For a given recipe, 8 cups of flour are mixed with 12 cups of sugar. How many cups of flour should be used if 27 cups of sugar are used? Assuming a constant ratio, fill out the table of equivalent ratios until you have found the value of x.

Taking into account the definition of a system of linear equations, the cost of each shirt is 12 and the cost of each pair of slacks is 18.

A system of linear equations is a set of two or more equations of the first degree, in which two or more unknowns are related.

Solving a system of equations consists of finding the value of each unknown so that all the equations of the system are satisfied. That is to say, the values ​​of the unknowns must be found and they must give the solution proposed in both equations.

In this case, a system of linear equations must be proposed taking into account that:

You buy 3 shirts and 2 pairs of slacks on sale at a clothing store for 72. The next day, a friend buys 2 shirts and 4 pairs of slacks for 96.

So, the system of equations to be solved is

[tex]\left \{ {{3S + 2PS=72} \atop {2S + 4PS=96}} \right.[/tex]

To solve a system of equations, it is decided to solve it using the substitution method, which consists of clearing one of the two variables in one of the equations of the system and substituting its value in the other equation.

Isolating the variable S from the first equation, you obtain:

3S= 72 - 2PS

S= (72 - 2PS)÷3

S= 72÷3 - 2PS÷3

S=24- 2/3PS

Replacing this expression in the second equation:

2(24 - 2/3PS) + 4PS= 96

Solving:

2×24 - 2×2/3PS+ 4PS= 96

48 - 4/3PS + 4PS= 96

48 + 8/3PS= 96

8/3PS= 96 - 48

8/3PS= 48

PS= 48÷ 8/3

PS= 18

Replacing this value in the expression S=24- 2/3PS, you obtain:

S= 24 -2/3×18

S= 24 - 12

S= 12

Finally, the cost of each shirt is 12 and the cost of each pair of slacks is 18.

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In the Second order decomposition, 2.0008 m are needed after 78.3 s, the concentration of the remaining HI is 3.56 m.

Second-Order Reaction:

A second-order reaction system with a single reactant species will have a squared dependence of the reaction rate on this reactant's molarity value. Therefore, the rate will show an exponential decrease over time as the reactant is consumed.

The integrated rate law for a second-order reaction is

1/[A]t = 1/[A]0 + kt

where

[A]t = the concentration of A at time t

[A]0 = the concentration of A at time 0 (i.e., at the beginning of the reaction)

k = the rate constant for the reaction

Given,

The second-order decomposition of hi has a rate constant of 2.80 x 10⁻³ m⁻¹s⁻¹.

Time = 78.3 s

Initial Concentration = 3.56 m

Here we need to find the second order decomposition.

Apply the values on the formula,

Then we get,

=> 1/[A]t = 1/(3.56 m) + 2.80 × 10⁻³ m⁻¹s⁻¹ x 78.3 s

=> 1/[A]t = 0.28 m⁻¹ + 0.2192 m⁻¹

=> 1/[A]t = 0.4992 m⁻¹

=> 1/[A]t = 1/0.4992 m

=> 1/[A]t = 2.0008 m

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Answer:

Step-by-step explanation:

Answer is 4250 students attend the college

4250 x .56 = 2,380

Answer:

Step-by-step explanation:

18/24=3/4

Answer:Translation

Step-by-step explanation:

Answer:

Could you show how the graph looks like?

Step-by-step explanation:

Answer:

2x(x + 3)

Step-by-step explanation:

2x² + 6x ← factor out 2x from each term

= 2x(x + 3)

Answer:

5 ornaments

Step-by-step explanation:

2 ornaments is 6 hours = 2/6 ornaments/hour = 1/3 ornaments/hour

1/3 ornaments/hour × 15 hours = 5 ornaments

Answer: 32 copies $3170

Step-by-step explanation:

The Properties that are used to solve 3+7+2+5+9 are Closure Property of Addition and Multiplication , Commutative Property of Addition and Distributive Property Reverse .

In the question

the given expression is 3+7+2+5+9

= 3+7+2+5+9

= 3+9+5+9        ( Closure Property of Addition as 7+2=9 )

= 3+5+9+9        ( Commutative Property of Addition as 9+5=5+9 )

= 8+9+9            ( Closure Property of Addition as 3+5=8 )

= 8+(1+1)9          ( Distributive Property Reverse )

= 8+2*9             ( Closure Property of Addition as 1+1=2 )

= 8+18               ( Closure Property of Multiplication as 2*9=18 )

=26                   ( Closure Property of Addition as 8+18=26 )

Therefore , the Properties that are used to solve 3+7+2+5+9 are Closure Property of Addition and Multiplication , Commutative Property of Addition and Distributive Property Reverse .

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Using complementary angles, the measure of angle 4 is of 39º.

If two angles A and B are complementary, the sum of their measures is of 90º.

In this problem, angles 3 and 4 are complementary, hence:

m<3 + m<4 = 90º.

Angles 1 and 3 are opposite by the same vertex, hence they are congruent and we can find x as follows:

m<1 = m<3

4x - 13 = 2x + 19.

2x = 32

x = 16.

The measure of angle 3 is given by:

m<3 = 2(16) + 19 = 51.

Hence the measure of angle 4 is found as follows:

m<3 + m<4 = 90º.

51 + m<4 = 90º.

m<4 = 39º.

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Final answer:

I would play the game because we could win with probability 17/27.

Information about the possibility that something will happen is provided by probability. For instance, meteorologists use weather patterns to forecast the likelihood of rain. Probability theory is utilized in epidemiology to comprehend the connection between exposures and the risk of health outcomes.

According to the First Law of Probability, the outcomes of one chance event have no bearing on those of succeeding chances occurrences. Consequently, the chance of getting heads the second time you flip it remains at 1 in 2. The chances of getting heads on the sixth flip, even if you got five consecutive heads, stay at 12.

Everyday existence heavily relies on probability. Weather predictions, sports and gaming tactics, insurance purchases or sales, internet shopping, and online gaming.

Explanation:

If both of your dice, or at least one of them, match at least one of the other player's dice, you win. This provides us five scenarios where we win. Let's use the letters A, B, C, and D to represent the results of the dice, with your dice being A and B and the other player's being C and D. The five possibilities are:

1) [tex]A = B[/tex]

2) [tex]A = C[/tex]

3) [tex]A = D[/tex]

4) [tex]B = C[/tex]

5) [tex]B = D[/tex]

A B C D

1) [tex]6 * 1 * 6 * 6[/tex] A can be anything, B has 1 option, C and D can be anything.

2) [tex]6 * 5 * 1 * 6[/tex] A can be anything, C has 1 option, A != B so B has 5 options.

3) [tex]6 * 5 * 5 * 1[/tex] A can be anything, D has 1 option, A !=B and A != C so B and C have 5 options.

4) [tex]5 * 6 * 1 * 5[/tex] B can be anything, C has 1 option, A != B and A != D so B and D have 5 options.

5) [tex]5 * 6 * 4 * 1[/tex] B can be anything, D has 1 option, A != B so A has 5 options, C != A and C != B so it has 4 options.

Therefore, it becomes [tex](6^3 + 6^2*5 + 2*6*5^2 + 6*5*4) / 6^4[/tex]

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The location of the orca relative to the surface of the water is 13.36 below the surface

The given parameters are

Initial = 0 feet i.e  surface of the water

Dives below = 25.5 feet.

Swims up = 12.14 feet.

The location of the orca relative to the surface of the water is calculated as

Location = Initial - Dives below + Swims up

This gives

Location = 0 - 25.5 + 12.14

Evaluate

Location = -13.36

Hence, the location of the orca relative to the surface of the water is 13.36 below the surface

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The correct answer 4+3w=5.

Variables in an equation are typically English alphabets and can have any real value that the equation is satisfied with. They also include coefficients and constants. In an equation, constants are the independent numbers for the variables, and coefficients are the numbers connected to the variables. Algebraic equations with orders equal to one or one are known as linear equations.

An analytical claim that two things are equal is known as an equation. Either a term or an expression are present in an equation. An equation is a statement of equality in mathematics that contains one or more variables.

Let the unknown variable be w,

4+(w×3)=5

4+3w=5

Solving ,

3w=5-4

3w=1

w=1/3

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Answer:

scale factor = 3

Step-by-step explanation:

the scale factor is the ratio of corresponding sides, copy to original , so

scale factor = [tex]\frac{12}{4}[/tex] = [tex]\frac{9}{3}[/tex] = 3

Answer: -100/27

Step-by-step explanation:

[tex]x^3 - 4[/tex]=

[tex](\frac{2}{3} )^3 - 4[/tex]=

[tex](\frac{2^3}{3^3} ) - 4[/tex]=

[tex]\frac{8}{27} - 4[/tex]=

([tex]\frac{8}{27} - 4[/tex])*27/27=        ==> multiply by 27 to get rid of denominator

(8-4*27)/27=

(8-108)/27=-100/27

Answer:

y=-3x-7/3

Step-by-step explanation:

You just subtract 18x from both sides and then divide by 6 on both sides to get it, lmk if that was what your asking for :)

The number of groups of 3/4 that are in 11/4 will be 3 2/3.

The number of 3/4 that are in 6 1/2 will be 8 2/3.

It should be noted that from the diagram given, you want to get solutions to the numbers circled and this will be solved accordingly.

The number of groups of 3/4 that are in 11/4 will be:

= 11/4 ÷ 3/4

= 11/4 × 4/3

= 11/3

= 3 2/3

Also, the number of 3/4 that are in 6 1/2 will be:

= 6 1/2 ÷ 3/4

= 13/2 ÷ 3/4

= 13/2 × 4/3

= 26/3

= 8 2/3

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Answer: D

Step-by-step explanation:

Quotient means division

The puck travelled a distance of 53.8 meters when the puck is 120 centimeters before the opponent's goal and puck travelled a distance of 56.2 meters when the puck is 120 centimeters after the opponent's goal.

Given that the distance to the opponent's goal from the player's current position is 55 meters. And after the shot, the puck is 120 centimeters from his opponent's goal.

We need to find out how many meters the puck travelled.

Also given there are 100 centimeters in 1 meter.

So, 55 meters = 55 × 100 centimeters

⇒ 55 metets = 5500 centimeters

Now, we are given that the puck is 120 centimeters from the opponent’s goal. It is not clear whether the puck landed before or after the goal post. So, considering both cases.

Case 1: the puck is 120 centimeters beyond the opponent's goal.

So, the distance travelled by the puck is

5500 centimeters + 120 centimeters = 5620 centimeters

Divide 5620 by 100 to convert centimeters to meters.

The puck travelled a distance of 5620 cm or 56.2 meters.

Case 2: the puck is 120 centimeters before the opponent's goal.

So, the distance travelled by the puck is

5500 centimeters - 120 centimeters = 5380 centimeters

Divide 5380 by 100 to convert centimeters to meters.

The puck travelled a distance of 5,380 cm or 53.8 meters.

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Answer:

y=3x-7

Step-by-step explanation:

Choose 2 points.

(3, 2) and (4, 5)

Use slope formula.

y2-y1/x2-x1

5-2/4-3=

=3/1=3

Slope is 3.

The y-intercept is when x is 0. The y-intercept was already given. It is -7.

Y-intercept is -7.

Now you can use the slope-intercept formula.

y=mx+b

m=slope=3

b=y-intercept=-7

y=3x-7

Hope this helps!

Please mark as brainliest if correct!

Answer:

A

Step-by-step explanation:

answer:

3/8 is the slope, also stated as .4 (from 3.75)

the segment length is 8.5 (using the pythagorean theorem)

Answer:

$2.50

Step-by-step explanation:

The parametric equations for this line :

x=11+5s , y=4s , z=2+6s

The value of t that creates the point (11,0,2)

Substitute 11 for x:

11

10

t=1

check that t=1 works for the y and z values:

15−1=0

15+1=2

These check, t=1

Tangent vector:

dxdt=5√t

dydt=5t4−1

dzdt=5t4+1

The tangent vector for all points, ¯v(t), is:

¯v(t)={5√t}ˆi+{5t4−1}ˆj+{5t4+1}ˆk

The tangent vector at the indicated position is the object of our interest:

¯v(1)=5ˆi+4ˆj+6ˆk

The vector equation of the tangent line :

(x,y,z)=(11,0,2)+s(5ˆi+4ˆj+6ˆk)

Parametric equations can be used to describe all types of curves that can be represented on a plane but are most often used in situations where curves on a Cartesian plane cannot be described by functions (e.g., when a curve crosses itself).

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The parametric equation of the line that passes through the points (5,2,7) and (8,–6,1) is [tex]\vec r= < 5,2,7 > +\lambda < 3,-8,-6 >[/tex]

Also, the point (17,–30,31) does not lie on the line.

for given question,

We need to find the parametric equation of the line that passes through the points (5,2,7) and (8,–6,1)

Let [tex]\vec r_0= < 5,2,7 >[/tex]

and

[tex]\vec v= < 8-5,-6-2,1-7 > \\\\\vec v= < 3,-8,-6 >[/tex]

where vector v is the direction vector.

So, the equation of the line would be,

[tex]\vec r=\vec r_0+\lambda \vec v\\\\\vec r= < 5,2,7 > +\lambda < 3,-8,-6 >[/tex]

Now we need to determine whether the point (17, -30, 31) is on the line.

Let [tex]< 17,-30,31 > = < 5,2,7 > +\lambda < 3,-8,-6 >[/tex]

For first component,

⇒ 17 = 5 + 3λ

⇒ 3λ = 12

⇒ λ = 4

For the second component,

⇒ -30 = 2 - 8λ

⇒ -8λ = -32

⇒ λ = 4

For third component,

⇒ 31 = 7 - 6λ

⇒ -6λ = 24

⇒ λ = -4

since the values of the λ are not consistent, the point (17,–30,31) does not lie on the line.

Therefore, the parametric equation of the line that passes through the points (5,2,7) and (8,–6,1) is [tex]\vec r= < 5,2,7 > +\lambda < 3,-8,-6 >[/tex]

Also, the point (17,–30,31) does not lie on the line.

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The unit segments from 3 to 7 are infinite.

The number from 3 to 7 is given.

We have to find out the no. of segments between the two numbers.

What is algebra ?

Algebra is the branch that deals with various symbols and the arithmetic operations such as addition , division , etc.

As per the question ;

Consider any number x such that 3 < x < 6

Then ;

The segment from x to x+1 is a unit segment and, by definition, it will lie within the interval to 7.

As, there are infinitely many possible choices for x, then there are infinitely many unit segments.

i.e.,

from 3 to 4

from 3.1 to 4.1

from 3.01 to 4.01

from 3.00002 to 4.00001

and you can keep adding decimal digits forever.

Thus , there are infinite unit segments from 3 to 7.

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Answer: I hope this helps you.

Step-by-step explanation:

The given vector can be expressed as B = B (cos θ  x ^ + sin θ  y ^)

The strength of the field and its angle with respect to a particular coordinate axis must be known in order to express the magnetic field B using unit vectors. Trigonometry can be applied after this information is known.

Let's utilize trigonometry if the angle we have is with respect to the x-positive axis's side.

          cos θ = Bₓ / B

            sin θ = B / B

            Bx = By cos θ

            B_{y} = B sin θ

so the resulting vector is

            B = Bₓ i ^ + B_{y} j ^

unit vectors

            x ^ = i ^

            y ^ = j ^

B = B (cos θ  x ^ + sin θ  y ^)

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Answer:

third one for me same thing.