Help me out here please!!!

Answer:

Normal force = 751.75 N

Explanation:

It is given that,

The combined weight of the cyclist and the bike is 800 N

We need to find the magnitude of the normal force of the ground on the bike. It can be given by the formula as follows :

[tex]N=mg\cos\theta[/tex]

mg = W, combined weight of cyclist and bike

[tex]N=W\cos\theta\\\\N=800\times \cos(20)\\\\N=751.75\ N[/tex]

So, the magnitude of the normal force of the ground on the bike is 751.75 N.

The magnitude of the normal force of the ground on the bike is 751.752 N

The formula for that will be used to calculate the normal force of the ground on the bike is expressed as:

[tex]N= Fcos \theta[/tex]

F is the combined weight

[tex]\theta[/tex] is the angle of inclination

Given the following paramters

F = 800 N

[tex]\theta[/tex] = 20 degrees

Substitute the given parameters into the formula:

[tex]N=800 \times cos20^0\\N=800 \times 0.9397\\N=751.752N[/tex]

Hence the magnitude of the normal force of the ground on the bike is 751.752 N

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Answer:

bc of their paw pads, they don't get the traction they need in order to be able to get a firm grip to push off of on the table for each bound

Explanation:

Answer:

Soils develop faster in warm, moist climates and slowest in cold or arid ones. Rainfall is one of the most important climate factors in soil formation.

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Soil formation occurs more swiftly in warm, humid areas than it does in cold or arid ones.One of the most crucial climatic variables for the formation of soil is rainfall. The breakdown of large soil particles into smaller ones is accelerated by creatures such as bacteria, plants, and animals.

The rate of chemical reactions is accelerated by rising temperature, which also accelerates soil formation. Faster plant and bacterial growth in warmer climates aids in the weathering of materials and the formation of soils.

The formation of soil is another indirect effect of climate on organisms. Weathering is accelerated by precipitation and warm temperatures, which increases the amount of soil development. Rainfall increases the amount of organic matter, lowers pH, accelerates the leaching of basic ions, moves mud, etc.

Therefore, In warm, wet regions, soil development happens more quickly than in cold or arid ones. One of the most crucial climatic variables for the formation of soil is rainfall.

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 35 g

volume = 5 g/cm³

We have

[tex]volume = \frac{35}{5} \\ [/tex]

We have the final answer as

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Answer: they move side to side

Explanation:

i took the test

Answer:

124m/s

Explanation:

v=u+at

v=119+(0.5×10)

v=119+5

v=124m/s

Answer:

Centripetal acceleration must involve a change in a. an object's tangential speed.

Explanation:

Centripetal acceleration must involve a change in direction of motion of the object.

centripetal acceleration is the acceleration of a body traversing a circular path. Because velocity is a vector quantity (that is, it has both a magnitude, the speed, and a direction), when a body travels on a circular path, its direction constantly changes and thus its velocity changes, producing an acceleration. The acceleration is directed radially toward the center of the circle.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

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Answer:

Hans Christian Oersted

Explanation:

Answer:

Newton 3 laws

Explanation:

1.object will not change its motion unless a force acts on it . 2.the force on an object is equal to it's time mass on acceleration. 3. When 2 o jecys interact they apply forces to each other of equal.

Recall that

v² - u² = 2 a ∆x

where u and v are initial and final velocities, respectively; a is acceleration; and ∆x is the distance traveled (because the skater moves in only one direction).

So we have

(5.8 m/s)² - (8.8 m/s)² = 2 a (6.0 m)

a = ((5.8 m/s)² - (8.8 m/s)²) / (12 m)

a = -3.65 m/s²

Answer:

Water because the salt will just make it colder and the sugar won't do anything

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

where

m is the mass

f is the force

We have

[tex]a = \frac{275}{18} \\ = 15.277777...[/tex]

We have the final answer as

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Answer:

about 42.35 m/s

Explanation:

Use the equation for accelerated motion (g), and with zero initial velocity that doesn't include time:

[tex]v_f^2=v_i^2+2\,a\,\Delta x[/tex]

which for our case would reduce to:

[tex]v_f^2=v_i^2+2\,a\,\Delta x\\v_f^2=0+2\,9.8\,(91.5)\\v_f^2= 1793.4\\v_f=\sqrt{1793.4} \\v_f \approx 42.35[/tex]

then the velocity just before hitting would be about 42.35 m/s

Answer:

a

[tex]The  \ price \  for \   Compact\ fluorescent\ bulbs \ is  \ C_T  = \$ 21.067\\The   \ price \  for \    incandescent\ bulb \ is \ C_t  = \$ 43.98[/tex]

b

[tex]The \  amount  \  saved \ is  \ C_S =  \$ 22.913[/tex]

c

[tex]The \ resistance \  is \ R =  626.1 \Omega[/tex]

Explanation:

From the question we are told that

   The power used by incandescent bulb [tex]P_r  =  23.0 W[/tex]

    The power used by  Compact fluorescent bulb [tex]P_p  =  100W[/tex]

     The life span of  Compact fluorescent bulb is  [tex]t = 1000 \  hours[/tex]

    The  prices of   Compact fluorescent bulb is [tex]C_c = \$ 12 [/tex]

    The  prices of incandescent bulb is [tex]C_i = \$ 0.76 [/tex]

     The life span of   incandescent bulb is  [tex]t_k = 750   \ hours[/tex]

      The cost of electricity is [tex]C_e =  \$ 0.090/ kilowatt-hour = \frac{0.090}{1000} = \$0.00009 / W / h[/tex]

    The duration of daily bulb usage is [tex]t_d  =  4 \  hours[/tex]

Generally 3 years of bulb usage  in hours is mathematically evaluated as

    [tex]t_3 =  3 *  365 *  t_d[/tex]

=>   [tex]t_3 =  3 *  365 *  4[/tex]

=>   [tex]t_3 =  4380 \ h [/tex]

Generally the cost to power a 23W bulb for the above duration  is mathematically represented as

 [tex]Z = 23 *  t_3 * C_e[/tex]

=>   [tex]Z = 23 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 9.0667[/tex]

The number of Compact fluorescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]N  =  \frac{t_3}{ t}[/tex]

=>  [tex]N  =  \frac{4380}{1000}[/tex]

=>   [tex]N  = 0.438 [/tex]

=>  [tex]N  \approx  1 [/tex]

The total cost of  usage  for the Compact fluorescent bulb   is  mathematically represented as

      [tex]C_T  =  Z +C_c[/tex]

=>   [tex]C_T  =  9.0667 +12[/tex]

=>   [tex]C_T  = \$ 21.067 [/tex]    

The number of  incandescent bulbs required to  achieve this about of time is mathematically represented as

       [tex]M =  \frac{t_3}{ t_k}[/tex]

=>  [tex]M  =  \frac{4380}{750}[/tex]

=>   [tex]M  = 6 [/tex]

Generally the cost to power a 100W bulb for the above duration  is mathematically represented as

 [tex]Z = 100 *  t_3 * C_e[/tex]

=>   [tex]Z = 100 *  4380 * 0.00009[/tex]

=>   [tex]Z = \$ 39.42[/tex]

The total cost of  usage  for the incandescent bulbs    is  mathematically represented as

      [tex]C_t  =  C_e + [6 *C_i][/tex]

=>   [tex]C_t  =  39.42 + [0.76 *  6][/tex]

=>   [tex]C_t  = \$ 43.98[/tex]    

Generally the total amount saved is mathematically represented as

   [tex]C_S =  C_t - C_T[/tex]

=>   [tex]C_S =  43.98 - 21.067[/tex]

=>   [tex]C_S =  \$ 22.913[/tex]

Generally the resistance of the Compact fluorescent bulb is  

    [tex]R =  \frac{V^2}{P}[/tex]

    [tex]R  =  \frac{120^2}{23}[/tex]

[tex]R =  626.1 \Omega[/tex]

Answer:

V = 0.07525 [m³]

U  = 655.74 [kJ]

Explanation:

To solve this problem we must use the superheated refrigerant table for refrigerant 134a. The attached image shows the specific volume and specific internal energy values for a pressure of 800 [kPa] and a temperature of 120 [°C].

m = mass =2 [kg]

the specific volume = v = 0.037625 [m³/kg]

The volume of the tank can be found using the following expression:

V = v*m

V = 0.037625*2 = 0.07525 [m³]

The Specific internal energy = u = 327.87 [kJ/kg]

U = u*m

U = 327.87*2 = 655.74 [kJ]

Focus on vector A. Start at the base of the vector which is at (1,1)

Then notice how we have to move 3 units to the right and 2 units up to get to the tip of the vector where the arrow is located. So this is at (4,3)

The fact that we moved 3 units to the right and 2 units up means that vector A is <3, 2>

So we'll type 3 in the first box and 2 in the second box.

======================================================

We use the same idea for vector B

Start at the base and move to the tip. Doing so has us move 1 unit left and 3 units down.

Vector B = <-1, -3>

We type -1 in the first box, and -3 in the second box.

======================================================

Finally onto vector C

Start at the base (0,0). To move to the tip, we need to go 3 units left and 3 units up

Vector C = <-3, 3>

-3 goes in the first box and 3 goes in the second box

======================================================

In general, vectors are useful to tell us a specific direction in which to go. They're useful in physics to determine how exactly a force is being applied, or how a particle is moving.

Answer:

[tex]F= 17,075\ N[/tex]

Explanation:

When the car is under an accelerating force and hits a tree, the instant force received by the tree is the same force that is accelerating the car.

The accelerating force can be calculated using Newton's second law:

[tex]F=m\cdot a[/tex]

Where m is the mass of the car and a is the acceleration.

[tex]F=3,415\ kg\cdot 5\ m/s^2[/tex]

[tex]\boxed{F= 17,075\ N}[/tex]

Answer:

[tex]3. \: From \: 6 \: to \: 8 \: seconds, \: Elan \: \\ accelerated \: \: faster \: than \: Anna. [/tex]

Answer:

9.9 × 10^-16N

Explanation:

Given that a 2070 kg space station orbits Earth at an altitude of 5.37×105 m. Find the magnitude of the force with which the space station attracts Earth. 

Calculating the gravitational field strength.

g = Gm/R^2

Where G = 6.67408 × 10-11 m3 kg-1 s-2

g =(6.67408 × 10-11 × 2070)/5.37 × 10^5

g = 1.38069×10^-7 / 2.88369^11

g = 4.788×10^-19 m/s

Force F = mg

Substitute g into the formula

F = 2070 × 4.79×10^-19

F = 9.9 × 10^-16N

Answer:

Humans' internal body temperature is a great example of homeostasis. ...

Glucose is the most basic form of sugar, and the only type the body can use directly. ...

When bacteria or viruses that can make you ill get into your body, your lymphatic system kicks in to help maintain homeostasis.

Explanation:

Answer:

Option D, is closest to the answer = 950.

Answer: D. 9.5x102 kilogram.meters/second

Explanation:

correct for plato

Answer:

A

Explanation:

Switches are used to block electrical currents, thus needing to be made out of insulating material.

Answer:

26 m/s

Explanation:

v = u + at

Given that,

and v ( final velocity) = ?

v = 18 + ( 4 × 2)

v = 18 + 8

v = 26 m/s

Answer:

The magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14

Explanation:

The magnetic field at center of a circular loop is given by

[tex]B = \frac{\mu _{o}I }{2R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the radius

For the magnetic field of a long straight wire, it is given by

[tex]B = \frac{\mu _{o}I }{2\pi R}[/tex]

Where B is the magnetic field

[tex]\mu _{o}[/tex] is the free space permeability constant ( [tex]\mu _{o}[/tex] = 4π × 10⁻⁷ N/A²)

[tex]I[/tex] is the current

and [tex]R[/tex] is the distance from the wire

Then, to calculate the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I, that will be

[tex]\frac{\mu _{o}I }{2R} \div \frac{\mu _{o}I }{2\pi R}[/tex]

= [tex]\frac{\mu _{o}I }{2R} \times \frac{2\pi R }{\mu _{o}I}[/tex]

= [tex]\pi[/tex]

(NOTE: [tex]\pi[/tex] = 3.14)

Hence, the magnetic field at the center of a circular current loop of radius R divided by the magnetic field at a distance R away from a very long straight wire carrying the same current value I is [tex]\pi[/tex] or 3.14.

Answer: The motion of a ball falling down through the atmosphere, or a model rocket being launched up into the atmosphere are both examples of Newton's first law. The motion of a kite when the wind changes can also be described by the first law.

Explanation:

Answer:

20.14 KG

Explanation:

apex keepy o heads up stay positive don't stress over something useless big future 4 all of yall!

The mass is 20.14 kg

Answer:  If you are performing an experiment on the effect of spraying plants with different chemicals, you would try to maintain the same pressure and maybe the same volume when spraying your plants. The independent variable is the one factor that you are changing. It is one factor because usually in an experiment you try to change one thing at a time.

Explanation:

Answer:

Thirty years ago, the culture of American sports took a new course. An idea shouldered by a former sports communication executive, along with his son and other partners, would go on to transform the way we consume, analyze and interpret the world of athletics, and would influence international sport culture as well. While sports have always acted as a medium for those looking to escape the drudgeries of work, a way to channel negative emotions into something engaging and entertaining, ESPN presented a new opportunity for fans: an all-encompassing cable network for not only sports itself but also for the culture surrounding sports.,

Explanation:

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