Ascending :  1  2  3  4  5  6  7  8  9  10

Descending :  10  9  8  7  6  5  4  3  2  1

*/

Explanation:

Answer:

Look at the other answer that guy knows what he is talking about

Explanation:

Answer:

b and c

Explanation:

sorry if there wrong

Answer: A, B, and C

Explanation:

Answer:

D by using a larger IP address correct

Explanation:

Correct answer I hope this helps you :)

Answer:

answer b

is correct

Answer:

Nelson proposed a system where copying and linking any text excerpt, image or form was possible.

Explanation:

Ted Nelson is one of the theoretical pioneers of the world wide web who is best known for inventing the concept of hypertext and hypermedia in the 1960s. As one of the early theorists on how a networked world would work.

How I know:

I goggle it.

Answer:

#include <cmath>

#include <iostream>

using namespace std;

int getSphereSize(double length, double breadth, double height) {

   double diagonal = sqrt(length * length + breadth * breadth + height * height);

   if (diagonal <= 4)

       return 4;

   if (diagonal <= 6)

       return 6;

   if (diagonal <= 8)

       return 8;

   if (diagonal <= 10)

       return 10;

   if (diagonal <= 12)

       return 12;

   return 0;

}

int main() {

   double length, breadth, height;

   int sphereCounts[5] = {0};

   int sphereSize;

   while (true) {

       // Get dimensions of the box

       cout << "Enter the dimensions of the box:\n";

       cout << "Length: ";

       cin >> length;

       cout << "Breadth: ";

       cin >> breadth;

       cout << "Height: ";

       cin >> height;

       if (length <= 0 || breadth <= 0 || height <= 0)

           break;

       sphereSize = getSphereSize(length, breadth, height);

       if (sphereSize == 0)

           cout << "The box cannot fit in any of the spheres";

       else

           cout << "The box can fit in the " << sphereSize << "-inch sphere";

       // Increment the counter

       if (sphereSize == 4)

           sphereCounts[0]++;

       else if (sphereSize == 6)

           sphereCounts[1]++;

       else if (sphereSize == 8)

           sphereCounts[2]++;

       else if (sphereSize == 10)

           sphereCounts[3]++;

       else if (sphereSize == 12)

           sphereCounts[4]++;

       cout << "\n\n";

   }

   cout << "\nNumber of 4-inch spheres: " << sphereCounts[0];

   cout << "\nNumber of 6-inch spheres: " << sphereCounts[1];

   cout << "\nNumber of 8-inch spheres: " << sphereCounts[2];

   cout << "\nNumber of 10-inch spheres: " << sphereCounts[3];

   cout << "\nNumber of 12-inch spheres: " << sphereCounts[4];

   cout << endl;

   return 0;

}

Explanation:

The "cmath" library is included in the c++ program. The getSphereSize function is used to return the sphere size the rectangle dimension can fit into. It program continuously prompts the user for the length, breadth, and height of the rectangle and passes the values to the getSphereSize function in the while but breaks if any or all of the variable value is zero.

The sizes of the sphere objects in inches are collected in an array of five integer values of zeros and are incremented by one for every match with a rectangle.

Answer:

In Java:

import java.util.*;

class Main {  

public static void minGap(int intArray[], int arrlength) {  

 if(arrlength <2){return;}

 int minm = Math.abs(intArray[1] - intArray[0]);  

 for (int i = 2; i < arrlength; i++)  

  minm = Math.min(minm, Math.abs(intArray[i] - intArray[i - 1]));  

 System.out.print("Minimum Gap = " + minm);  

}  

public static void main(String arg[]) {  

 Scanner input = new Scanner(System.in);

 int arrlength;

 System.out.print("Array Length: ");

 arrlength = input.nextInt();

 int[] intArray = new int[arrlength];

 for(int i = 0;i<arrlength;i++){

     intArray[i] = input.nextInt();

 }

 minGap(intArray, arrlength);  

} }

Explanation:

The minGap method begins here

public static void minGap(int intArray[], int arrlength) {

This checks if array length is 1 or 0. If yes, the program returns nothing

 if(arrlength <2){return;}

If otherwise, this initializes the minimum gap to the difference between the 0 and 1 indexed array elements

 int minm = Math.abs(intArray[1] - intArray[0]);  

This iterates through the array elements

 for (int i = 2; i < arrlength; i++)  

This checks for the minimum gap

  minm = Math.min(minm, Math.abs(intArray[i] - intArray[i - 1]));  

At the end of the iteration, the minimum gap is printed

 System.out.print("Minimum Gap = " + minm);  

}  

The main method begins here

public static void main(String arg[]) {  

 Scanner input = new Scanner(System.in);

This declares the length of the array

 int arrlength;

This prompts the user for array length

 System.out.print("Array Length: ");

This gets the user input

 arrlength = input.nextInt();

This declares the array

 int[] intArray = new int[arrlength];

The following iteration gets input for the array

 for(int i = 0;i<arrlength;i++){

     intArray[i] = input.nextInt();

 }

This calls the minGap method  

minGap(intArray, arrlength);  

}

Answer:

Ask about next steps and the best way to communicate.

Send a follow-up email within 24 hours.

Explanation:

An interview is a well-organized conversation where one participant asks questions, and the other person gives answers to those questions.

Essential tasks that need to be done after an interview is over are as follows:

1. Ask about next steps and the best way to communicate.

2. Send a follow-up email within 24 hours.

Answer:

Ask about next steps and the best way to communicate.

Send a follow-up email within 24 hours.

Answer:

Follows are the solution to this question:

Explanation:

In this question, the equation will be written as the coefficients for each of the bases, that is from the above quantum states b is given as follows:

[tex]\to | b \rangle = 0.4 | 00 \rangle + 0.65 | 01 \rangle + 0.2 | 10 \rangle + 0.61 | 11 \rangle[/tex]

Therefore the equation can be written as in the state b:

[tex]\to \mathbf{state_b = [0.4, 0.65, 0.21, 0.61]}[/tex]

Answer:

ZeroDivisionError

ValuError

Explanation: Edg 2020-2021

Answer:

1.ZeroDivisionError

2.ValueError

Explanation:

took test

Answer:

Length x Width x Hight

Explanation:

Answer:

8

Explanation:

Gear reduction = driven gear teeth / driving gear teeth

First stage reduction :

Driven gear teeth = 36

Driving gear teeth = 12

36 /12 = 3

Second stage reduction :

Driven gear teeth = 60

Driving gear teeth = 12

60 /12 = 5

First stage + second stage

3 + 5 = 8

Answer:

There can some challenges when giving and receiving peer feedback in a peer assessment. Some people can be harsh in their assessments of your work. Some students cannot take that and because of that it can cause them to question a lot of their work. People can also be wrong when it comes to the assessment

Answer:

I need to have better photos in order to assist you...

Explanation:

I will attempt to get back with you if you can provide more clearer photos.

num1 = float(input("Enter your first number: "))

num2 = float(input("Enter your second number: "))

operation = input("What operation would you like to do? Type: add, subtract, multiply, or divide. ")

def add(n, n1):

   return n + n1

def subtract(n, n1):

   return n - n1

def multiply(n, n1):

   return n*n1

def divide(n, n1):

   return n/n1

if operation.lower() in ["add", "+"]:

   result = add(num1, num2)

   print(num1,"+",num2,"=",result)

elif operation.lower() in ["subtract", "-"]:

   result = subtract(num1, num2)

   print(num1,"-",num2,"=",result)

elif operation.lower() in ["multiply", "*"]:

   result = multiply(num1, num2)

   print(num1, "*", num2, "=", result)

elif operation.lower() in ["divide", "/"]:

   result = divide(num1, num2)

   print(num1, "/", num2, "=", result)

else:

   print("Not a valid operation.")

I wrote my code in python 3.8. I hope this helps.

Answer:

Line graphs allow us to see overall trends such as an increase or decrease in data over time. Bar graphs are used to compare facts.

Answer:

The program in python is as follows:

for i in range(0,6):

   for i in range(0,9):

       print(" ",end='')

   print("|",end='')

print()

for i in range(1,61):

   print(i%10,end='')

Explanation:

See attachment for program output format

The next two instructions create a nested for loop

for i in range(0,6):

   for i in range(0,9):

This prints 9 spaces

       print(" ",end='')

This prints a vertical line at the top of the end of the spaces printed

   print("|",end='')

This prints a new line

print()

This iterates from 1 to 60

for i in range(1,61):

This prints 1, 2, 3....9, then 0, 6 times on a straight line

   print(i%10,end='')

Answer:

Optical signals have very high frequencies. A high frequency means a short wave length because the wave length is inversely proportional to the frequency (λ = v/f), where v is the propagation speed in the media.

Explanation:

Since optical signals have a greater frequency, measured in nanometers, their wavelengths are shorter (10-9 meter). A billionth of a meter is equal to one nanometer (nm), a unit of length.

An electromagnetic signal is an optical signal. It has oppositely polarised magnetic and electric fields.

The frequency of this EM pulse is typically very high (in the order of THz). As a result, measuring it in terms of wavelength is more practical.

The frequency of optical communications are very high. Since the wave length and frequency are inversely related, a high frequency implies a short wavelength.

To a receiving end, where the light signal is processed as data, the fiber transfers "data" by light.

As a result, fiber optics serves as a "pipe" or transmission medium for signals that need to travel vast distances quickly.

Thus, the optical signals used in optical fiber cables have a very short wavelength.

For more details regarding optical signal, visit:

https://brainly.com/question/17646651

#SPJ2

Answer:

SSL VPN

Explanation:

Secure Sockets Layer, or SSL VPN, is the second common VPN protocol.

A big plus for SSL VPNs is that they can allow segmented access for users. For example, users can be limited to checking email and accessing shared drives rather than having access to the entire network.

SSL VPNs come in two types, SSL portal and SSL tunnel.

SSL Portal VPNs

SSL Portal VPNs allow a user to securely access the web from a browser once the user logs into the VPN’s online portal using a specified method of authorization.

This type of SSL VPN gets its name because of how the user accesses it – through a single web page, or portal. The page acts as a single gateway to the other services available on the secured network.

SSL Tunnel VPNs

SSL Tunnel VPNs allow the user to not only access the web securely, but to also use applications and other network services that aren’t based on the web.

Due to their sophisticated segmentation capabilities, SSL VPNs often require more skill to implement.

VPNs are not a cure-all

Of course, what you could do is circumvent the entire debate around VPN SSL vs IPSEC. Our Gatekeeper offering is an enhanced alternative to VPN with no client, that still offers two-factor authentication to secure remote access.

Wherever you land between VPN SSL vs IPSEC, of if you join #TeamGatekeeper, having one of these tools to protect web traffic is a great way to help secure information, but it’s not an end-all be-all security solution.

After all, a VPN won’t protect your employees from social engineering attacks such as email phishing.

(hope this helps can i plz brainlist it will make my day :D hehe)