For the reaction So3 + H2O -> H2SO4, how many grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid

Answers

Answer 1

Answer:

320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.

Explanation:

The balanced reaction is:

SO₃ + H₂O → H₂SO₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

SO₃: 1 moleH₂O: 1 moleH₂SO₄: 1 mole

Being the molar mass of each compound:

SO₃: 80 g/moleH₂O: 18 g/moleH₂SO₄: 98 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

SO₃: 1 mole* 80 g/mole= 80 gramsH₂O: 1 mole* 18 g/mole= 18 gramsH₂SO₄: 1 mole* 98 g/mole= 98 grams

Then you can apply the following rule of three: if 1 mole of sulfuric acid is produced by the reaction of 80 grams of sulfur trioxide, 4 moles of sulfuric acid is produced from how much mass of sulfur trioxide?

[tex]mass of sulfur trioxide= \frac{4 moles of sulfuric acid* 80 grams of sulfur trioxide}{1 mole of sulfuric acid }[/tex]

mass of sulfur trioxide= 320 grams

320 grams of sulfur trioxide are required to produce 4.00 mol of sulfuric acid.

Answer 2

The mass of the required compound is 320 grams

Chemical reactions

Given the chemical equation expressed as:

[tex]SO_3 + H_2O \rightarrow H_2SO_4[/tex]

According to stochiometry, 1 mole of SO3  produces 1 mole of H2SO4, hence the moles of SO3 will also be 4.00moles

Determine the mass of SO3

Mass = mole * molar mass

Mass = 4.0 * [32+3(16)]

Mass = 4.0 * 80

Mass = 320 grams

The mass of the required compound is 320 grams

Learn more on stoichiometry here:  https://brainly.com/question/16060223


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