for hundreds of years scientists deny the existence of rogue waves until the presence of when was finally caught on record. when and where was the first time a rogue wave was measured?

Answers

Answer 1

Answer:

A rogue wave estimated at 18.3 meters (60 feet) in the Gulf Stream off of Charleston, South Carolina. At the time, surface winds were light at 15 knots.

Explanation:

Rogue, freak, or killer waves have been part of marine folklore for centuries, but have only been accepted as real by scientists over the past few decades.

Rogues, called 'extreme storm waves' by scientists, are those waves which are greater than twice the size of surrounding waves, are very unpredictable, and often come unexpectedly from directions other than prevailing wind and waves.

Most reports of extreme storm waves say they look like "walls of water." They are often steep-sided with unusually deep troughs.

Since these waves are uncommon, measurements and analysis of this phenomenon is extremely rare. Exactly how and when rogue waves form is still under investigation, but there are several known causes:

Constructive interference. Extreme waves often form because swells, while traveling across the ocean, do so at different speeds and directions. As these swells pass through one another, their crests, troughs, and lengths sometimes coincide and reinforce each other. This process can form unusually large, towering waves that quickly disappear. If the swells are travelling in the same direction, these mountainous waves may last for several minutes before subsiding.

Focusing of wave energy. When waves formed by a storm develop in a water current against the normal wave direction, an interaction can take place which results in a shortening of the wave frequency. This can cause the waves to dynamically join together, forming very big 'rogue' waves. The currents where these are sometimes seen are the Gulf Stream and Agulhas current. Extreme waves developed in this fashion tend to be longer lived.

Hope this helps, have a nice day/night! :D

Answer 2

On January 1st, 1995, the first accurate measurement of a rogue wave took place. It was captured by a laser detector on Statoil's Draupner oil drilling rig, which is situated 100 miles off the Norwegian coast.

What is rogue wave?

Although rogue, freak, or killer waves have been mentioned in maritime legend for many years, scientists have only recently acknowledged their existence.

Scientists refer to these waves as "rogues," or "severe storm waves," since they are more than twice as large as the waves around them, very unpredictable, and frequently arrive from directions other than the prevailing wind and waves.

Extreme storm waves are typically described as looking like "walls of water" in reports. Frequently, they have steep sides and exceptionally deep valleys.

Measurements and analyses of this phenomenon are extremely rare because these waves are not common.

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Related Questions

A rock climber’s shoe loosens a rock, and her climbing buddy at the bottom of the cliff notices that the rock takes 3.20 s to fall to the ground. How high up the cliff is the rock climber?

Answers

Answer:

50.176 [m].

Explanation:

1) the required height can be calculated using the formula:

h=V₀*t+1/2* g*t₂, where V₀ - initial velocity of the rock, t - elapsed time, g - 9.8 m/s²;

2) if V₀=0, t=3.2, g=9.8, then

h=0.5*9.8*3.2²=1024*49*10⁻³=50.176 [m].≈50[m].

if an astronaut has a mass of 80kg on earth, what is their mass on the moon?

Answers

Answer:

130 N basically

Explanation:

A car of mass 1500 kg is moving with a velocity of 30 m/s. If the velocity-time graph for this car
is a horizontal line parallel to the time axis, then the velocity of the car at the end of 25 s will be

Answers

Answer:

v=30m/s

Explanation:

m = 1500kg

v = 30m/s

t = 25s

The velocity time graph is parallel to the time axis,

that means The Velocity is constant. ('constant' means remains same).

Therefore, after 25s, v=30m/s

The metal hammer has a mass of 1500 kg and it hits the baseplate
with a speed of 8.0 m/s.
0 Calculate the kinetic energy of the hammer as it hits the baseplate.

Answers

Answer:

2300.68

Explanation:

The metal hammer has a mass of 1500 kg and it hits the baseplate

with a speed of 8.0 m/s.

0 Calculate the kinetic energy of the hammer as it hits the baseplate. there for it will create the kinetic energy of 2300.68 as it hits the baseplate.

1. If the mass of an object is measured in kg and the velocity is measured in m/s, what is the unit for momentum?​

Answers

The unit for momentum is equal to Kgm/s.

Given the following data:

Unit of mass = Kilogram (kg).Unit of velocity = meter per seconds (m/s).

To determine the unit for momentum:

What is momentum?

In Science, momentum can be defined as a multiplication of the mass of an object and its velocity.

Mathematically, momentum is giving by this formula;

[tex]Momentum = mass \times velocity[/tex]

Substituting the given parameters into the formula, we have;

[tex]Momentum = kg \times m/s\\\\[/tex]

Momentum = Kgm/s.

Read more on momentum here: brainly.com/question/15517471

The best evidence for dark matter in the milky way comes from the observation that the rotation curve

Answers

It’s quite flat at great distance from the center

Which choice can be classified as a pure substance?
A. homogeneous mixture
B. compound
C. heterogeneous mixture
D. solution

Answers

Definitely a compound mixture

Please Help

A car travels on a straight road with velocity components of 20 m/s west and 70 m/s south. What is the total distance the car travels in 50 s?

Answers

I know I don’t know what the problem

A 10 kg box is motionless on the floor. If the coefficient of static friction is 0.4 and the coefficient of kinetic friction is 0.3 (between the box and the floor), find the force required to start the block in motion
Please I need help ❤️

Answers

The force required to start the block in motion is equal to 39.2 Newton.

Given the following data:

Mass of box = 10 kgCoefficient of static friction = 0.4 Coefficient of kinetic friction = 0.3

To determine the force required to start the block in motion:

Note: The force that is required to start the block in motion must be greater than or equal to the force of static friction.

Mathematically, the force of static friction is given by the formula;

[tex]Fs = uFn = umg[/tex]

Where;

Fs represents the force of static friction.μ represents the coefficient of friction.[tex]F_n[/tex] represents the normal force.g is the acceleration due to gravity.m is the mass of an object.

Substituting the given parameters into the formula, we have;

[tex]F_s = 0.4 \times 10 \times 9.8\\\\F_s = 4 \times 9.8\\\\F_s = 39.2\;Newton[/tex]

Read more on force of static friction here: https://brainly.com/question/25686958

what types of electromagnetic radiation does the sun emit?

Answers

Answer:

https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf

Explanation:

Menciona tres diferencias entre un planeta y un satélite natural.

Answers

Answer:

1. Un planeta gira alrededor del Sol mientras que un satélite  gira alrededor de un planeta.

2. Tamaño

3. Aspectos Físicos

4. Creación

what is the model size to actual size

Answers

Answer:

You have to divide your real measurement to the model. For example, if your real measurement is 5m and your model is 20cm, divide 5/20 =1/4 and that means the ratio would be 1:4.

Explanation:

which of these MANNER of death? (select all that apply)
1-blood loss
2-cessation of brain function
3-accidential death
4-stabbing
5-pulmonary arrest
6-homicidal death
7-natural death
8-shooting

Answers

Answer:

3, 4, 6, 7, 8 are manners of death.

Tại sao khi bị sì hơi quả bóng bay sẹp lại?

Answers

Answer:

what is this language??

các phân tử khí sẽ bị lọt ra ngoài, theo nguyên tắc vật lý thì áp suất khí bên trong càng cao thì các hạt phân tử khí bị lọt ra càng nhanh.

true and false? When an object remains stationary, any forces acting on it must be balanced.

Answers

Answer:

Balanced forces acting on a stationary object cause the object to remain at rest. True: Forces can give energy to an object it acts on causing the object to change it state of motion. If forces acting on an object are balanced, they do not cause a change in motion.

Answer:

False

Explanation:

It is NOT possible for just three forces to be acting upon an object and they still balance each other. A free-falling object experiences a balance of forces.

ASAP
A truck is speeding up (with a constant acceleration) from rest to 45 m/s and it takes it 15 seconds to do so. How far will the car travel?

Answers

Answer:

675 KM

Explanation:

hAVE A NICE DAY

675 km
Hope that helps

which of the following changes will result in a weaker electromagnet

Answers

Answer:

Changing the metal core for a different metal will make the electromagnet stronger or weaker.

Explanation:

Hope this helped, nya~ :3

7. A taxi is travelling at 15 m/s. Its driver accelerates with acceleration 3 m/s2 for 4 s. What is its new velocity​

Answers

Hi there!

To solve, we can use the following equation:

vf = vi + at

vi = initial velocity (m/s)

a = acceleration (m/s²)

t = time (s)

vf = final velocity (m/s)

Plug in the given values:

vf = 15 + 3(4)

vf = 15 + 12 = 27 m/s

Answer:

[tex]\boxed {\boxed {\sf 27 \ m/s}}[/tex]

Explanation:

We are asked to find the new or final velocity of a taxi.

We will use the following kinematic equation:

[tex]v_f=v_i+at[/tex]

The car was initially traveling at 15 meters per second. It accelerated at 3 meters per second squared for 4 seconds.

[tex]v_i=[/tex]15 m/s[tex]a=[/tex]3 m/s ²t= 4 s

Substitute the values into the formula.

[tex]v_f= 15 \ m/s + (3 \ m/s^2* 4 \ s)[/tex]

Multiply the numbers in parentheses.

3 m/s/s * 4 s = 3 m/s *4 = 12 m/s

[tex]v_f= 15 \ m/s +12 \ m/s[/tex]

Add.

[tex]v_f=27 \ m/s[/tex]

The new velocity of the taxi is 27 meters per second.

In the very distant future, given our best model of the accelerating universe, what will the universe look like?

Answers

The models of the universe allow finding the result for how serious the universe in the distant future is:

In the distant future the galaxies are far apart and the interaction between them would be negligible.

The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.

Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.

Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.

In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:

In the distant future the galaxies are far apart and the interaction between them would be negligible.

Learn more about the motion of the galaxies here:  brainly.com/question/18212080

please help me please help​

Answers

Answer:

Answer Distance is 5 × 10⁴ km

Explanation:

Gravitational formular

[tex]{ \tt{F = \frac{GMm}{ {r}^{2} } }} \\ [/tex]

F is the gravitational forceG is the universal gravitational constantr is the separation distanceM & m are the masses

For the first case;

[tex]{ \tt{F _{1} = \frac{GMm}{2.5 \times {10}^{4} } }} \\ [/tex]

For the second case;

[tex]{ \tt{F _{2} = \frac{GMm}{r _{2}} }} \\ [/tex]

but F2 = ½F1

Therefore, F1 = 2F2

Hence:

[tex]{ \tt{ \frac{GMm}{2.5 \times {10}^{4} } =2 \times \frac{GMm}{r _{2} } }} \\ \\ { \tt{ \frac{1}{2.5 \times {10}^{4} } = \frac{2}{r _{2} } }} \\ \\ { \tt{r _{2} = 2 \times 2.5 \times {10}^{4} }} \\ \\ { \underline{ \tt{ \: \: r _{2} = 5 \times {10}^{4} \: km \: \: }}}[/tex]

Answer: Distance is 5 × 10⁴ km

Explanation:

If you have a rocket that has a mass of 20kg and is accelerating at 25 m/s what force
would that rocket experience?
a . 20N
b . 40000N
c. 500N
d. 25N

Answers

F = ma
F = (20kg) x 25
= 500N
So your answer is C :)
Always remember “FAM” In the shape of a triangle … so F will be at the top and A&M at the bottom that way you will remember that F = mass x acceleration

How is a controlled variable different from a responding variable? O A. A controlled variable changes due to changes in the responding variable during the experiment. B. A controlled variable stays the same throughout an experiment, but a responding variable changes, C. A controlled variable changes throughout an experiment, but a responding variable stays the same. O D. A controlled variable stays the same due to changes in the responding variable during the experient.​

Answers

Answer:The controlled variable is the one that you keep constant. The responding variable or variables is what happens as a result of the experiment

Explanation:Mark me brainly please

Q2) You pick up some nails with your fingers from a pile of nails and find that they appear to stick together. Are they made out of iron or steel? Explain your answer.

Answers

Answer:

Iron is correct answer. ... Since Magnet is also made up of Iron, Nickel and Cobalt. Therefore, it attracts iron towards it.

Hi can u help me in my physics homework

Answers

Answer:

a.) [tex]5 seconds[/tex]

b.) [tex]9.5 m/s[/tex]

Explanation:

Solution is attached.

A boy standing on a bridge 150m above the canyon floor throws a stone downward with a speed of 20.0m/s.
A) with what velocity will it hit the ground?
B) How long will it take to descend?

Answers

Answer:

57.97m/s

12.1s

Explanation:

Use one of the key equations of accelerated motion and sub in the values

vf^2=vi^2+2aΔd

vf^2=(20)^2+(2*9.8)(150)

vf^2 = 3340

vf = 57.79m/s (square rooted both sides)

now use another equation

Δd = (vi+vf/2)Δt

and rearrange for Δt

Δt = (2Δd-vf)/vi

sub in values

Δt = (2*150-57.79)/20

Δt = 12.1s

mark me as brainliest if this helped!

The steepest street in the world is Baldwin Street in Dunedin, NZ. It is inclined at an angle of 380 , with the horizontal. A child slides down the street with a constant velocity on a sled with high friction runners. What is the coefficient of friction between the sled runners and the street?

Answers

Newton's second law allows to find the result for the friction coefficient of the street is:

The friction coeficinwete is: μ = 0.78

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body.

           ∑ F = m a

Where bold indicates vectors, m is to mass and acceleration.

In the attached we see a free body diagram, it is a diagram of the forces without the details of the body, the x-axis is parallel to plane also shown with the positive in the direction of movement, going down the plane and the y-axis perpendicular to the plane.

Let's use trigonometry to break down the weight.

        Sin θ = [tex]\frac{W_x}{W}[/tex]  

        cos θ = [tex]\frac{W_y}{W}[/tex] / W

        Wₓ = W sin θ

         [tex]W_y[/tex]  = W cos θ

We write Newton's second law for each axis.

y-axis

         N- [tex]W_y[/tex]  = 0

         N = mg cos θ

x-axis

        Wₓ - fr = ma

Since they indicate that the body goes down at a constant speed, the acceleration is zero.

         W sin θ = fr

The friction force is the macroscopic representation of the interactions between the two surfaces and the formula.

         fr = μ N

we substitute.

          fr = μ mg cos θ

         mg sin θ = μ cos θ  

        μ = tan θ

Let's calculate.

         μ = tan 38.0

         μ = 0.78

In conclusion using Newton's second law we can find the results for the friction coefficient of the street is:

The frivtion coefficient is:  μ = 0.78

Learn more about the coefficient of friction here:  brainly.com/question/11808898

If the momentum of the NASA space shuttle as it leaves the atmosphere is 3.75 x 10^8 kg ·m/s and its mass is 75000 kg, what is its speed?

Answers

Hi there!

We know that:

Momentum (p) = mass (kg) × velocity (m/s)

Or:

P = mv

We can rearrange the equation to solve for speed:

P/m = v

Plug in the given values:

(3.75 × 10⁸)/75000 = 5000 m/s

In the year 2081 in a shipping port on the moon, workers for Ore-Space, Inc., hoist a 500.0 kg hunk of anorthosite moon rock by a chain. (Neglect the weight of the chain.) The block is initially accelerating at 4.0 m/s.


How much force is being exerted by the chain?

Answers

Answer:

2,800 n

Explanation:

hope this helps, have a nice day/night! :D

The force of 2812.5 N is being exerted by the chain.

What is force?

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Given that:

Mass of the  hunk of anorthosite moon rock : m = 500.0 kg.

Acceleration of the hunk: a = 4.0 m/s².

Acceleration due to gravity in moon = 1.625 m/s².

So, required force = 500.0(4.0 +1.625) n = 2812.5 N.

The force of 2812.5 N is being exerted by the chain.

Learn more about force here:

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If the pressure of a gas is kept constant and the temperature (in Kelvin) is cut in half, the volume will _________.

Answers

Answer: be cut in half

Explanation:

Rope A is tied to block 1, and rope B is attached to both block 1 and block 2 as shown in the diagram. Block 1 has a mass of 4.2 kg and block 2 has a mass of 2.6 kg. You lift both blocks straight up. Calculate the magnitude of tension in each of the ropes when the blocks

Move at constant velocity of 1.5 m/s [up]
Find the magnitude of tension in each rope when the blocks are accelerating at 1.2 m/s^2 [up].
The maximum tension the strings can withstand is 90. N. Knowing this, determine the maximum acceleration of the blocks that would not break the rope.

Answers

Hi there!

Part 1:

If the blocks are moving at a constant velocity:

∑F = 0

Begin by summing the forces acting on each block. Let the upward direction be positive.

∑F₁ = Ta - M₁g - Tb

∑F₂ = Tb - M₂g

Sum the forces:

∑F = Ta - M₁g - Tb + Tb - M₂g

∑F = Ta - M₁g - M₂g = 0

Solve for Tension A:

Ta = M₁g + M₂g (Let g = 9.8 m/s²)

Ta = 4.2(9.8) + 2.6(9.8) = 66.64 N

Now, solve for tension B using the summation of ∑F₁:

0 = Tb - M₂g

Tb = (2.6* 9.8) = 25.48 N

Part 2:

We can use the same method, but incorporate the acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

(M₁ + M₂)a + M₁g + M₂g = Ta

(4.2 + 2.6)(1.2) + 4.2(9.8) + 2.6(9.8) = 74.8 N

∑F₂ = Tb - M₂g

M₂a + M₂g = Tb  = 28.6 N

Part 3:

Since the top string experiences most of the tension, we can use its equation to calculate the maximum acceleration:

∑F = Ta - M₁g - M₂g

(M₁ + M₂)a = Ta - M₁g - M₂g

a = (90 - M₁g - M₂g)/(M₁ + M₂)

a = 3.435 m/s²

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If it was not for you, I would never have turned over a new leaf," Sam whispered in gratitude, recalling the drunken man he saw a while ago.A year ago, after being retrenched from his computer company, Sam felt dejected and worried about how he was going to provide for his family. The situation worsened when he failed to secure a job after months of intensive searching. Soon, Sam began to indulge in alcoholic drinks to drown his sorrows. His savings which was used to sustain the family expenses during his retrenchment was tremendously depleted by his drinking habits. Soon his wife, Catherine, became the family's sole bread winner.Catherine's efforts to stop Sam from drinking were futile. Alcohol had transformed the once-gentle family man into a violent beast. Sam began to hit his wife when she refused to give hi money for his drinks. Once Catherine tried hiding his drinking bottles, hoping to stop Sam from drinking. Sam was so agitated when he could not find his bottles that he locked Marie into her bedroom and threatened her into revealing the hiding place. The incident instilled terror in Marie and thereafter, she tried her best to avoid SamThese traumatic incidents continued until the launch of the "stop Drinking" campaign by the government. Striking and persuasive posters were put up in the public to persuade alcoholics to kick their habit. None of them succeeded in bringing Sam to his senses except one. The poster illustrated an alcoholic man abusing his wife while their terrified daughter cried helplessly. The slogan accompanying the poster was: 'Will Your Children Be Able To Draw A Happy Family Again?'. Sam suddenly recalled a poster entitled 'Happy Family' drawn by Marie for school before he began drinking. As if released from a spell, he realized how irresponsible and abusive he had been. Overcome with guilt, he quit drinking totally."Sam, why aren't you going to sleep?" asked a concerned Catherine."I'm coming, Catherine," Sam replied with a smile as he headed for his room Write a program that copies only unsigned numbers from Array1 to another Array2. The Array1 has both signed and unsigned numbers in assembly language 1messageTwo friends went bowling. One friend scored 130 points and the other friend scored 83 points. How does the value represented by the 3 in 130 compare to the value represented by the 3 in 83?It is 3 times greaterIt is 10 times greaterIt is 47 times greaterIt is 50 times greater 58. The frequency distribution below summarizes employee years of service for Alpha Corporation. Determine the width of each class.Years of service Frequency1-56-102011-152516-201021-25526-30 During the summer, the __________ Hemisphere is tilted toward the Sun, and the weather conditions are relatively calm. Brian invests 7500 into his bank account. He receives 6% per year compound interest. How many years will it take for Brian to have more than 10000?