Find AC. FIND X USING THE PICTURE. BELOW. WILL MARK BRANLIEST FOR FIRST ONE TO ANSWER

Find AC. FIND X USING THE PICTURE. BELOW. WILL MARK BRANLIEST FOR FIRST ONE TO ANSWER

Answers

Answer 1

Answer:

AC ≈ 50.5

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan29° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{BC}{AC}[/tex] = [tex]\frac{28}{x}[/tex] ( multiply both sides by x )

x × tan29° = 28 ( divide both sides by tan29° )

x = [tex]\frac{28}{tan29}[/tex] ≈ 50.5 ( to the nearest tenth )

Answer 2

Answer:

50.5

Step-by-step explanation:

In the right triangle, focus on angle A.  The side marked 28 is the opposite side, and the side marked  x  is the adjacent side.  The trigonometric ratio that uses those two side is the tangent ratio.

tangent = (opposite) / (adjacent)

[tex]\tan{29^\circ}=\frac{28}{x}[/tex]

Multiply both sides by  x.

[tex]x\cdot \tan{29^\circ}=28[/tex]

Divide by tan 29 degrees.

[tex]x=\frac{28}{\tan{29^\circ}}[/tex]

Use a calculator (in degree mode!) to approximate  x.

[tex]x \approx 50.5[/tex]


Related Questions

Write the equation of a sine or cosine function to describe the graph.

Answers

Answer:

Step-by-step explanation:

Average = (Ymax + Ymin)/2 = (4 + (- 2))/ 2  = 1

Amplitude =  (Ymax - Ymin)/2 = (4 - (- 2))/ 2  = 3

y is at a maximum when x = 0, so cosine function is easy.

one cycle (2π radians) is completed in 2π/3

therefore

y = 1 + 3cos(2π(x /(2π/3))

y = 1 + 3cos(3x)

Answer(s):

[tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1 \\ y = 3cos\:3x + 1[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 1 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{\pi}{6}} \hookrightarrow \frac{-\frac{\pi}{2}}{3} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 0 \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{3}\pi \\ Amplitude \hookrightarrow 3[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 3sin\:3x + 1,[/tex]in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{6}\:unit[/tex]to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{6}\:unit,[/tex]which means the C-term will be negative, and by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{\pi}{6}} = \frac{-\frac{\pi}{2}}{3}.[/tex]So, the sine graph of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 3sin\:(3x + \frac{\pi}{2}) + 1.[/tex]Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [-\frac{2}{9}\pi, -\frac{1}{2}],[/tex]from there to [tex]\displaystyle [\frac{4}{9}\pi, -\frac{1}{2}],[/tex]they are obviously [tex]\displaystyle \frac{2}{3}\pi\:units[/tex]apart, telling you that the period of the graph is [tex]\displaystyle \frac{2}{3}\pi.[/tex]Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = 1,[/tex]in which each crest is extended three units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

7+q+4=4+7+q
What property?

Answers

Answer:

Commutative Property of Addition

Step-by-step explanation:

This is because the commutative property of addition and multiplication is

[tex]a+b=b+a\\a*b=b*a[/tex]

and as an example

[tex]5+9=14 \\9+5=14\\10*6=60\\6*10=60[/tex]

Hello everybody! Can anybody help me out with this fairly simple multiple choice algebra problem? Thanks! ​

Answers

Answer:

l = P -2w

________ D is the correct choice

2

pls help me right now!

and pls show your solution properly​

Answers

I'm not good in math ok bye

A) Atra = 0.5 ( 7 + 3 ) x 3 = 15 cm^2

B) Atri1 = 1/2 x 3 x 2 = 3 cm^2

Atri2 = 1/2 x 3 x 2 = 3 cm^2

Arec = 3 x 3 = 9 cm^2

Atra = Atri1 + Atri2 +  Arec = 3 + 3 + 9 = 15 cm^2

ok done. Thank to me :>

what if 5476 divided by 74? i need the working out too please!

Answers

I hope that the attachment helps you..

Simplify.

81‾‾‾√

18

9

−3

−18

Answers

9514 1404 393

Answer:

  (b)  9

Step-by-step explanation:

Maybe you want to simplify ...

  [tex]\sqrt{81}=\sqrt{9^2} =\boxed{9}[/tex]

I NEED HELP !!!! PLZ HELP ME UNDERSTAND THIS

Answers

Answer:

Step-by-step explanation:

an alloy is 70% iron. How much of this alloy do you need if you want to obtain 50.35 lb of iron?

Answers

Answer:

1007/20

Step-by-step explanation:

You helped me so i help you. Here you go my friends sorry i dont have an explanation. Good luck !

Use proportions.  X is what you want.

70      50.35lb

__  =   _____

100          x

Cross multiply to get 70x = 5035

Solve to get about 71.93 lbs of the alloy.

Can someone please help me I will mark u brilliant

Answers

Answer:

the whole number 5 goes to the left of the decimal

Step-by-step explanation:

so think about it this way...

I have  10 dots   ..........  that is 1.0 but if I only have 5 of the 10 I have 0.5. if you have anymore questions just ask and ill help

Rachel invests $25,000 at age 25. She hopes the investment will be worth $125,000 when she turns 50. If the interest compounds continuously, approximately what rate of growth will she need to achieve her goal? Round to the nearest tenth of a percent.

Answers

The rate of growth will she need to achieve her goal is 2.8%

The formula for finding the compound amount is expressed as:

[tex]A =P(1+\frac{r}{n} )^{nt}[/tex]

P is the amount invested = $25000

t is the time in years = 25 years

A is the amount = $125000

r is the rate in %

Substitute the given parameters into the formula to have:

[tex]125000 =25000(1+r )^{25}\\5 =(1+r)^{25}\\log5=25log(1+r)\\log(1+r)=\frac{log5}{25} \\log(1+r)=0.02796\\1+r = e^{0.02795}\\1+r=1.0283\\r = 1.0283 -1\\r = 0.0283\\[/tex]

Hence the rate of growth will she need to achieve her goal is 2.8%

Learn more about compound amount here: https://brainly.com/question/18442810

Can you help please?

Answers

Answer:

Step-by-step explanation:

Show all work to identify the asymptotes and zero of the function f of x equals 3 x over quantity x squared minus 9.

Answers

Answer:

Asymptotes: x = -3, x = 3, y = 0

Step-by-step explanation:

Given function:

f(x) = 3x / (x² - 9)

Zero of the function:

f(x) = 03x / (x² - 9) = 0x = 0, x ≠ -3; 3

Vertical asymptotes:

x² - 9 = 0x² = 9x = √9x = -3; x = 3

Horizontal asymptotes:

The horizontal asymptote is y = 0, since the degree of the numerator is 1, while the degree of the denominator is 2.

The graph with asymptotes and zero is attached

Find the 20 th term of the given sequence 2, 5, 8, 11,..

Answers

Answer:

14,17, 20

Step-by-step explanation:

Kindly see the picture I have solved it as required

10% of $70 = what is the answer i do not now it.

Answers

Answer:

10% 0f 70 is 7

Step-by-step explanation:

70÷10=7

10%=7

Due Tomorrow: Answer question 21 with steps

Answers

[tex]\\ \sf\longmapsto tan28=\dfrac{BC}{AC}[/tex]

[tex]\\ \sf\longmapsto 0.5317=\dfrac{BC}{29.3}[/tex]

[tex]\\ \sf\longmapsto BC=29.3(0.5317)[/tex]

[tex]\\ \sf\longmapsto BC=15.5mi[/tex]

Now

[tex]\\ \sf\longmapsto AB^2=29.3^2+15.5^2[/tex]

[tex]\\ \sf\longmapsto AB^2=848.49+240.25[/tex]

[tex]\\ \sf\longmapsto AB^2=1088.74[/tex]

[tex]\\ \sf\longmapsto AB=32.9mi[/tex]

Josh volunteers at a library. One weekend, he put 234 returned books back on the shelves. Of those books 2/3 were hardcover books and the rest were paperback books. How many paperback books did Josh put back on the shelves?

Answers

Answer: 78 paperback books.

Step-by-step explanation:

1. Since 2/3 of the books are hardcover books, then 1/3 of the books are paperback books.

2. 234/3 = 78 books.

Answer:

78 paperback books

Step-by-step explanation:

234 x (2/3) = 156

234 - 156 = 78

Find a 33 matrix Sij so that the product SijA is the same as the matrix A after applying the row operation Ri $ Rj .

Answers

Answer:

We want the ith row of the new matrix SijA to be the old jth row of A, so we need the ith row of Sij to extract the jth entry of column of A.

This mean the ith row of Sij must have a 1 in the jth entry and 0's everywhere else.

Similarly, the jth row of Sij must have a 1 in the ith entry and 0's everywhere else.

in the piecewise notation this is

(Sij)kl ={1 if k=i and l=j, 1 if k=k and l=i; 1 if k=l but k#i,j, 0 otherwise

Step-by-step explanation:

If an object's position over time is given by the function d(t)=(t^2 +3)e^-1/2 for greater than 0 , on what interval is the object's position increasing and concave down ?

Answers

Answer:

Step-by-step explanation:

[tex]d(t)=(t^2+3)e^\frac{-1}{2} \\d'(t)=2t e^{-\frac{1}{2} }\\it~ is~ increasing ~if~d'(t)>0\\e^{-\frac{1}{2} } =\frac{1}{e^\frac{1}{2} } >0\\so~t>0\\and~decreasing~if~t<0\\[/tex]

so it is concave upward at t=0

Skip count by 100 starting with 95.
95, ____, ____, ____, ____

Answers

Answer:

195, 295, 395, 495?

Step-by-step explanation:

96,97,98, skip number 99 and then 100

evaluate the expression 5+3
some one answer me with a question not a link ​

Answers

Answer:

8

Step-by-step explanation:

Add 5 and 3

-Lexi

Given the function h (x) = –22 - 4, the value of h(-5) would be?

Answers

Answer:

At the value of x = 3 the function H(x) is undefined. (answer is 3)

Step-by-step explanation:

h (x) = 1/(x-5)2 + 4 (x-5) +4

Solution :

We know that for the values of x where denominator is zero the function H(x) is not define.

(x -5)2 +4 (x -5 ) +4 = 0

x2 -6x +9 =0

x2 - 3x - 3x +9 = 0

(x - 3)2 = 0

So x= 3

At x = 3 the function H(x) is undefined. (3 is your answer)

which is the correct answer??
geometry

Answers

Answer:

SAS || Side - Angle - Side

Step-by-step explanation:

You have 2 sets of congruent sides, and one set of congruent angles between them. (SAS)

That angle is congruent because ∠QRP and ∠TRS are vertical angles, and vertical angles have the same measurement.

Dylan had 300 5p coins in a box last month. He now has 360 5p coins. Find the percentage increase.

Answers

300 + 60 = 360360 ÷ 5 = 72

Therefore the percentage increase is 72

72

A shoe store uses a ​40% markup for all of the shoes it sells. What would be the selling price of a pair of shoes that has a wholesale cost of ​$71​?

Answers

Answer:

40% * 71 = Markup price

40% of 71 is 28.4, so i added the two together and got 99.4

so...

$28.4 + $71 = $99.40

Tp 3 Work Backwards
1. Bowser, Abby, and Chuckles are 3 dogs with a
combined age of 44. Bowser is 6 years older than
Abby. Abby is 2 years younger than Chuckles, c.
Which expression could be used to find the age of
Chuckles?

Answers

Answer:

Your equation option is possibly in here somewhere.

Step-by-step explanation:

A = C - 2

B = A + 6  → A = B - 6

C - 2 = A = B - 6 → B = C + 4

44 = C + B + A

44 = C + (C + 4) + (C - 2)

44 = 3C + 2

42 = 3C

C = 7

Javier worked 45 hours last week. His hourly rate for hours worked is $ 8.75 . After his 40 hour work week, he is paid time and a half for overtime. What is Javier’s gross pay for last week?

Answers

Pay for regular time = 40 hours x $8.75 = $350

Pay for overtime:
45-40= 5 hours

Overtime rate = $8.75 x 1.5 = 13.125

> 13.125 x 5 = 65.625

His gross pay= 65.625 + $350 = $415.625

The gross pay that Javier gets for last week is $415.625.

What is rate?

Rate is a measurement to determine the change in one quantity with respect to another quantity.

Given that,

Rate for 1 hour = $8.75,

Since, Javier worked 45 hours last week,

So total amount got by Javier = 45×8.75=393.75

According to condition,

Last 5 days Javier is paid half more amount for overtime,

Therefore,

Javier amount of overtime gets by Javier in last 5 days

=8.75×5/2

=21.875

Total amount = 393.75+21.875=415.625

So the gross pay for last week is $415.625.

To know more about Rate on :

https://brainly.com/question/28580620

#SPJ2

if someone helps me with dis ill def give em brainliest​

Answers

Answer:

with what?

Step-by-step explanation:

I think you forgot to attach something.

Please answer and show your work

Answers

Answer:

check online for more information

Use the table below to answer the following question,
2:
хо 1 2 3 4 5 6
y 100 200 400 800 1,600 3,200 6,400
Which equation BEST fits the data given in the table?
se 3:
Of(x) = { (200)*
Of(x) = 100(2)*
uge 4
f(x) = 200)
age 5
Of(x) = 200(2)*
5
Previous Page
Next Page
Page 2 of 11

Answers

Answer Of(x) = 200(2)

Step-by-step explanation:

Of(x) = 200(2)

Find complex numbers z=(x,y) such that
[tex]z ^{2} = - 5 - 12i[/tex]


Answers

Answer:

I don't know..,.............,,.,.......,

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