Find the mass of 5.60 L O2 at 1.75 atm and 250.0 K

Answers

Answer 1

Answer:

Moles O2 = pV/RT = 2.75 x 5.60 / 0.08206 x 250=0.751

mass = 32 g/mol x 0.751 mol= 24.0 g

Explanation:

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Answer 2

The mass of 5.60 Liter oxygen at 1.75 atm pressure and 250.0 K temperature is 24.0 gram.

What is ideal gas equation?

Ideal gas equation is a hypothesis which tells about the behavior of gas at standard condition and it is represented as:

PV = nRT, where

P = pressure = 1.75 atm

V = volume = 5.60 L

R = universal gas constant = 0.0821 L.atm /K.mol

T = temperature = 250 K

n is the moles of gas which will further define as:

n = W/M, where

W = required mass

M = molar mass

Now putting all the value in the above ideal gas equation and calculate for moles as:

n = (1.75)(5.60) / (0.0821)(250)

n = 0.751

Molar mass of oxygen is 32 g/mol and we calculate their required mass as:
W = 32 g/mol x 0.751 mol= 24.0 g

Hence, the required mass of oxygen is 24.0 g.

To know more about ideal gas equation, visit the below link:
https://brainly.com/question/25290815


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Using the balanced chemical equation:
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Determine the amount of grams of N2 is produced If 4.03 moles of NH3 react?

Answers

Your answer and workings are all mentioned in the picture below.

Taking into account the reaction stoichiometry, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Reaction stoichiometry

In first place, the balanced reaction is:

4 NH₃ + 3 O₂  → 2 N₂+ 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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The molar mass of the compounds is:

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Mass of N₂ formed

The following rule of three can be applied: if by reaction stoichiometry 4 moles of NH₃ form 56 grams of N₂, 4.03 moles of NH₃ form how much mass of N₂?

[tex]mass of N_{2} =\frac{4.03 moles NH_{3} x56 grams of N_{2} }{4 moles NH_{3}}[/tex]

mass of N₂= 56.42 grams

Then, 56.42 grams of N₂ are formed when 4 moles of NH₃ react.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

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