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Answer:

C. Hydrogen bonds​

Explanation:

Strongest intermolecular force

Hydrogen Bonding (H-Bonding)

Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen, and are the strongest intermolecular force.

Answer: C hydrogen bonds

Explanation:

Answer:

Solid

Explanation:

Molecules in solids only vibrate in place, while the other two have moving molecules

Explanation:

The general equation for an endothermic reaction is: Reactants + Energy → Products.

Hope it helps :)❤

The equation represents an endothermic reaction is reactants + energy

products.

Endothermic reactions are chemical reactions in which the reactants soak up warm strength from the surroundings to form products.

Learn more about the endothermic reaction here:-https://brainly.com/question/6506846

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Answer:

60.86 g of PH₃

Explanation:

We'll begin by calculating the number of mole of H₂ that will occupy 60 L. This can be obtained as follow:

22.4 L = 1 mole of H₂

Therefore,

60 L = 60 / 22.4

60 L = 2.68 mole of H₂.

Next, we shall determine the number of mole of PH₃ produced by the reaction of 60 L (i.e 2.68 mole) of H₂. This can be obtained as follow:

P₄ + 6H₂ –> 4PH₃

From the balanced equation above,

6 moles of H₂ reacted to produce 4 moles of PH₃.

Therefore, 2.68 moles of H₂ will react to to produce = (2.68 × 4)/6 = 1.79 moles of PH₃.

Finally, we shall determine the mass of 1.79 moles of PH₃. This can be obtained as follow:

Mole of PH₃ = 1.79 moles

Molar mass of PH₃ = 31 + (3×1)

= 31 + 3 = 34 g/mol

Mass of PH₃ =?

Mass = mole × molar mass

Mass of PH₃ = 1.79 × 34

Mass of PH₃ = 60.86 g

Thus, 60.86 g of PH₃ were obtained from the reaction.

Answer:

No

Explanation:

AgNO₃ + KCl --> AgCl + KNO₃

This reaction is a precipitation reaction. AgCl is formed as a white solid due to its low solubility in water.

Answer:

Explanation:

The standard molar mass is:

For (S )-1-chloro-4-ethyl-2-methylhexane = 162.5 g/mol

For triphenylphosphine  = 262 g/mol

For  ( S )-1-chloro-4-ethyl-2-methyl triphenylphosphonium = 424.5 g/mol

The mass required for 81% yield = [tex]\dfrac{81}{100} \times Theoretical \ yield = 4.15 g[/tex]

Theoretical yield = [tex]\dfrac{4.15}{0.81}[/tex]

= 5.1235 g

thus, since 424.5 g yield produce from 162.5 g

∴

5.1235 g yield will produce = [tex]\dfrac{162.5}{424.5}\times 5.1235 \ g[/tex]

= 1.9613 g of alkyl halide (-chloro) required.

Also, since 424.5 g yield produce from 262 g phosphine

∴

5.1235 g yield will produce = [tex]\dfrac{262}{424.5}\times 5.1235 \ g[/tex]

= 3.1622 g of triphenylphosphine required.