Given the domain {-4, 0, 5}, what is the range for the relation 12x + 6y = 24?

A.
{-4, 4, 14}
B.
{2, 4, 9}
C.
{-12, -4, 6}
D.
{12, 4, -6}

Answer: 157.19

Step-by-step explanation:

Answer:  The answer is -2

Step-by-step explanation: I want points and trust me this answer is correct

Answer:

x = 15°

Step-by-step explanation:

(5x-15) + 75 + 3x = 180

8x + 60 = 180

8x = 120

x = 15°

Answer:

c

Step-by-step explanation:

Answer:

C is the answer

Answer: 63.1

Step-by-step explanation:

Answer:

Step-by-step explanation:

(1-2*1) (3*2+4*-1*1- 1*2)

=-1 (6+4-1-2)

-1*7

-7

Answer:

=

7

Step-by-step explanation:

Answer:

8.36 I think

Step-by-step explanation:

Answer: 2/9

Steps: 8/36 simplified is 2/9.

Plz mark brainliest:)

Answer:

x= 9/a

Step-by-step explanation:

Answer:

b=(d-c)/a

Step-by-step explanation:

Just gotta switch them around a bit

Answer:

its 10

Step-by-step explanation:

I got it right

Answer:

the answer is 1/8

thank you

if you loved my answer then please like it and mark as brainliest

Answer:

237ft²

63.5ft

Step-by-step explanation:

Given parameters:

  Length  = 19[tex]\frac{3}{4}[/tex] ft

   Width  = 12ft

Unknown:

Area of rectangle  = ?

Perimeter of rectangle  = ?

Solution:

Area of rectangle  = length x width

                              = 19[tex]\frac{3}{4}[/tex] x 12

                               = [tex]\frac{79}{4}[/tex] x 12

                               = 79 x 3

                              = 237ft²

Perimeter of rectangle  = 2(length + width)

                                      = 2 (19.75 + 12 )

                                     = 63.5ft

Answer:

the transformation T(a, b) can be change the pre image to the final image by following the rule as we explain below

if A(x, y) is a pre image, then A ' ( x', y') is its image, and x' = a+x, y' = b + y, where because of T(a, b) transformation

in our case Quadrilateral GHJK has vertices G(2, 3), so the coordinates of G”

can be found with

T(-4, -5) applied to G(2, 3) ⇒ G' (-4 +2, -5+3)=G' (-2, -2)

T(-4, -5) applied to G' (-2, -2) ⇒ G"(-4-2, -5-2) =G"(-6, -7)

the coordinates of G” are (-6, -7)

Step-by-step explanation:

Answer:

its c on edg (-1, -7)

Step-by-step explanation:

Answer: The numerator and denominator degrees of freedom (respectively) for the critical value of F are 4 and 118 .

Step-by-step explanation:

We know that , for critical value of F, degrees of freedom for numerator = k-1

and for denominator = n-k, where n= Total observations and k = number of independent variables.

Here, Numbers of independent variables(k) = 5

Total observations (n)= 123

So, Degrees of freedom for numerator  = 5-1=4

Degrees of freedom for denominator =123-5= 118

Hence, the numerator and denominator degrees of freedom (respectively) for the critical value of F are 4 and 118 .

Answer:

Let's define the variables:

S = # of sweet pepper seeds in the mix pack.

H = # of hot pepper seeds in the mix pack.

Let's suppose that $3.30 is the mean price of the seeds in the mix pack.

Then we have two equations:

S + H = 16.

(S*$2.85 + H*$4.29)/16 = $3.30

Now let's solve this system.

The first step is isolating one variable in one of the equations, i will isolate S in the first equation.

S = 16 - H.

Now we can replace this in the second equation, and solve it for H.

( (16 - H)*$2.85 + H*$4.29)/16 = $3.30

( (16 - H)*$2.85 + H*$4.29) = $3.30*16 = $52.80

$45.60 + H*$1.44 = $52.80

H*$1.44 = $52.80 - $45.60 = $7.20

H = $7.20/$1.44 = 5

Then in the mix pack there are 5 hot-pepper seeds.

And the other 11 must be sweet-pepper seeds

Algebraic equations are equations that contain unknown variables.

The number of packets of sweet-pepper seeds is 11 and the number of packets of hot-pepper seeds is 5.

Let's represent:is

The number of packets of sweet-pepper seeds = s

The number of packets of hot-pepper seeds = h

Based on this question, our system of equations are:

$2.85 x s + $4.29 x h = $3.30(16)

2.85s + 4.29h = 52.8...........Equation 1

s + h = 16...........Equation 2

s = 16 - h

We substitute 16 - h for s in Equation 1

2.85(16 - h) + 4.29h = 52.8

45.6 -2.85h + 4.29h = 52.8

Subtract 45.6 from both sides

45.6 - 45.6 -2.85h + 4.29h = 52.8 - 45.6

1.44h = 7.2

h = 5

There are 5 hot-pepper seeds in the assortment.

Solving for the number of sweet-pepper seeds.

s = 16 - h

s = 16 - 5

s = 11

There are 11 sweet-pepper seeds in the assortment.

Therefore, the number of packets of sweet-pepper seeds is 11 and the number of packets of hot-pepper seeds is 5.

To learn more, visit the link below:

brainly.com/question/12978834

Answer:

2(6-4.05+8)

Step-by-step explanation:

2(6-48+43.05+8)

Answer:

Step 1) 7*7 = 49

Step 2)  49/5 = 9.8

Answer:

Step-by-step explanation:

7x7=49, 49 divided by 5=9.8, hope I helped! :P

Answer:

35 failed and 140 passed

Step-by-step explanation:

Let  p = number who passed

f = number who failed

p+f = 175

4 times the number of students passed as failed, so we need to balance this to set it equal

4f = p

Substitute this into the first equation

4r+f = 175

5f = 175

5f/5 =175/5

f = 35

Now find the number who passed

p = 4f

p = 4*35

p =140

Step-by-step explanation:

12

Answer:

11

Step-by-step explanation:

11+12+13 =36

So  Kate would be 11. Bradley would be 12. And Cameron would be 13

The length of Bob's drive as a fraction = 5/5

Let the length of his total drive be = x

30 miles driven by Bob as a fraction =

= 3/5 of x = 30

= 3/5x = 30

= 5/x = 30 ÷ 3 ( transposing ×3 from LHS to RHS changes ×3 to ÷3 )

=5/x = 10

= x = 10 × 5 ( transposing ÷5 from LHS to RHS changes ÷5 to ×5 )

= x = 50

Now we have to see what is =

= 2/5 of 50

= 2/5 × 50

= 100/5

= 20 miles

So , total length of Bob's drive = 30 miles + 20 miles = 50 miles .

∴ The total length of Bob's drive is 50 miles .

5x+6+92 = 22x-4

5x+98 = 22x-4

add 5x to both sides

98 = 27x-4

add 4 to both sides

102 = 27x

divide both sides by 27

x = 3 and [tex]\frac{7}{9}[/tex]

-5.33333333333

I used a calulator can I get brainliest please

====================================

Work Shown:

2/15 = h/125

2*125 = 15*h .... cross multiply

250 = 15h

15h = 250

h = 250/15

h = (5*50)/(5*3)

h = 50/3

-----------------

Extra info:

50/3 = (48+2)/3

50/3 = (48/3)+(2/3)

50/3 = 16 + (2/3)

50/3 = 16 & 2/3

The improper fraction 50/3 converts to the mixed number 16 & 2/3

Another way to see this is to use long division to get 50/3 = 16 remainder 2.

Answer:

90000

Step-by-step explanation:

Y = x(600 - x)

Let's rearrange the equation so that we have

Y = x(-x + 600)

Y = -x² + 600

When you take a look at parabolas, we know that their maximum or minimum values are usually on the axis of symmetry. This axis of symmetry has an equation of

x = -b/2a,

In this question, the axis of symmetry is

x = -600 / -2

x = 300

This means that planting 300 trees will maximize your yield. If you substitute for x = 300 into the equation, the maximum yield will be

y = 300 (600 - 300)

y = 90000.

Answer: 300

Step-by-step explanation:

use the formula X=-b/2a

x=-600/-2

x=300

[tex]\large\underline{\bf \red{Step \:by\: Step \:Explanation:}}[/tex]

Let us take ,

Also let us consider x > y .

According to first Condition :-

⇒ x - y = 1.

⇒ x = y + 1. .............(i)

According to second Condition :-

⇒ x × y = 30 .

⇒ ( y + 1 )y = 30 . [ From (i) ]

⇒ y² + y = 30.

⇒ y² + y - 30 = 0 .

⇒ y² + 6y - 5y -30 = 0.

⇒ y ( y + 6 ) -5 ( y + 6 ) = 0 .

⇒ ( y + 6 ) ( y - 5 ) = 0 .

[tex]\red{\bf \longmapsto y = 5 , (-6)}[/tex]

Here y can sustain both values 5 and minus 6 as y is an integer.

So , x = -6 , 5 .

Hence possible answers are ,

[tex]\boxed{\purple{\bf x = -6 , y = -5 }}[/tex]

[tex]\qquad\qquad\qquad \bf Or [/tex]

[tex]\boxed{\purple{\bf x = 6 , y = 5 }}[/tex]

.

Answer:

1.   [tex]n: n^3 > 0[/tex] is not true for negative integers

2.  [tex]45\ and\ 45[/tex] show that all angles do not have different measure

3.  [tex]Fraction = \frac{1}{3}[/tex]

Step-by-step explanation:

Solving (1):

[tex]n: n^3 > 0[/tex]

Take

[tex]n = -1[/tex]

[tex]-1^3 = -1[/tex]

[tex]n: n^3 > 0[/tex] is not true for negative integers

Solving (2):

The angles of a right angled triangle are:

[tex]45, 45\ and\ 90[/tex]

[tex]45\ and\ 45[/tex] show that all angles do not have different measure

Solving (3):

When

[tex]Bills = 48[/tex]

[tex]Counterfeit = 16[/tex]

The fraction is calculated as thus:

[tex]Fraction = \frac{Counterfeit}{Bills}[/tex]

[tex]Fraction = \frac{16}{48}[/tex]

[tex]Fraction = \frac{1}{3}[/tex]

Similarly, when

[tex]Bills = 39[/tex]

[tex]Counterfeit = 13[/tex]

[tex]Fraction = \frac{Counterfeit}{Bills}[/tex]

[tex]Fraction = \frac{13}{39}[/tex]

[tex]Fraction = \frac{1}{3}[/tex]