2cosAcosB =
• cos(A + B) + cos(A - B)
• sin(A - B) + tan(A + B)
Answer:
2cosAcosB = cos( A + B ) + cos( A - B )
The ages of the students in a statistics class are listed below. If the 18-year-old student has a birthday and turns 19, how will it affect the mean and median ages of the class?
Ages: 14, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 17, 18
A
Both the mean age and the median age will increase.
B
The mean age will increase, and the median age will remain the same.
C
The mean age will remain the same, and the median age will increase.
D
The mean age will remain the same, and the median age will decrease.
The mean age will increase, and the median age will remain the same.
Option B is the correct answer.
What is a mean?It is the average value of the set given.
It is calculated as:
Mean = Sum of all the values of the set given / Number of values in the set
We have,
Ages:
14, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 17, 18
The mean of the ages.
= (14 + 15 + 15 + 16 + 16 + 16 + 16 + 17 + 17 + 17 + 17 + 17 + 18) / 13
= 211/13
= 16.23
The median of the ages.
= 16
Now,
18 becomes 19.
14, 15, 15, 16, 16, 16, 16, 17, 17, 17, 17, 17, 19.
Mean = 212/13 = 16.3
Median = 16
Thus,
The mean age is increased.
The median is the same.
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which one is great 10% or 1.0- which on is greater 30% or 1/3- which one is greater 0.9 or 95%- which one is greater 80% or 5/8
Answer:
see exp
Step-by-step explanation:
1.0, 1/3, 95%, 80%
I can write an equation
Answer: y = -x + 2
Step-by-step explanation:
If you are familliar with the point-slope form this is very helpful
Point-slope:
[tex]y-y_1=m(x-x_1)[/tex]
Plug in our values of [tex]m = -1, y_1=-1,x_1=3[/tex] to get:
[tex]y-(-1) = -1(x-3)[/tex]
Simplify
[tex]y+1=-x+3[/tex]
[tex]y=-x+2[/tex]
Ive been trying to get this question but i still cant seem to understand it please help
Answer:
D:x=2
Step-by-step explanation:
Rest of the triangle is just a distraction. The distance from B to any point in the bysector is the same as the distance from C to the same point (you can look at BDF and CDF and notice they're congruent by SAS). at this point it's just solving
[tex]2x + 3 = 4x - 1 [/tex]
which has 2 as a solution
need help math problem give you 5 stars and a good rating if you do this
Answer:
Add 9.6 then divide by 3.2
the sum of three consecutive odd integers is 129. find the integers
Answer:
[tex]\huge\boxed{\sf 41,\ 43, \ 45}[/tex]
Step-by-step explanation:
Let the three consecutive integers be x, x + 2 and x + 4
So, the given condition is:
x + x + 2 + x + 4 = 129
3x + 6 = 129
Subtract 6 to both sides
3x = 129 - 6
3x = 123
Divide 3 to both sides
x = 123/3
x = 41
So, the integers are:
x = 41
x + 2 = 41 + 2 = 43
x + 4 = 41 + 4 = 45
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807What is a 15% tip on a meal that costs $38.40?
Answer:
its $5.76
Step-by-step explanation:
because $38.40 / 15 is $5.76
Which set of data has a mean of 11 and a mode of 7?
A. 7, 8, 22, 7, 11
B. 3, 5 , 7, 7, 11, 15
C. 2, 5, 7, 11, 23, 18
Answer:
its a.
Step-by-step explanation:
Pls help plz thank you
Answer:
14, 31, 62
Step-by-step explanation:
11 + 3 = 14
14*2 = 28
28 + 3 = 31
31*2=62
find the total amount due on the simple interest loan if the principle is $3000 with a rate of 5% for 10 years
Step-by-step explanation:
hope it will help you......
hello need help question below
Pre college need helppp
Answer:
check online for more information
The mean temperature for the first 7 days in January was 4 °C.
The temperature on the 8th day was 6 °C.
What is the mean temperature for the first 8 days in January?
Find the equation of a line whose slope is 6 and passing through (3 , 3 ).
Answer:
y=6x-15
Step-by-step explanation:
y-y1=m(x-x1)
y-3=6(x-3)
y-3=6x-18
y=6x-18+3
y=6x-15
5/50 divided by 15/30 solve it out for me please
Answer:
1/5
Step-by-step explanation:
First and foremost, I want to simplify these fractions, just to make everything a lot easier when I actually get to dividing. 5/50 can be divided by 5/5 to get 1/10, and 15/30 can be divided by 15/15 to get 1/2. So, now we're dividing 1/10 by 1/2.
To divide fractions, we can multiply the first fraction (in this case, 1/10) by the reciprocal of the second fraction (in this case, 1/2). The reciprocal of 1/2 is 2, so we can multiply 1/10 by 2 to find our answer. 1/10 × 2 = 2/10, or 1/5, so this is our final answer.
Hopefully that's helpful! If you have any further questions, let me know. :)
The quotient of given fractions is 1/5.
Given that, 5/50 divided by 15/30.
What are fractions?In Mathematics, fractions are represented as a numerical value, which defines a part of a whole. A fraction can be a portion or section of any quantity out of a whole, where the whole can be any number, a specific value, or a thing.
Now, 5/50 ÷ 15/30
Keep the first fraction 5/50 same change the division symbol and reciprocate the fraction 15/10
That is, 5/50 × 30/15
= 1/10 × 2/1
= 2/10
= 1/5
Therefore, the quotient of given fractions is 1/5.
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2 1/2 divided by 5/2
[tex]\dfrac{2 \tfrac 12 }{\tfrac 52}\\\\\\\\= \dfrac{\left(\tfrac 5 2\right)}{\left(\tfrac 52 \right) }\\\\\\\\=1[/tex]
NO NEED FOR LINKS NEED HELP RIGHT NOW
Answer:
1a.2
2a. 9
3a. 6000
1b. 9000
2b. 3000
3b. 9
Step-by-step explanation:
Hope you could get an idea from here.
Doubt clarification - use comment section.
2/5 x 7/9 = ( fractions )
Answer:
32/45 is your required answer
Answer:
your answer will be 14/45
Step-by-step explanation:
2/5 × 7/9
= 2 × 7
5 × 9
= 14/45
I need help with this
Answer:
check online for more information
please help i only have a few minutes left!!
Answer:
VI
Step-by-step explanation:
The letter "A" is a vowel and a capital letter, so this should be categorized in group VI, where the vowel circle and the capital letter circle overlap.
Answer:
F
Step-by-step explanation:
It is a capital letter and a vowel
Jorge heard that as a general rule, he should save at least 10% of his take-home pay. If Jorge’s take-home pay is $2950 per month, what is the minimum amount per year that he should save?
Answer:
$295
Step-by-step explanation:
2950 · 0.10 = 295
a^3/2a^0 simplify pls i need help
Answer:
a^3/2
Step-by-step explanation:
a^3/2a^0
We already know that any value to the zeroth power is 1, so we can start off by rewriting the equation as
a^3/2(1)
We also know that any value multiplied by 1 would result in itself. In this case, 2(1) is 2
Thus, our simplified expression is
a^3/2
Is the sum of 3/5 and v13 a rational or Irrational number
Answer:
The sum of 3/5 and Square root of 13 is irrational. Since square root of 13 is irrational. And when you add it gives u irrational.
40 people attended the play. 15 were women, 10 were men, and 15 were children. what fraction were men?
Answer:
10/40 were men, or simplified the amount is 1/4 of the total is men
What is the range of tanx?
1. all real numbers
2. -1 ≤ y ≤ 1
3. y > 0
all real numbers except the 90 and 270 because of cosx
Circle A has a circumference of 9 cm. Circle B has a radius of 5 cm.
Which circle has the larger circumference?
About how many centimeters larger is it?
Answer:
B has a bigger circumference.
It is larger by 69.5 cm
Step-by-step explanation:
B: 3.14×5²=78.5
A: 9
: West Gorham High School is to be located at the population center of gravity of three communities: Westbrook, population 16,000; Scarborough, population 22,000; and Gorham, population 36,500. Westbrook is located at 43.6769˚N, 70.3717˚W; Scarborough is located at 43.5781˚N, 70.3222˚W; and Gorham is located at 43.6795˚N, 70.4447˚W.
a. Where should West Gorham High School be located?
b. If only two pieces of adequate land are available for sale: Baker’s Field at 43.6784˚N, 70.3827˚W; or L onesome Acres at 43.5119˚N, 70.3856˚W, using rectilinear distances, which is closer to the site located in part (a)?
Answer:
(a) 43.6490°N, 70.3928°W
(b) Baker's Field
Step-by-step explanation:
The locations are all within a 7-mile square, so we will make the assumption of a flat Earth with parallel longitude lines. Then the "central" location will be the weighted average of the latitude and longitude coordinates.
(a)Total population is 16000 +22000 +36500 = 74,500. For purposes of the arithmetic, we will subtract 43 from latitude and 70 from longitude, then multiply each fraction by 10. Similarly, we will divide each population by 1000.
The weighted average location is found from ...
(16/74.5)(6.769, 3.717) +(22/74.5)(5.781, 3.222) +(36.5/74.5)(6.795, 4.447)
= (1.4537, 0.7983) +(1.7071, 0.9515) +(3.3291, 2.1787) = (6.490, 3.928)
The center of gravity is about 43.6490°N, 70.3928°W.
__
(b)The coordinate differences from the center of gravity are (in (°lat, °long)) ...
Baker's Field: (0.0294, -0.0101)
Lonesome Acres: (-0.1371, -.0072)
Clearly, Baker's field is closer to the site of part (a).
_____
Additional comment
Distance calculations could be refined further by considering that a degree of longitude at this latitude represents about 0.72 times the distance of a degree of latitude. In this problem, the location of Lonesome Acres has a latitude difference that is several times any of the other coordinate differences, so it is clearly much farther away from the desired location.
The calculations done here are a sort of first-level approximation. The least-significant digits in the coordinates represent a distance of less than 50 feet. If you really want accuracy to that level, then the (approximately) spherical shape of the Earth needs to be accounted for. As a second-level approximation, some reference point needs to be identified, and coordinates in miles (or feet) need to be expressed in relation to that reference. The best accuracy would be obtained using spherical trigonometry to identify the distances.
We expect any school that is constructed to be somewhat larger than 50 feet in any direction, so accuracy to the 4th decimal place in these locations is probably not required--except to satisfy some answer-checker.
What is 4/5 divied by 2/5
Answer:
2
Have a nice day :D
Answer:
2
Hope this helps
What is 5 x 2 3/10 as a mixed number in the simplest form
?
Answer:
11 1/2Step-by-step explanation:
5 × 2 3/10 = 5 × (2 + 3/10) =5 × 2 + 5 × 3/10 = 10 + 3/2 = 10 + 1 1/2 =11 1/2[tex]\large{{\sf{5 \times 2 \frac{3}{10} = \frac{115}{10} = \frac{115 \div 5}{10 \div 5} = \frac{23}{10} = {\large{\underline{\boxed{\sf{\green{11 \frac{1}{2} }}}}}}}}} \\ [/tex]