The pH of tomato juice is 4, thus tomato is a (an) _______________ substance
Answer:
Acidic
Explanation:
pH from 0-6.9 are acidic substances
pH of 7 are neutral
pH above 7 to 14 are badic substances
Answer: Acidic
Explanation:
PH of 1-6 is considered acidic.
PH of 7 is neutral.
PH of 8-14 is considered basic (alkaline)
balance : _ Na + _ H2O
Answer:
2, 2
Explanation
What is the chemical formula for this?
Answer:
-OOH
Explanation:
This forms an acid if it comes in contact with a metal
Answer:
HO2; Hydroperoxyl
Explanation:
Since there are two oxygen molecules, and one hydrogen molecule, it can be classified as a hydroperoxyl molecule.
It is an inorganic compound with the following characteristics
Covalent compound (O,H are nonmetals) Valence of O (O must form an octet): 6 Valence of H: 1 Total valence electrons: 13 Molar mass: 33.01 g/molWhich of the following accurately describes the orbital path of most planets in our solar system?
The orbital path is in a perfect circle.
The orbital path looks circular.
The orbital path is in a large elliptical shape.
The orbital path varies greatly from planet to planet.
If you have 1.5 grams of silver nitrate, how many grams of silver could
you produce?
Answer:
0.95g of Ag we can produce
Explanation:
To solve this question we have to convert the mass of silver nitrate (AgNO₃) to moles. The moles of silver nitrate = Moles of Ag. Then, with molar mass of Ag we can know the mass of silver:
Moles AgNO₃ -Molar mass: 169.87g/mol-:
1.5g * (1mol / 169.87g) = 0.0088 moles Ag
Mass Ag -Molar mass: 107.87g/mol-:
0.0088 moles Ag * (107.87g / mol) =
0.95g of Ag we can producedefine a lone pair and give example
Answer:In chemistry, a lone pair refers to a pair of valence electrons that are not shared with another atom in a covalent bond and is sometimes called an unshared pair or non-bonding pair. Lone pairs are found in the outermost electron shell of atoms. They can be identified by using a Lewis structure.
Hey guys so my cuz gave me this stone when he went to mexico
can u plz tell me what kind of stone this is?
Answer:
pretty sure that's an old jolly rancher
I used a stick of (vegan) butter as our example of thinking about how temperature changes the properties of something when it is wamer or cooler.
1. What is something else you could use to describe how temperature affects the properties of when it is warmer or cooler? How does this change whether it is warm or cold. Describe it.
Which pieces of equipment are
needed to calculate the velocity of a
falling object?
A stopwatch and balance
B speedometer and magnet
C compass and tape measure
D tape measure and stopwatch
How do I perform a titration on coca-cola or Pepsi, when I cannot see the color change because the color is too dark. The indicator is phenolphthalein.
Answer: maybe you need to do very dilute solution?
Explanation: you should have an pH meter instead of indicator.
Phosphoric acid H3PO4 have three ekvivalent points.
Another way could be using a conductivity meter.
What is the value that is MEASURED in a lab?
Answer:
To use standard laboratory measurement devices to measure length, volume and mass amounts.
PLSSSS ANSWERRRRRR?????
Write a short paragraph about how gases are all around you. Provide at least 2 examples
Answer:fart and carbon are all around is
Explanation:
URGENT!!! PLEASE HELP!!!
file:///home/chronos/u-83abb8ba8be89334c9d7433161c45cb8ec059a4c/MyFiles/Downloads/The_Strange_Case_of_Avogadro_Airlines.pdf
Answer:
what is your question sorry cause I don't trust hope you understandanymore feel free tell me your question you are struggling with l be glad to help you
explain why copper 2 oxide is a base although it does not turn litmus paper to blue
Answer:
See explanation
Explanation:
Copper II oxide is a base but not an alkali. An alkali is a soluble base. Since Copper II oxide is not soluble in water then it is not an alkali.
Let us recall that the change of colour of litmus with an alkali requires the presence of water. In the absence of water, solid Copper II oxide does not turn red litmus paper blue.
The ability to turn red litmus paper blue is commonly observed with alkalis and Copper II oxide is not an alkali.
Also recall that since Copper II oxide is not soluble, hydroxide ions are absent hence Copper II oxide does not turn red litmus paper blue.
pleaaseeee help im failing so bad3
what element has 5 protons, 7 electrons, and 6 neutrons
Answer: Boron
Explanation: lol
Answer:
Boron. (What kind of name is that?????????????)
Explanation:
PLEASEEEEE ANSWERRR??
PLEASE Answer asap! Compare two periodic families below. You must include at least two facts about each family. You may use any description of properties or periodic trends to help you.
Answer:
The alkali metals/group 1 are recognized as a group and family of elements. These elements are metals. Sodium and potassium are examples of elements in this family. Hydrogen is not considered an alkali metal because the gas does not exhibit the typical properties of the group. The largest family of elements consists of transition metals/group 3-12/group 3a. The center of the periodic table contains the transition metals, plus the two rows below the body of the table (lanthanides and actinides) are special transition metals. Even though both are metals, transition metals have higher melting points; they have higher density; they are less reactive with water; they react and form ions with different charges, but Group 1 metals only form 1+ ions. (Hope the is helpful! You can reword it if you want...)
Which of the following is a TRUE statement?
a.
A molecule always has three types of elements present
b.
Compounds always include the elements hydrogen and sodium
c.
Compounds include things we use in our everyday lives
d.
All elements prefer to hang out with other elements and form molecules
Answer:
b
Explanation:
The gas phase decomposition of phosphine at 120 °C
PH3(g)1/4 P4(g) + 3/2 H2(g)
is first order in PH3 with a rate constant of 1.80×10-2 s-1.
If the initial concentration of PH3 is 8.48×10-2 M, the concentration of PH3 will be 2.45×10-2 M after
s have passed.
Answer:
The decreasing in concentration occurs after 69.0s
Explanation:
A first order reaction follows the equation:
Ln [A] = -kt + ln[A]₀
Where [A] is the concentration of the reactant after time t
k is rate constant of the reaction
And [A]₀ is the initial concentration of the reactant
Replacing:
Ln 2.45x10⁻²M = -1.80x10⁻²s⁻¹*t + ln8.48x10⁻²
-3.709 = -1.80x10⁻²s⁻¹*t -2.467
-1.2416 = -1.80x10⁻²s⁻¹*t
69.0s = t
The decreasing in concentration occurs after 69.0s
True/False: Energy can’t be created or destroyed: it can only be transferred from one place to another.
Answer:
true
Explanation:
Answer:
True.
Explanation:
It is true that energy cannot be made or lost, but it can move. For example, if you touch a metal pole and get a static shock, then the energy from the pole is being transferred to you. However, energy was not made or lost in the process. So, energy cannot be made or destroyed, but it can be moved. This also means there was the same amount of energy in the universe as there was millions of years ago. Hope this helps!
Which of the following is an indication that a substance has undergone a chemical change?
A.
No new product has been formed.
B.
The color of the substance has not changed.
C.
The original constitute has not changed.
D.
The molecular structure has changed.
Answer:
D.
Hope it helps!!!!!!!!!
H IT H-C --H + Ħ Н The model above shows the structural formula for ethane. What is the chemical formula for ethane? OA. C2H6 OB. 2CH3 Oc. 8CH OD. C6H2
Answer:
B
Explanation:
A projectile is projected with an initial velocity of 40 m/s at a 45o angle to the horizontal. , calculate the total time travelled.
Answer:
5.77 s
Explanation:
From the question,
The total time travelled by the projectile = Time of flight (T)
T = 2usinθ/g............ Equation 1
Where T = Time of Flight of the projectile, u = Initial velocity, θ = Angle of projection to the horizontal, g = acceleration due to gravity
Given: u = 40 m/s, θ = 45°
Constant: g = 9.8 m/s²
Substitute these values into equation 1
T = 2(40)sin(45°)/9.8
T = 80sin(45°)/9.8
T = 80×0.7071/9.8
T = 5.77 s
The shape of the directly sunlit portion of the Moon as viewed from
Earth
your answer:
lunar phases
There
are
approximately
317,000,000
people
in
the
U.S.,
and
the
area
of
the
U.S.
is
about
4,000,000
square
miles.
If
the
people
were
spread
out
evenly,
about
how
many
people
are
there
per
square
Answer:
yesddgfhzxhcvnjxkcncjzdkccchjjbxbxbbk
Calculate the value of Key in the following reaction if the equilibrium concentrations are
[H2S] -0.25 M, (H2) - 0.88 M, [S2] -0.44M.
2 H2Sig) = 2 H2(g) + S218)
Answer:
The value of the equilibrium constant Kc is 5.45
Explanation:
The "Law of Mass Action" states:
"For a reversible reaction in chemical equilibrium at a given temperature, it is true that the product of the concentrations of the products raised to the stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients is a constant."
This constant was called the equilibrium constant. For a reaction:
aA + bB ⇄ cC + dD
the equilibrium constant Kc is:
[tex]Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }[/tex]
In this case, the balanced reaction is:
2 H₂S → 2 H₂ + S₂
So, the equilibrium constant Kc is:
[tex]Kc=\frac{[H_{2} ]^{2} *[S_{2} ] }{[H_{2} S]^{2} }[/tex]
The equilibrium concentrations are
[H₂S] =0.25 M[H₂]= 0.88 M[S₂]= 0.44MReplacing in the definition of equilibrium constant:
[tex]Kc=\frac{(0.88 M)^{2} *0.44 M }{(0.25 M)^{2} }[/tex]
Solving:
Kc= 5.45
The value of the equilibrium constant Kc is 5.45
What is the mass of 5.6 moles of Iron (III) Oxide?
Answer:
312.731
Explanation:
it had a long answer but im sure ur teacher wanted u to round it
hope this helps!
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:)
HURRY!!!!!! HELP PLEASEEE
To begin the experiment, 1.65g of methane CH4 is burned in a bomb calorimeter containing 1000 grams of water. The initial temperature of water is 18.98oC. The specific heat of water is 4.184 J/g oC. The heat capacity of the calorimeter is 615 J/ oC . After the reaction the final temperature of the water is 36.38oC.
2. Calculate the change in temperature, ΔT. Show your work. (1pt)
3. Calculate the heat absorbed by water. Use the formula qwater = m • C • ΔT
Show your work (2pts)
4.Calculate the heat absorbed by the Calorimeter. Use the formula:
qcal = Ccal • ΔT Show your work. (2pts)
5. The total heat absorbed by the water and the calorimeter can be calculated by adding the heat calculated in steps 3 and 4. The amount of heat released by the reaction is equal to the amount of heat absorbed with the negative sign as this is an exothermic reaction. (2pts)
a.Using the formula ΔH = - (qcal + qwater ) , calculate the total heat of combustion. Show your work.
b. Convert heat of combustion (answer from part a) from joules to kilojoules. Show your work.
6. Evaluate the information contained in this calculation and complete the following sentence: (2pts)
This calculation shows that burning _______ grams of methane [TAKES IN] / [GIVES OFF] energy (Choose one).
7. The molar mass of methane is 16.04 g/mol. Calculate the number of moles of methane burned in the experiment. Show your work. (2pts)
8. What is the experimental molar heat of combustion in KJ/mol? Show your work. (2pts)
9. The accepted value for the heat of combustion of methane is -890 KJ/mol . Explain why the experimental data might differ from the theoretical value in 2-3 complete sentences. (2pts)
10. Given the formula:
% error= |(theoretical value - experimental value)/theoretical value)| x 100
Calculate the percent error. Show your work. (2pts)
The calorimter is equal to the heat released by the reaction. Calculate the heat released by the reaction.
What is the reaction?The reaction to the news can vary depending on who you are speaking to. For some, the news may be welcomed as a sign of progress and a move in the right direction. Others may be apprehensive, uncertain of the potential outcomes or changes that may come as a result. Some may be angry and frustrated, feeling as though the news has been a long time coming and they have not been given a say in the matter.
1. ΔT = 36.38oC - 18.98oC = 17.4oC
2. qwater = m • C • ΔT
qwater = (1000g)(4.184J/g oC)(17.4oC)
qwater = 71376.8 J
3. qcal = Ccal • ΔT
qcal = (615J/ oC)(17.4oC)
qcal = 10666.1 J
4. qreaction = qwater + qcal
qreaction = 71376.8 J + 10666.1 J
qreaction = 82042.9 J
To learn more about reaction
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