Which nucleus completes the following equation?
Answer:
B. [tex]\frac{218}{85} At[/tex]
Explanation:
A P E X
The nucleus that completes the following equation is ²²⁶Ac₈₉
²²²Fr₈₇ →⁴He₂ + ²²⁶Ac₈₉
Therefore the correct answer is option C.
What is radioactive decay?The phenomenon of Radioactive decay is a type of nuclear reaction in which the unstable nucleus of a radioactive element lose energy in the form of nuclear radiation, some examples of radioactive decay are alpha decay, decay, and beta decay.
The complete equation for the nuclear reaction is
²²²Fr₈₇ →⁴He₂ + ²²⁶Ac₈₉
For the given problem the nucleus completes the given equation is ²²⁶Ac₈₉. The correct answer is option C.
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WILL MAKE BRAINLIEST! How does Hooke’s law help us understand the force and energy in elastic materials?
Answer:
How does Hooke’s law help us understand the force and energy in elastic materials?:
When the elastic materials are stretched, the atoms and molecules deform until stress is been applied and when the stress is removed they return to their initial state
Explanation:
A charge of +3.5 nC and a charge of +5.0 nC are separated by 40 cm. Find the equilibrium position for a -6.0 nC charge.
Answer: [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Explanation:
Given
The magnitude of the first charge is [tex]Q_1=3.5\ nC[/tex]
The magnitude of the second charge is [tex]Q_2=5\ nC[/tex]
[tex]-6\ nC[/tex] charge must be placed in between the two charges to establish equilibrium
The electrostatic force is given by
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
Equilibrium will be established when force by both the charges balance out each other. Suppose [tex]-6\ nC[/tex] is placed at a distance of [tex]x[/tex] cm from [tex]3.5\ nC[/tex] . So, we can write
[tex]\Rightarrow \dfrac{k(3.5)(-6)}{x^2}=\dfrac{k(5)(-6)}{(40-x)^2}[/tex]
Canceling similar terms
[tex]\Rightarrow \left [ \dfrac{40-x}{x}\right ]^2=\dfrac{10}{7}\\\\\Rightarrow \dfrac{40-x}{x}=\sqrt{\dfrac{10}{7}}=1.195\\\\\Rightarrow 40-x=1.195x\\\Rightarrow 40=2.195x\\\Rightarrow x=18.22\ cm[/tex]
Thus, the equilibrium position is [tex]18.22\ cm[/tex] from [tex]3.5\ nC[/tex] charge.
Answer:
What school do you go to?
Explanation:
Thomas helps his older brothers, who own a junk yard, on the weekends to earn extra money. He likes to help them push broken-down cars to the back of the junk yard because it makes him feel strong. Last Saturday, they pushed three cars with different weights, and he noticed he used different amounts of force for each one. The cars were the following weights:white car: 2,700 poundsred car: 1,500 poundsblue car: 2,100 poundsThink about how much force is needed to move each car. Which correctly organizes the cars in order from the most to least amount of force needed to move them
Answer:
white, blue and red
Explanation:
Force is given by
[tex]F=ma[/tex]
where
m = Mass of object
a = Acceleration of the object
If the acceleration is same for all the cars the force needed to be applied will depend on the mass of the car. The heaviest car requiring the most force and the lightest car requiring the least amount of force.
Here, the weight of the cars in descending order is white, blue and red.
So, the cars in order from the most to least amount of force needed to move them is white, blue and red.
A baseball sits motionless near first base on a baseball diamond. What statement best explains why the baseball remains motionless?
A. The forces acting on the baseball are all balanced.
B. There are no forces acting on the baseball.
C. The dirt is placing an unbalanced force on the baseball.
D. The force on the baseball is unbalanced due to gravity.
Answer:
B
Explanation:
There are no forces acting in the baseball
Which of these statements are true about hydroelectric power? A.It is the most widely used renewable energy source in the world. B.It never disrupts ecosystems. C.It is not always available. D.A hydroelectric dam controls the force of moving water to generate electricity.
A decibel measures the _____________ of sound.
A.pitch
B,frequency
C.loudness
D.amplitude
En las olimpiadas del 2012 del colegio villapalos maria gano la carrera de los 100 m en 10,56 s y la de 200 m en 22,34 s ¿en cual fue mas veloz
Answer:
Fue mas velóz en los 100 m.
[tex]v_{1}=9.47\: m/s[/tex]
Explanation:
Tomando en cuanta que la definición de velocidad es:
[tex]v=\frac{\Delta x}{t}[/tex]
Donde:
Δx es el desplazamientot es el tiempoLa primera velodcidad esta dada por:
[tex]v_{1}=\frac{100}{10.56}[/tex]
[tex]v_{1}=9.47\: m/s[/tex]
La segunda velocidad sera:
[tex]v_{1}=\frac{200}{22.34}[/tex]
[tex]v_{1}=8.95\: m/s[/tex]
Por lo tanto, en el primer tramo fue más rápido.
Espero te haya ayudado!
Find the tension in the two groups that are holding the 2.9 kg object in Pl., One makes an angle of 35.6° with respect to the vertical group 2 is pulling horizontally
Answer:
≈ 20.35 N [newton's of tension]
Explanation:
( (2.9 × 9.8) ÷ cos(35.6°) ) × sin (35.6°) =
( (28.42) ÷ (≈0.813) ) × (≈0.582) =
(≈34.96) × (≈0.582) = 20.3449446.... ≈ 20.35
Which statement is true of an alpha particle?
A. It is electromagnetic radiation, not a true particle.
B. It is an electron.
C. It is the largest decay particle
D. It is a particle that travels at the speed of light.
Answer:
Atoms are made up of various parts; the nucleus contains minute particles ... neutrons, and the atom's outer shell contains other particles called electrons. ... Physical Forms of Radiation; Radioactive Decay; Nuclear Fission; Ionizing Radiation ... of high-energy waves that can travel great distances at the speed of light and ...
Explanation:
The true statement of an alpha particle is it is an electron. The correct option is B.
What is an alpha particle?The alpha particle are composite particles which consists of two protons and two neutrons tightly bonded together. They are ejected from the inside the nucleus of heavy radioactive particles, also called alpha decay.
Atoms are made up electrons orbiting in outer shells, protons and neutrons in the nucleus. The radioactive particle emit highly ionized radioactive rays which ionize electrons emitting alpha particle.
Thus, the correct option is B.
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What specific type of tide has the smallest difference between high and low tide?
Answer: Neap tides
Explanation: Neap tides are tides that have the smallest tidal range, and they occur when the Earth the Moon, and the Sun form a 90o angle. They occur exactly halfway between the spring tides when the Moon is at first or last quarter.
What net force would be required for a 50.5 kg wolf to accelerate at 5.0 m/s^2
Answer:
[tex]\boxed {\boxed {\sf 252.5 \ Newtons }}[/tex]
Explanation:
Force is the push or pull on object that can cause different things, like acceleration. According to Newton's 2nd Law of Motion, it is the product of mass and acceleration.
[tex]F=m*a[/tex]
The mass of the wolf is 50.5 kilograms and the acceleration is 5.0 meters per square second. Therefore:
[tex]m= 50.5 \ kg[/tex][tex]a= 5.0 \ m/s^2[/tex]Substitute the values into the formula.
[tex]F= 50.5 \ kg * 5.0 \ m/s^2[/tex]
Multiply.
[tex]F=252.5 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 Newton. Our answer of 252.5 kg*m/s² is equal to 252.5 Newtons.[tex]F= 252.5 \ N[/tex]
The force required is 252.5 Newtons.
Highlight two factors which shows that heat from the sun does reach the earth's surface by convection.
radiation
when the suns radiation fall on the earth and its objects they receive heat energy and hence get heated. Thus the suns heat reaches the earth by. the process of radiation
Absence of medium is the factor which shows that heat from the sun does reach the earth's surface by convection.
The heat of the sun reaches the earth only through radiation because radiation does not require any medium for the transfer of energy but convection and conduction required a medium to transfer heat energy.
We know that there is no medium present in vacuum so convection and conduction are impossible in a vacuum that's why the sun's heat does not reach the earth by conduction or convection.
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PLS HELP ME
Secondary waves CANNOT travel through
a.
rock.
b.
liquids.
c.
Earth’s mantle.
d.
Earth’s crust.
Answer:
B. Liquids
Explanation:
Just had this question on my test.
Hope this helps :)
The image shows the magnetic field lines around a magnet.
Which statements are true for this magnet?
- the right pole is the south pole
- the left pole is the south pole
- the left pole is the north pole
- the right pole is the north pole
Choose all that apply
Answer:
The right pole is the south pole
The left pole is the north pole
Explanation:
Reason : -
Magnetic field lines emerge from North pole to South pole in a bar magnet.
An object has an angular velocity of 1.0 rad and an angular acceleration of 0.5 rad/s. Is the speed of its rotation increasing or decreasing?
Answer:
increasing
Explanation:
Given that,
Initial angular speed =1 rad/s
Angular acceleration = 0.5 rad/s²
We know that the angular acceleration is given by :
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}[/tex]
Where
[tex]\omega_f[/tex]city and t is time is the final angualr velo
As the angular acceleration of the object is positive. It means that the final speed of the object is more than that initial. As a result, the speed of its rotation is increasing.
A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. ten second later, he is moving at 15 m/s. what is his acceleration
Answer:
1 m/s²
Explanation:
From the question,
Using
a = (v-u)/t.................... Equation 1
Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.
Given: v = 15 m/s, u = 5 m/s, t = 10 s
Substitute these values into equation 1
a = (15-5)/10
a = 10/10
a = 1 m/s²
Hence the acceleration of the bicycle is 1 m/s²
A boy walks towards a stationary plane mirror at a speed of 12ms^1 what is the relative speed of approach of the boy and his image? (a)zero (b)1.2ms^-1 (c) 2.4ms^-1 (d)1.44ms^-1
Answer:
a
Explanation:
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Is this right? Please help me ITS SOCIOLOGY
An object has an acceleration of 18.0 m/s/s. If the net force acting upon this object were doubled, then its new acceleration would be m/s/s.
Answer:
36.m/s/s
Explanation:
A firework is launched with a force of 700 N and a momentum of 200 kg-m/s. How much time before is explodes?
Answer:
t = 0.28 seconds
Explanation:
Given that,
Force acting on a firework, F = 700 N
The momentum of the firework, p =200 kg-m/s
We need to find the time before it explodes. Ket the time be t. We know that, the rate of change of momentum is equal to external frce. So,
[tex]F=\dfrac{P}{t}\\\\t=\dfrac{P}{F}\\\\t=\dfrac{200}{700}\\t=0.28\ s[/tex]
So, the required time is equal to 0.28 seconds.
How do you find the velocity of a moving car?
Answer:
Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt. Speed (or rate, r) is a scalar quantity that measures the distance traveled (d) over the change in time (Δt), represented by the equation r = d/Δt.
Explanation:
hope this helps a little bit sorry if i got it wrong
A physics student of mass 43.0 kg is standing at the edge of the flat roof of a building, 12.0 m above the sidewalk. An unfriendly dog is running across the roof toward her. Next to her is a large wheel mounted on a horizontal axle at its center. The wheel, used to lift objects from the ground to the roof, has a light crank attached to it and a light rope wrapped around it; the free end of the rope hangs over the edge of the roof. The student radius 0.300 m and a moment of inertia of 9.60 kg m^2 for rotation about the axle, how long does it take her to reach the side walk, and how fast will she be moving just beofre she lands?
Answer:
The speed of the student just before she lands, v₂ is approximately 8.225 m/s
Explanation:
The given parameters are;
The mass of the physic student, m = 43.0 kg
The height at which the student is standing, h = 12.0 m
The radius of the wheel, r = 0.300 m
The moment of inertia of the wheel, I = 9.60 kg·m²
The initial potential energy of the female student, P.E.₁ = m·g·h₁
Where;
m = 43.0 kg
g = The acceleration due to gravity ≈ 9.81 m/s²
h = 12.0 h
∴ P.E.₁ = 43 kg × 9.81 m/s² × 12.0 m = 5061.96 J
The kinetic rotational energy of the wheel and kinetic energy of the student supporting herself from the rope she grabs and steps off the roof, K₁, is given as follows;
[tex]K_1 = \dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2[/tex]
The initial kinetic energy, 1/2·m·v₁² and the initial kinetic rotational energy, 1/2·m·ω₁² are 0
∴ K₁ = 0 + 0 = 0
The final potential energy of the student when lands. P.E.₂ = m·g·h₂ = 0
Where;
h₂ = 0 m
The final kinetic energy, K₂, of the wheel and student is give as follows;
[tex]K_2 = \dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2[/tex]
Where;
v₂ = The speed of the student just before she lands
ω₂ = The angular velocity of the wheel just before she lands
By the conservation of energy, we have;
P.E.₁ + K₁ = P.E.₂ + K₂
∴ m·g·h₁ + [tex]\dfrac{1}{2} \cdot m \cdot v_{1}^2+\dfrac{1}{2} \cdot I \cdot \omega_{1}^2[/tex] = m·g·h₂ + [tex]\dfrac{1}{2} \cdot m \cdot v_{2}^2+\dfrac{1}{2} \cdot I \cdot \omega_{2}^2[/tex]
Where;
ω₂ = v₂/r
∴ 5061.96 J + 0 = 0 + [tex]\dfrac{1}{2} \times 43.0 \, kg \times v_{2}^2+\dfrac{1}{2} \times 9.60 \, kg\cdot m^2 \cdot \left (\dfrac{v_2}{0.300 \, m} }\right ) ^2[/tex]
5,061.96 J = 21.5 kg × v₂² + 53.[tex]\overline 3[/tex] kg × v₂² = 21.5 kg × v₂² + 160/3 kg × v₂²
v₂² = 5,061.96 J/(21.5 kg + 160/3 kg) ≈ 67.643118 m²/s²
v₂ ≈ √(67.643118 m²/s²) ≈ 8.22454363 m/s
The speed of the student just before she lands, v₂ ≈ 8.225 m/s.
Which of the following ways of writing 1000w is incorrect?
1) 1 kW
2) 1 x 10³ W
3) 10 x 10³ W
4) 1.0 x 10³ W
Answer:
the third one is incorrect
Explanation:
10 x 10³= 10^1 x 10^3 = 10^4
A 1.80-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 15.0 N is required to hold the object at rest when it is pulled 0.200 m from its equilibrium position (the origin of the x axis). The object is now released from rest from this stretched position, and it subsequently undergoes simple harmonic oscillations.
(a) Find the force constant of the spring.
N/m
(b) Find the frequency of the oscillations.
Hz
(c) Find the maximum speed of the object.
m/s
(d) Where does this maximum speed occur?
x = ±
m
(e) Find the maximum acceleration of the object.
m/s2
(f) Where does the maximum acceleration occur?
x = ±
m
(g) Find the total energy of the oscillating system.
J
(h) Find the speed of the object when its position is equal to one-third of the maximum value.
m/s
(i) Find the magnitude of the acceleration of the object when its position is equal to one-third of the maximum value.
m/s2
Answer:
Explanation:
(a) Force constant = force/displacement = 15/0.2
=75 N/m
(b) For SHM with spring, the angular frequency = sqrt ( force constant / mass )
= sqrt ( 75 / 1.8 )
= 6.455
Frequency = Angular frequency / 2pi
= 1.03Hz
(c) Maximum speed is when object's potential energy is at minimum.
1/2*mass*speed^2 = 1/2*force constant*displacement^2
speed^2 = 75*0.2^2/1.8 = 1.67
speed = sqrt (1.67)
= 1.29 m/s
(d) It occurs at x=0
(e) Maximum acceleration = Force / m = 15/1.8
= 8.33 m/s^2
(f) It occurs at x=0.2m
Answer:
Explanation:
given:
The mass of the object attached to the spring: m = 1.80 kg
The magnitude of the maximum horizontal force exerted: F = 15.0 N
The amplitude of the spring-object oscillation: A = 0.200 m
a. k=15/.2=75N/m
b. (2pi*frequency)^2 = k/m = 75/1.8 = 41.67
frequency = 1.03Hz
c. max speed^2 = amplitude^2*k/m = 0.2^2 * 41.67
max speed = 1.29 m/s
d. x=0m
e. max accel = F/m = 15/1.8 = 8.33 m/s^2
f. x=0.2m
e. energy = 1/2*k*A^2
= 1/2*75*0.2^2
= 1.5J
A toy gun uses a spring to shoot plastic balls (m = 50 g). The spring is compressed by 3.0 cm. Let k=2.22 × 105 N/m. (a) Of course, you have to do some work on the gun to arm it. How much work do you have to do? (b) Suppose you fire the gun horizontally. How fast does the ball leave the gun? (c) Now suppose you fire the gun straight upwards. How high does the ball go?
Answer:
Explanation:
Given that:
mass of the plastic ball = 50 g = 50 × 10⁻³ kg
spring constant (k) = 2.22 × 10⁵ N/m
compression of spring (x) = 3.0 cm = 3 × 10⁻² m
a) Work done:
[tex]= \dfrac{1}{2}kx^2 \\ \\ = \dfrac{1}{2}\times 2.22 \times 10^{5}\times (3 \times 10^{-2})^2 \\ \\ = 99.9 \ J[/tex]
b) When the gun is fired horizontally;
In the spring, the potential energy is changed to kinetic energy.
i.e.
[tex]\implies \dfrac{1}{2}kx^2 = \dfrac{1}{2}mv^2 \\ \\ 2.22 \times 10^5 \times (3\times 10^{-2}) ^2 =50 \times 10^{-3} \times v^2\\ \\ \mathbf{v= 63.2 m/s}[/tex]
c) The max height the bullet will reach if the gun is being shot upward is:
[tex]H_{max}= \dfrac{v^2}{2g} \\ \\ H_{max}= \dfrac{63.2^2}{2\times 9.8}[/tex]
[tex]\mathbf{H_{max}= 203.9 \ m}[/tex]
Your little cousin loves ice cream bars. You buy him one and he starts to lick it. As you sit down on a park bench, he drops
the bar on the seat of the bench. You pick up the bar to throw it away, but he starts to cry, so you shrug and give it back to
him. Will he definitely get sick?
Answer:
nop
Explanation:
It is not certain whether the child will get sick from eating the ice cream bar that was dropped on the bench.
What is contamination?Contamination refers to the presence or introduction of harmful substances or organisms into a material, environment, or food source.
There is a possibility that the ice cream bar could have picked up bacteria or other contaminants from the bench that could make the child sick. However, the risk of illness depends on a number of factors, including the cleanliness of the bench, the length of time the ice cream was in contact with the bench, and the overall health of the child's immune system.
To reduce the risk of illness, it is important to wash hands and surfaces frequently, especially when handling food. If possible, it is best to discard food that has come into contact with potentially contaminated surfaces to prevent the spread of illness. However, if the child has already eaten the ice cream bar and does become sick, it is important to monitor their symptoms and seek medical attention if necessary.
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Why would you have trouble breathing at high altitudes?
A. it is colder at the top of a mountain
B. the oxygen molecules are spread farther apart
C. the oxygen molecules are closer together
Answer:
A. It is colder at the top of a mountain
Explanation:
Which best summarizes a concept related to the work-energy theorem?
- When work is positive, the environment does work on an object.
- When work is negative, the environment does work on an object.
- When work is positive, the kinetic energy in a system remains constant.
- When work is negative, the kinetic energy in a system remains constant.
this is times pls help!
Answer:
When work is positive, the environment does work on an object.
Explanation:
According to the work-energy theorem, the net work done by the forces on a body or an object is equal to the change produced in the kinetic energy of the body or an object.
The concept that summarizes a concept related to the work-energy theorem is that ''When work is positive, the environment does work on an object.''
Answer:
Your answer is A!
Have a good day!
At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant
Answer:
Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer
answer : mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]
To calculate for weight of Bananas = m * g where g = 9.8
Explanation:
Given an amplitude ( A )= 29.8981
Spring constant = x ( unknown )
maximum speed of Bananas( v ) = wA ( unknown )
question : calculate the weight of the bananas
First step : calculate the period of oscillation
T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )
next step : express T in terms of mass ( m ) of the bananas
= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]
∴ m/k = A^2 / v^2
hence mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]
To calculate for weight = m * g